f. scardina infn-lns catania, university of messina v. greco, m. di toro jet quenching dynamics...
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F. Scardina INFN-LNS Catania, F. Scardina INFN-LNS Catania, University of MessinaUniversity of Messina
V. Greco, M. Di V. Greco, M. Di ToroToro
Jet quenching Dynamics
[Based on arXiv:1009.1261 (today) ]
OutlineOutline Our simple modelOur simple model Quenching observables :Quenching observables :• Nuclear modification factorNuclear modification factor
• RRAAAA(quarks)/R(quarks)/RAAAA(gluons)(gluons) linked to the flavour linked to the flavour dependence of dependence of ΔΔEE
Open questions Open questions
• Simultaneous description of both Simultaneous description of both RRAAAA and and VV22 is yet theoretical challenge – is yet theoretical challenge – “azimuthal puzzle”“azimuthal puzzle”
• High PHigh PTT protons less suppressed than pions protons less suppressed than pions - - flavor puzzleflavor puzzle
Conclusion and future developmentsConclusion and future developments
dydp/Nd
dydp/Nd
N)p(R
Tpp
TAA
collTAA 2
21 22
22
2 2yx
yx
pp
ppcosv
xy z
• Elliptic flowElliptic flow
Modelling jet quenchingModelling jet quenchingOur model is based on the approximation by which jets lose energy in a bulk medium that is expanding and cooling independently from the jets energy loss. Initial conditionInitial condition
Hadronization with Hadronization with AKK fragmentation AKK fragmentation function D(z)function D(z)
Density profile for the Bulk medium
Hard partons distributions in momenta coordinates (pQCD) in space (Ncoll) Energy loss (gluon Energy loss (gluon
bremsstrahlung,GLV) bremsstrahlung,GLV)
20
0
3 2
4
9
TsR P
log,r,CE
0 ,r,Glauber Model (Wood Saxon)Sharp Ellipse
3s
TsConstant
204 QlnTs with 22 2 TQ
Application of the model to evaluate Application of the model to evaluate AAR
AAR Integrated for pT> 6 GeV
For there are non-perturbative mechanisms (coalescence)
GeVPT 5
π0 Au+Au at 200 AGeV
Open questions Open questions
Azimuthal puzzle Azimuthal puzzle Simultaneous description of both RSimultaneous description of both RAAAA and V and V22 is yet a theoretical is yet a theoretical challengechallengeThe experimental data show V2 above theoretical prediction
High PHigh PTT protons less protons less suppressed than suppressed than pionspions
RA
A Au
+A
u c
en
tral
0-1
2%
protons
pions
because they come more from gluons…
…and gluons are more suppressed than quarks ΔΔE for E for gluons=9/4*gluons=9/4* Δ ΔE E for quarksfor quarks
But protons should be more But protons should be more suppressed suppressed
RAA(q)/RAA(g)≤1
Flavor puzzleFlavor puzzle AA
pAA RR
RAA(q)/RAA(g)=9/4
Does it mean?
One solution to azimuthal puzzle: Energy One solution to azimuthal puzzle: Energy loss near Tcloss near Tc
Sharp Ellipse
Wood Saxon
Predominant energy loss at low T [Liao, Shuryak Phys. Rev. Lett. 102 (2009)] Solution of azimuthal puzzle?
We analyze relation between T dependence of quenching and v2,with RAA fixed on Data they are strongly
related
20-30% 20-30%
RRAAAA (quark)/ (quark)/RRAAAA(gluon) and Temperature dependence of (gluon) and Temperature dependence of energy lossenergy loss
The ratio is related to temperature dependence of energy loss it is not necessarely 9/4The ratio is lower if quenching mainly occur close to Tc
RAA fixed on experimental data for pions (RAA=0.2)
Sharp Ellipse
4
9
RRAAAA (quark)/ (quark)/ R RAAAA (gluon) (gluon) profile dependence profile dependence Wood Saxon
The two profiles show opposite behavior
Rigid case is not adequate
Sharp Ellipse
Over simplified case: all quarks lose the same amount of energy and all
gluons lose ΔEgluon =9/4*ΔEquark
Minimal realistic case: 2 classes of quarks quenched + unquenched,
always with ΔEg =9/4*ΔEq
The ratio is dominated by those The ratio is dominated by those particles which do not lose energyparticles which do not lose energy
Sharp Ellipse: direct relation T<->τ
Wood Saxon: No direct relation T<->τ(Surface -> low T also at early times)quenching at low T (later tau)
• Many particles escape without Eloss; those in the inner part must be strongly quenched (red dot dash line)
quenching at low T• E is strong in a layer on the surface -> all particles must cross this layer so all particles lose energy
≠
RRAAAA (quark)/R (quark)/RAAAA(gluon): profile and T dependence of (gluon): profile and T dependence of energy lossenergy loss
One solution to flavor puzzle:Jet conversionOne solution to flavor puzzle:Jet conversion
