hcl, j( =1) agust,www,...sept10/ppt-211210ak.ppt agust,heima,....sept10/xls-211210ak.xls...
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HCl, j(=1)
agust,www,...Sept10/PPT-211210ak.pptagust,heima,....Sept10/XLS-211210ak.xlsagust,heima,....Sept10/PXP-211210ak.pxpagust,heima,...Sept10/Look for J7-211210.pxpagust,heima,....Sept10/PXP-311210ak.pxpagust,heima,....juni09/grof fyrir J astond-150609hrh.xls
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6.05.55.04.54.03.53.0
agust,heima,....Sept10/PXP-211210ak.pxp; Lay:0, Gr:2
j(=1; S) Green
E(J´,J´-1)
J´
250
200
150
100
50
0
x103
89.2589.2089.1589.10x10
3
J'=7 (?)
S
2 3 4
5
agust,heima,...Sept10/Look for J7-211210.pxp
2? 3 4 5AK assignment
H35Cl+
35Cl+
H+
S
j(=1; S)Green / j(=1; S)AK
NB: 35Cl+/H35Cl+ is very high according to Q line according to KM; see slide 6 below
NB: actuallyThis could be J´=2 (35Cl+)
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765432
agust,heima,....Sept10/PXP-211210ak.pxp; Lay:1, Gr:1
S
j(=1; P,Q,R,S) Green
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765432
Probably not correct since this point should be larger due toInteraction with V, v´=20; see slide 3 above
Fits nicely with the R serie datai.e. points
agust,heima,....Sept10/PXP-211210ak.pxp; Lay:1, Gr:1 & ...XLS-211210ak.xls
S, AK
KM´s paper manuscript (TS(II) paper, version 12.12.10, fig. 2a
0
0.2
0.4
0.6
0.8
1
1.2
1 2 3 4 5 6J´
CalcExp
I(35
Cl+
)/I(
H35
Cl+
) ra
tio
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765432
E(J´,J´-1)
J´
agust,heima,....Sept10/PXP-311210ak.pxp; Lay:2, Gr:3 & ..
j(=1; Q) Green
a = 21.667 ± 3.02b = 18.358 ± 0.498
GreenE(J´)Q
89030.2889087.0289166.7
89261.1989374.9489506.1889656.63
J´01234567
agust,heima,....Sept10/XLS-211210ak.xls
agust,heima,....Sept10/XLS-211210ak.xls
35
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25
20
15
65432
E(J´,J´-1)
J´
agust,heima,....Sept10/PXP-311210ak.pxp; Lay:3, Gr:4 & ..
V(=1; Q), v´=20; Green
a = 1.128 ± 1.84 b = 6.446 ± 0.434
agust,heima,....juni09/grof fyrir J astond-150609hrh.xls
Energy level89085.6
89092.4789107.6189126.4789152.9489187.5489227.03
J'0123456
Orkumunur á þrepum
6.8715.1318.8726.4634.6139.49
agust,heima,....juni09/grof fyrir J astond-150609hrh.xls
)1()1(´)(´)(
)1()1(´)(´)(´0
´0
´´´20
02
02
´0
´0
´´´10
01
01
JJJJBJEJE
JJJJBJEJE
For 1 = Rydberg state and 2 0 ion-pair state
Here Calculated both for j and V,v´=20 states
89.78
89.76
89.74
89.72
89.70
89.68
x103
2.01.51.00.50.0
E1 (J´)
E10(J´)
(E10(J´) +E20(J´))/2
E20(J´)
(E2 (J´)
2/1
202
01
2
102
0112 ´)(´)(´)(´)(´)(
2
12
4
1´)(
JEJEJEJEJEJW
agust,heima,....Sept10/aHCl(3+1)j3S(0)Calc-141210ak.pxp, Lay: 8, Gr:12
J´(V, v´=21)
J´(j, v´=0)
)
W12 derived
E10(J´) E1 (J´) and E2
0(J´) needed:
Different ways to evaluted W12 (W12´) from E0(J´), E(J´) and EV(J´)via (J´) (= E(J´)-E0(J´)), see:http://www3.hi.is/~agust/rannsoknir/rempi/hcl/Jan11/PDF-020111ak.pdf
agust,heima,...Jan11/XLS-020111ak.xls
The above calculation for E0 evaluations is based on E(J´=7) = E0(J´=7)
j(1) V, v´=20H35Cl H35Cl
j(1) j(1) j(1) V,v´=20 W12 W12´J´ E(J´)=nju(Q)+E(J´´) EV(J´)=nju(Q)+E(J´´) comment DE0 DE E0 D(E-E0) EV0
0 89085.61 89030.27762 89092.47 40.025 89030.97 0.689132522 89091.78087 lower 6.510291 4.6034712 89087.02064 89107.61 58.383 56.743023 89089.35 2.329109201 89105.28089 lower 6.521512 2.6623963 89166.70465 89126.47 76.741 79.684009 89166.09 0.613899507 89127.0839higher 4.931851 1.4237034 89261.19301 89152.94 95.099 94.488363 89261.19 0.003262073 89152.94326higher 0.594238 0.1328765 89374.93689 89187.54 113.46 113.74387 89374.65 0.29013646 89187.83014higher 7.367937 1.3451956 89506.17522 89227.03 131.82 131.23833 89506.46 0.286529879 89227.31653higher #NUM! #NUM!7 89656.63475 150.17 150.45953 89656.63 0