su dung simulink de mo phong cac mach dien 1 chieu 4447
TRANSCRIPT
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I HC BCH KHOA H NI
VIN IN
------------------------------
CC MCH IN MT CHIU M PHNGTRONG MATLAB
GVHD Trng Vn TrngSVTH Phan Cng TonSHSV 20082784
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Nam nh - 2012
I- Chnh lu it
1- Chnh lu ba pha hnh tia
Khi ti l R thun tr:
S chnh lu khng iu khin hnh tia, ti R
Cc thng s ca mch:
in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
+=
+=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10
Kt qu m phng:
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Khi ti l R + E:
S chnh lu khng iu khin hnh tia, ti R + Eteminator
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
+=
+=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 100V
Kt qu m phng:
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Khi ti l R + E + L:
S chnh lu khng iu khin hnh tia, ti R + E + L
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
+=
+=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 100V, L = 10e-03
Kt qu m phng:
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2 -Chnh lu ba pha hnh cu
Khi ti l R + E:
S chnh lu khng iu khin hnh cu, ti R + E
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
+=
+=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 100V
Kt qu m phng:
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Khi ti l R + E + L:
S chnh lu khng iu khin hnh cu, ti R + E + L
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
+=
+=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 100V, L = 10e-03
Kt qu m phng:
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II- Chnh lu Thyristor
1 -Chnh lu Thyristor mt pha, na chu k
S chnh lu Thyristor mt pha, na chu k, ti R + L
Cc thng s ca mch:in p ngun cn chnh lu:
)100sin().2(1101 tsqrtu =
Ti: R = 10, L = 10e-03Gc m Thyristor = 300
Kt qu m phng:
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Khi s chnh lu c thm it D0
S chnh lu Thyristor mt pha, na chu k, ti R + L, c D 0
Cc thng s ca mch:in p ngun cn chnh lu:
)100sin().2(1101 tsqrtu =
Ti: R = 10, L = 10e-03Gc m Thyristor = 300
Kt qu m phng:
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2 -Chnh lu Thyristor cu mt pha
Khi ti l R + L
S chnh lu Thyristor cu mt pha, ti R + L
Cc thng s ca mch:
in p ngun cn chnh lu:)100sin().2(1101 tsqrtu =Ti: R = 10, L = 100e-03Gc m Thyristor = 300
Kt qu m phng:
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Khi s chnh lu c thm it D0
S chnh lu Thyristor cu mt pha, ti R + L, c D 0
Cc thng s ca mch:in p ngun cn chnh lu:
)100sin().2(1101 tsqrtu =
Ti: R = 10, L = 100e-03Gc m Thyristor = 300
Kt qu m phng:
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Khi ti l R + L + E
S chnh lu Thyristor cu mt pha, ti R + L + E
Cc thng s ca mch:in p ngun cn chnh lu:
)100sin().2(1101 tsqrtu =
Ti: R = 10, L = 100e-03, E = 30V
Gc m Thyristor = 300
Kt qu m phng:
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Khi s chnh lu c thm it D0
S chnh lu Thyristor cu mt pha, ti R + L + E, c D 0
Cc thng s ca mch:
in p ngun cn chnh lu:)100sin().2(1101 tsqrtu =Ti: R = 10, L = 100e-03, E = 30VGc m Thyristor = 300
Kt qu m phng:
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Khi s lm vic ch nghch lu ph thuc
S chnh lu Thyristor cu mt pha, ti R + L + E, NLPT
Cc thng s ca mch:in p ngun cn chnh lu:
)100sin().2(1101 tsqrtu =
Ti: R = 10, L = 100e-03, E = 100VGc m Thyristor = 1200
Kt qu m phng:
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3- Chnh lu Thyristor ba pha hnh tia
Khi ti l R + L
S chnh lu Thyristor ba pha hnh tia, ti R + L
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, L = 10e-03
Gc m Thyristor = 300
Kt qu m phng:
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Khi s chnh lu c thm it D0
S chnh lu Thyristor ba pha hnh tia, ti R + L
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, L = 10e-03
Gc m Thyristor = 600
Kt qu m phng:
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Khi ti l R + E
S chnh lu Thyristor ba pha hnh tia, ti R + ECc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 100VGc m Thyristor = 300
Kt qu m phng:
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24
Khi s lm vic ch nghch lu ph thuc
S chnh lu Thyristor ba pha hnh tia, ti R + E, NLPT
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 200VGc m Thyristor = 1200
Kt qu m phng:
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24
Khi ti l R + L + E
S chnh lu Thyristor ba pha hnh tia, ti R + E + L
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 100V, L = 100e-03Gc m Thyristor = 300
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Kt qu m phng:
Khi s lm vic ch nghch lu ph thuc
S chnh lu Thyristor ba pha hnh tia, ti R + E + L, NLPT
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, E = 200V, L = 100e-03
Gc m Thyristor = 1200
Kt qu m phng:
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4- Chnh lu Thyristor ba pha hnh cu
Khi ti l R + L
S chnh lu Thyristor ba pha hnh cu, ti R + L
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
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Ti: R = 10, L = 10e-03Gc m Thyristor = 300
Kt qu m phng:
Khi ti l R + L + E
S chnh lu Thyristor ba pha hnh cu, ti R + L + E
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, L = 10e-03, E = 100VGc m Thyristor = 300
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Kt qu m phng:
Khi s lm vic ch nghch lu ph thuc
S chnh lu Thyristor ba pha hnh cu, ti R + L + E, NLPT
Cc thng s ca mch:in p ngun cn chnh lu:
)240100sin().2(110
)120100sin().2(110
)100sin().2(110
0
3
0
2
1
=
=
=
tsqrtu
tsqrtu
tsqrtu
Ti: R = 10, L = 10e-03, E = 200V
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Gc m Thyristor = 1200
Kt qu m phng:
III- B bm in p mt chiu (HACHEUR)
S b bm ni tip
Cc thng s ca s :in p ngun cn bm: U = 176VCc thng s ca mch: C = 4.8e-06; LC = 1901e-06Ti: R = 1; L = 200e-03; E = 100V
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T = 0.002s; T1 = 0.001s
Kt qu m phng: