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KHI NGNH KINH T - TI CHNH

K THI S TUYN I HC FPT

TH NG

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PHN 11.1. K nng tnh ton1.2. K nng phn tch x l tnh y ca thng tin1.3. K nng suy lun, t duy logic

PHN 22.1. Ch s thng minh IQ2.2. Kin thc Kinh t - x hi

P N V HNG DN1.1. K nng tnh ton1.2. K nng phn tch x l tnh y ca thng tin1.3. K nng suy lun, t duy logic2.1. Ch s thng minh IQ2.2. Kin thc Kinh t - x hi

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Cc bn th sinh thn mn, cc bn c c s chun b tt hn cho k thi tuyn sinh vo i

hc FPT, ti liu ny s gip cc bn lm quen vi dng thi ca trng. Trc ht, cc bn cn hiu rng k thi s tuyn ca Trng i hc

FPT khng nhm mc ch nh gi cc kin thc ph thng cng nh i hi bn phi nh v dnh qu nhiu thi gian cho vic n luyn. K thi ny nhm nh gi ng kh nng t duy ton hc, t duy logic v mt s kh nng khc ang nm chnh trong con ngi bn, v vy vic chun b qu nhiu cng khng em li li th. iu quan trng nht l cc bn cn nm chc c cu trc thi, yu cu ca tng dng . Sau l vic luyn tp qua thi mu v cc thi hon chnh cng b trn website ca chng ti lm quen vi dng thi v cch phn b thi gian lm bi. Vic phn b thi gian lm bi l rt quan trng v cc bn ch c trung bnh hn 1 pht cho 1 cu hi, v vy hy tm b qua nhng cu m bn cha thy c hng gii ngay tp trung cho cu tip theo, sau chng ta s quay li khi cn thi gian. Cng khng nn b trng cc cu khng c tr li v tr li sai s khng b tr im.

Mong cc bn c k v thc hin ng theo nhng hng dn sau y ca chng ti c th t c hiu qu cao nht trong k thi. Nu c iu g cha r, cc bn ng e ngi gi in hay trc tip n cc Vn phng t vn tuyn sinh ca Trng c tr gip.

1. c k phn Hng dn lm bi thi tuyn sinh v nghin cu k cu trc ca bi thi hon chnh.

2. Lm th thi mu c trn website tuyensinh.fpt.edu.vn hiu hn v dng bi thi. Khng cn tnh thi gian lm bi. Rt kinh nghim v vic hiu dng thi. Tt nht l chia s, rt kinh nghim vi bn b trong lp.

3. Lm th thi hon chnh c trn website tuyensinh.fpt.edu.vn vi ng thi gian 120 pht. i chiu kt qu v rt kinh nghim vic phn b thi gian.

4. Hng ngy dnh thi gian n tp mt s cu hi trong cc thi mu khc ngm hn v cch lm bi.

Ch cn nh vy, Bn sn sng cho k thi tuyn sinh ca Trng i hc FPT!

TRNG I HC FPT

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BI THI GM 100 CU HI TRC NGHIM VI CC LA CHN KHC NHAU.

- PHN 1: NH GI NNG LC T DUY LOGIC, PHN NY GM 3 NI DUNG TRC NGHIM:

Phn 1.1 gm 20 cu (t cu 1 n cu 20) l cc cu hi kim tra k nng tnh ton

Phn 1.2 gm 25 cu (t cu 21 n cu 45). Mi cu hi s c 2 d kin i km (1) v (2). C 5 phng n tr li cho trc chung cho tt c cc cu nh sau:

A) Ch dng d kin (1) l c th tr li cu hi, nhng ch dng d kin (2) th khng .

B) Ch dng d kin (2) l c th tr li cu hi, nhng ch dng d kin (1) th khng .

C) Phi dng c 2 d kin (1) v (2) mi tr li c cu hi, tch ring tng d kin s khng tr li c.

D) Ch cn dng mt d kin bt k trong 2 d kin cho cng tr li c cu hi.

E) Dng c 2 d kin cho cng khng th tr li c cu hi.

Nhim v ca th sinh l tm ra phng n ng cho mi cu hi.

Phn 1.3 gm 15 cu (t cu 46 n cu 60).

- PHN 2: NH GI CH S THNG MINH V KIN THC KINH T X HI, GM 40 CU (T CU 61 N CU 100)

HNG DN LM BI

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CU 1

Vi tt c cc cp s thc x, y, gi tr ca l :

A. Max{x, y}B. Min{x, y}C. |x+y|D. Trung bnh cng ca |x| v|y|E. Trung bnh cng ca |x+y| v x-y

CU 2Cc gc ca tam gic c t l sau 2:3:4. Gc nh nht ca tam gic l:A. 300 B. 400 C. 700 D. 750 E. 800

CU 3Nu F(1) = 2, F(n) = F(n-1)+1/2 vi mi s nguyn n>1 th F(101)=A. 49 B. 50 C. 51 D. 52 E. 53

CU 4S no l ln nht trong cc s di y?A. 2300 B. 3200 C. 4100 D. 2100+3100 E. 350 + 450

CU 5Mi ngi trong nhm 50 c gi u c tc nu hay tc vng v mt xanh hay

mt nu. Nu 14 c c tc nu mt xanh, 31 c c tc vng v 18 c c mt nu th s c tc vng mt nu l:

A. 5 B. 7 C. 9 D. 11 E. 13

CU 6S 70! tn cng bng bao nhiu ch s 0?A. 12 B. 13 C. 14 D. 15 E. 16

PHN 1.1. K NNG TNH TON

PHN 1

2|| yxyx ++

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CU 7nh ngha php ton * cho cc s thc dng nh sau: a*b = ab/(a+b). Cho

bit 4*(4*4) bng bao nhiu?A. 3/4 B. 1 C. 4/3 D. 2 E. 16/3

CU 8Nu ng knh ca mt ng trn tng n v th chu vi ca n tng bao

nhiu n v?A. 1/ B. C. 2/2 D. 2 E. 2.

CU 9C 1 nhm bn i hi nm. Bn hi c t nht hi c 1/7 tng s nm hi

c. Bn hi c nhiu nht hi c 1/5 s nm hi c. Hi nhm bn c bao nhiu ngi?

A. 4 B. 5 C. 6 D. 7 E. Khng xc nh c

CU 10

Cho S s n thuc tp s nguyn A l mt s nguyn l:

A. 2 B. 3 C. 4 D. 5 E. 6

CU 11Trong h trc ta xy, (d) l ng thng i qua (0,0) v (1,2). ng thng

(m) cha (0,0) v vung gc vi (d). Phng trnh ca ng thng (m) l A. y = (-1/2) x B. y = (-1/2) x + 1 C. y = - xD. y = - x + 2 E. y = - 2x

CU 12Trong mt phng, im A nm trn ng trn c tm l O, im O nm trn ng

trn c tm l A. Hai ng trn ct nhau ti B v C. S o gc BAC l bao nhiu? A. 600 B. 900 C. 1200 D. 1350 E. 1500

CU 13C bao nhiu s nguyn t 1 n 1000 chia ht cho 30 m khng chia ht cho 16 ?A. 29 B. 31 C. 32 D. 33 E. 38

214

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=nnA

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CU 14Cho 3 im A(-1,2) , B(6,4) , C(1,20) trn mt mt phng. C bao nhiu im D

trn mt phng bn im A, B, C, D l nh ca mt hnh bnh hnh ?A. 0 B. 1 C. 2 D. 3 E. 4

CU 15Trung bnh cng ca hai s bng 2007. Mt trong 2 s bng 7. Hi s cn

li bng bao nhiu?A. 2000 B. 4014 C. 2007 D. 4007 E. 1007

CU 16Nu bn ni tt c cc nh ca mt tht gic li th c bao nhiu t gic c

hnh thnh t cc nh ?A. 72 B. 36 C. 25 D. 35 E. 120

CU 17C bao nhiu s c 5 ch s khc nhau tng i mt?A. 144 B. 27216 C. 4386 D. 6432 E. 720

CU 18Nu trung bnh cng ca hai s l 6 v trung bnh nhn ca chng l 10 th hai

s l nghim ca phng trnh:A. x2 + 12x + 100 = 0 B. x2 + 6x + 100 = 0 C. x2 - 12x - 10 = 0D. x2 - 12x + 100 = 0 E. x2 - 6x + 100 = 0

CU 19Trong vn phng, mi ngy vi ln ng ch giao cho c th k nh my bng

cch t ti liu ln chng h s ca c th k. Khi c thi gian, c th k mi ly ti liu trn cng ca chng h s nh my. Nu c tt c 5 ti liu v ng ch giao cc ti liu theo th t 1, 2, 3, 4, 5 th th t no sau y khng th l th t ti liu m c th k nh my chng?

