hukum konservasi
TRANSCRIPT
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2
2( )
v xa t
t t
∂ ∂= =
∂ ∂
v p
t r
ρ ∂ ∂
× = −∂ ∂
1 pv dt
r ρ
∂= − ×
∂∫
( ) ( )( )1 21( )
p t p t v t dt
r ρ
−≈ ∫
V
p v Z v c ρ = × =
2 p I p v
c ρ = × =
( ) ( )2 2
0 02sin cos
ka av U t kr U t kr
r r ω ω = − − + −
10logref
I IL I = ÷
20logref
pSPL
p = ÷
( )
( ) ( )
2
1 4
2 2 2 2
1 4
20logc A fF
W f F f F
÷= ÷+ +
( ) ( )
2
2
2 2 2 2
2 3
20log A c A f
W W f F f F
÷= + ÷+ +
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( )3
2 2
5
20log B c A f
W W f F
÷= + ÷ ÷+
101210101
10 log 15 10 9 1024
Lnd L
nd L+ ÷
÷ = × + ×
1210101
10 log 15 10 9 1024
Lnd L
eq L
÷
÷
= × + ×
50%i
i
c D
T = ≤∑
5 2 0,5100 49, 34%
16 12,1 32 D
= + + = ÷ ÷ ÷
1i
i
c D
T = ≤∑
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