3/ Vo thi im no sau y tin trnh ch thao tc trn a ch o, khng bao gi thy c cc a ch vt l a/ Thi im bin dch b/ Thi im np c/ Thi im x l d/ Cu a,b l ng p n : c 4/ Trong vic cp pht vng nh lin tc cho tin trnh, m hnh no cho php di chuyn tin trnh trong b nh sau khi np : a/ M hnh Linker-Loader b/ M hnh Base-Limit c/ C hai cu u ng d/ C hai cu u sai p n : a 5/ Thut ton chn on trng tho mn nhu cu cho mt tin trnh (trong phn on vng nh ) a/ First-fit b/ Best-fit c/Worst-fit d/Khng cu no ng p n : d 6/ Hin tng phn mnh l : a/ Vng nh b phn thnh nhiu vng khng lin tc b/ Vng nh trng c dn li t cc mnh b nh nh ri rc c/ Tng vng nh trng tho mn nhu cu nhng cc vng nh ny li khng lin tc nn khng cp cho tin trnh khc d/ Khng cu no ng p n : c 7/ Trong k thut cp pht vng nh phn on mt a ch o c th hin bi: a/ B trong s l s hiu phn on, d l a ch tng i trong s b/ B vi base l ch s nn, limit l ch s gii hn c/ Khng cu no ng d/ C hai cu u ng p n : a 8/ Vi a ch logic v thanh ghi nn STBR, thanh ghi gii hn STLR a ch vt l c tnh tng ng vi a ch logic l: a/ STLR -s-d b/ STBR+s+d c/ STLR- STBR+s+d d/ s+d p n :b 9/ Thut ton chn vng trng u tin ln np tin trnh l: a/ First-fit b/Best-fit c/Worst-fit d/ Khng cu no ng p n :a 10/ Thut ton chn vng trng u t do nh nht nhng ln np tin trnh l:

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a/ First-fit b/Best-fit c/Worst-fit d/ Khng cu no ng p n :b 11/ Thut ton chn vng trng u t do ln nht np tin trnh l: a/ First-fit b/Best-fit c/Worst-fit d/ Khng cu no ng p n :c 12/ Trong k thut phn trang nu kch thc khng gian a ch l 2m kch thc trang l 2n cu no sau y pht biu khng chnh xc: a/ n-m bit cao ca a ch o biu din s hiu trang v n bit thp cho bit a ch tng i trong trang b/ m-n bit thp ca a ch o biu din s hiu trang v n bit cao cho bit a ch tng i trong trang c/ m-n bit cao ca a ch o biu din s hiu trang v n bit thp cho bit a ch tng i trong trang d/ Cu b,c ng p n :c 13/ Xt c ch MMU trong k thut phn trang vi a o c dng chuyn i a ch ny sang a ch vt l, MMU dng bng trang, pht biu no sau y l chnh xc: a/ Phn t th d trong bng trang lu s hiu khung trang trong b nh vt l ang cha trang p b/ Phn t th p trong bng trang lu s hiu khung trang trong b nh vt l ang cha trang d c/ Phn t th p+d trong bng trang lu s hiu khung trang trong b nh vt l ang cha trang p d/ Phn t th p trong bng trang lu s hiu khung trang trong b nh vt l ang cha trang p p n :d 14/ K thut cp pht no sau y loi b c hin tng phn mnh ngoi vi a/ p n : a 15/ Gi s b nh chnh c phn vng c kch thc theo th t l 600k, 500k, 200k, 300k, cc tin trnh theo th t yu cu cp pht c kch thc 212K, 417K, 112K, 426K .Nu s dng thut ton Best-fit qu trnh cp pht b nh s nh th no : a/ 212K->600K, 417K->500K,112K->300K,426K->200K b/212K->600K, 417K->500K,112K->200K,426K->300K c/212K->300K, 417K->500K,112K->200K,426K->300K d/ Khng cu no ng p n : c 16/ Xt khng gian a ch c 8 trang, mi trang c kch thc 1K nh x vo b nh c 32 khung trang, Hi phi dng bao nhiu bt th hin a ch logic ca khng gian a ch ny a/ 32bit b/ 8 bit c/ 24bit d/ 13bit