A. 1, 2, 3, 4, 5 B. 2, 4, 3, 5, 1 C. 3, 2, 4, 1, 5D. 4, 5, 2, 3, 1 E. 5, 4, 3, 2, 1

CU 20C 1 nhm hc sinh d nh gp tin i cm tri. Nu mi bn ng 140

ngn th thiu 40 ngn. Nu mi bn ng 160 ngn th tha 60 ngn. Hi nhm hc sinh c bao nhiu bn?

A. 4 B. 5 C. 6 D. 8 E. Khng xc nh c

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CU 21Ngy hm qua Nam u xe mt bi xe m ngi ta thu ph gi u tin

cao hn cc gi tip theo. Nu tng tin ph u xe ca Nam ngy hm qua l 37.500 ng, th Nam tr tin cho bao nhiu gi u xe?

1) Gi u xe ti bi l 7.500 ng cho gi u tin v 5.000 cho mi gi tip theo hoc mt phn ca gi (lm trn ln)

2) Nu gi tin ca gi u tin l 10.000, s tin m Nam phi tr s l 40.000 ng.

CU 22Cho hm s th hm s f c mt tim cn ng v mt

tim cn xin?1) n3 - 4n - 48 = 0 . 2) n2 = 16

CU 23Tch ca x v y c ln hn 60? 1) Tng ca x v y ln hn 60. 2) Mi mt bin s x, y u ln hn 2.

CU 24Hy xc nh s lng khn gi trung bnh trong mi trn u bng ca

sn vn ng A trong 2 thng nm v su:1) S lng khn gi trung bnh trong mi trn u bng ca sn vn ng

A trong thng nm l 23.100, v trong thng su l 25.200.2) Sn vn ng A t chc 20 trn u bng trong thng nm v 22 trn

u bng trong thng su.

CU 25Cho s nguyn t l bi s ca s nguyn t s. S nguyn t c l bi s ca s2? 1) s < 4. 2) t = 18.

PHN 1.2. K NNG PHN TCH X L TNH Y CA THNG TIN

112)( 3

||

++

=xxxf

n

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CU 26Nu Q l s nguyn nm gia 10 v 100, th gi tr ca Q bng bao nhiu?1) Mt trong cc ch s ca Q hn ch s cn li 3 n v, v tng cc ch s

ca n bng 92) Q < 50

CU 27Mt on dy in c ct ra thnh 3 phn c di khc nhau, hi di

ca phn di nht? 1) Tng ca hai phn ngn nht l 36 mt. 2) Tng ca hai phn di nht l 40 mt.

CU 28Doanh thu trung bnh ca 3 b phn ca mt cng ty l 1.000.000 USD. Doanh

thu ca b phn km nht c nh hn 500.000 USD?1) B phn tt nht c doanh thu 1.300.000 USD.2) Mt b phn no c doanh thu 700.000 USD.

CU 29C bao nhiu ngi d Hi ngh Ton hc nm nay?1) C 70 ngi c mi d Hi ngh Ton hc nm nay.2) C 60% s ngi c mi d Hi ngh Ton hc nm nay n d.

CU 30Vi X lm y b trong vng 36 gi. Nu vi X v vi Y mi vi cung cp nc

c lp vi nhau, th c hai vi X v Y ng thi s tn bao nhiu thi gian lm y b?

1) Dung tch ca b l 24.000 m3. 2) Vi Y cng tn thi gian nh X lm y b.

CU 31Tp hp S c tnh cht: i) Nu x thuc S th 1/x thuc S ii) Nu x, y thuc S th x + y thuc SHi 3 c thuc S khng 1) 1/3 thuc S. 2)1 thuc S.

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CU 32Hai s nguyn dng x, y bng bao nhiu? 1) x + y = 528. 2) c s chung ln nht ca x v y bng 33.

CU 33Sn hiu Luxo ch gm ru cn v phm mu. T l gia ru cn v phm

mu trong sn Luxo l bao nhiu?1) C ng 7kg phm mu trong mt thng sn Luxo loi 12kg. 2) C ng 5kg ru cn trong mt thng sn Luxo loi 12kg.

CU 34B3 ln hn hoc bng B2? 1) B l s nguyn. 2) B l s dng.

CU 35x c phi l s nguyn t? 1) x l mt s chn. 2) x khng chia ht cho bt c mt s l no ln hn 1.

CU 36Khong cch t nh H n trng hay n th vin trung tm l ngn hn?1) Hm th hai H i bng xe p t nh n trng mt 20 pht.2) Hm th ba H i bng xe p t nh n th vin trung tm mt 25 pht.

CU 37Gi mt cn to tng ln bao nhiu phn trm? 1) Trc khi tng, gi mt cn to l 15.000 ng. 2) Gi to tng thm 2.000 ng/cn.

CU 38Nu x l lp phng ca mt s nguyn, 2 < x < 200 th gi tr ca x bng? 1) x l. 2) x l bnh phng ca mt s nguyn.

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CU 39Trong hnh ch nht ABCD, P l trung im ca AB, Q l trung im ca BC.

Din tch tam gic PBQ bng bao nhiu? 1) Din tch tam gic ABD bng 20 2) di cnh AB = 10

CU 40Tam gic ABC c phi l tam gic cn? 1) Tam gic ABC vung v c 1 gc bng 450.

2) T l cc cnh ca tam gic l

CU 41Lng thng ca An l bao nhiu?(1) Lng thng ca An gp i lng thng ca Bnh.(2) Lng thng ca Bnh bng 40% tng lng thng ca Chinh v ca An.

CU 42Cho P l mt tp hp cc s nguyn v 3 thuc P. C phi mi bi s nguyn

dng ca 3 u thuc P? 1) Mi s nguyn thuc P cng vi 3 u thuc P.2) Mi s nguyn thuc P tr i 3 u thuc P.

CU 43C phi k2 + k - 2 > 0?1) k < 1 2) k > -1

CU 44An mua 18 hp sa ti gm loi c ng v khng ng. Hi An mua

bao nhiu hp sa ti loi c ng? 1) An mua s sa ti loi c ng t hn s sa ti loi khng ng. 2) S sa ti loi khng ng m An mua l s l.

CU 45Gi tr ca x bng bao nhiu?1) x - 5 = 4 2) x2 = 81

2:3:1

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CU 46Mc d xe t in khng thi kh c hi ra mi trng, thc t vic chuyn

t t chy bng xng du sang t chy bng in khng ci thin c mi trng. in dng cho xe t in vn cn c sn xut ti nhng nh my in ch yu bng cch t cc nng lng ha thch nh than, du, kh t t nhin. V vy, bt c gim thiu no trong s dng nng lng ha thch nh vo vic thay th cc ng c t trong bng cc ng c in, thc t u i vi mt mc tng tng ng nhu cu sn xut ti cc nh my in.

iu no sau y, nu ng, s lm suy yu lp lun trn? A) Ton b h thng li in quc gia cn c cu li sn xut in cho cc

xe chy bng inB) Xe chy bng in tit kim nng lng hn rt nhiu so vi xe chy bng

xng duC) Than gy nhim nhiu hn kh t trong sn xut inD) Nghin cu cho thy hu ht mi ngi khng mun chuyn t xe chy

bng xng du sang xe chy bng in. E) Trong tng lai gn, nhng dng xe c kh nng chy c bng xng du v

bng in tin dng hn nhng dng xe ch c th chy bng in.

