Report copyright - 2014 1 · 2014. 1. 20. · 8 X)¥¡0 !n= (1;1;1) t˝\ ˘`··| \ä.! PQ!n= (t s;t2 s; s+ 3 8)(1;1;1) = 0 0|˝, s= t2 3 + t 3 + 1 8 tä. t| –Xì — PQX8t| ‹X’. jPQj = s (t s)2
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