p n :d 17/ Xt khng gian a ch c 8 trang, mi trang c kch thc 1K nh x vo b nh c 32 khung trang, Hi phi dng bao nhiu bt th hin a ch vt l ca khng gian a ch ny a/ 32bit b/ 8 bit c/ 15bit(215bit) d/ 13bit p n :c 17/ iu kin mt phn on c th thuc khng gian a ch ca 2 tin trnh: a/ Khng th c b/ Cc phn t trong bng phn on ca hai tin trnh ny cng ch n mt v tr vt l nht c/ Khng cu no ng p n : b Chng 7 : B nh o (12 cu) 1/ Thut ton thay th trang m chn trang lu c s dng nht trong tng lai thuc loi : a/ FIFO b/ LRU c/ Ti u d/ NRU p n : c 2/ Trong thut ton thay th trang c hi th hai nng cao trang c chn l trang : a/ Trang u tin c tm thy trong lp c u tin thp nht v khc rng. b/ Trang u tin c tm thy trong lp c u tin cao nht v khc rng . c/ Trang cui cng c tm thy trong lp c u tin thp nht v khc rng d/ Trang cui cng c tm thy trong lp c u tin cao nht v khc rng p n : a 3/ Thut ton thay th trang dng thi im cui cng trang c truy xut l thut ton : a/ FIFO b/ LRU c/ Ti u d/ NRU p n : b 4/ Thut ton thay th trang dng thi im trang s c s dng l thut ton : a/ FIFO b/ LRU c/ Ti u d/ NRU p n : c 5/Bit Dirty trong cu trc ca 1 phn t bng trang c ngha : a/ Cho bit trang no c truy xut n v trang no khng b/ Cho bit trang c tn ti trong b nh hay khng. c/ Cho bit trang b thay i hay cha cp nht trang trn a. p n : c 6/ Gi p l xc sut xy ra 1 li trang (0 s vector bit l 218 bit = 215 byte =32K=8 khi 8/ Vi mt a 20M kch thc mt khi l 1K, nu qun l khi trng dng DSLK cn bao nhiu khi qun l a ny bao nhiu: a/ 20 khi b/ 40 khi c/ 80 khi d/16 khi p n :b HD: 4K=212 byte 20M = 20*210 = 215 khi => cn dng 2 byte lu mt s hiu khi 1 khi =1024 byte lu c 512 s hiu khi Cn 20*210 /512 ~ 40 khi qun l a ny 9/ Trong h thng tp tin ca MS-DOS sector u tin, track 0, side 0 i vi a cng thng tin v : a/ Boot sector b/ Bng partition b/ Bng FAT c/ D liu thng p n : b 9/ Trong bng FAT ca h thng tp tin MS-DOS ngi ta m t loi a bng cch : a/ Dng 2 entry u tin ca bng FAT b/ Dng 1 entry u tin ca bng FAT c/ Dng entry ca bng th mc RDET d/ Khng cu no ng p n :a 10/ i vi h thng m mt tp tin, MS-DOS tm cc thng tin v tp tin : a/ Bng FAT b/ Bng th mc c/ Boot sector d/ Tt c u sai p n :b 11/ i vi tp tin ca WINDOW NTFS Partition, vi partition c kch thc t 8->16 Gb th s sector trn mt cluster l : a/ 8 Sector b/ 16 Sector c/ 32 Sector d/ 64 Sector p n : c