CU 47Gn y, do gii hn v ngn sch, mt cng ty sn xut xe hi ln tuyn b

ct gim chi tiu cho pht trin cng ngh mi. Ph gim c ca cng ty ca ngi bin php tit kim chi ph ny nh mt phng php hu hiu gip cng ty t c nhng ch tiu ti kha ng thi m bo duy tr li nhun cho giai on cn li ca nm. Nhng nh phn tch cng hoan nghnh k hoch ny v cho rng bin php ny s gip cng ty duy tr c sc cnh tranh trong khi th trng khch hng ang c xu hng thu hp nh hin nay.

iu no sau y, nu ng, s lm suy yu d on ca nhng nh phn tch nht?

A) Khch hng hu nh khng quan tm n nhng sn phm xe hi thiu tnh nng ci tin, sng to.

PHN 1.3. K NNG SUY LUN, T DUY LOGIC

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B) Cc cng ty thng thng phi trin khai rt nhiu hot ng marketing thc y nhu cu khch hng cho cc sn phm cng ngh mi.

C) Trong lnh vc sn xut xe hi, cc d n u t pht trin cng ngh khng phi lc no cng mang li hiu qu so vi chi ph b ra.

D) Khch hng quan tm nhiu n s an ton ca cc thit k xe hi hn l kha cnh thm m.

E) Mt cng ty i th ca cng ty trn tuyn b ct gim nhn s trong b phn nghin cu v pht trin ca h.

CU 48Khm ph khng gian ngoi tri t l mt s lng ph thi gian v tin thu

ca nhn dn. Tiu tn hng trm triu khm ph nhng iu tm thng nh s tn ti ca nc hoc ca nhng dng sng vi khun ti cc th gii khc tht qu v ngha trong khi chng ta phi i mt vi hng lot vn trn chnh hnh tinh ca chng ta, mt trong s l tng lai mng manh ca mi trng sng ca chnh chng ta.

Lp lun trn b qua kh nng rng: A) Nghin cu khng gian tn km hn nghin cu mi trng. B) Nghin cu khng gian c th em li nhng pht hin quan trng ng

dng cho mi trng v ti nguyn thin nhin trn tri t. C) Vic con ngi du hnh n nhng hnh tinh khc l hon ton kh thi trn

kha cnh khoa hcD) Kh nng c s tn ti ca dng sng c tri thc u trong v tr l rt nh. E) Nhng nghin cu v mi trng c quan tm nhiu hn trong thi gian

gn y.

CU 49 gi chn nhn vin, cng ty Dch v Gip vic pht trin mt k hoch

nhm nng cao tinh thn lm vic ca nhn vin. Theo k hoch ny, cng ty s tr cp cho vic trng gi con em nhn vin, ci thin iu kin xe ca nhn vin v h tr cho nhn vin tip tc hc ln cao hn.

iu no sau y, nu ng, s cng c tt nht cho s thnh cng ca k hoch trn

A) Nhng i th cnh tranh ca cng ty ang trin khai k hoch tr cp trng gi con em nhn vin ca h.

B) Ch c mt s t nhn vin ca cng ty Dch v Gip vic ang theo hc ln cao hn.

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C) Th trng vic lm cho ngi gip vic hin nay kh cnh tranh. D) Cng ty gn y mt mt s nhn vin do b vic. E) Mt nghin cu ch ra rng xe l mt trong nhng iu nhn vin cha

hi lng ti cng ty.

CU 50Trong mt cuc thm d kin gn y, ng c vin A nhn c 60% t l

ng h trong khi ng c vin B ch nhn c 50% t l ng h. V vy, ng c vin A chc chn s thng trong cuc bu c.

iu no sau y, nu ng, s cng c tt nht cho kt lun trn?A) ng c vin A quyn gp c nhiu tin cho qu bu c hn ng c vin BB) ng c vin A hin ang ng nhimC) ng c vin vi t l ng h cao hn s thng trong cuc bu c. D) Cuc bu c s din ra trong 2 tun naE) Kt qu thm d kin phn nh mt cch chung nht phiu bu ca c

tri trong ngy bu c.

CU 51 ti tr cho mt chng trnh xy dng, thnh ph Ameeville ang xem

xt nng thu tiu dng 4%. K hoch ny r rng khng hiu qu. Ngn sch t thu ca thnh ph s khng tng thm, v ngi tiu dng s gim chi tiu ca h t nht 4%.

iu no sau y, nu ng, cng c lp lun trn tt nht? A) Ngi tiu dng t do quyt nh chi tiu bao nhiu. B) Ngi tiu dng phn i k hoch tng thu. C) Chng trnh xy dng nhn c s ng h rng khp trong thnh ph. D) Ngi tiu dng trong thnh ph u bit n chng trnh xy dng E) Nu ngi tiu dng gi nguyn chi tiu nh hin nay, tin thu c t k

hoch tng thu s tha cho thnh ph trin khai d n xy dng.

CU 52Do tr cp cho khi cc trng i hc v cao ng cng b ct gim, hc ph

gia tng v cc iu kin tn dng tht cht, nhiu sinh vin v gia nh s phi xem xt li k hoch hc ln i hc. Rt c th nhiu ngi s t b k hoch hc i hc. V vy, trong thp nin ti, x hi s phi i mt vi s thiu ht lao ng c k nng.

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Lp lun trn da trn gi nh no sau y? A) Gio dc i hc l cn thit to ra ngun nhn lc c k nngB) Nu cc trng thng mi khng tng s hc sinh u vo, trong tng

li s thiu ht ngun nhn lc c k nng. C) Cc trng cao ng cng ng khng o to c sinh vin c k nng

tt bng cc trng cng lp. D) Chng trnh o to qua thc tp khng hiu qu bng cc chng trnh

o to ti nhng trng k thutE) Trong thp k ti, trnh v k nng s m bo cho ngi lao ng lng cao

CU 53Th vin ti thnh ph Midgeville l ni gip dn c trong vng c iu kin

cp nht cc kin thc vn ha v ngh thut. Ngi dn ti y, c bit l thanh thiu nin v ngi ln tui dnh rt nhiu thi gian ti th vin c sch bo, tham quan cc trin lm, xem phim ti liu v tham d nhng hi tho gio dc. V vy, vic thng c thnh ph ct gim mt phn ln ngn sch hot ng ca th vin s khin dn c ti Midgeville b thiu thn cc cc kin thc, thng tin vn ha, ngh thut.

Lp lun trn da trn gi nh no sau y? A) B su tp sch ti th vin Midgeville rt a dng v vn haB) Th vin Bidgeville, cch Midgeville na dm, c nhiu chng trnh v

ngh thut, truyn thng v s kin hn th vin Midgeville. Hn th na, th vin ny cn m ca cho ton b dn c ca cc khu vc ln cn.

C) Khi ngn sch th vin b ct gim, c dn ti Midgeville s khng c xem nhiu phim ti liu nh trc.

D) Hu ht mi ngi khi n th vin u khng mang theo sch hay bo ch ca mnh c.

E) Ngoi th vin, c dn ti Midgeville khng c bt c ni no khc cp nht cc thng tin v vn ha, ngh thut.

CU 54Trong mt cuc phng vn, bit mt ng vin c thnh tht hay khng

nn da vo vic ng vin c sn lng chia s thng tin khng tt v bn thn hay khng. Nu mt ng vin sn lng tit l nhng thng tin nh mnh tng b sa thi, hay ngh php hoc khng th nh my nhanh, ng vin cng s thnh tht v nhng thnh tu h t c trong cng vic trc y.

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Kt lun no sau y c th rt ra t lp lun trn?A) Nhng ng vin khng tit l mt thng tin khng tt no v tnh cch v

lch s cng vic ca h l nhng ng vin khng thnh tht. B) Vic khim tn t h thp bn thn lun lun c li cho ng vin. C) ng vin nn p dng hiu ng tm l ngc chim lng tin ca ngi

phng vn. D) ng vin vi bng cp hay chng ch tt c th ni di v kh nng ca h. E) Trong mt s trng hp, nhng thng tin c coi nh bt li ca ng

vin c th c ch.

