ky thuat chon mau
TRANSCRIPT
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Sampling TechniquesTran Van Hoang (MA.)
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Ths. Tran Van HoangChap 5-2
Cmau: 2
222/
zn
Trong o:- n: Son vcan ieu tra
- z/2 lahesotin cay c tra tbang
- : Sai socho phep
Xac nh c mau
Z tra t bng phn phi chun; hoc hm Excel: = NORMSINV(1-a/2)
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Ths. Tran Van HoangChap 5-3
V du 1: Ngi ta tien hanh ieu tra chon mau e xac nh mc thu
nhap trung bnh trong nam cua cac ho gia nh nong dan vi yeu cau:
Sai so 20.000
o tin cay 95%.
o lech tieu chuan ve thu nhap c tnh la 160.000d.
24620
160.96,12
22
2
22
2/
z
n
Xac nh c mau
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Ths. Tran Van HoangChap 5-4
2
2
2/ )1(
p
ppzn
Trong o:
P : Tyleca mu
z/2 lahesotin cay c tra tbang
p: sai socho phep
Xac nh c mau, c lng t l
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Ths. Tran Van HoangChap 5-5
V du: iu tra v ty le cac ho dan tren a ban Tp HCM
co s dung tai khoan ngan hang vi yeu cau sai so 1%,o tin cay 95%, ty le mot cuoc khao sat th nghiem trc
o la 9%. Xac nh so ngi can ieu tra (n).
146.3
01,0
)91,0).(09,0(96,1)1(2
2
2
2
ppzn
Xac nh c mau
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Sampling techniques
Ths. Tran Van Hoang
Convenience
Samples
Non-Probability Samples
Judgement
Probability Samples
Simple
RandomSystematic
StratifiedCluster
Quota
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Probability sampling
Items of the sample are chosen basedon known or calculable probabilities
Ths. Tran Van Hoang
Probability Samples
SystematicStratified ClusterSimple random
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Chon mau ngau nhien n gianSimple Random Samples
Lp danh sch cc i tng v sp xptheo th t t 1 n N
La chn cc n v mu bng cch bc
thm, quay su im: Nhanh
Nhc im: Kh thc hin i vi cc
tng th lnVD: Lp danh sch cc DN XK go theo
th t ABC
Ths. Tran Van Hoang
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Ly mu h thngSystematic Samples
Lp danh sch cc i tng v sp xptheo th t t 1 n N
Xc nh c mu mun ly (n)
Xc nh khong cch chn mu (k)Trong k n v ngu nhin chn 1 mu,
cc mu tip theo ti v tr 2k, 3k
Ths. Tran Van Hoang
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Ly mu h thngSystematic Samples
VD: N=60, n=10, k = N/n=6Chon 1 so ngau nhien trong khoang 1-6, chang han chon c
so 4, ta se co cac n v mau la 4, 10,16,22,28, 34, 40, 46, 52, 58
Ths. Tran Van Hoang
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Ly mu theo khi (cm)Cluster Samples
Tng th c chia thnh cc khiChn ngu nhin cc khi iu tra
u im: gn nh, ph hp cho nhng
tng th c s n v ln, khng philp danh sch tng th m ch lpdanh sch khi
Nhc im: Sai s cao
Ths. Tran Van Hoang
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Ly mu theo khi (cm)Cluster Samples
V d: iu tra mc sng h gia nh trna bn thnh ph, kh lp danh sch cch gia nh, nhng c th lp danh sch
cc Phng, mi Phng c coi l 1khi.
Ths. Tran Van Hoang
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Ly mu phn tngStratified Samples
S dng khi cc i v khc nhau v tnhcht (Thu nhp, sinh vin cc kha)
Tng th c chia thnh cc tng
mi tng ny ly mu theo phngphp ly mu ngu nhin n gin haymu h thng
Do s n v mi tng l khc nhau nnc mu ly ra mi tng cng khc nhauda trn t l ca tng so vi tng th
Ths. Tran Van Hoang
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Ly mu phn tngStratified Samples
Ho to Ssinh vin % sinh vin Ssinh vin lyra tng tng
Chnh quy 10.000 50 500
Hon chnh 2.000 10 100
Bng 2 2.000 10 100
Tichc 5.000 25 250Cao hc 1.000 5 50
20.000 100 1.000
Ths. Tran Van Hoang
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Chn mu phi ngu nhinNon-probability sampling
Lay mau thuan tien (Convenient sampling)Lay mau nh mc (Quotasampling)Lay mau phan oan (Judgement sampling)
Ths. Tran Van Hoang
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Lay mau thuan tienConvenient sampling
Mau thuan tien c dung khi muon co mot c lng s bove ket qua ban quan tam ma khong muon mat nhieu thi gian
va chi ph
Co the lay mau thuan tien bang cach en nhng ni co kha
nang gap oi tng ieu tra thuan tien nhat theo thi gian,
hoan canh, a iem.
Ths. Tran Van Hoang
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Lay mau phan oanJudgement sampling
Trong lay mau phan oan, chung ta phai quyet nh e chonoi tng tham gia hp tac vao mau khao sat bang cac phan
oan cac oi tng thch hp e ieu tra.
Tnh ai dien cua mau khao sat thc te se phu thuoc nhieu
vao kien thc va kinh nghiem cua ngi nghien cu ieu tra,
kien thc va mc o hp tac cua oi tng ieu tra
Ths. Tran Van Hoang
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Lay mau nh mcQuota sampling
Lay mau nh mc tng t lay mau xac suat phan tang vtrc tien phai chia tong the thanh cac tang.
Trong tng tong the con, ngi phong van co the chon oi
tng ieu tra theo cach thuan tien hoac phan oan.
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Tham kho thm cc sildeting Anh bn di.
Ths. Tran Van Hoang
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Simple Random Samples
Every individual or item from thepopulation has an equal chance of
being selected
Selection may be with replacement orwithout replacement
Samples can be obtained from a table
of random numbers or computer
random number generators
Ths. Tran Van Hoang
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Business Statistics: A-
Chap 1-21
Simple Random Samples
Every individual or item from the
population has an equal chance of
being selected
Selection may be with replacement
or without replacement
Samples can be obtained from a
table of random numbers or
computer random number generators
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Stratified Samples
Population divided into subgroups
(calledstrata) according to somecommon characteristic
Simple random sample selected from
each subgroupSamples from subgroups are combined
into one
Ths. Tran Van Hoang
PopulationDividedinto 4strata
Sample
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Systematic Samples
Decide on sample size: nDivide frame ofN individuals into
groups ofk individuals: k=N/n
Randomly select one individual fromthe 1st group
Select every kth individual thereafter
Ths. Tran Van Hoang
N = 64
n = 8
k = 8First Group
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Cluster Samples
Population is divided into severalclusters, each representative of thepopulation
A simple random sample of clusters isselected All items in the selected clusters can be used, or items can be
chosen from a cluster using another probability sampling
technique
Ths. Tran Van Hoang
Population
divided into 16
clusters.
Randomly selected
clusters for sample
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C l i c k t o e d i t c o m p a n y s l o g a n .Xin cm n