12/ Trong cu trc partition ca WINDOW NTFS thng tin v tp tin v th mc trn partition ny c lu trong: a/ Partition bootsector b/ Master File Table (MFT) c/ Cc tp tin h thng d/ Vng cc tp tin p n : b 13/ To, hu, m ,ng, c, ghi l cc tc v cn thit h iu hnh: a/ Qun l tp tin b/ Qun l b nh c/ Qun l tin trnh d/ Qun l mng e/ Khng cu no ng p n :a Chng 9 : Qun l nhp xut (12 cu) 1/ Thit b no sau y khng l thit b nhp/xut tun t : a/ Mn hnh b/ Bn phm c/ Chut d/ Card mng e/ a p n :e 2/ Vn chuyn DMA c thc hin bi : a/ B iu khin thit b b/ CPU c/ B nh trong d/ Cu a,b l sai p n : a 3/ V d trong ngn ng lp trnh C cu lnh
Count = Write(fd,buffer,nbytes);
thuc phn mm xut nhp no sau y: a/ iu khin thit b b/ Phn mm nhp xut phm vi ngi s dng c/ Phn mm nhp xut c lp vi thit b c/ Cu b,c l ng p n : b 4/ Trong h thng I/O a thi gian u c n ng khi cn thit trn mt track gi l : a/ Seek time b/ Tranfer time c/ Latency time d/ Khng cu no ng p n : c 5/ Trong h thng I/O a thi gian u c n ng track cn thit trn mt a gi l : a/ Seek time b/ Tranfer time c/ Latency time d/ Khng cu no ng p n : a

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6/ Khi h thng phi truy xut d liu khi lng ln th thut ton lp lch no sau y l hiu qu: a/ FCFS b/ SSTF c/ SCAN d/ C-SCAN e/ Cu a,b l ng f/ Cu c,d l ng p n : f 7/ Khi h thng phi truy xut d liu c s khi lin tc th thut ton lp lch no sau y l hiu qu nht: a/ FCFS b/ SSTF c/ SCAN d/ C-SCAN e/ Cu a,b l ng f/ Cu c,d l ng p n : a 8/ V d cn c cc khi sau 98,183,37,122,14,122,65,67 u c ti v tr 53, dng thut ton lp lch SCAN th u c s ln lt qua cc khi c th t no sau y: a/ 53, 37, 14, 65, 67, 98, 122, 124, 183 b/ 53, 65, 67, 98, 122, 124, 183,37,14 c/ 53, 14, 37, 65, 67, 98, 122, 124, 183 d/ 53, 183, 124, 122, 98, 67, 65, 37, 14 e/ Cu a,b l ng f/ Cu c,d l ng p n : e 9/ V d cn c cc khi sau 98,183,37,122,14,122,65,67 u c ti v tr 53, dng thut ton lp lch C-SCAN th u c s ln lt qua cc khi c th t no sau y: a/ 53, 37, 14, 65, 67, 98, 122, 124, 183 b/ 53, 65, 67, 98, 122, 124, 183,14,37 c/ 53, 14, 37, 65, 67, 98, 122, 124, 183 d/ 53, 183, 124, 122, 98, 67, 65, 37, 14 e/ Cu a,b l ng f/ Cu c,d l ng p n : b 10/ V d cn c cc khi sau 98,183,37,122,14,122,65,67 u c ti v tr 53, dng thut ton lp lch FCFS th u c s ln lt qua cc khi c th t no sau y: a/ 53, 37, 14, 65, 67, 98, 122, 124, 183 b/ 53, 65, 67, 98, 122, 124, 183,37,14 c/ 53, 14, 37, 65, 67, 98, 122, 124, 183 d/ 53, 98, 183, 37, 122, 14, 124, 65, 67 e/ Cu a,b l ng f/ Cu c,d l ng p n : d 11/ V d cn c cc khi sau 98,183,37,122,14,122,65,67 u c ti v tr 53, dng thut ton lp lch SSTF th u c s ln lt qua cc khi c th t no sau y: a/ 53, 37, 14, 65, 67, 98, 122, 124, 183 b/ 53, 65, 67, 37, 14, 98,122, 124, 183 c/ 53, 14, 37, 65, 67, 98, 122, 124, 183 d/ 53, 183, 124, 122, 98, 67, 65, 37, 14 e/ Cu a,b l ng