CU 55Hng qu, nu c s st gim v li nhun, cc cng ty i chng s phi tr

li cht vn ca c ng. V vy trnh nguy c st gim li nhun, lnh o cc cng ty ny thng da vo m hnh kinh doanh quen thuc, p dng trc v trnh th nghim nhng phng thc kinh doanh mi. Tuy nhin, sng to ch c th pht trin trong mi trng hng ti cc li ch di hn, chp nhn mo him v ci m vi nhng tng mi l.

Nu lp lun trn l ng, iu no sau y cng ng? A) Nhng doanh nghip t nhn thng i mi, sng to hn nhng doanh

nghip nh nc. B) N lc xy dng li th cnh tranh ca cc doanh nghip thng b cn tr

bi c ch s hu ca doanh nghip . C) Nhng ci tin i mi c th lm suy gim tc pht trin ca doanh nghip. D) Nhng nh u t chng khon thng c tm nhn ngn hnE) Mt s doanh nghip che y cc khon l ngn chn vic c ng bn

c phiu ca doanh nghip i.

CU 56Vn phng ca mt tp ch hin ang s dng mt my fax c v thng

xuyn hng hc. Hin vn phng ang xem xt liu c nn thay th chic my c ny bng mt my fax khc mi hn, d s dng v t b hng hc hn khng.

c quyt nh ng n cho trng hp ny, vn phng nn xem xt vn no sau y nht?

A) Sp ti, vn phng c chuyn n mt a im khc khng? B) Sp ti, s lng cng vn, giy t fax vn phng nhn mi ngy c thay

i khng?

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C) Sp ti vn phng c chuyn sang trao i thng tin qua th in t v hn ch s dng giy khng?

D) Nu vn phng thay th my fax, vn phng c thay th my photocopy khng?E) Sp ti, s lng trang giy mi ln fax c thay i khng?

CU 57Xe p phanh bng chn ang dn tr nn ph bin. Nhng chic xe p

ny khng c h thng phanh tay truyn thng nn c coi l nguy him hn nhng xe p kiu c. X lun trn mt tp ch khng nh rng xe p phanh chn l nguyn nhn chnh ca vic gia tng s lng cc v tai nn xe p trong thi gian gn y.

Cu hi no sau y nn c tm hiu c nh gi chnh xc v nhn nh ca phng vin trn?

A) Xe p phanh chn c c s dng trn cng mt loi ng v cng mt iu kin nh xe p phanh tay?

B) Trong cc v tai nn, nhng ngi iu khin xe p c bit v cc iu lut v quy nh trong s dng xe p khng?

C) Nm nay, s lng ngi p xe i m bo him c nhiu hn nm trc khng?

D) Li xe t c thng kh chu khi gp xe p trn ng khng? E) Xe p phanh chn c t hn xe p phanh tay khng?

CU 58Mt s loi thuc tr su c s dng 20 nm trc y c cha cc tc nhn

gy ung th. Tuy nhin, mt nghin cu tin hnh 10 nm trc y cho thy khng c s tng ln ca cc ca ung th trong nhng ngi tip xc vi cc loi thuc tr su ny.

Cu hi no sau y nn c tm hiu c nh gi chnh xc v kt qu ca nghin cu trn?

A) 20 nm trc y, c loi thuc tr su no m khng cha cht gy ung th khng?

B) Nhng loi thuc tr su trn hin nay cn s dng khng? C) Cn bnh ung th thng pht trin trong thi gian bao lu?D) C mt s loi ung th khng phi do thuc tr su m do nhng yu t

khc ng khng?E) 10 nm trc y, c quc gia no khng s dng thuc tr su khng?

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CU 59Dung: Nam gii khi nm gi cc cng v lnh o chnh tr v nhng khc

bit v tm sinh l v vn ha thng c xu hng i u v gy hn hn n gii. c im ng x ny gp phn lm gia tng xu hng khng hong, chy ua v trang v bng n chin tranh bo ng trn chnh trng quc t.

An: Nhng nhng nh lnh o n gii nh tng thng n v Israel cng a t nc h vo chin tranh y thi.

S phn bc ca An i vi lp lun ca Dung c sai st im no sau y?A) An coi lp lun ca Dung v mt nguyn nhn ca mt hin tng nh l

nguyn nhn duy nht ca hin tng .B) An khng a ra c v d phn bc v mt lnh o nam gii m khng

a t nc ca h vo chin tranh.C) B qua thc t l c hai nh lnh o n gii trn u c dn bu. D) Cho rng cch ng x ca n gii khng b nh hng bi cc yu t tm

sinh l hay vn ha. E) Gi nh rng hai nh lnh o n gii trn khng c la chn no khc

ngoi chin tranh.

CU 60Mt ngi ci la i xung mt hm ni. u tin, anh ta gp mt bin bo

vi mt trc l 30 v mt sau ghi 32. Anh ta ngh rng bin bo tip theo s ch rng anh ta i c ng na ng n chn hm ni. Tuy nhin, bin bo tip theo m anh ta gp li ghi 29 mt trc v 33 mt sau.

iu no sau y nu ng s gii thch r nht cho s khng nht qun trn. A) S ghi mt trc cc bin bo l ch khong cch n chn hm ni,

ch khng phi khong cch n nh trn hm ni. B) S ghi trn bin bo l tnh bng dm, khng phi bng km. C) Bin bo l dng cho ngi i b, khng phi cho ngi ci la. D) C mt bin bo gia hai bin bo trn b mt.E) Mt ai nghch ngm quay ngc hai mt ca bin bo.

19


CU 61 Trung bnh cng ca 3 s l 19, trong trung bnh cng ca 2 s u tin l

15. Hi s th 3 l bao nhiu?A) 4 B) 8 C) 9 D) 12 E) 27

CU 62Tm s tip theo trong dy s sau y: 6, 11, 21, 36, 56, 81, 111, (?)A) 136 B) 141 C) 144 D) 146 E) 151

CU 63GMS tng ng vi HLT cng nh KTW tng ng vi:A) JUV B) LSX C) LUX D) JSV E) LSV

CU 64 Hnh no trong s cc hnh di y khc vi cc hnh cn li?A) A B) B C) C D) D E) E

PHN 2.1. CH S THNG MINH IQ

PHN 2

20

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CU 65Hnh b thiu l hnh no sau y? A) A B) B C) C D) D E) E

CU 66C bao nhiu hnh trn c chm en bn trong?A) 11B) 12C) 13D) 14E) 15

CU 67Nu ti i 2 dm v hng ng, 4 dm v hng Nam, sau 3 dm v

hng ng, sau 4 dm v hng Bc, sau 2 dm v hng Ty, lc ny ti cch im xut pht bao xa v v hng no?

A) 6 dm v hng TyB) 6 dm v hng ngC) 3 dm v hng TyD) 3 dm v hng ng

21


CU 68Ngi n ng c 53 i tt mu trong ngn t: 16 i mu xanh ging ht

nhau, 25 i mu ging ht nhau v 12 i mu xm ging ht nhau. H thng n b hng v ng ta ng trong bng ti. Hi ng ta cn ly ra khi ngn ko bao nhiu i tt chc chn 100% ng y c mi mu 1 i?

A) 41 i B) 43 i C) 37 i D) 28 i

CU 69M ca Hoa c 3 a con. a u tn l Su, a th 2 tn l By. Vy tn a

th ba l g?A) Bn B) Tm C) Hai D) Hoa

CU 70S no s thay th vo v tr du hi tip tc dy s di y?1, 5, 13, 29, (?)A) 37 B) 52 C) 61 D) 79

CU 71Nu 1 chic xe tng tc trung bnh thm 5 dm/gi cho hnh trnh 150

dm, hnh trnh s kt thc sm hn 1 ting. Vy tc ban u trong chuyn i ca chic xe l bao nhiu?

