kinh te vi mo-tham khao

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  • 8/2/2019 Kinh Te Vi Mo-tham Khao

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    Chng 4

    Qu trnh sn xut v

    chi ph

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    Sn xut

    iu g quyt nh s lng hng ha ca mt hng sn

    xut? Cc yu t u vo (K, L, lao ng, nguyn vt liu)

    c nng sut nh th no?

    Cng ngh trong qu trnh sn xut l g?

    Chng tn bao nhiu? Chng ta mun ti thiu hacc chi ph.

    Mc sn lng mang li li nhun ti a l baonhiu?

    Hy bt u bng mt hm sn xutbiu din mi quanh gia cc yu t u

    vo v u ra:Q = f(L, K, M, )

    N cho chng ta bit mc sn lng ti a, Q, ng vinhng yu t u vo cho trc (L, K, M, v.v..) bng

    cch s dng cng ngh f

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    Mi quan h gia sn xut v chi ph

    Cng ngh sn xut

    u vo (cc yut sn xut)

    Qu trnh sn xut(hm sn xut)

    Xut phm

    Kha cnh kinh t ca sn xut

    Chi ph u vo

    La chn kinh ttrong sn xut

    Chi ph (gi thnh)ca xut phm

    Qunlcngnghvc

    hiph

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    Sn xut v chi ph

    INPUTS (NHP LNG)

    CHI PHOUTPUT

    (XUT LNG)(Sn phm hu hnh )

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    Phn tch sn xut trong ngn hn

    Ngn hnl khong thi gian trong vic thay imt yu t sn xut rt tn km. (t, nh, v.v)Trong di hn, tt c cc yu t u vo u thayi.

    Trong sn xut d nhin c hng chc (hng trm?)yu t u vo.Gi s K c nh trong ngn hn v L l yu t uvo duy nht l hng c th thay i. (m hnh hai

    yu t u vo.Hm sn xut Q = F(K,L)

    Mc sn lng ti a c th c sn xut vi

    K v vn v L v lao ng.

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    Tng sn lng

    V d Hm sn xut Cobb-Douglas V d: Q = F(K,L) = K.5 L.5

    K c c nh 16 v.

    Hm sn xut ngn hn:Q = (16).5 L.5 = 4 L.5

    Sn xut khi 100 v lao ng c sdng?

    Q = 4 (100).5= 4(10) = 40 v

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    Nng sut bin ca lao ng

    MPL =D

    Q/D

    L o lng sn lng to ra bi cngnhn cui cng.

    dc ca hm sn xut ngn hn (theolao ng).

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    Nng sut lao ng trung bnh

    APL = Q/L y l ch s o lng nng sut v mtk ton.

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    Sn xut vi mt yu t bin i

    Vn Lao ng Tng SL (Q)3 0 0

    3 1 5

    3 2 18

    3 3 30

    3 4 40

    3 5 45

    3 6 48

    3 7 49

    3 8 49

    3 9 45

    APL= Q/L MPL= (DQ/D L)--- ---

    5 5

    9 13

    10 12

    10 10

    9 5

    8 37 1

    6.1 0

    5 -4

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    Nng sut (li tc) bin gim dn

    Nng sut bin gim dnl quan st thc nghim vs phn ng ca yu t u ra i vi s gia tng cc yut u vo.

    Ngha l khi lng ca mt yu t u vo no tng ln(theo mc gia tng bng nhau), s thay i cc yu tu vo s tr nn nh hn sau mt im no .

    Cc c im:

    1. MPLbt u gimsau mt im no , khng phi trnn m.

    D on ca nh kinh t hc c in Malthus: Vi lng

    t ai c nh v MPL gim dn, cc ngun cung thcphm s tr nn khng . ng y b st iu g?

    2. Ceteris paribus. tc l nhng yu t u vo khc cgi khng i: K, nng lng, nguyn liu, & cng ngh.Nu bn tm ra mt cng ngh sn xut tt hn, ton b

    ng tng sn lng TP s dch chuyn!

