presentation kubi, kuboidi,prizmi
TRANSCRIPT
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Tema:Kubi,kuboidi dhe prizmi
Profesori: Kandidati:
Prof. ass Fitore Abdullahu Fitore Gorani-Rexhepi
UNIVERSITETI I PRISHTINES- FAKULTETI I EDUKIMIPROGRAMI PER AVANCIM TE KUALIFIKIMIT TE MESIMDHENESEVE
PUNIM SEMINARIK
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Përmbajtja :
1. Historiku i prizmit2. Zbatimi i prizmave në art3. Syprina e sipërfaqes së kubit, kuboidit dhe e prizmit4. Vëllimi i kubit, kuboidit dhe e prizmit5. Sistematizimi – të gjitha formulat 6. Puna praktike7. Literatura
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Paralelopipedi.Kuboidi dhe kubi
Baza
BazaBaza
Kuboid(paralelopiped)
(Baza drejtëkëndësh)
(Baza katror)
Kub
Baza paralelogram
Paralelopiped
Paralelopipedi mundet të jetë i drejtë dhe i pjerët
Paralelopipedi i drejtë me bazë drejtkëndësh-KUBOID(KUADRI)
Kuboidi me të gjitha brinjët e barabarta-KUB
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Katërkëndëshi ACGE ështëprerja diagonale
A
E
GD
F
B
CD
Prerja diagonale
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ABCD
Cilat faqe janë paralele?
Te paralelopipedi faqet e përballtajanë paralele dhe të barabarta
Prizmi me bazë paralelogram quhet paralelopiped
6 faqet e paralelopipedit janë paralelograme
A
A1
C1D1
B1
B
CD
ADD1A1
DCC1D1
A1B1C1D1 BCC1B1
ABB1A1
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Paralelopipedi.Kuboidi dhe kubi
Detyra 1Njehsoni diagonalen hapësinore të kuboidit me përmasaa=6cm,b=8cm dhe c=24
a
b
c
d
D
Zgjidhje:
d2=a2 + b2
D2=a2 +b2 +c2
222 2486 D
222 cbaD
cmD 266765766436
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Paralelopipedi.Kuboidi dhe kubi
Detyra 2.Njehsoni syprinën e kuboidit me përmasa a=6cm,b=8cm dhe c=10cm
Zgjidhje: S=2(ab+ac+bc)
S=2(6·8 +6·10 + 8·10)=2(48 +60 +80)=2·188=374cm2
a
b
c
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Paralelopipedi.Kuboidi dhe kubi
Detyra 3.Njehsoni syprinën dhe diagonalen hapësinore të kubid me brinjë a=5cm
aZgjidhje:
d2=a2 + a2
S=6a2
S=6·52
S=6·25=150cm2
D2=a2 + a2 + a2
D=a
265.873.153 cmaD
3
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Hapja(rrjeti) dhe syprina
e prizmit
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Rrjeti i prizmit trekëndor
a
a a
a
H
B
B
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B
B
а
а
а а
а
H
Rrjeti i prizmit katërkëndor
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Syprina e prizmit është e barabartë me shumën
e syprinave të bazave dhe syprinën e faqeve
anësore(mbështjellësit)të tij.
S = 2B + M ku M=P•H
S=2a(a+2H)
Syprina e prizmit të rregullt katërkëndor
Ha3
4
3a 2
M
BS=2B+M
aH32
3a 2
S
Syprina e prizmit të rregullt trekëndor
2
3a3 2 B
HaM 6
H)23(3 aaS
Syprina e prizmit të rregullt gjashtëkëndor
B=a·b; M=2ab+2aH+2bH
S=2B+M=2ab+2aH+2bH=
=2(ab+aH+bH)
S=2(ab+aH+bH)
Syprina e kuadrit(kuboidit)
S=2B+M
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B
B
M
а
а
а а
а
H
а=4cm
H=5cm
Zgjidhje:
211280322 cmMBS
S-syprina
B-baza
M-mbështjellësi
Syprina e prizmit është e barabartë me shumën
e syprinave të bazave dhe syprinën e faqeve
anësore(mbështjellësit)të tij.
S = 2B + M ku M=P•H
Detyra 1:Njehso syprinën e prizmës së
rregullt katërkëndore me brinjën e bazës
a=4cm dhe lartësi H=5cm.
Syprina
B=a2=42=16cm2
M=4·a·H=4·4·5=80cm2
B=a2 M=4·a·H S = 2B + M
S=2a(a+2H)
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Detyra 2:Njehsoni syprinën e prizmit të rregullt
trekëndor me brinjë të bazës a=6cm dhe lartësi
H=8cm
Syprina
a
a a
a
H
а=4cm
H=5cm
B
B
M
2cm14,17514414.3114457.1522 MBS
Ha3
4
3a 2
M
B
2
22
57.154
73.136
4
73.16
4
3acmB
S=2B+M
2144863Ha3 cmM
Ha32
3a 2
S
Zgjidhje
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a=4cm
H=
5cm
Zgjidhje:
Detyra 3.Njehsoni syprinën e prizmit të rregullt
gjashtëkëndor me brinjë të bazës a=4cm dhe lartësi
H=5cm
Syprina
a
a
a a
aa
HM
B
B
2cm04.20312004,8312052.4122 MBS
2
3a3 2 B
HaM 6
Ha62
3a32
2
S
2
22
52.412
73.1163
2
343
2
3a3cmB
2120546Ha6 cmM
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Syprina
B
B
M
Detyra 4.Njehsoni syprinën e prizmit me bazë
katërkëndësh kënddrejt me brinjë a=5cm,b=4cm dhe
lartësi H=10cm
B=a·b; M=2ab+2aH+2bH
S=2B+M=2ab+2aH+2bH=
=2(ab+aH+bH)
S=2(ab+aH+bH)
a
b
c
ab
а=4cm
b=5cm
H=6cm
Zgjidhje:
S=2(ab+aH+bH)=2(5·4+5·10+4·10)=2(20+50+40)=220cm2
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Punë doreKroni
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1. Matematika kl. 7 nga autoret: Ramadan Zejnullahu, Ejup Hamiti, Eda Vula,Sejdi Bilalli
2. Burime nga interneti: http://www.slideshare.net/isakramadani/paralelopipedirelated=1http://www.slideshare.net/fictiongirl13/historia-e-zhvillimit-te-matematikes?related=1
3. Pune dore: “Kroni”
Literatura :
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Jufaleminderit përvëmendje