intrusion de agua 2
TRANSCRIPT
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Periodo Pseudo
Permanente
Pd(td)= 1j2(lnreD+0 ,80907) Pd(td)=(2jreD" 2)*tD+In reD-3j4
Pd(tD)=lj2tD Pd(tD)=2jreD"2
tDa=O,l
5.- Determinar el influjo de agua con la siguiente ec:
_ U~(tD)-We(tDj_l)P~(tDj) ( )We(t Dj) - We(t Dj -1) + . If Dj -t Dj-l
P D(t Dj) - t Dj-l P D (t Dj )
Modelo Pseudo Permanente de Lang. (PSS) ~We = c / Wi (Pan - P an+\)
=_ W cfP a(t)
q c / i dt
J A ka=--=----
c/Wi c,Wi j.16oo
Calculo de la presion medio esquema UBP.
- = (p _ )e-atli + Pn+\ - P" ( -af),/-1)Pan+\ Pn+\ an Pn aM e
Calculo de la presion medio esquema SIBP.
- _ - - af),/+ Pn + Pn+l (1- -af),/)Pan+\ - Pane 2 e
1:- Primeramente determinamos la c1ase de variacion si es lineal 0 diferencial
Si reD< 0.5 Utilizamos la variacion Lineal metoda LIBP
>0.5 Utilizamos la variacion Gradual metodo SIBP
En nuestro caso Utilizamos el radio de drenaje adimensional determinado en la tabla 8
para acufferos radiales Leung para un radio de drene reD = 2.8 tenemos un valor de 0.
de SIBP que es mayor aiD,S
2.-Calculamosa a= (ry/ro2) * ; _ 0.4381~ =0.1175
(6/ro) x reD -1 0,54* 2.8 -1
Fecha detiempo
Presion
inicio Prom. tD ~t (tpSS)D
alios Psia
Sep-89 0,00 3952 0,00 0,00 1,979
Jul-91 1,83 3854 0,97 1,78 1,979
Ago-94 4,92 3839 2,61 12,83 1,979Nov 95 6 17 3713 3 27 20 19 1 979
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e-Qdt e-QM-l
e-Qdt_l-e-QM
l/aAt(Pn+Pn+1 )/2 Pmpd a P
l,OOE+OO O,OOE+OO #iDIVjO! 3952 O,OOE+OO 3952
-8,27E-35 1,00E+00 -1,27E-02 3903 1,00E+00 3903
-2,60E-92 1,00E+00 -4,74E-03 3847 1,00E+00 3847
-l,26E-115 l,OOE+OO -3,78E-03 3776 l,OOE+OO 3776
-1,87E-154 l,OOE+OO -2,83E-03 3653 l,OOE+OO 3653
-l,51E-171 1,00E+00 -2,54E-03 3573 1,00E+00 3573
-l,78E-185 l,OOE+OO -2,35E-03 3481 1,00E+00 3481
-2,24E-210 l,OOE+OO -2,07E-03 3344 l,OOE+OO 3344
ti*Wi We n+l L'lWe(Mbls)
15203 0 0
15203 745 745
15203 1604 859
15203 2676 1817
15203 4553 2737
15203 5762 3025
15203 7161 4135
15203 9244 5108
4.- Calculamos el tiempo adimensional to Can la siguiente formula para cada etapa d
presion
2.309kttD = B * 2 L'lt= to * tp tpss = 0.25*Re02
uWc(rwacuj
Can este metoda tenemos un volumen de entrada de agua de 9.244 MMBbls
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1.- Primeramente ealeulamos de la tabla 8.5 de 105 parametros del modelo
MPSS modifieado por LANG
5", / rg = In reD -0.75 = LN(2.8)-0.75 = 0.284
Si reo >20 se toma un valor eonstante de 0.9855 si es menor se utiliza la ec:
/3/ = in re D *0.0465 + 0.845 = In(2.8) *0.0465 + 0.845 = 0.893
EI at podemos leer de la tabla 8.4 de 105 parametros del modele modifieado 0 podemos
ealeular con la siguiente relacion
at = 5.4156* reD-1.6506= 5.4156*2.8-1.6506= 0.98
Wi = Jrx(r} -r:)xhx =2.851e+9
a= C ''7 /ro2)* 2 = 0.43816 =0.2255
(5/ro)xreD2 -1 0,284*2.82-1
Fecha detiempo
Presion
inicio Prom. to L'.t (tpss)o
Aiios Psia
Sep-89 0,00 3952 0,00 0,00 1,97~
Jul-91 1,83 3854 0,97 1,78 1,979
Ago-94 4,92 3839 2,61 12,83 1,979
Nov-95 6,17 3713 3,27 20,19 1,979
Die-97 8,25 3592 4,38 36,15 1,979
Nov-98 9,17 3554 4,87 44,63 1,979
Ago-99 9,92 3408 5,26 52,21 1,979
Die-OO 11,26 3280 5,97 67,23 1,979
e-Q4t e-Q4t_le-Q4t_
Pmpss al_e-Q4t r
l/aAton+1 ti*Wi
0 0 0 3952 OOE+OO 15203-
2.5ge-65 1,00E+00 -1.00 3898 1,00E+00 15203-
2.81e-174 1,00E+00 -1.00 3846 1,00E+00 15203-
1.83e-218 1,00E+00 -1.00 3769 1,00E+00 15203
-4.8e-292 1,00E+00 -1.00 3646 1,00E+00 15203
-0 1,00E+00 -1.00 3571 1,00E+00 15203
-0 1,00E+00 -1.00 3473 1,00E+00 15203
-0 l OOE+OO -1 00 3337 1 00E+00 15203
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We n+l ~We(Mbls)
a a824 824
1616 791
2778 19864651 2665
5792 3127
7279 4151
9347 5196
En las secciones anteriores fueron presentados varios model os para el calculo de la
entrada de agua acumulada proveniente de 105 acufferos. Cada uno de 105 modelos fue
utilizado para estimar el influjo acumulado del acuffero circular limitado. Para cada unode 105 modelos, se calculo en base al tiempo, el influjo acumulado del acuffero sujeto a
un historial de presion variable en el contacto. Los resultados estan presentados en la
tabla 8.11.
