sample survey design help formulas

2
= 1 =1 , = = =1 , 2 = 1 βˆ’1 1 βˆ’ 2 =1 = 1 βˆ’1 2 =1 βˆ’ 1 =1 2 ; 2 = 2 2 = 1 1 βˆ’ 2 =1 ; 2 = 1 βˆ’1 1 βˆ’ 2 =1 ; = 2 βˆ’ ; = 2 βˆ’ ; =2 = 2 2 βˆ’ ; = 2 2 βˆ’ ; = 2 + 2 = 2 βˆ’ 1 + 2 , β„Ž = 2 4 ; = 2 4 2 = ; = ; 2 = 1 βˆ’ ; 2 = βˆ’1 1 βˆ’ ; 2 = βˆ’1 1 βˆ’ ; = βˆ’ βˆ’1 1 βˆ’ ; = βˆ’ 1 βˆ’ βˆ’1 ; = βˆ’ βˆ’1 2 1 βˆ’ ; = βˆ’ 2 1 βˆ’ βˆ’1 = 1 βˆ’ βˆ’ 1 + 1 βˆ’ ; = 2 4 = = 1 =1 ; = 1 βˆ’ 2 =1 = 1 βˆ’ 2 < ; = 1 βˆ’ 1 βˆ’ 2 =1 = 1 2 βˆ’ 1 βˆ’ 2 < ; ∝ = 1 =1 ; = 1 βˆ’ 2 =1 = 1 βˆ’ 2 < ; = 1 βˆ’ 1 βˆ’ 2 =1 = 1 2 βˆ’ 1 βˆ’ 2 < ; = 2 β‡’ Β± β„Ž = β„Ž , β„Ž = β„Ž , β„Ž = 1 β„Ž β„Ž β„Ž =1 , β„Ž 2 = 1 β„Ž β„Ž βˆ’ β„Ž 2 β„Ž =1 , β„Ž 2 = 1 β„Ž βˆ’1 β„Ž βˆ’ β„Ž 2 β„Ž =1 , β„Ž 2 = 1 β„Ž βˆ’1 β„Ž βˆ’ β„Ž 2 β„Ž =1 , = 1 β„Ž β„Ž =1 β„Ž=1 = β„Ž β„Ž=1 β„Ž β„Ž β„Ž =1 = β„Ž β„Ž β„Ž=1 , = = β‰  = β„Ž β„Ž β„Ž=1 = β„Ž β„Ž β„Ž=1 , = ⟺ β„Ž = β„Ž β†’ = ⟹ β„Ž ∝ β„Ž = β„Ž 2 β„Ž=1 β„Ž 2 β„Ž β„Ž βˆ’ β„Ž β„Ž , = β„Ž 2 β„Ž=1 β„Ž 2 β„Ž β„Ž βˆ’ β„Ž β„Ž , = , = β„Ž 2 β„Ž=1 β„Ž 2 β„Ž β„Ž βˆ’ β„Ž β„Ž , = β„Ž 2 β„Ž=1 β„Ž 2 β„Ž β„Ž βˆ’ β„Ž β„Ž , = β„Ž 2 β„Ž 2 β„Ž=1 / β„Ž 2 + 1 β„Ž β„Ž 2 β„Ž=1

