m.130412za transformatoren leerjaar 1 antwgruijs.com/bestanden/eenfase transformatie en... · gh...
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![Page 1: M.130412ZA Transformatoren leerjaar 1 antwgruijs.com/bestanden/Eenfase transformatie en... · gh rserxz ydq hhq hhqidvhwudqvirupdwru rpvfkulmyhq hq gdduelm gh yrojhqgh ]dnhq ehqrhphq](https://reader031.vdocuments.pub/reader031/viewer/2022022117/5c9b7c7409d3f215138b46f8/html5/thumbnails/1.jpg)
M.1
3041
2ZA
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E Nt
= − ⋅ ΔΦΔ
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U U N N ofUU
NN1 2 1 2
1
2
1
2
: := = Ook geldt: U2 x N1 = U1 x N2
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UU N
NV2
1 2
1
400 501000
20=⋅
= × =
NN U
Uwnd2
1 2
1
1100 400230
1913=⋅
= × ≈
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U2 = (U1 x N2) / N1 => (400V x 440wi) / 1520wi= 115,7894V
N2 = (U2 x N1) / U1 => (400V x 5000wi) / 10000V = 200wi
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U1 = (U2 x N1) / N2 => (24V x 1140wi) / 72wi = 380V
N1 = (U1 x N2) / U2 => (230V x 88wi) / 32wi= 632,5wi
N2 = (U2 x N1) / U1 => (28V x 230wi) / 115V = 56wi
U3 = (U1 x N3) / N1 => (115V x 264wi) / 230wi= 132V
Uad = U2 + U3 + U4 => 28V + 132V + 60V = 220V
N4 = 120 wi => Nts = N2 + N3 + N4 => 56wi + 264wi+ 120wi = 440 wi
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nNN
= 1
2
KUU
= 1
2
n KNN
UU
= = =1
2
1
2
Ubc = U3 - U4 => 10V - 11V = -1V
Ubd = U3 = 10V
Uac = U2 + U3 - U4 => 1V + 10V - 11V = 0V
Uad = U2 + U3 => 1V + 10V = 11V
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KUU
= 1
2
UUK2
1=
A nNN
. = = =1
2
480240
2
B UUn
V. 21 230
2115= = =
C De transformatieverhouding berekenen we met de formule. ::
KUU
= = =1
2
230115
2
K = 5 => U2 = U1 / K = 300V / 5 = 60V
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nNN
UUn
V
= = =
= = =
1
2
21
1500300
5
205
4
IUR
A mAL
22 4
1000 04 40= = = =,
K = 9,583 => U1 = K x U2 = 9,583 x 24 230V
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I III1 22
1
8 40 1 551
5 : : := = ⇒ = =
P U Is1 1 1= ⋅
P U Is2 2 2= ⋅
Ook geldt: N1 x I2 = I1 x N2
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P Ps s1 2=
UU N
NV
IUR
AL
21 2
1
22
230 400800
115
11557 5
2
=⋅
= × =
= = =
,
II N
NA1
2 2
1
2 400800
1=⋅
= × =
nNN
= = =1
2
800400
2
P en Ps s1 2 .
P U I VA
P U I VAs
s
1
2
1 1
2
230 1 230
2 115 2 230
= ⋅ = × =
= ⋅ = × =
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UU N
NV2
1 2
1
2 000 24300
160=⋅
= × =.
nNN
= = =1
2
30024
12 5,
P P kVA VA
IP
UA
IP
U
s s
s
s
1 2
1
2
10 10 000
10 0002 000
5
1
11
22
= = =
= = =
= =
.
..
00 000160
62 5 12 5 5 62 52 1
., : , ,= = ⋅ = × = A of I n I A
IUR
AL
22 160
1016= = =
NN
UU
II
1
2
1
2
2
1
= =
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(n) =5 => N1 : N2 = 5 : 1=> U2 = (U1 x N2) / N1 => (230V x 1) / 5 = 46V
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