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State of Texas Assessments of Academic Readiness ST A AR TM VOLUME SURFACE AREA AREA Triangle A h = 1 2 b Rectangle or parallelogram A bh = Rhombus A dd = 2 12 Trapezoid A b + 1 2 1 2 ( ) b = h Regular polygon A aP = 1 2 Circle A r = π 2 Prism S Ph = S Ph B = + 2 Pyramid S P B = + l 1 2 S P = l 1 2 Cylinder S rh r = + 2 2 2 π π S rh = 2 π Cone S r = π l S r r = + π π l 2 Sphere S r = 4 2 π Prism or cylinder V Bh = Pyramid or cone V Bh = 1 3 Sphere V r = 3 π 4 Circle or C r = 2 π C d = π STAAR GEOMETRY REFERENCE MATERIALS CIRCUMFERENCE Lateral 3 Total 1

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Page 1: Formula Chart

State of Texas Assessments of

Academic Readiness

STAARTM

VOLUME

SURFACE AREA

AREA

Triangle A h= 12

b

Rectangle or parallelogram A bh=

Rhombus A d d=2 1 2

Trapezoid A b+12 1 2

( )b= h

Regular polygon A aP= 12

Circle A r= π 2

Prism S Ph= S Ph B= +2

Pyramid S P B= +l12

S P= l12

Cylinder S rh r= +2 2 2π πS rh= 2π

Cone S r= π l S r r= +π πl 2

Sphere S r= 4 2π

Prism or cylinder V Bh=

Pyramid or cone V Bh= 13

Sphere V r= 3π4

Circle orC r= 2π C d= π

STAAR GEOMETRYREFERENCE MATERIALS

CIRCUMFERENCE

Lateral

3

Total

1

Page 2: Formula Chart

Pythagorean theorem a b c2 2 2+ =

A C

BTrigonometric ratios

A = opposite leghypotenuse

sin

A = adjacent leghypotenuse

cos

A = opposite legadjacent leg

tan

Midpointx x y y

1 2 1 2

2 2

+ +,

Distance formula d x x y y= − + −( ) ( )2 1

22 1

2

Slope of a line my y

x x=

−2 1

2 1

Slope-intercept form of a linear equation y mx b= +

Point-slope form of a linear equation y y m x x− = −1 1

( )

Standard form of a linear equation Ax By=C+

STAAR GEOMETRYREFERENCE MATERIALS

30°

2xx

60°

x 3

30° – 60° – 90° triangle

x

x

45°

45°

x 2

45° – 45° – 90° triangle

COORDINATE GEOMETRY

RIGHT TRIANGLES

( )