find the surface area of each

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Find the surface area of each. (P)/2 + B = (20×3)(15)/2 + 20√(10 2 +20 2 )/2 = 623.2 in 2 (P)/2 + B (10×6)(14)/2 + (8.7)(10×6)/2 679.8 ft 2 8.7 S = (P)/2 + B = 2π(8)(√(15 2 +8 2 )/2 + π( = 200π ft 2 S = (P)/2 + B = 2π(√(8 2 -6 2 )(8)/2 + π(6 = 70.3π m 2

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Find the surface area of each. S = (P ℓ )/2 + B = 2π(8)(√(15 2 +8 2 )/2 + π(8 2 ) = 200π ft 2. S = (P ℓ )/2 + B = (20×3)(15)/2 + 20√(10 2 +20 2 )/2 = 623.2 in 2. 8.7. S = (P ℓ )/2 + B = (10×6)(14)/2 + (8.7)(10×6)/2 = 679.8 ft 2. S = (P ℓ )/2 + B - PowerPoint PPT Presentation

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Page 1: Find the surface area of each

Find the surface area of each.

S = (Pℓ)/2 + B = (20×3)(15)/2 + 20√(102+202)/2 = 623.2 in2

S = (Pℓ)/2 + B = (10×6)(14)/2 + (8.7)(10×6)/2 = 679.8 ft2

8.7

S = (Pℓ)/2 + B = 2π(8)(√(152+82)/2 + π(82) = 200π ft2

S = (Pℓ)/2 + B = 2π(√(82-62)(8)/2 + π(6.92) = 70.3π m2

Page 2: Find the surface area of each

Ch 12.5Volumes of

Pyramids & Cones

Standard 9.0Students compute the volumes of pyramids and cones and commit to memory the formulas for

pyramids.

Learning Target:I will be able to solve problems involving the volume of pyramids and cones.

Page 3: Find the surface area of each

Theorem 12-11

Page 4: Find the surface area of each

Volume of a Pyramid

Find the volume of the square pyramid.

Answer: The volume of the pyramid is 21 cubic inches.

Volume of a pyramid

Multiply. 21

s 3, h 7

Page 5: Find the surface area of each

Brad is building a model pyramid for a social studies project. The model is a square pyramid with a base edge of 8 feet and a height of 6.5 feet. Find the volume of the pyramid.

A. 416 ft3

B.

C.

D.

Volume of a pyramid

B = s2 , s = 8 , h = 6.5

Multiply.

= (64)(6.5)

= 138.7

V = Bh1313

Page 6: Find the surface area of each

Theorem 12-12

Page 7: Find the surface area of each

Volume of a Cone

A. Find the volume of the oblique cone in terms of π.

Simplify

B = π r2

r = 9.1, h = 25

= 690π

Volume of a coneV = Bh13

Page 8: Find the surface area of each

Volume of a Cone

B. Find the volume of the cone in terms of π.

Simplify.

Volume of a cone

r = 5, h = 12

= 100π

B = π r2

V = Bh13

Page 9: Find the surface area of each

A. 141π m3

B. 8746π m3

C. 112π m3

D. 2915π m3

A. Find the volume of the oblique cone in terms of π.

Volume of a cone

B = π r2 , r = 20.6 , h = 20.6

Multiply.

= π(424.36)(20.6)

= 2915π

V = Bh1313

Page 10: Find the surface area of each

A. 960π m3

B. 40π m3

C. 320π m3

D. 880π m3

B. Find the volume of the cone in terms of π.

Volume of a cone

B = π r2 , r = 8 , h = 15

Multiply.

= π(64)(15)

= 320π

V = Bh1313

Page 11: Find the surface area of each

Find Real-World Volumes

SCULPTURE At the top of a stone tower is a pyramidion in the shape of a square pyramid. This pyramid has a height of 52.5 centimeters and the base edges are 36 centimeters. What is the volume of the pyramidion? Round to the nearest tenth.

Volume of a pyramid

B = 36 ● 36, h = 52.5

Simplify.

= s2 h13

B = s2

Page 12: Find the surface area of each

A. 18,775 cm3

B. 19,500 cm3

C. 20,050 cm3

D. 21,000 cm3

SCULPTURE In a botanical garden is a silver pyramidion in the shape of a square pyramid. This pyramid has a height of 65 centimeters and the base edges are 30 centimeters. What is the volume of the pyramidion? Round to the nearest tenth.

Volume of a pyramid

B = s2 , s = 30 , h = 65

Multiply.

= π(900)(65)

= 19500

V = Bh1313

Page 13: Find the surface area of each