hitungan luas 2003

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I. Luas Pertama 2L = 2L = 0 – ( 1,587 . 20 ) 2L = 0 – 31,74 L = L = 15,87 m 2 II. Luas Kedua 2L = 2L = 0 – ( 1,587 . 20 + 1,239 . 20 ) 2L = 0 – ( 56,52) 2L = - 56,52 L = L = 28,26 m 2 III. Luas Ketiga 2L = 2L = 0 – ( 1,239 . 32 + 0,486 . 32) 2L = 0 – ( 55,2 ) 2L = - 55,2 L = L = 27,6 m 2 IV. Luas Keempat 2L i = 2L i = 0 – ( 0,486 . 6,5 ) 2L i = 0 – ( 3,159 ) 2L i = - 3,159 L i = L i = 1,5795 m 2 2L ii = 2L ii = 0 – ( 2,3485 ) 2L ii = - 2,3485 L ii = L ii = 1,17425 m 2 L iv = L i + L ii = 1,5795 + 1,17425

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I. Luas Pertama

2L = 2L = 0 ( 1,587 . 20 )

2L = 0 31,74

L = L = 15,87 m2

II. Luas Kedua

2L = 2L = 0 ( 1,587 . 20 + 1,239 . 20 )

2L = 0 ( 56,52)

2L = - 56,52

L = L = 28,26 m2

III. Luas Ketiga2L = 2L = 0 ( 1,239 . 32 + 0,486 . 32)

2L = 0 ( 55,2 )

2L = - 55,2

L = L = 27,6 m2

IV. Luas Keempat

2Li = 2Li= 0 ( 0,486 . 6,5 )

2Li = 0 ( 3,159 )

2Li = - 3,159

Li = Li = 1,5795 m2

2Lii = 2Lii = 0 ( 2,3485 )

2Lii = - 2,3485

Lii = Lii = 1,17425 m2

Liv = Li + Lii = 1,5795 + 1,17425

= 2,75375

V. Luas Kelima

2L = 2L = 0 ( 0,427 . 20 )

2L = 0 ( 8,54 )

2L = - 8,54

L = L = 4,27 m2

Ltotal = Li + Lii + Liii + Liv + Lv

= 5,87+28,26+27,60+2,75375+4,275

= 78,75375 m2