f/ Cu c,d l ng p n : b 12/ Trn a cc sector c s hiu lin tip nhau lun nm k bn nhau a/ ng b/ Sai p n :b Cu 1 : Nhng thit b lp 1 no sau y c s dng m rng mng LAN : a. Hub b. Switch c. Repeater d. Bridge Cu 2 : Byte u tin ca mt a ch IP c dng: 11000001. Vy n thuc lp no: a. Lp D b. Lp E c. Lp C d. Lp A Cu 3 : Byte u tin ca mt a ch IP c dng: 11100001. Vy n thuc lp no: a. Lp B b. Lp C c. Lp D d. Lp E Cu 4 : Giao thc no thc hin truyn cc thng bo iu khin gia cc gateway hoc trm ca lin mng: a. ARP (c ch chuyn a ch TCP/IP thnh a ch vt l) b. ICMP(nghi thc thong bo li) c. RARP (Giao thc phn tich ia chi ao) d. TCP Cu 5 : Lnh ping s dng cc gi tin no sau y : a. echo b. TTL c. SYN d. FIN Cu 6 : Lp no thc hin vic chn ng v chuyn tip thng tin; thc hin kim sot lung d liu v ct/hp d liu: a. Session b. Network c. Transport d. Data link Cu 7 : Phng thc no m trong c hai bn u c th ng thi gi d liu i: a. Full duplex b. Simplex c. Half duplex d. Phng thc khc Cu 8 : a ch IP no sau y l hp l: a. 192.168.1.2 b. 255.255.255.255 c. 230.20.30.40 d. Tt c cc cu trn Cu 9 : a ch IP no sau y l a ch qung b cho mt mng bt k: a. 172.16.1.255 b. 255.255.255.255 c. 230.20.30.255 d. Tt c cc cu trn Cu 10: Trong s cc cp giao thc v cng dch v sau, cp no l sai :

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a. SMTP: TCP Port 25 b. FTP: UDP Port 22 c. HTTP: TCP Port 80 d. TFTP: TCP Port 69 e. DNS: UDP Port 53 Cu 11 : a ch 19.219.255.255 l a ch g? a. Broadcast lp B b. Broadcast lp A c. Host lp A d. Host lp B Cu 12 : Trong kin trc phn tng mng, tng no c lin kt vt l a. Tng 1 b. Tng n c. Tng i d. Tng i 1 Cu 13: Topo mng cc b no m tt c cc trm phn chia chung mt ng truyn chnh: a. Bus b. Star c. Ring d. Hybrid Cu 14: Dch v no cho php chuyn cc file t trm ny sang trm khc, bt k yu t a l hay h iu hnh s dng: a. FTP b. Telnet c. Email d. WWW Cu 15: Lp no cung cp phng tin truyn thng tin qua lin kt vt l m bo tin cy : a. Physical b. Data link c. Network d. Transport Cu 16: Lp B c php mn ti a bao nhiu bit cho subnet : a. 8 b. 6 c. 14 d. 2 Cu 17: Byte u tin ca mt a ch IP c dng : 00000001. Vy n thuc lp no: a. Lp A b. Lp C c. Lp B d. Lp D Cu 18: Lp no cung cp phng tin truyn thng tin qua lin kt vt l m bo tin cy : a. Physical b. Network c. Data link d. Transport Cu 19: Thit b mng trung tm dng kt ni cc my tnh trong mng hnh sao (STAR) a. Switch/Hub b. Router c. Repeater d. NIC Cu 20: Lnh no di y c dng xc nh ng truyn (trong h iu hnh Windows) a. nslookup b. Route c. ipconfig d. Tracert