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Important formulas

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𝑦 =1

𝑛 𝑦𝑖

𝑛

𝑖=1

, 𝜏 = 𝑁𝑦 =𝑁

𝑛 𝑦𝑖

𝑛

𝑖=1

, 𝑠2 =1

𝑛 βˆ’ 1 𝑦1 βˆ’ 𝑦 2𝑛

𝑖=1

=1

𝑛 βˆ’ 1 𝑦𝑖

2

𝑛

𝑖=1

βˆ’1

𝑛 𝑦𝑖

𝑛

𝑖=1

2

; 𝐸 𝑠2 =𝑆2

𝜎2 =1

𝑁 𝑦1 βˆ’ πœ‡ 2𝑁

𝑖=1

; 𝑆2 =1

𝑁 βˆ’ 1 𝑦1 βˆ’ 𝑦 2𝑁

𝑖=1

; 𝑉 𝑦 =𝑆2

𝑛 𝑁 βˆ’ 𝑛

𝑁 ; 𝑉 𝑦 =

𝑠2

𝑛 𝑁 βˆ’ 𝑛

𝑁 ; 𝐡=2 𝑉 𝑦

𝑉 𝜏 =𝑁2𝑆2

𝑛 𝑁 βˆ’ 𝑛

𝑁 ; 𝑉 𝜏 =

𝑁2𝑠2

𝑛 𝑁 βˆ’ 𝑛

𝑁 ; 𝑛 =

𝑁𝑆2

𝑁𝐷 + 𝑆2=

𝑁𝑠2

𝑁 βˆ’ 1 𝐷 + 𝑠2,π‘€β„Žπ‘’π‘Ÿπ‘’ π·πœ‡ =

𝐡2

4 ;𝐷𝜏 =

𝐡2

4𝑁2

𝑝 = 𝑦 ; 𝜏 = 𝑁𝑝 ; 𝜎2 = 𝑝 1 βˆ’ 𝑝 ; 𝑆2 =𝑁

𝑁 βˆ’ 1𝑝 1 βˆ’ 𝑝 ; 𝑠2 =

𝑛

𝑛 βˆ’ 1𝑝 1 βˆ’ 𝑝 ;

𝑉 𝑝 = 𝑁 βˆ’ 𝑛

𝑁 βˆ’ 1 𝑝 1 βˆ’ 𝑝 ; 𝑉 𝑝 =

𝑁 βˆ’ 𝑛

𝑁 𝑝 1 βˆ’ 𝑝

𝑛 βˆ’ 1; 𝑉 𝜏 =

𝑁 βˆ’ 𝑛

𝑁 βˆ’ 1 𝑁2𝑝 1 βˆ’ 𝑝

𝑛; 𝑉 𝜏 =

𝑁 βˆ’ 𝑛

𝑁 𝑁2𝑝 1 βˆ’ 𝑝

𝑛 βˆ’ 1

𝑛 =𝑁𝑝 1 βˆ’ 𝑝

𝑁 βˆ’ 1 𝐷 + 𝑝 1 βˆ’ 𝑝 ; 𝐷𝑝 =

𝐡2

4

πœ‡ 𝑝𝑝𝑠 =𝜏 𝑝𝑝𝑠𝑁

=1

𝑛𝑁

π‘¦π‘–πœ‹π‘–

𝑛

𝑖=1

; 𝑉 πœ‡ 𝑝𝑝𝑠 =1

𝑛

𝑦𝑗

π‘πœ‹π‘—βˆ’ πœ‡

2

πœ‹π‘—

𝑁

𝑗=1

=1

𝑛

π‘¦π‘–π‘πœ‹π‘–

βˆ’π‘¦π‘—

π‘πœ‹π‘—

2

πœ‹π‘–πœ‹π‘—

𝑁

𝑖<𝑗

;

𝑉 πœ‡ 𝑝𝑝𝑠 =1

𝑛 𝑛 βˆ’ 1

π‘¦π‘–π‘πœ‹π‘–

βˆ’ πœ‡ 𝑝𝑝𝑠 2

𝑛

𝑖=1

=1

𝑛2 𝑛 βˆ’ 1

π‘¦π‘–π‘πœ‹π‘–

βˆ’π‘¦π‘—

π‘πœ‹π‘—

2𝑁

𝑖<𝑗

; πœ‹π‘– ∝ 𝑦𝑖

𝜏 𝑝𝑝𝑠 =1

𝑛

π‘¦π‘–πœ‹π‘–

𝑛

𝑖=1

; 𝑉 𝜏 𝑝𝑝𝑠 =1

𝑛

𝑦𝑗

πœ‹π‘—βˆ’ 𝜏 𝑝𝑝𝑠

2

πœ‹π‘—

𝑁

𝑗=1

=1

𝑛

π‘¦π‘–πœ‹π‘–βˆ’π‘¦π‘—

πœ‹π‘—

2

πœ‹π‘–πœ‹π‘—

𝑁

𝑖<𝑗

;