15,06
9,24
9,35
8,65
7,28
Tabla 8.11 - Comparaci6n entre /05 varios mode/os de influjo de aqua
Como se pude observar el metodo de Fetkovich es el mas optimista para nuestros
alculos y 105 metod os mas recomendable son: Van Everdinger, PSS y MPSS de Leung
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A NIM A L .S IN D A NG E R
,,{' \?o..\'{q l"'OII
Many g!JimoJ$are in danger of
ex:tiQ.cticJDbecause we are
destroying the rainforests,~---
The -Lavclnrhinoceros one lived
in the rainforests of many
countries: in the north of India,
through ~0do-China and ~u.:tb
tbrougb Malaysia and the [slands
of Indonesia. But today there are
only about one thousand of these
animals in the world, some living
in Vietnam and some living in the
Ujung Kulon NationaLforest Parkon the island of Java , where forest
workers protect them.
Today, there are many forest
park in the rainforests of the
world. Animals need(~e parks"
because some ~p-e~l~$.have to travel
many B i J ( ) . !11~ lr _ ? S _ to find food. The
Par'~ Nationaldes ~I}~ in
Rwanda, for e > 5 .q j'n p - J ~ , protects the
mountain gorilla and saves it from~---extinction.
Some animals are in dangerJl.l 'Y \\C''_ 1c:iu f)
be~2H.~e P i ~ ~ p L ~ " w 9 [ ; 1 lt~(% ~f'scR~~'V,.i~{'C:ia.there are only 2,500 hyacinth -
m(lcaw~ now living in the forest of
LmLn A~~:_But in 1989, people
caught 500 hyacinth maca~s and
sold them in pe!:~~9Fs~,
(~) When you vjsit a pet shop, ask
about the animals there. D,id
somebody catch any of them in the
rainforests, put them into boxes,
and fly them to the pet shop)
Zoos in many countries of the----
VJorldare helping to p-rotect ..
animals in danger. The golden lion
tamarin comes from f?r:'.aziJ's.fol'est
near the sea.
( G The forest there is'-'
disappearing fast and people
caught hundreds of these tamar ins
and sold them in pet shops. There
were only a few left in the
rainforest. But many golden lion
tamarins were born in zoos, and
scientists have taken some of them
back to the Poco das Antas forest
Park near Rio..9s.janeiro.
/~ f ) Animals born in zoos know'-' nothing a_~out)life in the
rainforest. Someone must tea~h
thetn how to find food Q n d keep
away from danger. Janis Cartel'
teaches chjmpanzees about life in
the rainforest of the Gambia
because they were born in zoos:aIJ'away from forest. In Borneo,
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va CA8ULARY
grea-:- : grcn -, hurt : donar
bu rn : qu emar - coal : carbon
fog neblina - snow : nieve
dead : muerto - stone p ledr o
smoke : humo - lake logo'
aw ley - but pero
- dangerous : peligroso
- because o T , : debido 0
- oil : petroleo, oceite
- fuel : combustible
- Do!lution : contaminacionI
ENGLISH
- [)i- ,
4 Acid rain'liuv iG . Ac i'-- :-
\ .I ..
0t.:lc.l rJln IS:l ~re:1[ Qroblc:m in m: lnl'
counrrie s i n rh e \.'lorrh', ,vbnr foods
:.!n~cirinks - ,=-:ln~_s, for c::'(~mpic: _ I
coni :ciln :Jc ic :> hur che:~do ao r hurr
~lnybod~'. Qrdinaq/.r;J.in is J ij,,!e
J~ici, roo)Bt.:r srr on g a cid is
(J;:lngerous. elf bacj:eries
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~-. . .
1. Why are animals in danger? ')
" 'J'
3. What do animals need t olive bf~Her? ;:,l . .,.L .:, I. !. _,;:,
4. Which are the palces that prntf.:cttfw "nirn;;\l'>,'
5. Where do golden lion tam;:1rins live novi? -
6. Where can you buy macaws?-V Y nJ J z..{ ,1.'1).0-,-, I ' .,_. ,,] .C I (.!
1- i J
pet shops/-- -------- ~
destroying
- - _ . _ - _ ...._- - ---------
M . I . d r . ~ . . b I ;- J - 1 '\ h . fany anima s are III -----.- ---------------- 01extlllctlOn ecause peop e are -- -.~-....------.-----. t e ram orest ..l
\ .today there are about one thousand of J;:lVan Hhinoceros in the . 1 ). ./ :: - : : . . - - - - - - some are protected by
forests workers. There are many _~sJ( - inthe rainforests of the world .. Then; many animals --~~~22J
r nf ..'. t'I' .. .large park.sto find food. Today there ar~ 2500 --- -----------.:. -~------..:-------- liVing In the forests.
I -
Zoos help to _n ~-dlC the animals in danger; in the forest people catch them and selll them in --,--:~-::
_________J _
But there are animals that don't know about ------------- ...----------- in the forests and somebody teach thei
Animals need plenty of space to grow in
In Latin America p~ople can sell animals in pet shops
The people that visit the zoos can feed the animals
In Rio de Janeiro there are many forest parks
Some people teach animal ~how to live in the forests
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