materiais i 10 - dosagem de concretos
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𝐸 =𝜎
𝜀
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γ
γ δ
γ δ
δ δ
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𝐹𝑐𝑗 = 𝑓𝑐𝑘 + 1,65 ∗ 𝑆𝑑
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𝐹𝑐𝑗 = 𝑓𝑐𝑘 + 1,65 ∗ 𝑆𝑑
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𝐹𝑐28 = 25 + 1,65 ∗ 5,5 = 34,1 𝑀𝑃𝑎
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𝑎/𝑐 =𝐶𝑎𝐶𝑐
∴ 𝐶𝑐 =𝐶𝑎
𝑎/𝑐
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𝐶𝑐 =𝐶𝑎𝑎/𝑐
=200
0,475= 421 𝑘𝑔/𝑚³
𝐶𝑎 = 200 𝑙/𝑚³
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𝐶𝑏 = 𝑉𝑐 ∗ δ𝑐𝑜𝑚𝑝𝑎𝑐𝑡𝑎𝑑𝑎
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𝐶𝑏 = 𝑉𝑐 ∗ δ𝑐𝑜𝑚𝑝𝑎𝑐𝑡𝑎𝑑𝑎 = 0,715 𝑥 1500 = 1072 𝑘𝑔/𝑚³
𝐶𝑏0 = 𝐶𝑏1 = 50% 𝐶𝑏 = 536 𝑘𝑔/𝑚³
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𝑉𝑚 = 1 − (𝐶𝑐𝛾𝑐
+𝐶𝑏𝛾𝑏
+𝐶𝑎𝛾𝑎)
𝐶𝑎𝑟 = 𝛾𝑚 𝑥 𝑉𝑚
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γ γ γ
γ
𝑉𝑚 = 1 −𝐶𝑐𝛾𝑐
+𝐶𝑏𝛾𝑏
+𝐶𝑎𝛾𝑎
= (421
3100+1072
2700+
200
1000) = 0,267
𝐶𝑚 = 𝛾𝑚 𝑥 𝑉𝑚 = 2650 𝑥 0,267 = 708 𝑘𝑔/𝑚³
𝐶𝑐 = 421 𝑘𝑔/𝑚³𝐶𝑎 = 200 𝑙/𝑚³ 𝐶𝑏 = 1072 𝑘𝑔/𝑚³
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𝐶𝑐𝐶𝑐
∶𝐶𝑚𝐶𝑐
∶𝐶𝑏𝐶𝑐
∶𝐶𝑎𝐶𝑐
= 𝑐 ∶ 𝑎 ∶ 𝑏 ∶ 𝑎/𝑐
421
421∶708
421∶536
421∶536
421∶200
421=
1 ∶ 1,68 ∶ 1,27: 1,27 ∶ 0,48
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10
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𝛾 =𝑀
𝑉∴ 𝑉 =
𝑀
𝛾
1 ∶ 1,68 ∶ 1,27: 1,27 ∶ 0,48
γ γ γ
1:1,68
1,47:1,27
1,43:1,27
1,40: 0,48 =
1: 1,14: 0,89: 0,91: 0,5
50 ∶ 1,14 ∗ 50 ∶ 0,89 ∗ 50 ∶ 0,91 ∗ 50 ∶
0,48 = 50 ∶ 57 ∶ 44,5 ∶ 45,5 ∶ 24 𝑑𝑚³
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50 ∶ 84 ∶ 63,5 ∶ 63,5 ∶ 24 𝑘𝑔
50 ∶ 57 ∶ 44,5 ∶ 45,5 ∶ 𝟐𝟒 𝑑𝑚3
ℎ =𝑀𝑎
𝑀𝑠100% ∴ 𝑀𝑎 =
ℎ
100∗ 𝑀𝑎𝑟𝑒𝑖𝑎 =
5,5
100∗ 84 = 4,6 𝑘𝑔;
24 − 4,6 = 19,4 𝑘𝑔 𝑜𝑢 𝑑𝑚3
84 + 4,6 = 88,6 𝑘𝑔
88,6
1,47= 60,3 𝑑𝑚³
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1 ∶ 1,68 ∶ 1,27: 1,27 ∶ 0,48,
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γ
γ δ
γ δ
δ δ
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γ
γ δ
γ δ
δ
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