tinh toan u-trench cover

8/8/2019 Tinh Toan U-Trench Cover

1/24

Follow 22 TCN 272-05 for bridge and Culvert designing standard

Open Culvert Concrete grade f'c=

b= 1000 mm ==> =

L= 500 mm

h= 100 mm

50 mm

q= 6.8 0.68

=> p= 278.8N/mm

L= 500 mm

=> M= ### N.mm

Preliminarily determine the number of reforcement rebar:

240 Mpa ==>= 0.19

===> 860.901

rebar diameter: d= 16 mm ==> n= 4.28

Choose : n= 5.00 1005.31

reverification

The position of nuetral line will be determined base on the balance equation of

C = 11.322mma= 9.462 mm50mm

Destructive moment:

==> 10,922,278.62 (N.mm ) OK

Verification of the maximum steel content:

Condition:

Where: C= 11.322

50

0.23 < 0.42 OK

Verification of the minimum steel content:

Rk=

ts= E

c=

kg/cm2 = N/mm2

fy=

As= mm2

==>As= mm2

ds=

Mph

=

dc=

C/dc=


2/24

Condition:

Where : 0.010 > 0.004

Result: OK

Final conclusion: OK

Pmin

=As/b.h=


3/24

Follow The standart for bridge

30 Mpa 25

0.836 440

3.45 Mpa

930,977.31 Mpa

(or Mpa) 500

QT79

0.15

A= 0.13 ==> =

0.36

Where: 30.00

compressive and tensile stress: 240

b= 1000

50

==> 848.78

Choose rebar:

d= 16==> Choose n = 5

Verification:

==> = 0.16

###

Result: OK

c= T/m3

Ru=

Rt=

ho=

Ft=

==>Mph

=


4/24


5/24

and Culvert designing dated in 1979 (Former Standard)

1000

410

==>

0.14

Mpa

Mpa

mm

mm

mm ==>n= 4.22nos ###

==> A= 0.15 and x= 8.04 mm

N.mm

mm2

==>Ft= mm2


6/24


7/24


Open Culvert Concrete grade f'c

b= 4000 mm ==> =

L= 1900 mm

h= 200 mm

50 mm

===> Effective height of cross section:

150 mm

q= 6.8 0.68

=> p= 278.8N/mm

L= 1900 mm

=> M= ###N.mm

Moments of the compressive and tensile stress at the cen

we have these equation as follow:

Define:

and

The structure of reinforcement concrete shall meet the cr

and A=

Rebars arrangement:

-Compressive rebar:

Sellect: d'= 16 mm

280 Mpa

Preliminarily determine the number of compressive rebars:

Compressive rebar area:

-22,697.17 ==> n'=

Sellect: n'= 18nos ==>

-Tensile rebar:

Sellect: d= 16 mm

280 Mpa

The number of tensile rebar will be determined as follow:

Tensile rebar area:

33,672.69 ==> n=

Rk=

at= E

c=

ds=

kg/cm2 = N/mm2

=C/ds

1=

d's=

f'y=

A's= mm2

A's=

ds=

fy=

As= mm2


8/24

Sellect: n= 22nos ==> As=

Re-Verification the force bearing capactity of reinforcement concrete:

0.01 ==> OK

and A= 0.01

The distance from outer side of compressive concrete area to the nuetral line

C= 2.64 mm

The height of compressive stress block will be:

a= 2.21 mm

The Ultimate destructive moment will be determined as follow:

###N.mm > MConclusion: PASS


Condition:

Where: C= 2.64 mm

150

0.02 < 0.42 OK


Condition:

Where : 0.006 > 0.003

Result: OK

Final conclusion:

Coefficient 1=

Mph

=

dc=

C/dc=

Pmin

=As/b.h=


9/24


30 Mpa 25

0.836 440

3.45 Mpa

930,977.31 Mpa

1900

(or Mpa)

QT79

ter line of tensile rebar or compressive concrete area

iteria of the ultimate steel contents where :

