proyecto de vias terrestres

3
A (84,395; 55,382) B (85,169; 55,571) PI 1 (84,507; 55,614) PI 2 (85,070; 55,256) Distancias. API 1 = ( X¿¿ PI X A ) 2 +( Y ¿¿ PIY A ) 2 ¿¿ API 1 = ( 84,50784,3 95 ) 2 +(55,61455,382) 2 API 1 = 257.62mts. PI 1 PI 2 = ( X¿¿ PI 2X PI1 ) 2 +( Y ¿¿ PI 2Y PI1 ) 2 ¿¿ PI 1 PI 2 =¿¿ PI 1 PI 2 =667.18 mts PI 2 B= ( X¿¿ BX PI 2 ) 2 +( Y ¿¿ BY PI 2 ) 2 ¿¿ PI 2 B = ( 85,16985,070) 2 +( 55,57155,256) 2 PI 2 B= ¿ 330.19 mts. Rumbos. Rbo= tg 1 ( X PI1 X A ) ( Y PI1Y A ) Rbo= tg 1 ( 84,50784,395 ) ( 55,61455,382) Rbo 1=25°46´10” NE Rbo= tg 1 ( X PI2 X PI1 ) ( Y PI 2Y PI 1 ) Rbo= tg 1 ( 85,07084,507) ( 55,25655,614) Rbo 2=57°32´55” SE Rbo= tg 1 ( X B X PI 2 ) ( Y BY PI2 ) Rbo= tg 1 ( 85,16985,070) ( 55,57155,256) Rbo 3=17°26´50” NE

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curvas horizontales

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A (84,395; 55,382)B (85,169; 55,571)(84,507; 55,614) (85,070; 55,256) Distancias.=== 257.62mts.==

==330.19 mts.

Rumbos.Rbo= Rbo= Rbo 1=254610 NERbo= Rbo= Rbo 2=573255 SERbo= Rbo= Rbo 3=172650 NE

===964055===1050015

11= 60KPH

= =175.785 mts.= = ) = 117.092

= =190.92 mts.= = ) = 135.77CADENAMIENTO ANALITICO=0+000+=257.62-117.092=140.53 mts.= =140.53+175.785 =316.32 mts

=+[=316.32+[-(117.092+135.77)]=730.64 mts=730.64+190.92=921.56 mts921.56+ (330.19 -135.77)= 1115.98=1+115.98