A) 20 dm/gi B) 25 dm/giC) 30 dm/gi D) 35 dm/gi

CU 7260% ca 240 cng vi 55% ca 120 l bao nhiu?A) 250 B) 220 C) 210 D) 240

CU 73 0, 19, 38, 57, (?), 95, (?)Hy tm hai s cn thiu trong dy trn.A) 61 & 112 B) 76 & 114 C) 69 & 109 D) 75 & 115

CU 74Nu 5 ngi cng xy mt ci nh phi mt 28 ngy th vi 8 ngi s mt bao

lu xy, gi s rng ai cng c nng sut nh nhau.A) 12 ngy B) 17,5 ngy C) 11,5 ngy D) 9 ngy

22

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CU 75 5, 10, 30, 60, 180, 360, 1080, (?), (?)Hy tm hai s cn thiu trong dy trn.A) 2160 & 4320 B) 2160 & 6480 C) 3240 & 6480 D) 3240 & 9720

CU 76Ai l ngi ginh gii nht Vietnam Idol 2010?A) Vn Mai Hng B) Lu Phng AnhC) Trn Nguyn Uyn Linh D) Nguyn Ln Nh

CU 77Ai l nh v ch Chung kt cuc thi ng ln nh Olympia 2011 (nm th 11)A) V Bch Nht B) L Bo LcC) Thi Ngc Huy D) Phm Th Ngc Oanh

CU 78Ai l ngi giu nht th trng chng khon Vit Nam nm 2010 do bo in

t VnExpress.net cng bA) on Nguyn c B) Trn nh LongC) ng Thnh Tm D) Phm Nht Vng

CU 79i hi i biu ton quc ng Cng sn Vit Nam c t chc t 12-

19/1/2011 l i hi ln th my? A) 10 B) 11 C) 12 D) 13

PHN 2.2. KIN THC KINH T - X HI

23


CU 80Cng dn thuc tui no c quyn tham gia bu c i biu Quc hi

kha 13 v Hi ng nhn dn cc cp nhim k 2011/2016?A) T 18 tui tr lnB) T 19 tui tr lnC) T 20 tui tr lnD) T 21 tui tr ln

CU 81Quc hi thng qua ngh quyt min thu thu nhp c nhn i vi cc

khon thu t tin lng tin cng, nm trong bc 1 ca biu thu l:A) Di 4 triu ng/thng B) Di 5 triu ng/thngC) Di 7 triu ng/thng D) Di 9 triu ng/thng

CU 82Quc gia no gi vai tr Ch tch ASEAN trong nm 2011?A) Vit Nam B) Indonesia C) Thi Lan D) Malaysia

CU 83Quc gia no hin c tr lng khai thc vng ln nht th gii theo c tnh

ca Bloomberg?A) n B) Trung Quc C) Nga D) Nam Phi

CU 84Gio s Ng Bo Chu ot huy chng Fields vo nm no?A) 2008 B) 2009 C) 2010 D) 2011

CU 85a phng dn u c nc v thu ht vn u t trc tip ca nc ngoi

c cp giy php thi k 1988 2009:A) H Ni B) ng Nai C) Bnh Dng D) TP H Ch Minh

24

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CU 86Ch s gi tiu dng bnh qun su thng u nm 2011 tng so vi bnh qun

cng k nm 2010:A) Khong 16 % B) Khong 8% C) Khong 20% D) Khong 25%

CU 87Hin ti Vit Nam c tt c bao nhiu mng di dng c cp php:A) 1-3 mng B) 4-6 mng C) 7-9 mng D) 10-12 mng

CU 88World Cup 2014 s c t chc quc gia no?A) Anh B) c C) Nam Phi D) Brazil E) Mexico

CU 89u khng phi l 1 nhn hng ca UnileverA) Omo B) Sunsilk C) Kem WallsD) Khng c Phng n no trong cc la chn trn

CU 90Nho gio cn c gi l:A) Pht gio B) Khng gio C) Minh gio D) o gio

25


26

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P N V HNG DNPHN 1.1. K NNG TNH TON

CU 1: ph du gi tr tuyt i ta xt hai trng hp :

Nu x > y th Nu x < y th

Vy p n: A

CU 2 : Nu A : B : C = 2 : 3 : 4 th A : (A+B+C) = 2 : (2+3+4) = 2 : 9. Tng ba gc trong mt tam gic bng 1800. T suy ra A = 400. p n. B

CU 3: Ta dng phng php i li. F(n) = F(n-1) + 1/2 = F(n-2) +1/2 +1/2 = F(n-3) +1/2+1/2+1/2 = = F(1) + (n-1)/2. Vi n=101, ta c F(101) = F(1) + 50 = 52.p n: D Ghi ch: Dy s tho mn iu kin F(n) = F(n-1) + d vi mi n = 2, 3, c gi

l mt cp s cng. Ta c cc cng thc c bn sau : F(n) = F(1) + (n-1)d.

CU 4: Ta c gng so snh, a v cng mt ly tha. Ta c 2300=8100, 3200=9100, cn 2100+3100 < (2+3)100 = 5100, v 350 + 450 < (3+4)50 =

750. Vy 3200 l s ln nht. p n: B

CU 5: t NX l s c gi tc nu mt xanh, NN l s c gi tc nu mt nu, VX l s c gi tc vng mt xanh v VN l s c gi tc vng mt nu. Khi ta c

xyxyxyxyx =++=++22

||

yyxxyyxyx =++=++22

||

},{2|| yxMaxyxyx =++

27


(1) NX + NN + VX + VN = 50 (tng s cc c gi)(2) NX = 14(3) VX + VN = 31 (tng s cc c gi tc vng)(4) N N + VN = 18 (tng s cc c gi mt nu)Ta cn tm VN. T (1), (2), (3) suy ra NN = 50 14 31 = 5. T (4) suy ra VN = 13.p n: E

CU 6: Mt s tn cng bng n ch s 0 khi n chia ht cho ng 10n, tc l ta phi tm xem c bao nhiu cp 2 v 5 trong phn tch nguyn t ca 70!. T 1 n 70 c cc s 5, 10, 15, , 70 chia ht cho 5 (14 s), trong c 2 s chia ht cho 52 l 25 v 50. V vy lu tha ca 5 trong 70! l 14+2 = 16. Lu tha ca 2 trong n! lun ln hn ly tha ca 5 trong n!, do vy ta tm c ti a 16 cp 2 v 5.

p n: E

CU 7: Ta thc hin php ton trong ngoc n trc. C 4*4 = 4.4/(4+4) = 2. T 4*(4*4) = 4*2 = 4.2/(4+2) = 4/3.

p n: C

CU 8: Gi s ng knh ca ng trn ban u l d th chu vi ca n l p = d.. Nu ng knh tng ln n v th chu vi mi l p=(d+). Suy ra chu vi tng (d+) - d = 2 n v.

p n: D

CU 9: Gi s c m bn i hi nm v tng s nm hi c l T. Khi s nm trung bnh l T/m, do vy ta c

T/7 < T/m < T/5, tc l 1/7 < m < 1/5, hay 5 < m < 7. Suy ra m = 6.p n: C

CU 10:

l c ca 9. V 9 c 6 c s nguyn l +1, +3, +9 nn s tm c 6 s n tha mn.

p n: E

22

92

942

984214

++

+ nZ

nZ

nZ

nnZ

nn

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CU 11: Cc kin thc cn c gii bi ton ny :(a) Phng trnh ng thng i qua 2 im(b) Mi lin h gia 2 h s gc ca 2 ng thng vung gc.(c) Phng trnh ng thng i qua 1 im vi h s gc cho trc

ng thng d c phng trnh

ng thng vung gc vi d s c h s gc l

T phng trnh ng thng m l p n: AGhi ch: C th gii bi ny bng phng php loi tr. R rng cc p n B v

D b loi v cc ng thng tng ng khng i qua gc to . p n C cng b loi theo trc quan. Ch cn hai p s A v E l cn phi tnh.

CU 12: Theo bi ta c AB = AC = OA = OB = OC. Suy ra cc tam gic OAB v OAC u. Suy ra BAC = BAO + OAC = 600 + 600 = 1200.

p n: C

CU 13: Ta gii bi ton bng cch ly s cc s nguyn t 1 n 1.000 v chia ht cho 30, tr i s cc s nguyn t 1 n 1.000 v chia ht cho c 30 v 16 (tc l chia ht cho 240).