𝑉 𝜏 𝑝𝑝𝑠 =1

𝑛 𝑛 βˆ’ 1

π‘¦π‘–πœ‹π‘–βˆ’ 𝜏 𝑝𝑝𝑠

2𝑛

𝑖=1

=1

𝑛2 𝑛 βˆ’ 1

π‘¦π‘–πœ‹π‘–βˆ’π‘¦π‘—

πœ‹π‘—

2𝑛

𝑖<𝑗

; 𝐡 = 2 𝑉 𝜏 𝑝𝑝𝑠 β‡’ 𝜏 𝑝𝑝𝑠 Β± 𝐡

π‘Šβ„Ž =π‘β„Žπ‘, π‘€β„Ž =

π‘›β„Žπ‘›, 𝑦 β„Ž =

1

π‘›β„Ž π‘¦β„Žπ‘–

π‘›β„Ž

𝑖=1

, πœŽβ„Ž2 =

1

π‘β„Ž π‘¦β„Žπ‘– βˆ’ πœ‡β„Ž

2

π‘β„Ž

𝑖=1

, π‘†β„Ž2 =

1

π‘β„Ž βˆ’ 1 π‘¦β„Žπ‘– βˆ’ πœ‡β„Ž

2

π‘β„Ž

𝑖=1

,

π‘ β„Ž2 =

1

π‘›β„Ž βˆ’ 1 π‘¦β„Žπ‘– βˆ’ 𝑦 β„Ž

2

π‘›β„Ž

𝑖=1

, πœ‡ =1

𝑁 π‘¦β„Žπ‘–

π‘β„Ž

𝑖=1

𝐿

β„Ž=1

= π‘β„Žπ‘

𝐿

β„Ž=1

π‘¦β„Žπ‘–π‘β„Ž

π‘β„Ž

𝑖=1

= π‘Šβ„Žπœ‡β„Ž

𝐿

β„Ž=1

,

π’š 𝒔𝒕 = π‘Ύπ’‰π’š 𝒉

𝑳

𝒉=𝟏

β‰  𝑦 = π‘€β„Žπ‘¦ β„Ž

𝐿

β„Ž=1

= π‘›β„Žπ‘› 𝑦 β„Ž

𝐿

β„Ž=1

, 𝑦 𝑠𝑑 = 𝑦 ⟺ π‘β„Žπ‘

=π‘›β„Žπ‘›β†’ 𝑦 𝑠𝑑 = 𝑦 ⟹ π‘›β„Ž ∝ π‘β„Ž

𝑉 𝑦 𝑠𝑑 = π‘Šβ„Ž2

𝐿

β„Ž=1

π‘†β„Ž2

π‘›β„Ž π‘β„Ž βˆ’ π‘›β„Žπ‘β„Ž

, 𝑉 𝑦 𝑠𝑑 = π‘Šβ„Ž2

𝐿

β„Ž=1

π‘ β„Ž2

π‘›β„Ž π‘β„Ž βˆ’ π‘›β„Žπ‘β„Ž

,

𝜏 𝑠𝑑 = 𝑁𝑦 𝑠𝑑 , 𝑉 𝜏 𝑠𝑑 = π‘β„Ž2

𝐿

β„Ž=1

π‘†β„Ž2

π‘›β„Ž π‘β„Ž βˆ’ π‘›β„Žπ‘β„Ž

, 𝑉 𝜏 𝑠𝑑 = π‘β„Ž2

𝐿

β„Ž=1

π‘ β„Ž2

π‘›β„Ž π‘β„Ž βˆ’ π‘›β„Žπ‘β„Ž

, 𝑛 = π‘β„Ž

2π‘†β„Ž2𝐿

β„Ž=1 /π‘€β„Ž

𝑁2𝐷 +1𝑁 π‘β„Žπ‘†β„Ž

2πΏβ„Ž=1

𝑉 𝑦 𝑠𝑑 = π‘Šβ„Žπ‘†β„Ž

πΏβ„Ž=1

2

π‘›βˆ’ π‘Šβ„Žπ‘†β„Ž

2πΏβ„Ž=1

𝑁; 𝑛 =

π‘β„Žπ‘†β„ŽπΏβ„Ž=1

2

𝑁2𝐷 + π‘β„Žπ‘†β„Ž2𝐿

β„Ž=1

; π‘›π‘π‘Ÿπ‘ = π‘β„Žπ‘†β„Ž

2πΏβ„Ž=1

𝑁𝐷 +1𝑁 π‘β„Žπ‘†β„Ž

2πΏβ„Ž=1

β‰… π‘β„Žπ‘ β„Ž

2πΏβ„Ž=1

𝑁𝐷 +1𝑁 π‘β„Žπ‘ β„Ž

2πΏβ„Ž=1

π‘›β„ŽπΆπ‘“=

π‘›π‘β„Žπ‘†β„Ž π‘β„Žπ‘†β„ŽπΏβ„Ž=1

⟹ 𝑛𝑁𝑒 = π‘β„Žπ‘†β„Ž

πΏβ„Ž=1

2

𝑁2𝐷 + π‘β„Žπ‘†β„Ž2𝐿