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    Q

    L

    Q=F(K,L)

    Nng sutbin tng

    dn

    Nngsutbin

    gimdn

    Nng sut binm

    MP

    AP

    Cc giai on sn xut

    Cc c im:Nu MPL> 0, Q tng

    Nu MPL< 0, Q gim

    Nu MPL= 0, Q t cc i

    Nu MPL > APL, APLtngln

    Nu MPL < APL, APLgimxung

    MPL = APLti APLcc i

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    Nng sut theo quy m

    Trong di hn tn ti mi quan h no gia cc yu t u vo v yu

    t u ra?

    Tt c inputs: Output qu trnh sn xut cho thy

    Tng gp i tng gp i NS khng i theo quy m

    Tng gp i < tng gp i NS gim dn theo quy mTng gp i > tng gp i NS tng dn theo quy m

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    ng ng lng

    S kt hp cc inputs (K, L) em li cho nh sn xut cng

    mc sn lng. Hnh dng ca ng ng lng phn nh mc thay thd hay kh gia cc yu t trong khi vn duy tr cng mc snlng.

    T l m nh sn xut c th thay th gia cc inputs v duytr cng mc sn lng gi l t l thay th k thut binMRTS. MRTSmang du m v thng gim dn

    MRTSKL = K/L l s lng lao ng tng ln thay th chos lng vn gim xung nhm m bo mc sn lngkhng i.

    Gi tr tuyt i ca t l thay th k thut bin chnh l dcca ng ng lng.

    Trong mi quan h vi nng sut bin MP

    MRTSKL

    = MPL

    /MPK

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    dc ca ng ng lng

    dco lng K m hng

    c th gim dng thmmt n v L, sao cho gi Qkhng i

    Slng tng thm t Y n X= DL * MPL

    Slng mt i t Y n X

    = DK * MPK Trn cng mt ng ng

    lng DL * MPL + DK * MPK =0

    DK/ DL = - MPL/ MPK - MPL/ MPKc gi l T l

    thay th k thut bin MRTS,

    K

    L

    Q = 500

    Y

    X

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    ng ng lng tuyn tnh

    Vn v lao ng lnhng yu t thayth cho nhau honho

    Q3Q2Q1

    Sn lngtng

    L

    K

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    ng ng lng Leontief

    Vn v lao ng lnhng yu t bsung hon ho

    Vn v lao ngc s dng theo tl c nh

    Q3

    Q2

    Q1

    K

    Sn lng

    tng

    L

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    ng ng lng Cobb-Douglas

    Cc inputs khngthay th cho nhauhon ton

    T l thay th k

    thut bin gim dn Phn ln cc quytrnh sn xut cng ng lng

    dng ny

    Q1

    Q2

    Q3K

    L

    Sn lng tng

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    ng ng ph

    S kt hp cc inputsvi cng mc chi ph

    Vi gi cc inputs chotrc, ng ngph cng xa gc ta gn lin vi nhngmc chi ph cao hn.

    S thay i gi cc

    input lm thay i dc ca ng ngph

    K

    LC1

    C0

    L

    Kng ng ph mido gim tin lng(gi ca lao ng).

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    ng ng ph

    ng ng ph cho thy

    tt c nhng kt hp (L,K)c th c mua vi mtmc tng chi ph chotrc.

    TC = wL + rK K = (-w/r)L + (TC/r)

    Tung gc l TC/r

    Honh gc l TC/w

    dccho bit cc mcgi tng ica hai input( dc = -2 ngha l munmua thm 1 n v L, phi

    mua t i 2 v K)

    Lng

    Vn (K)TC3/r

    TC2/r

    TC1/r

    TC1/w

    TC2/w

    TC3/w

    dc = -w/r

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    Ti thiu ha chi ph

    Nng sut bin trn mi ng b ra phibng nhau cho tt c cc inputs:

    Ni cch khcr

    MP

    w

    MPKL

    rwMRTS

    KL

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    Ti thiu ha chi ph

    Q

    L

    K

    im ti thiuha chi ph dc ng

    n ph= dc ng

    ng lng

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    Thu cng nhn c nng sut cao nht?

