Report copyright - Chapter 11, Solution 1. 800 - wiki.sj.ifsc.edu.br · Chapter 11, Solution 3. 10cos(2t +30°) → 10∠30°, ω=2 1H → jωL =j2 -j2 j C 1 0.25 F = ω → I 4 Ω I1 2 Ω I2 + −
Please pass captcha verification before submit form
Please pass captcha verification before submit form