Cu 21: Lp no cung cp cc phng tin ngi s dng c th truy nhp c vo mi trng OSI v cung cp cc dch v thng tin phn tn: a. Transport b. Presentation c. Session d. Application Cu 22: Tng hai trong m hnh OSI tch lung bit t Tng vt l chuyn ln thnh: a. Frame b. Segment c. Packet d. PSU Cu 23 : Cc trm hot ng trong mt mng va nh my phc v (server), va nh my khch ( client) c th tm thy trong mng no ? a. Client/Server b. Ethernet c. Peer to Peer d. LAN Cu 24 : kt ni trc tip hai my tnh vi nhau ta c th dng : a. Cp cho (Cross- Cable) b. Cp thng ( Straight Cable) c. Rollover Cable d. Khng c loi no Cu 25 : M hnh phn lp OSI c bao nhiu lp : a. 7 b. 4 c. 5 d. 2 Cu 26 : Cc n v d liu giao thc trong lp 2 ca m hnh OSI c gi l : a. PDU b. Packet c. CSU d. Frame Cu 27 : Mt mng con lp A mn 5 bit chia subnet th SM s l : a. 255.248.0.0 b. 255.255.255.1 c. 255.255.255.248 d. 255.255.255.128 Cu 28 : Mt mng con lp A mn 7 bit chia subnet th SM s l : a. 255.255.254.192 b. 255.254.0.0 c. 255.248.0.0 d. 255.255.255.254 Cu 29 : Mt mng con lp A cn cha ti thiu 255 host s dng SM no sau y : a. 255.255.254.0 b. 255.0.0.255 c. 255.255.255.240 d. 255.255.255.192 Cu 30 : Mt mng con lp A mn 1 bit chia subnet th SM s l : a. 255.255.128.0 b. 255.128.0.0 c. 255.255.255.240 d. 255.255.128.0 Cu 31 : Mt mng con lp B mn 5 bit chia subnet th SM s l : a. 255.255.248.0 b. 255.255.255.1 c. 255.255.255.248

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d. 255.255.255.128 Cu 32 : Mt mng con lp B mn 7 bit chia subnet th SM s l : a. 255.255.254.0 b. 255.255.254.192 c. 255.255.255.240 d. 255.255.255.254 Cu 33 : Mt mng lp B cn chia thnh 3 mng con s dng SM no sau y : a. 255.255.224.0 b. 255.0.0.255 c. 255.255.192.0 d. 255.255.255.224 Cu 34 : Mt mng lp B cn chia thnh 9 mng con s dng SM no sau y : a. 255.255.240.0 b. 255.0.0.255 c. 255.224.255.0 d. 255.255.255.224 Cu 35 : Mt mng lp B cn chia thnh 15 mng con s dng SM no sau y : a. 255.255.224.0 b. 255.0.0.255 c. 255.255.240.0 d. 255.255.255.224 Cu 36: Lp C c php mn ti a bao nhiu bit cho subnet : a. 8 b. 6 c. 4 d. 2 Cu 37 : Mt mng lp C cn chia thnh 5 mng con s dng SM no sau y : a. 255.255.224.0 b. 255.0.0.255 c. 255.224.255.0 d. 255.255.255.224 Cu 38 : Mt mng lp C cn chia thnh 3 mng con s dng SM no sau y : a. 255.255.224.0 b. 255.0.0.255 c. 255.255.255.192 d. 255.255.255.224 1. Pht biu no sau y v vic phn chia cc hot ng mng thnh nhiu tng l SAI: a) Gim phc tp. b) Chun ho cc giao din. c) n gin ho vic ging dy v hc tp. d) Cho php ngi dng la chn bt k phn tng (layer) no thch hp v ci t cho h thng mng ca mnh. 2. Nhng im li khi s dng m hnh theo cu trc phn tng (chn 2): a) Cho php chia nh vn phc tp thnh cc vn nh hn d gii quyt. b) Thay i trn mt tng khng nh hng n cc tng khc. c) Thay i trn mt tng nh hng n tt c cc tng cn li. d) Gii hn vic s dng bi mt nh cung cp. 3. nh ngha qu trnh ng gi d liu: a) L qu trnh chuyn d liu sang mt nh dng thch hp truyn trn mng. b) L qu trnh d liu di chuyn t tng Application xung tng Physical. c) L qu trnh b sung vo PDU nhn c t tng trn mt header v mt trailer to thnh PDU ca tng hin hnh, sau chuyn xung tng di. d) Tt c u ng. 4. D liu s truyn nh th no trong m hnh OSI.