    Ti sao cu tr li i khi l Khng?

    Chng ta gi s hng mun thu thm mt cng nhnna. Hng c th chn mt cng nhn tay ngh caov mt cng nhn tay ngh thp.

    MPtay ngh cao = 2 MPtay ngh thp

    Nhng nng sut khng phi l yu t duy nht phixem xt

    Ptay ngh cao = 3Ptay ngh thp

    S ti u ha i hi rng MPcao / Pcao =

    MPthp/Pthp Tuy nhin, MPcao / Pcao < MPthp/Pthp

    V vy, hng nn thu cng nhn tay ngh thp v hc sn lng cao hn trn mt ng b ra.

    Ki h t & b t h

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    Kinh t xy & v san bng cc ta nh

    Xy dng Gara u xes dng hai

    input B tng & t ai Trc ht cho MPC/ PC = MPLand/Pland

    vng ngoi ca M

    Nu xy bi u xe trong khu vc nithnh, Ptcao hn, cc yu t khc

    khng i MPC/ PC > MPLand/Pland Cng ty xy dng chuyn sang s

    dng nhiu B tng v chng ta thycc bi u xe cao tng trong cc thnhph

    San bng ta nh: dng cht n hay ruMPCht n/ PCht n ? MPL/PL

    Cch no p dng Hong Kong v M?

    Plr hn nhiu Hong Kong cc hng chuyn san bng ta nh Hong Kong s dng nhiu L

    Ph h hi h

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    Phn tch chi ph

    Cc loi chi ph Chi ph c nh

    (FC)

    Chi ph bin i(VC)

    Tng chi ph(TC)

    Chi ph chm

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    Tng chi ph v chi ph bin i

    C(Q): Tng chi ph tithiu sn xut cc mcsn lng :

    C(Q) =VC+FC

    VC(Q): Chi ph thay

    i theo sn lng

    FC: Chi ph khng thay

    i theo sn lng

    $

    Q

    C(Q) =VC+FC

    VC(Q)

    FC

    hi h h hi h h

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    Cc chi ph c nh v chi ph chm

    FC: chi ph khng ikhi sn lng thay i

    Chi ph chm: chi ph bmt vnh vin sau khi nc tr

    $

    Q

    FC

    C(Q) = VC + FC

    VC(Q)

    Chi h t b h

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    Chi ph trung bnh

    Tng chi ph trung bnh

    ATC = AVC + AFCATC = C(Q)/Q

    Chi ph bin i

    trung bnhAVC = VC(Q)/Q

    Chi ph c nh

    trung bnhAFC = FC/Q

    Chi ph bin

    MC = DC/DQ

    $

    Q

    ATC

    AVC

    AFC

    MC

    Quan h chi ph trung bnh chi ph bin

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    Quan h chi ph trung bnh-chi ph bin

    Nu chi ph bin < chi ph

    trung bnh, chi ph trungbnh s gim

    Nu chi ph bin > Chi phtrung bnh, Chi ph trungbnh s tng ln

    MC = AC ti im cc tiuca AC

    $

    Q

    Q

    $/unit4

    4

    20

    100

    TC

    MC

    TVC

    TFC

    AVC

    ATC

    Chi ph trung bnh c chtrong vic phn tch cc chi

    ph m hng pht sinhcho n hin ti.

    Chi ph bin c ch trongvic phn tch cc chi ph mhng s pht sinh trong

    tng lai.