[Ko, Liu, Zhang Phys. Rev C 75][Liu, Fries Phys. Rev C 77]
We also have introduced this mechanism in our code:
results confirmed
To solve it inelastic collisions that cause a change of the flavor have been invoked[See Ko talk]The conversion rate is given by the collisional width
432144
2
3412432
434
3
333
3
23
23
2
1
2
11
2222222
1
pppp
Mfff
E
d
E
d
E
dg
EKCC
ppp
ppp
RAA(q)/RAA(g)
without conversion Kc=0conversion kc=6
Eloss at high T
GLVcGLV α(T)Eloss at low T
Exp
Correlation RCorrelation RAAAA (quark)/R (quark)/RAAAA (gluon)-V (gluon)-V22
(Wood-Saxon) RAA (PT) fixed on experimental data for pions
Lattice QCD EoS state moves V2 and RAA(q)/RAA(g) to the right
31/T )T(T
To get close to experimental data: DE stronger close to phase transition is need
But If E is stronger close to Tc deviations of (T) from the free gas approximation become important -> use lQCD EoS
n
c
T
TaT
3
1
a= 0.15; n=1.89
flavor conversion becomes more necessary
Eloss at low T EoS lattice QCD
20-30%
Conclusions and Conclusions and PerspectivePerspective
If one goes beyond RAA, a realistic profile for the fireball is needed
Different ΔE(T) generate very different RAA(q)/RAA (g) and v2
Observed v2 and RAA(q)/RAA(g) seem to suggest a ΔE stronger near Tc + a strong flavor conversion
Sensitive to deviation from the free gas expansion (EoS) for Eloss (T~Tc)
What goes on for LHC conditions?
Future DevelopmentsFuture Developments transport code takes into account collisional and radiative energy loss joint to a dynamics consistent with the used EoS
[Greiner Group][Catania]
Initial condition Density profile for the bulkIn longitudinal direction evolves according to the Bjorken expansion at the velocity of light
1. Glauber Model partecipant distribution2. Sharp elliptic shape
Momenta space
High PT partons distribution
Coordinates space (Ncoll)
Dal profilo di densita otteniamo il profilo di T 31
T Ideal gas
The initial transverse density profile can be modelled in two different way
The spectra are calculated in the NLO pQCD scheme
fnfT
f
T Bp
A
pd
dN
12
[Ko, Liu, Zhang Phys. Rev C 75][Liu, Fries Phys. Rev C 77]
The value of the parameters Af ,Bf and nf are taken from Ref.
Glauber Model
AAAA dzz,y,b
xˆy,xT̂
2
NNinelABcoll )b,y,x(T̂BA)b,y,x(N
NucleoniBroglieDe R
The trasverse density profile for the bulk is proportional to the partecipant distribution The hard parton distribution in space coordinates scales with the number of binary Nucleon collision
PartN
aRr
expCr1
0
)b,y,x(T̂)b,y,x(T̂)b,y,x(T̂ BAAB
)b,y,x(N part
Proiezione lungo l’asse x
Density profile for the bulkDensity profile for the jet
Hadronization
)z(Dpd
dNdz
pd
dNhf
f
f
fh
h
22
z=ph/pp
[S. Albino, B. A. Kniehl, and G. Kramer, Nucl. Phys B597]
The parton distribution after the quenching are employed to evaluate the hadron spectrum by indipendent jet fragmentation using the AKK fragmentation function )z(D hf
Ts Tp
Ratio RAA(q)/RAA(g) We consider a simplified case in which all quarks lose the the same amount of energy DE and all gluons lose their energy according to DE=9/4*DE
Spectra are shifted by a quantity equal to the energy lost
Partons that finally emerge with an energy pT Are those which before quenching had an energy pT+e*η where η=1 for quarks and 9/4 for gluons
T
TTAA pf
EpfpR
Epf
pf
pf
Epf
gR
qR
Tg
Tg
Tq
Tq
AA
AA
49
There is no reason why this ratio must be 9/4
Over simplified case: all quark lose the the same amount of energy
and all gluons lose ΔEg =9/4*ΔEquarkMinimal realistic case: 2 classes of quarks undergoing different
quenching, always with ΔEg =9/4*ΔEqThe ratio is dominated by the way The ratio is dominated by the way the energy loss is distributed the energy loss is distributed among partonsamong partonsSharp Ellipse: direct relation T<->τ
Wood Saxon: No direct relation T<->τ(Surface -> low T also at early times)
quenching at high T • particles lose energy early;all particle lose energy (dotted line)
quenching at high T• No DE at the surface but only in the inner part of the fireball (strong DE); particles in the surface escape almost without Eloss
quenching at low T (later tau)• Many particles escape without Eloss; those in the inner part must be strongly quenched blue thin line)
quenching at low T• DE is strong in a layer on the surface -> all particles across this layer so all particles lose energy
≠
RRAAAA (quark)/R (quark)/RAAAA(gluon): profile and T dependence of (gluon): profile and T dependence of energy lossenergy loss
≠