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Review S system for spontaneous processes > 0 S surroundings energetic disorder = - H sys T S system = q r T positional disorde + S surroundings = S universe

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= - H sys T. = q r T. Review. S system. + S surroundings. = S universe. > 0. for spontaneous processes. S surroundings. energetic disorder. S system. positional disorder. = - H T. -. S system + S surroundings = S universe. > 0. - PowerPoint PPT Presentation

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ReviewSsystem

for spontaneous processes

> 0

Ssurroundings energetic disorder= - Hsys

T

Ssystem = qr

T

positional disorder

+ Ssurroundings = Suniverse

Ssystem + Ssurroundings = Suniverse

for spontaneous processes

> 0

Ssurroundings = - H

T

H2O(s) H2O(l)at 298 K spontaneous

H > 0

Ssurr < 0

-

Ssurr does not contribute to spontaneity

Ssystem + Ssurroundings = Suniverse

for spontaneous processes

H2O(s) H2O(l)at 298 K spontaneous

-

S positional disorder

solid liquid increasing disorder

S > 0

+

S does contribute to spontaneity

Ssystem + Ssurroundings = Suniverse

H2O(s) H2O(l)

solid liquidpositive

S

endothermicnegative

- H / T

At high T

At low T

Suniv

Suniv < 0

> 0

-+

Suniverse= Ssystem+ Ssurroundings > 0

2NO2 (g)

NO2 - brown, toxic gasN2O4 - colorless gas

Ssurr = - H / T

H

= (9.66)

Ssurr 0 favors spontaneity

- 2 Hof NO2

-58 kJ mol-1

= Hof N2O4

N2O4 (g)

+

- (33.5)2 =

>

2NO2 (g) N2O4 (g)

S =

So (J mol-1 K-1)N2O4

NO2

304.18239.95

S - (239.95)]= -175.7 J/mol K

2 mol gas 1 mol gas non-spontaneous

= [304.18 2

Soproducts - So

reactants

+Suniverse= Ssystem+ Ssurroundings > 0

-

2NO2 (g) N2O4 (g)

+Suniverse= Ssystem+ Ssurroundings > 0

-

-175.7 J mol-1 K-1

S -H / T+58 kJ mol-1

T(K)At high T

At low T

Free Energy

Ssystem+ Ssurroundings = Suniverse > 0

S

H -

G

GG

- H T

= Suniverse> 0

< 0TS = - TSuniverse

H - TS

= = HH - - TTSS

GG

- T

G = H - TS

G < 0

G > 0

G = 0

G = wmax

G is an extensive State function

Gof = 0

Gorxn =

spontaneous reaction

non-spontaneous reaction

equilibrium

maximum useful work

elements in standard states

Gof products - Go

f reactants

GG = = HH - - TTSScalculate Go for:

CH4 (g)

Gorxn =

- [ ]

= - 819 kJ

Gorxn = Ho

rxn - TSorxn

[Gof CO2 (g)+ ]

= [-892 kJ]-[ ](298K) (-242 J/K) = -819 kJ

+ 2O2 (g) CO2 (g) + 2H2O (l)

(Gof H2O (l))2

Gof CH4 (g) + 2(Go

f O2 (g))

Rubber band Thermodynamics

State 1 = relaxed State 2 = stretched

go from State 1 to State 2

What is sign of Go

What is sign of Ho --

What is sign of So

Go = Ho - TSo ++ -- --

++

GGoo = = HHoo - T - TSSoo

HHoo

++ --

-- ++

++ ++

-- --

positive

always positive

always negative

negative

negative

positive

high T

low T

SSoo GGoo

low T

high T

Equilibrium

Go = Ho - TS Go = 0

Ho

phase changes

Ho Hof prod -

___________________________

Soprod -= T

TSo = 0 = So

T

T = So

Ho- Ho

Hof react

Soreact

2NO2 N2O4-58 kJ

-175.7 J/K= 331 K

chemical reactions

tin buttons

Napoleon - 1812

white tin

ΔHof (kJ/mol) So (J/mol K)

grey tin0.0 51.55

-2.1 44.14

Snwhite SngreyΔHo = -2.1 - 0.0 = -2.1 kJ

ΔSo = 44.14 - 51.55= -7.4 J/mol K

T = -2100 J

-7.4 J/K

= 283 K = 10oC

∆G298 = .105 kJ ∆G233 = -.376 kJ