Mt cch tng qut, s cc s nguyn dng t 1 n n v chia ht cho k l [n/k] (k hiu phn nguyn). Vy :

Trong 1.000 s nguyn dng u tin c+ [1.000/30] = 33 s chia ht cho 30 + [1.000/240] = 4 s chia ht cho 240Suy ra p s l 33 4 = 29.p n: A

.2020

010 xyyx =

=

.21

29


CU 14: Vi ba im A, B, C v tr bt k (khng thng hng) th nh D c th l cc im i xng ca A qua trung im BC, ca B qua trung im CA v ca C qua trung im AB. Suy ra c 3 im nh vy.

p n: D

CU 15: Trung bnh cng ca hai s bng 2.007 th tng ca hai s bng 4.014. Mt trong hai s bng 7 th s cn li bng 4.007.

p n: D

CU 16: C 4 nh bt k to thnh mt t gic.

Suy ra p s l p n: D

CU 17: Mt s c 5 ch s c dng abcde. Ch s a c 9 cch chn (a phi khc 0). Ch s b, sau khi chn a, c 9 cch chn (b phi khc a). Tip theo c c 8 cch chn, d c 7 cch chn v e c 6 cch chn. Vy p s l 99876 = 27.216. p n: B

CU 18: Trung bnh cng ca hai s l 6 suy ra tng hai s l 12. Trung bnh nhn ca chng l 10 suy ra tch ca chng l 100. Vy theo nh l Vi-et, hai s l nghim ca phng trnh x2 12x + 100 = 0. p n: D

CU 19: Theo iu kin ca bi, sau khi tp ti liu k xut hin th cc tp ti liu k-1, k-2, ..., 1 cng xut hin. Do (D) l khng th xy ra, v khi c ti liu s 4 tc l cc ti liu 1, 2, 3 c t ln, th ti liu s 3 phi c nh my trc ti liu s 2. Cc trng hp khc u c th xy ra. p n: D

CU 20: Gi m l s hc sinh ca nhm. T l s tin cn c (tnh bng ngn) Khi 140m = T 40 160m = T + 60Tr hai phng trnh cho nhau, ta c 20m = 100 suy ra m = 5.p n: B

30

HNG DN LM BI

CU 21: D kin 1) tr li cu hi, bng cch ly 37.500-7.500 = 30.000 l s tin phi tr cho cc gi tip theo, vn c mc ph l 5.000/gi. D kin 2) ch cho ta bit tin ph u xe sau ca gi u tin l 30.000, khng tr li cu hi.

p n: A

CU 22: Tim cn ng ca hm s phn thc l cc phng trnh dng x = a vi a l gi tr m ti mu s bng 0, v c tim cn xin khi bc ca t s ln hn mu s 1 n v. Do vy th hm s y = f(x) lun c tim cn ng x = -1, v c tim cn xin khi v ch khi |n| = 4. iu kin 2) r rng l tho mn, cn iu kin 1) tng ng vi

(n 4)(n2 + 4n + 12) = 0 n = 4 cng tho mn. Vy p n l D.p n: D

CU 23: Nu x + y > 60 th khng kt lun xy > 60, chng hn vi cc cp (30, 31) v (62, -1). Vy 1) l khng . Nu ch dng 2), tc l ch bit x > 2, y > 2 th cng khng th suy ra c xy > 60, chng hn (3, 3) v (30, 30). Kt hp c 1) v 2), nu x + y > 60 v x, y > 2 th s dng (x-2)(y-2)>0, khai trin ra ta c xy > 2(x+y)-4 > 60.

p n: C

CU 24: V mi thng c s trn u c th khc nhau nn t 1) cha th kt lun v s lng khn gi trung bnh ca mi trn. Tt nhin, mt mnh thng tin th hai cng khng gii bi ton, v khng c thng tin v s khn gi. Nu c c hai thng tin 1) v 2), th s lng khn gi trung bnh c th tnh theo cng thc

y t s l tng s khn gi trong thng nm v thng su, v mu s l tng s trn u trong hai thng ny. p n: C

PHN 1.2. K NNG PHN TCH X L TNH Y CA THNG TIN

31


CU 25: Nu ch dng 1) th ch suy ra c s =2 hoc s = 3, khi y khng th kt lun t l bi s ca s2, chng hn vi s = 2, c th ly t = 4 hoc t = 6. Nu ch dng 2) th cng khng kt lun c, chng hn c th ly s = 2 hoc s = 3

p n: E

CU 26: Gi thit ni rng Q l mt s c hai ch s. T thng tin 1) ta c hai s l 63 v 36. Thng tin 2) r rng cng l khng . Nu kt hp c hai thng tin ny th ta c s l 36.

p n: C

CU 27: D kin 1) khng cho bit thng tin v on di nht nn khng . D kin 2) khng cho bit thng tin v on ngn nht nn cng khng . Nu kt hp c 1) v 2), gi s a < b < c l di 3 phn th ta c: a + b = 36, b + c = 40, r rng cng khng kt lun (3 n m ch c 2 phng trnh).

p n: E

CU 28: Gi s doanh thu cc b phn l a < b < c. Ta c a + b + c = 3.000.000.Cu hi l c phi a < 500.000?Nu c 1) th a + b = 1.700.000. Lc a cng c th ln hn 500.000 (chng

hn a = 600.000, b = 1.100.000) cng c th nh hn 500.000 (chng hn a = 450.000, b = 1.250.000).

Nu ch c thng tin 2) th r rng a c th nh hn 500.000, (chng hn a = 400.000, b = 700.000, c = 1.900.000), cng c th ln hn 500.000 (chng hn a = 600.000, b = 700.000, c = 1.700.000). Nh vy 2) khng .

Nu c c 1) v 2) th a = 700.000, b = 1.000.000, c = 1.300.000. T ta c th khng nh cu tr li l khng.

p n: C

CU 29: Ch 1) th khng bit s ngi n d. Ch 2) cng khng thng tin, v khng bit s ngi c mi. Kt hp 1) v 2) s bit c s ngi i d l 60%70 = 42.

p n: C

32

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CU 30: iu kin 1) r rng khng gip ch g v khng c thng tin v Y. iu kin 2) cho thy nu X v Y cng cung cp nc th s tn mt na thi gian. p n: B

CU 31: Nu c 1) th dng tnh cht i) t 1/3 thuc S suy ra 3 thuc S. Nu c 2) th t gi thit 1 thuc S, dng ii) 2 ln ta c 1+1 = 2 thuc S v 1 + 2 = 3 thuc S. p n: D

CU 32: iu kin 1) khng thng tin tm x v y. iu kin 2) ng ring cng khng gip g c, v c nhiu cp c UCLN bng 33. Kt hp 1) v 2), gi s ta c x + y = 528 v UCLN(x, y) = 33. Ta cn tm xem c bao nhiu cp tha mn cc iu kin ny. gin c cc con s, t x = 33x, y = 33y vi UCLN(x, y) = 1. Ta s c x + y = 16. R rng c nhiu cp (x,y) nguyn t cng nhau tho mn phng trnh ny, chng hn (1, 15), (3, 13). Do ta cng khng tm c x, y.

p n: E

CU 33: Nu dng 1) s bit c khi lng cn l 5kg. Ch dng 2) cng tm c 7kg phm mu trong sn Luxo.

p n: D

CU 34: Nu B l s nguyn th B3 c th ln hn cng c th nh hn B2, chng hn vi B = 2 hoc B = -2, do vy 1) l khng . Nu B l s dng th cng c cc kh nng tng t, chng hn B = 2 hoc B = 0.5. Nu kt hp c hai iu kin th B nguyn dng, suy ra B > 1. V ta c khi B3 > B2.

p n: C

CU 35: 1) r rng khng kt lun, v 2 l s nguyn t nhng 4 th khng. iu kin 2) cng khng kt lun, chng hn v d 2 v 4 th mt s l nguyn t, mt s khng phi. Kt hp 1) v 2), khi y x l s chn khng c c l ln hn 1, nhng r rng vi v d trc 2 v 4, cng khng th kt lun x l s nguyn t.

p n: E

33


CU 36: Khng c g khng nh l H s i xe p vi vn tc khng i, do cc thng tin ni trn kt hp li cng khng kt lun v khong cch.

