proyecto de vias terrestres
DESCRIPTION
curvas horizontalesTRANSCRIPT
A (84,395; 55,382)B (85,169; 55,571)(84,507; 55,614) (85,070; 55,256) Distancias.=== 257.62mts.==
==330.19 mts.
Rumbos.Rbo= Rbo= Rbo 1=254610 NERbo= Rbo= Rbo 2=573255 SERbo= Rbo= Rbo 3=172650 NE
===964055===1050015
11= 60KPH
= =175.785 mts.= = ) = 117.092
= =190.92 mts.= = ) = 135.77CADENAMIENTO ANALITICO=0+000+=257.62-117.092=140.53 mts.= =140.53+175.785 =316.32 mts
=+[=316.32+[-(117.092+135.77)]=730.64 mts=730.64+190.92=921.56 mts921.56+ (330.19 -135.77)= 1115.98=1+115.98