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    Chi ph c nh

    $

    Q

    ATC

    AVC

    MC

    ATC

    AVC

    Q0

    AFC Chi ph C

    Q0

    (ATC-AVC)

    = Q0 AFC

    = Q0(FC/ Q0)

    = FC

    hi h bi i

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    Chi ph bin i

    $

    Q

    ATC

    AVC

    MC

    AVCChi ph B

    Q0

    Q0AVC

    = Q0[VC(Q0)/ Q0]

    = VC(Q0

    )

    hi h

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    $

    Q

    ATC

    AVC

    MC

    ATC

    Tng CP

    Q0

    Q0ATC

    = Q0[C(Q0)/ Q0]

    = C(Q0)

    Tng chi ph

    T h ki h hi ki h h

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    Tnh kinh t v phi kinh t do quy m pht sinh t mi quan

    h phi tuyn tnh gia cc inputs v output.Sn xut giai on IKhi cc inputs tng, output tng theo t l ln hn. V d:Gp i inputs th output tng hn gp i.

    Nguyn nhn: Tng thm cc inputs to iu kin cho vicchuyn mn ha.

    Sn xut giai on IIKhi inputs tng, output tng nhng theo t l nh hn. V

    d: Gp i inputs th output tng t hn gp i.

    Nguyn nhn: Tng thm inputs to ra s cht chi khnggian v/hoc nhng kh khn trong vic phn vic v qunl.

    Tnh kinh t v phi kinh t theo quy m

    T h ki h h

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    Tnh kinh t nh quy m

    LRAC

    $

    Sn lng

    Kinh t theoquy m

    Phi kinh ttheo quy m

    T h ki h t hi ki h t th

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    Cc giai on sn xut dn n tnh kinh t v phi kinh t theo quy

    m

    Kinh t theo quy m: chi ph trung bnh gim khi sn lng tng.

    Phi kinh t theo quy m: chi ph trung bnh tng khi sn lng gim.

    v slng Tng chiph

    Tng chi ph trung bnh

    10,000 $1.0 triu $1.0 triu/10,000 = $100

    15,000 $1.4 triu $1.4 triu/ 15,000 = $93

    20,000 $1.9 triu $1.9 triu/ 20,000 = $95

    Kttheo

    quy m

    Phi kttheo quym

    Tnh kinh t v phi kinh t theo quy m

    T h ki h t hi ki h t th

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    $

    v sn lng

    ATC

    AVC

    MC

    AFC

    chuyn mnha

    Trong khong ny, hng tip tc c tnh kinh t theoquy m mc d s cht chi bt u xut hin S cht chi cha trm trng ln t tc ng

    dng tch ly ca chuyn mn ha

    Kt theo quy m

    Tnh kinh t v phi kinh t theo quy m

    V d

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    V d

    Tng chi ph: C(Q) = 10 + Q + Q2

    Hm chi ph bin i:VC(Q) = Q + Q2

    Chi ph bin i khi sn xut 2 v:

    VC(2) = 2 + (2)2 = 6

    Chi ph c nh:FC = 10

    Hm chi ph bin:MC(Q) = 1 + 2Q

    Chi ph bin sn xut 2 v:MC(2) = 1 + 2(2) = 5

    H hi h hi h

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    Hm chi ph ca nhiu sn phm

    C(Q1

    , Q2

    ): Chi ph sn xut hai sn phmchung

    Dng hm s tng qut:

    C(Q1, Q

    2)= f+ aQ

    1Q

    2+ b(Q

    1)2 + c(Q

    2)2

    T h ki h t th h i

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    Tnh kinh t theo phm vi

    C(Q1

    , Q2

    ) < C(Q1

    , 0) + C(0, Q2

    )

    Sn xut lin kt hai sn phm r hnsn xut ring bit.

    V d?

    S r hn cho Time-Warner cung cpnhng dch v kt ni Internet v dch vtin nhn Instant Messaging chung so vi

    cung cp dch v ring l.