p n: E

CU 37: (1) khng cho bit to tng gi ln bao nhiu, (2) khng cho bit gi ban u. Nu kt hp li (1) v (2) th ta thng tin bit gi to tng bao nhiu phn trm, chnh l (2.000/15.000) 100%.

p n: C

CU 38: C cc s 8, 27, 64, 125 l lp phng ca mt s nguyn nm gia 2 v 200. Nu c 1) th ta c 2 ng vin l 27 v 125. Nh vy 1) khng . Nu c 2) ta c 1 ng vin duy nht l 64.

p n: B

CU 39: iu kin (1) cho bit din tch tam gic BAC cng bng 20, do vy din tch tam gic PBQ bng 201/4 = 5. iu kin (2) ch cho bit di mt cnh th khng tnh din tch.

p n: A

CU 40: Nu c 1) th kt lun c tam gic ABC l tam gic vung cn. iu kin 2) cho bit ba cnh khng bng nhau, vy tam gic khng cn.

p n: D

CU 41: (1) khng v khng bit lng ca Bnh. (2) cng khng v thiu thng tin v Chinh v Bnh. Cc d kin trn kt hp li cng khng bit c lng ca An, v thiu thng tin ca Chinh.

p n: E

CU 42: Nu c 1) th do 3 thuc P nn 6, 9, 12, ... cng thuc P. Vy mi bi s nguyn dng ca 3 u thuc P. Vy 1) . iu kin 2) ch bit c rng 3, 0, -3, -6, l thuc P, nhng khng c thng tin v 6, 9, 12, Vy 2) l khng .

p n: A

34

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CU 43: gii bi ton ny ta cn kim tra cc iu kin trong (1) v (2) c nm trong khong nghim ca bt phng trnh k2 + k - 2 > 0. Bt phng trnh k2 + k 2 > 0 c nghim l ngoi khong (-2, 1). iu kin k < 1 cha c phn nghim v phn khng nghim ca bt phng trnh, do 1) khng . Tng t, iu kin k > -1 cha c phn nghim v phn khng nghim ca bt phng trnh, nn 2) khng . Nu kt hp c hai iu kin li th 1 < k < 1 nm trn trong min khng nghim ca bt phng trnh, nh th ta c th tr li khng cho cu hi ca . p n: C

CU 44: D kin (1) khng v khng bit t hn bao nhiu. (2) cng khng v khng c mi lin h gia s lng hai loi sa. Thm ch nu kt hp c hai d kin th ta vn c th a ra nhiu phng n, v c rt nhiu s b hn mt s l. p n: E

CU 45: T 1) th ta c ngay x = 9. T 2) c 2 trng hp x = 9 hoc x = -9. Vy 2) khng . p n: A

35


CU 46: La chn cc p n (A), (C) v (E) u gii quyt cc vn khng lin quan n lp lun nu ra. La chn (D) nm ngoi phm vi lp lun nu ra bi v li xe khng mun chuyn sang i xe t in, lp lun ch ni n nh hng mi trng c th xy ra khi li xe chuyn sang i xe in. Lp lun (B) trc tip lin quan ti kt lun ni trn; nu xe chy bng in tit kim nng lng hn xe chy bng xng du th r rng l s cn t nng lng ha thch hn sn xut ra chng.

p n: B

CU 47: Cc nh sn xut v cc nh phn tch u cho rng pht trin cng ngh khng phi l mt yu t quan trng trong li nhun. Tuy nhin la chn (A) li i ngc li vi gi thit ny, v vy y l p n ng lm suy yu lp lun. La chn (B),ngc li, nm ngoi phm vi lp lun, la chn (C) ng h cho lp lun, v vy loi b (B) v (C). La chn (D) v (E) u khng thch hp.

p n: A

CU 48: Lp lun ny coi nh ngha mi trng ca vic nghin cu v tr. Loi b la chn (A) v la chn ny ng h cho kin ca tc gi. La chn (B) ch ra c tc dng v mi trng v ti nguyn v vy y l la chn ng. La chn (C) v (D) nm ngoi phm vi lp lun, la chn (E) khng thch hp.

p n: B

CU 49: c th ng h c cho k hoch ca Cng ty Dch v Gip vic, bn cn ch ra c rng tinh thn s c nng ln bng nhng vic m k hoch ang hng n (trng gi con em, ci thin ch xe, h tr hc cao ln). Phng n Cc i th cnh tranh ca Cng ty khng ph hp, v vy loi tr la chn (A). La chn (B) th thc t lm suy yu k hoch ca cng ty -> Loi tr (B). Cc chi tit c th v tnh hnh cng vic ca ngi gip vic khng thc

PHN 1.3. K NNG SUY LUN, T DUY LOGIC

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s c nh hng ti k hoch cho d chng c th xy ra -> Loi tr la chn (C) v (D). La chn (E) ch ra rng Cng ty Dch v ny c th gii quyt c vn v s khng hi lng bng cch ci thin ch xe, v vy y l la chn ng.

p n: E

CU 50: Kt lun l ng c vin A s ginh chin thng trong cuc bu c ch da trn c s duy nht rng s ngi ng h cho ng c vin A cao hn ca ng c vin B. Bn cn thm bng chng kt ni c t l ny vi kh nng c c - la chn(C ) p ng c iu . La chn (A), (B), (D) v (E) khng lm r vn a ra, khng a ra c t l bu c cao hn cho ngi thng cuc trong cuc bu c.

p n: C

CU 51: Lp lun ny cho rng xut tng thu s khng lm tng ngun thu nhp, bi v chi tiu tiu dng s gim. iu ny xy ra, ngi tiu dng phi c kh nng kim sot mc chi tiu ca h, iu m p n A nu ra. S phn i ca ngi tiu dng i vi thu hoc chng trnh ny l khng lin quan, bi v lp lun ny bn v chi tiu ca h, ch khng ni v quyn biu quyt ca h, do vy iu ny s loi b p n B, C, D. Vic np thu y cng khng lin quan, do loi b p n E.

p n: A

CU 52: Nhng gi thit trn lp lun cho rng cc vn ti chnh c kh nng lm gim s lng tuyn sinh i hc, nhng khng cp n cc k nng. p n A kt ni cc gi thit a ra vi kt lun bng cch trch dn mt mi quan h trc tip gia gio dc i hc v cc k nng. p n B, ngc li, l nm ngoi phm vi ca lp lun, v n cp n cc trng thng mi, trong khi p n C li a ra 1 s so snh gia trng cao ng cng ng i vi trng cao ng cng lp. p n D l khng thch hp bi v n so snh cc chng trnh o to qua thc tp vi cc chng trnh o to ti nhng trng k thut. Trong khi , p n E a ra 1 d bo v nm ngoi phm vi lp lun a ra.

p n: A

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CU 53: p n A khng thuc phm vi ca lp lun, b sch trong th vin c a dng v vn ha nh cc hnh thc khc gii tr khc hay khng, khng c ngha trong trng hp ny. p n B, ngc li, lm suy yu lp lun bng vic ch ra mt ngun khc lm giu thm vn vn ha cho c dn Midgeville. p n C a ra mt d on v do khng thuc phm vi vn , trong khi p n D l khng thch hp. p n E l iu cn thit i vi lp lun a ra, v n cho thy rng ct gim ti tr c th gy ra tn thng ng k i vi hnh thc vn ha quan trng nht ca c dn th trn. p n: E

CU 54: on vn tho lun v mc sn lng tit l thng tin ca mt ng vin s cho bit tnh trung thc ca ng vin th no. Theo , p n A ni hi qu v vn , trong khi s la chn B, C, D l vt qu phm vi ca on vn. p n E chnh l s la chn trc tip ph hp vi l lun ca tc gi. p n: E

CU 55: on vn m t cch m cc c ng c th khin cc nh lnh o doanh nghip tr nn qu bo th, v nhng tng mi c th mt thi gian thc hin v c th dn n mt s suy gim ng k v li nhun. Loi b p n A v B, v 2 p n ny a ra lp lun qu nng n. p n C ng v l 1 lp lun ging vi lp lun ca tc gi. p n D l qu cc oan v p n E li nm ngoi phm vi ca lp lun. p n: C

