phep thu cho diem thi hieu va tcvn

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  • 8/12/2019 Phep Thu Cho Diem Thi Hieu Va Tcvn

    1/6

    4.2.4. Php thmc chp nhn (consumer acceptance test)- Php th

    cho im thhiu

    Mc ch

    Xc nh mc a thch hay kh nng chp nhn ca ngi tiu dng

    i vi cc sn phm nh gi.

    Nguyn tc

    Cc mu c phc v theo trt t ngu nhin.Ngi th th nm tng

    mu theo th t t tri sang phi v cho bit mc a thch ca h i vi

    tng mu trn thang im th hiu

    Cch tin hnh php th

    Mu thS lng mu th ty thuc vo mc phc tp v tnh cht ca mu

    ging nh trong php th xp dy.

    Cc mu c trnh by theo trt t hnh vung Latin Williams (ph lc

    1).

    Ngi thNgi th l ngi tiu dng c kinh nghim s dng sn phm, cha qua

    hun luyn. Ngi th c nhim v cho im trn thang im theo s thch ca

    mnh, do y cng l mt nhc im ca php th cho im th hiu. Bi v

    mi ngi th c mt s thch khc nhau, hay ni cch khc l khung i chiu

    khc nhau. V vy, khi cho im, ngi th da trn khung i chiu ca mnh

    t a ra cc kt qu m c th l cng s im nhng ngha ca n li

    hon ton khc nhau. Do , lng ngi th cho php th ny cng ln cng

    tt v i km theophp th mc chp nhn lun lun l mt bng cu hi

    thu nhn thng tin v thi quen tiu dng hay quan im, hay cm xc ca

    ngi tiu dng. T bng cu hi kt hp vi d liu cm quan mi cho ta thy

    c ci nhn tng qut v ngi tiu dng, phn nhm ngi tiu dng v c

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    lch bnh phng do sai s. Do , t s gia phng sai ca nhn t v phng

    sai ca sai s c gi l gi tr F hay l Ftest. Gi tr F ny biu th s bin thin

    gp ca cc tr trung bnh ca nhn t c quan tm so vi tr trung b nh chung

    ca tp hp d liu, chia cho sai s trung bnh bnh phng. y l gi tr chnh

    trong phn tch phng sai.

    C 2 gi thuyt:

    - H0(null hypothesis): khng c s khc bit gia cc mu th (sn phm).

    - HA(Alternative hypothesis): c s khc bit ng k gia cc mu th (sn

    phm).

    Bng 4.4. Bng ANOVA ca phn tch phng sai theo mt yu t

    (one way within subject)

    Ngun ca sbin ng

    t do(df)

    Tng cc bnhphng (SS)

    Trung bnh

    bnh phng(MS)

    Gi tr F

    Sn phm(A) a-1 SSA MSA MSA/ MSAS

    Ngith(S) s-1 SSS MSS

    S*A (phn d) (a-1)(s-1) SSAS MSAS

    Tng as-1 SStotal

    a: s sn phm (mu th)

    s: s thnh vin hi ng(ngi th)

    tnh ra c gi tr F, ngi ta bin i thng qua cc cng thc tnh

    ton nh sau:

    1. Tng bnh phngTngbnh phng ca sn phm (A):

    = (...)Tng bnh phng ca ngi th (S): = (. ..)

    Tng bnh phng caphn d(AS)

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    =( . .+..)2. Trung bnh bnh phngTrung bnh bnh phng mu:

    = 1Trung bnh bnh phng ca ngi th:

    = 1Trung bnh bnh phng caphn d:

    = (

    1) (

    1)

    3. Tng quan phng saimu(F) =

    Tra bng phn b F (Bng 12, ph lc 2)ng vi bc t do ca sn phm v bc

    t do ca sai s v so snh gi tr Ftnh

    Nu Ftnh Ftra bng: Chp nhn gi thuyt HA Nu Ftnh< Ftra bng: Chp nhn gi thuyt H0

    - Nu tnh gi trF v cho thy rng tn ti mt skhc bit c ngha gia cc

    sn phm (t 3 sn phm tr ln), chng ta cn phi xc nh c thcc mu

    no c skhc bit vi nhau bng cch tnh gi trskhc bit nhnht LSD

    (Least Significant Difference) mc ngha 5%.

    Cng thc tnh gi tr LSD nh sau:

    = 2 Trong : t l gi tr ti hn t cho php kim nh hai pha (tra bng 10, ph

    lc 2)ng vi bc t do ca sai s.

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    - Tip theo tnh hiu s gi tr trung bnh ln lt gia cc sn phm v so snh

    vi gi tr LSD.

    +Nu hiu s gi tr trung bnh nh hn gi tr LSD th gia 2 sn phm

    khngkhc nhau mc ngha 5%.

    +Nu hiu s gi tr trung bnh ln hn gi tr LSD th gia 2 sn phm

    c s khc nhau c ngha mc ngha 5%.