    B sung chi ph

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    B sung chi ph

    Chi ph bin sn xut hng ha 1 gimkhi sn xut nhiu hn hng ha 2:

    DMC1/DQ2 < 0.

    V d?

    Da b v tht b

    H hi h hi h

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    Hm chi ph nhiu sn phm

    C(Q1, Q2) = f + aQ1Q2 + (Q1 )2 + (Q2 )2

    MC1(Q1, Q2) = aQ2 + 2Q1

    MC2(Q1, Q2) = aQ1 + 2Q2

    Tnh b sung chi ph: a < 0 Tnh kt theo phm vi: f > aQ1Q2

    C(Q1 ,0) + C(0, Q2 ) = f + (Q1 )2 + f + (Q2)2C(Q1, Q2) = f + aQ1Q2+ (Q1 )

    2 + (Q2 )2

    f > aQ1Q2: sn xut lin kt r hn

    V d:

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    V d:

    C(Q1, Q2) = 90 - 2Q1Q2 + (Q1 )2 + (Q2 )2

    C tnh b sung chi ph?

    C, v a = -2 < 0

    MC1(Q1, Q2) = -2Q2 + 2Q1

    C tnh kt theo phm vi?

    C, v 90 > -2Q1Q2 Hm cho vic st nhp cng ty?

    Kt lun

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    Kt lun

    ti a ha li nhun (gim thiu chiph) cc nh sn xut

    phi s dng inputs sao cho nng sutbin ca mi input phn nh gi m

    hng phi tr s dng input s kt hp ti u cc inputs c c

    khi

    MRTSKL = (w/r). Cc hm sn xut l nn tng gip xc

    nh hnh vi ti a ha li nhun trong

    nhng chng tip theo.

    p dng

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    Hng A-1 cung cp cc tm kim loi dng bnngoi my bay. Sn xut cc tm ny ch ihi 5 my to tm kim loi vi chi ph $300 mimy, v cng nhn.

    Cng nhn c th c tuyn dng bt k lcno trn th trng vi mc lng $7000 mtngi.

    Th trng tm kim loi mang tnh cnh tranh

    rt cao v gi th trng cho mi tm l $50. Da trn bng di y Hng A-1 nn thubao nhiu cng nhn ti a ha li nhun?

    p dng

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    My to tmkim loi Cng nhn S tm csn xut

    5 0 0

    5 1 6005 2 1000

    5 3 1290

    5 4 14805 5 1600

    5 6 1680

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    Nu A-1 thu 4 cng nhn, li nhunca n l

    1480 x 50-7000x4-300x5=44500

    Nu n thu thm mt cng nhn,doanh thu s tng thm 120x50=6000,v chi ph s tng thm 7000.

    Do nu thu thm mt cng nhn

    li nhun ca n s gim.

    Chi ph bin hay chi ph trung bnh

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    Hng ca bn c th sn xut 10,000 nv sn phm vi tng chi ph $1 triu, hay11,000 n v sn phm vi tng chi ph$1.2 triu. Hng c th bn ra th trng

    vi gi c nh $120 n v tt c nhngsn phm m n c th sn xut.

    Hng nn sn xut 10,000 n v hay11,000 n v?

    Chi ph bin hay chi ph trung bnh

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    Phn tch chi ph trung bnh

    Chi ph TB @ 10,000 v = $1 triu / 10,000 = $100/ v Chi ph TB @ 11,000 v = $1.2 triu / 11,000 = $109/ v

    Ti mc gi $120/ v, gi ln hn chi ph cho mi v sn phm.

    Nn sn xut thm 1,000 v.

    Phn tch chi ph bin

    Chi ph bin ca vic sn xut thm 1,000 v

    = TC / v sn lng = ($1.2 tr $1 tr) / (11,000 10,000)= $200/ v

    mc gi $120/ v, gi thp hn chi ph bin. Khng nn sn xut thm 1,000 v.