β„Ž=1

, 𝑛𝐢𝑓 = π‘β„Ž

2 π‘ β„Ž2

π‘€β„Ž

πΏβ„Ž=1

𝑁2𝐷 + π‘β„Žπ‘ β„Ž2𝐿

β„Ž=1

, 𝑛𝑆 = π‘Šβ„Žπ‘†β„Ž

2πΏβ„Ž=1

𝐷 +1𝑁 π‘Šβ„Žπ‘†β„Ž

2πΏβ„Ž=1

𝐢 = 𝑐0 + π‘β„Žπ‘›β„Ž

𝐿

β„Ž=1

, π‘›β„Ž βˆπ‘Šβ„Žπ‘†β„Ž

π‘β„Ž, π‘€β„Ž =

π‘›β„Žπ‘›=

π‘Šβ„Žπ‘†β„Ž π‘β„Ž

π‘Šβ„Žπ‘†β„Ž π‘β„Ž πΏβ„Ž=1

, π‘›β„Ž = 𝐢 βˆ’ 𝑐0 π‘Šβ„Žπ‘†β„Ž π‘β„Ž 𝐿

β„Ž=1

π‘Šβ„Žπ‘†β„Ž/ π‘β„ŽπΏβ„Ž=1

𝑛 = π‘Šβ„Žπ‘†β„Ž π‘β„Ž

πΏβ„Ž=1 π‘Šβ„Žπ‘†β„Ž π‘β„Ž 𝐿

β„Ž=1

𝐷 +1𝑁 π‘Šβ„Žπ‘†β„Ž

2πΏβ„Ž=1

= π‘β„Žπ‘†β„Ž π‘β„Ž

πΏβ„Ž=1 π‘β„Žπ‘†β„Ž π‘β„Ž 𝐿

β„Ž=1

𝑁2𝐷 + π‘β„Žπ‘†β„Ž2𝐿

β„Ž=1

𝑝 𝑠𝑑 = π‘Šβ„Žπ‘ β„Ž

𝐿

β„Ž=1

, 𝑉 𝑝 𝑠𝑑 = π‘β„Ž2𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž

π‘›β„Ž βˆ’ 1 π‘β„Ž βˆ’ π‘›β„Žπ‘β„Ž

𝐿

β„Ž=1

, 𝑉 𝑝 𝑠𝑑 =1

𝑁2 π‘β„Ž

2𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž

π‘›β„Ž βˆ’ 1 π‘β„Ž βˆ’ π‘›β„Žπ‘β„Ž

𝐿

β„Ž=1

;

𝑛 = π‘β„Ž

2 π‘β„Ž

π‘β„Ž βˆ’ 1 𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž

πΏβ„Ž=1

𝑁2𝐷 + π‘β„ŽπΏβ„Ž=1

π‘β„Žπ‘β„Ž βˆ’ 1 𝑝 β„Ž

1 βˆ’ 𝑝 β„Ž β‰ˆ

π‘β„Ž2𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž

π‘€β„Ž

πΏβ„Ž=1

𝑁2𝐷 + π‘β„ŽπΏβ„Ž=1 𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž

, π‘€β„Ž =π‘›β„Žπ‘›β‰…

π‘β„Ž 𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž π‘β„Ž

π‘β„Ž 𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž π‘β„Ž πΏβ„Ž=1

π‘€β„Ž =π‘›β„Žπ‘›β‰…

π‘β„Ž 𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž

π‘β„Ž 𝑝 β„Ž 1 βˆ’ 𝑝 β„Ž πΏβ„Ž=1