interpolasi polinominal orde-4
DESCRIPTION
Mata Kuliah Metode NumerikTRANSCRIPT
Tugas Metode Numerik :
Soal : Selesaikan Interpolasi Orde ke-4 dengan data-data sebagai berikut;e^x x3 = 3.5
x0 = 1.0 x4 = 4.0x1 = 1.5 Cari; x = 2.0x2 = 3.0
Jawab: 2.7183 33.115454.4817 54.59815
20.0855 e^2 = 7.3891Beda hingga langkah 1
4.4817 - 2.7183 = 3.52681.5 - 1.0
20.0855 - 4.4817 = 10.402573.0 - 1.5
33.1155 - 20.0855 = 26.059833.5 - 3.0
54.5982 - 33.1155 = 42.96544.0 - 3.5
Beda hingga langkah 210.4026 - 3.5268 = 3.4379
3.0 - 1.026.0598 - 10.4026 = 7.8286
3.5 - 1.542.9654 - 26.0598 = 16.90557
4.0 - 3.0Beda hingga langkah 3
7.8286 - 3.4379 = 1.7563033.5 - 1.0
16.9056 - 7.8286 = 3.6307734.0 - 1.5
Beda hingga langkah 43.6308 - 1.7563 = 0.624824
4.0 - 1.0
b0 = 2.7183 b3 = 1.756303b1 = 3.5268 b4 = 0.6248b2 = 3.4379
2.7183 + 3.5268 + 1.7189 + -0.8782 + 0.4686= 7.5545
Et = 7.5545 - 7.3891 x 100% = 2.24%7.3891
f(x) =
f(x0) = f(x3) =f(x1) = f(x4) =f(x2) = f(x) =
f[x1, x0] =
f[x2, x1] =
f[x3, x2] =
f[x4, x3] =
f[x2, x1, x0] =
f[x3, x2, x1] =
f[x4, x3, x2] =
f[x3, x2, x1, x0] =
f[x4, x3, x2, x1] =
f[x4, x3, x2, x1, x0] =
f4[x] =
Dari perhitungan Interpolasi Polinominal Orde-4 di atas didapat hasil Error (Et) terhadap nilai eksaksebesar; 2.24%
Eka Hidayat Dariyanto (121910301036) - Metode Numerik Kls. A