pitagorin poucak
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Ova prezentacija je tu za one koji zele nauciti nesto o pitagorinom poucku i provjezbati par zadatakaTRANSCRIPT
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Pitagorin poučak
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Pitagorin poučak
• Ako četiri površinom jednaka trokuta iz lijevog kvadrata drugačije složimo, dobit ćemo desni lik.
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• Na prethodnom prikazu vidimo da je zbroj površina kvadrata nad katetama po površini jednak kvadratu nad hipotenuzom
• Ovu povezanost između duljina kateta i duljine hipotenuze u pravokutnom trokutu nazivamo Pitagorinim poučkom
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Pitagorin poučak:
U pravokutnom trokutu površina kvadrata nad hipotenuzom jednaka je zbroju površina kvadrata nad katetama.
c2=a
2+b
2
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Napomena:
Pravokutni trokut kojemu su duljine stranica prirodni brojevi nazivamo Pitagorinim trokutom.
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Primjer 1.
• U pravokutnom trokutu ABC možemo izračunati duljinu hipotenuze ako su poznate duljine kateta: a = 6.5 cm i b = 3.8 cm.
cmc
cmc
bac
bac
5.7
8.35.6 22
22
222
=+=
+=
+=Pomoć
Kako napisati Formulu
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Primjer 2.
Ako je poznata duljina jedne katete a = 4.3 cm i duljina hipotenuze c = 12.1 cm primjenom Pitagorina poučka možemo izračunati duljinu druge katete.
cmb
cmb
acb
acb
3.11
3.41.12 22
22
222
=−=
−=
−=
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Zadaci za vježbu:
• Izračunavanje hipotenuze
• Izračunavanje katete a
• Izračunavanje katete b
• Primjena Pitagorina poučka
• Kraj
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Izračunavanje hipotenuze
U trokutu ABC izračunaj kolika je duljina hipotenuze c ako je a = 6.2 cm i b = 8.4 cm.
a) 38.44 cm
b) 2.89 cm
c) 10.44 cm
d) 109 cm
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Izračunavanje katete a
U trokutu ABC izračunaj kolika je duljina katete a ako je b = 5.3 cm i c = 8.9 cm.
a) 7.14 cm
b) 28.09 cm
c) 51.12 cm
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Izračunavanje katete b
U trokutu ABC izračunaj kolika je duljina katete b ako je a = 4.2 cm i c = 8.2 cm.
a) 17.64 cm
b) 7.04 cm
c) 49.6 cm
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Primjena Pitagorina poučka
Koliku će visinu doseći preklopljene ljestve duljine 2.5 m ako je za stabilnost ljestava na tlu potreban razmak 1.2 m?
a) 2.42 m
b) 1.44 m
c) 1.58 m
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Bravo! Točno si riješio postavljeni zadatak.
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Pogrešni rezultat.Pokušaj ponovo!
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Zadatak 1.
• Postupak
cmc
cmc
bac
bac
44.10
4.82.6 22
22
222
=+=
+=+=
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Zadatak 2.
• Postupak
cma
cma
bca
bca
14.7
3.59.8 22
22
222
=−=
−=−=
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Zadatak 3.
• Postupak
cmb
cmb
acb
acb
04.7
2.42.8 22
22
222
=−=
−=−=
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Zadatak 4.
• Postupak
mb
mb
acb
acb
42.2
6.05.2 22
22
222
=−=
−=−=
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Kako dodati formulu na slajd koristeći MS Equationa
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Kraj