CU 56: xc nh xem c nn thay th my fax c, vn phng nn xem xt xem liu nhu cu s dng my fax trong tng lai c thay i hay khng. La chn A cp n a im, khng lin quan n nhu cu s dng my fax. La chn B cp n s lng cng vn, giy t nhn fax n nhng s lng cng vn, giy t gi fax i li khng c cp n. Nu tng s lng cng vn, giy t nhn v gi fax gim r rt, vn phng c th quyt nh s khng thay th my fax c, tuy nhin, ch bit mi s lng cng vn, giy t nhn fax th khng quyt nh c nn thay th hay khng. La chn C l p n chnh xc v a ra la chn thay th cho my fax. Nu vn phng chuyn sang trao i thng tin qua th in t v hn ch s dng giy th my fax thc s khng cn thit. La chn D cp n my photocopy, khng phi nhu cu i vi my fax. La chn E cp n s lng trang giy mi ln fax, khng lin quan n nhu cu cn tip tc s dng my fax. p n: C

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CU 57: nh gi lp lun rng liu thiu h thng phanh tay truyn thng c phi l nguyn nhn gia tng cc v tai nn xe p hay khng, cn tm thng tin c th loi tr cc nguyn nhn lm gia tng cc v tai nn. La chn A l p n ng, v a ra kh nng ng l trong cc iu kin khc nhau s c th lm gia tng cc v tai nn. C th iu kin ng x khi i xe s gy ra tai nn ch khng phi bn thn phanh chn ca xe p. La chn B ni n vic i xe p thng thng nn khng thch hp lm r vn . La chn C cp n vic i m bo him, yu t ny nh hng n c hai loi ngi i xe p. La chn D cp n ngi li xe hi th u nh hng n c 2 loi xe p. La chn E cp n gi tin u khng lin quan n nguyn nhn gia tng tai nn.

p n: A

CU 58: nh gi kt qu nghin cu, cn xem xt liu rng trong qu trnh 10 nm t khi s dng thuc tr su n khi tin hnh cuc nghin cu c thi gian cn bnh ung th pht trin hay khng. La chn A cp n cc loi thuc tr su khc nn khng phi l p n ng. La chn B cp n vn s dng thuc tr su hin nay nn khng lin quan n cuc nghin cu 10 nm trc. La chn C l p n ng v cp n thi gian bnh ung th pht trin, iu nh hng n vic liu nghin cu c pht hin ra bnh ung th sau 10 nm s dng thuc tr su hay khng. La chn D cp n cc nguyn nhn khc gy nn bnh ung th, khng lin quan n kt qu ca cuc nghin cu. La chn E cp n vic thiu thuc tr su th khng lin quan n c thuc tr su ln bnh ung th. p n: C

CU 59: Dung lp lun rng, v khc bit v tm sinh l v vn ha, cc nh lnh o nam gii c xu hng i u, lm tng nguy c xung t v chin tranh. (Bn thn tuyn b ny l kh m h: Cc nh lnh o nam gii c xu hng lm iu ny, gp phn gia tng cc cuc xung t). An c gng bc b kin ca Dung bng cch a ra trng hp c th trong cc nh lnh o n a t nc h n chin tranh, tuy nhin, kin ca Dung ch ra rng: thng thng cc nh lnh o nam gii c xu hng hnh vi nh vy, nhng cng khng phi l ch c nam gii mi lm nh th. iu ny tng ng vi la chn A (p n ng). Do Dung cha bao gi ni rng tt c cc nh lnh o nam gii s a t nc ca h n chin tranh, nn nhng v d phn bc v cc nh lnh o nam gii m Dung a ra s khng bc b lp lun , v th la

39


chn B l sai . Cc phng php v ng c ca cc nh lnh o n khng lin quan n lp lun ca Dung, nn la chn C, D, E l khng chnh xc.

p n: A

CU 60: Nghch l y l: nu bin bo th 2 ch rng anh ta i c na qung ng n chn hm ni th ti sao con s ghi mt trc v mt sau ca bin bo li khng ging nhau? La chn B v C hon ton khng lin quan n s khng nht qun gia cc bin bo nn khng cn phi gii thch. Do ngi ci la i t trn nh ni xung chn ni, La chn D v E cng khng th l gii c bi v ngay c khi mt bin bo b mt i hay hai mt ca bin bo b quay ngc th cng s khng c bin bo no vi con s ghi mt trc v mt sau u khp nhau. Tuy nhin, la chn A (p n ng), nu mt trc ca bin bo l ch khong cch n chn hm ni v mt sau l ch khong cch n nh hm ni th con s mt trc v mt sau bin bo tip theo 29 mt trc v 33 mt sau s khp vi tin trnh i xung ca ngi ci la.

p n: A

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CU 61: Tng ca 3 s l 57, trong c 2 s c tng l 30. Vy s cn li l 27.p n: E

CU 62: Hiu gia s ng sau v s ng ngay trc ln lt l 5, 10, 15, 20, 25, 30. Vy s tip theo trong dy l 111+35 = 146.

p n: D

CU 63: Trong bng ch ci, ch H v ch T ng ngay sau ch G v S, v L ng ngay trc M. Vy KTW s tng ng vi LSX.

p n: B

CU 64: Hnh C c nh hnh trn mu en ch c 2 cnh ni vi cc nh khc, vi cc hnh cn li nh ny u c 3 cnh ni.

p n: C

CU 65: Trong mi hng, thu c hnh th 3, nu ta xp chng ln nhau 2 hnh u tin th cc khuyn cng kch c nu c cng mu trng s tr thnh en, v nu khc mu s tr thnh trng.

p n: B

CU 66: Vi mi chm en xt xem c bao nhiu hnh trn cha n. C tt c 12 hnh trn.

p n: B

CU 67: V hnh m t ng i nh di y.Do vy lc ny ti ang cch im xut pht 3 dm v hng ng.p n: D

PHN 2.1. CH S THNG MINH IQ

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CU 68: Trng hp ti nht l ng ta ly ra 25 i mu v 16 i mu xanh, tc l tng cng 41 i. Do m bo 100% mi mu c 1 i th s i tt ng ta ly ra phi ti thiu l 42 i. Ch c p n B l t c yu cu ny.

p n: B

CU 69: Hoa l mt trong 3 a con nn nu 2 a u l Su v By th Hoa phi l a th ba.

p n: D

CU 70: Hiu gia s ng sau v s ng lin trc ln lt l 4, 8, 16. Vy s tip theo trong dy l 29+32=61.

p n: C

CU 71: Nu gi v l tc ban u th thi gian i ht qung ng 150 dm s l 150/v, v thi gian nu tng tc thm 5 dm/gi l 150/(v+5). Vy ta c phng trnh

150/v-150/(v+5) = 1. p n ng s l v = 25.p n: B

CU 72: Cch n gin nht l tnh trc tip 60% 240 + 55% 120 = 144+ 66 =210.

p n: C

CU 73: S ng sau hn s ng trc 19 n v. S cn thiu u tin l 57+19 = 76 v s cui cng l 95+19 = 114.

p n: B

CU 74: Thi gian t l nghch vi s lng nhn cng, vy 8 ngi s lm trong 285/8 = 17,5 (ngy).

p n: B

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CU 75: C cc cp s theo quy lut (5, 10), (30, 60), (180, 360), vy s tip theo l 1.0802 =2.160. Li c cc cp (10, 30), (60, 180), (360, 1.080). Do vy s cui cng l 2.1603 = 6.480.

p n: B

PHN 2.2. KIN THC KINH T - X HI

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78

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86

90

77

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87

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H NITa nh DETECH, S 8 Tn Tht Thuyt, T Lim, H Niin thoi: (04)37 68 77 17

TP. NNG 146D Nguyn Th Thp, Qun Lin Chiu, TP. Nngin thoi: (0511) 37 35 913

TP.H CH MINHTo nh Innovation, Cng vin phn mm Quang Trung, P.Tn Chnh Hip, Q.12, TP. HCM in thoi: (08) 5437 17 77

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