0.55

0.40

40.00 mm

-113 nos

3619

150.00 mm

167.47 nos

c= T/m3

mm2


10/24

4,423.36

as follow:

mm2


11/24


4000

410

==>


12/24


13/24



b= 4000 mm ==> =

L= 1900 mm

h= 200 mm

50 mm

===> Effective height of cross section:

150 mm

q= 6.8 0.68

=> p= 278.8N/mm

L= 1900 mm

=> M= ###N.mm

Moments of the compressive and tensile stress at the cen

we have these equation as follow:

Define:

and

The structure of reinforcement concrete shall meet the cr

and A=

Rebars arrangement:

-Compressive rebar:

Sellect: d'= 16 mm

280 Mpa

Preliminarily determine the number of compressive rebars:

Compressive rebar area:

-22,697.17 ==> n'=

Sellect: n'= -112 nos ==>

-Tensile rebar:

Sellect: d= 16 mm

280 Mpa

The number of tensile rebar will be determined as follow:

Tensile rebar area:

7,534.64 ==> n=

Rk=

at= E

c=

ds=

kg/cm2 = N/mm2

=C/ds

1=

d's=

f'y=

A's= mm2

A's=

ds=

fy=

As= mm2


14/24

Sellect: n= 38.00 nos ==> As=

Re-Verification the force bearing capactity of reinforcement concrete:

0.55 ==> Fail

and A= 0.40

The distance from outer side of compressive concrete area to the nuetral line

C= 99.07 mm

The height of compressive stress block will be:

a= 82.79 mm

The Ultimate destructive moment will be determined as follow:

###N.mm > MConclusion: PASS


Condition:

Where: C= 99.07 mm

150

0.66 > 0.42 Fail


Condition:

Where : 0.010 > 0.003

Result: OK

Final conclusion:

Coefficient 1=

Mph

=

dc=

C/dc=

Pmin

=As/b.h=


15/24


30 Mpa 25

0.836 440

3.45 Mpa

930,977.31 Mpa

1900

(or Mpa)

QT79

ter line of tensile rebar or compressive concrete area

iteria of the ultimate steel contents where :

0.55

0.40

40.00 mm

-113 nos

-22519

150.00 mm

37.47 nos

c= T/m3

mm2


16/24

7,640.35

as follow:

mm2


17/24


4000

410

==>


18/24


19/24



b= 4000 mm ==> =

L= 1900 mm

h= 200 mm

50 mm

q= 6.8 0.68

=> p= 278.8N/mm

L= 1900 mm

=> M= ### N.mm

Preliminarily determine the number of reforcement rebar:

240 Mpa ==>= 0.12

===> 6,314.34

rebar diameter: d= 16 mm ==> n= 31.40

Choose : n= 32.00 6,434

reverification

The position of nuetral line will be determined base on the balance equation

C = 18.11 mma= 15.14 mm150 mm

Destructive moment:

==> 219,935,026.58 (N.mm ) OK


Condition:

Where: C= 18.11

150

0.12 < 0.42 OK


Rk=

ts= E

c=

kg/cm2 = N/mm2

fy=

As= mm2

==>As= mm2

ds=

Mph

=

dc=

C/dc=


20/24

Condition:

Where : 0.008 > 0.004

Result: OK

Final conclusion: OK

Pmin

=As/b.h=


21/24


30 Mpa 25

0.836 440

3.45 Mpa

930,977.31 Mpa

(or Mpa) 1900

QT79

0.09

A= 0.08 ==> =

0.36

Where: 30.00

f compressive and tensile stress: 240

b= 4000

150

==> 6263.14

Choose rebar:

d= 16==> Choose n = 32

Verification:

==> = 0.09

###

Result: OK

c= T/m3

Ru=

Rt=

ho=

Ft=

==>Mph

=


22/24


23/24


4000

410

==>

0.08

Mpa

Mpa

mm

mm

mm ==>n= 31.15nos 6433.98

==> A= 0.08 and x= 12.87 mm

N.mm

mm2

==>Ft= mm2


24/24

tinh toan u-trench cover

Documents