permodelan transmisi daya listrik
TRANSCRIPT
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Permodelan Transmisi Daya Listrik
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Penyaluran Daya
Dalam menyalurkan daya selalu terjadi Rugi2
Bentuk rugi-rugi adalah berupa rugi2 daya dan rugi tegangan
Besarnya rugi2 ditentukan oleh konduktor dan panjang saluran transmisi
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Karateristik Saluran Transmisi
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Permodelan saluran Transmisi
r , Tahanan saluranL , InduktansiC , CapasitansiG , Konduktansi umumnya diabaikan
paramater2 tsb persatuan panjang → panjang dan tak uniform
r L
G C
r L
G C
r L
G CVs
VR
. . . .
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Saluran
1. Saluran Pendek : 50 Mile
Pemodelan saluran adalah R dan L
2. Saluran Menengah 50 < l < 150 Mile
Pemodelan saluran adalah R , L dan C
3. Saluran Panjang 150 Mile
Pemodelan saluran adalah R, L, C dan G
Pembagian Saluran
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Jaringan 2 Kutub (2-port Network) dan Konstanta ABCD
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Saluran
Parameter Umum
%100xV
VVV
FL
FLNL −=
Persamaan Umum saluran transmisi
Vs = A VR + B IR
Is = C VR + D IR
Pengaturan Tegangan
)0( == RS
NL IkrnA
VV
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Saluran Pendek
Is = I = IR
Vs = VR + IRZZ= R + j w L = z lz = Impedansi per satuan panjangl = Panjang saluran
Permodelan
R L
VsVR
Is IRI
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Saluran PendekVs = VR + Z IR
Is = IR
Saluran pendek
A = 1, B = Z,
C = 0, dan D = 1
Maka parameter saluran
%100xV
VVsV
R
R−=
Pengaturan tegangan pada sisterima
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Saluran Medium
Model Phi
Model T
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Saluran Medium Phi-1Rangkaian
Y = y l = j w C
Y : Admitansi Capasitive totaly : Admitansi persatuan panjang
didapatkan
Diperoleh
R L
Vs VR
Is IR
2
Y
2
Y
I
Vs = VR + I Z
I = IR + (VR½Y)
Is = I + (Vs ½ Y)
Vs = (1+ ½ YZ)VR + IR Z
Is = Y(1+ ¼ YZ)VR + (1+ ½ YZ)IR
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Saluran Medium Phi-2Rangkaian
Y = y l = j w C
Y : Admitansi Capasitive totaly : Admitansi persatuan panjang
Sebelumnya didapatkan
A = D = 1 + ½ YZ
B = Z
C = Y (1 + ¼ YZ)
Diperoleh parameter saluran
R L
Vs VR
Is IR
2
Y
2
Y
I
Vs = (1+ ½ YZ)VR + IR Z
Is = Y(1+ ¼ YZ)VR + (1+ ½ YZ)IR
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Saluran Medium T-1Rangkaian T
Diperoleh
Sehingga diperoleh persamaan
R/2 L/2
Vs VR
Is IR
Y
Vs = VC + (½ Z) IS
Vc = VR + (½ Z) IR
Is = IR + Vc Y
R/2 L/2
VC
Vs = (1+ ½ YZ)VR + Z(1+ ¼ YZ)IR
Is = YVR + (1+ ½ YZ)IR
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Saluran Medium T-2Rangkaian T
Diperoleh
A = D = 1 + ½YZ
B = Z(1 + (1/4YZ)
C = Y
Sehingga diperoleh parameter
R/2 L/2
Vs VR
Is IR
Y
Vs = (1+ ½ YZ)VR + Z(1+ ¼ YZ)IR
Is = YVR + (1+ ½ YZ)IR
R/2 L/2
VC
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Saluran panjang-6
didapatkan
A = D = 1 + ½ YZ
B = Z (1 + YZ/6)
C = Y (1 + YZ/6)
Diperoleh parameter saluran
Vs = (Cosh l ) VR + (Sinh l ) Z IR
Is = ((Sinh l )/Zc)VR + (Cosh l ) IR
= konstanta rambatan transmisi =
l = panjang saluran
ZY /
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Parameter A, B, C dan D
◼ Persamaan umum saluran Vs = AVr + BIr
Is = CVr + DIrSaluran pendek : A = D = 1, B = Z, C = 0
Saluran medium
Rangkaian
A = D = 1 + ½ YZB = ZC = Y (1 + ¼ YZ)
Rangkaian T
A = D = 1 + ½YZB = Z(1 + (1/4 YZ)C = Y
A = D = 1 + ½ YZB = Z (1 + YZ/6)C = Y (1 + YZ/6)
Saluran panjang
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Latihan : soal dan coba dikerjakan
Suatu saluran transmissi 150 KV, 50 HZ pada sisi terima dibebani 50 MVA dengan power faktor 0,8 lagging bila parameter2 salurannya:
r= 0,172 ohm/mile, L = 2,18 mH/mile,
C = 0,0136 F/mile dan G = 0
Gambarkan Rangkaian Ekivalensi nya Tentukan : a. Tegangan dan Arus pada sisi kirim
b. Daya pada sisi kirim
c. Rugi2 transmissi dan Effisiensi transmissi
Bila panjang saluran : A. 40 miles
B. 100 miles dan C. 160 miles (nanti)