a) Application , Network, Presentation, Session, Transport, Data Link, Physical. b) Application , Presentation, Session, Network , Transport, Data Link, Physical. c) Application , Presentation, Session, Transport, Network , Data Link, Physical. d) Application , Session, Presentation, Transport, Network , Data Link, Physical. 5. Trnh t dng d liu khi truyn t my ny sang my khc l: a) Data, segment, frame, packet, bit b) Data, packet, segment, frame, bit c) Data, frame, packet, segment, bit d) Data, segment, packet, frame, bit 6. Tng no chu trch nhim tch hp d liu cc tng trn to thnh mt gi tin gi l segment: a) Transport b) Network c) Data Link d) Physical 7. Cp nao thp nht thc hin vic kim soat sai y u: a) Cp Physical. b) Cp MAC. c) Cp Datalink. d) Cp Network. 8. Tng no ca m hnh OSI chu trch nhim m ha d liu theo dng m thanh, hnh nh, vn bn a) Application. b) Session c) Network d) Presentation. 9. Tng no trong m hnh OSI lm vic vi cc tn hiu in: a) Data Link. b) Network. c) Physical. d) Session. 10. n v d liu ca tng Physical l: a) Frame. b) Packet. c) Segment. d) Bit. 11. Cho bit c im ca a ch tng Data Link: (chn 2) a) Cn gi l a ch MAC. b) Cn gi l a ch mng. c) Cn gi l a ch vt l. d) Cn gi l a ch loopback. 12. Chc nng chnh ca tng Network (chn 2): a) iu khin vic truyn tin tin cy b) nh tuyn ng truyn c) Thm a ch MAC vo gi tin d) Thm a ch mng vo gi tin 13. Tng Transport c th thng tin trc tip vi cc tng Network v Presentation : a. ng b. Sai 14. Tng Network c th thng tin trc tip vi cc tng Datalink va Transport : a) ng b) Sai 15. Nu cc chc nng ca tng Transport (chn 2) a) Nn d liu b) nh dng thng ip c) nh s cc packet

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d) Chia nh d liu t tng trn xung to thnh cc segment 16. Chc nng ca tng session: a) M ha d liu b) iu khin cc phin lm vic c) Thm a ch mng vo d liu d) Tt c u sai 17. Nu cc chc nng ca tng Presentation (Chn 2) a) M ho d liu b) Gii m d liu c) Phn on d liu d) nh a chi logic mang 18. Pht biu no sau y m t ng nht cho tng Application a) M ho d liu. b) Cung cp nhng dch v mng cho nhng ng dng ca ngi dng. c) S dng a ch vt l cung cp cho vic truyn d liu v thng bo li , kin trc mng v iu khin vic truyn. d) Cung cp nhng tn hiu in v nhng tnh nng cho vic lin kt v duy tr lin kt gia nhng h thng. 19. Cp Network trong OSI va cp IP trong Internet tng ng nhau vi: a) Cung cung cp dich vu gi nhn thng tin gia hai may bt ky. b) Cung cung cp dich vu gi nhn thng tin tin cy. c) Co th hiu va giao tip vi nhau. d) Ca ba cu trn u ung. 20. Card mng c coi nh l thit b tng no trong m hnh OSI: a. Physical b. Data Link c. Network d. Transport IA CHI IP: 21. ia chi IP la: a) ia chi logic cua mt may tinh. b) Mt s nguyn 32 bit. c) Mt record cha hai field chinh: ia chi network va ia chi host trong network. d) Ca ba cu trn u ung. 22. ia chi IP la: a) ia chi cua tng chng trinh. b) ia chi cua tng may. c) ia chi cua ngi s dung t ra. d) Ca ba cu trn u ung. 23. ia chi IP c biu din tng trng bng: a) Mt gia tri nhi phn 32 bit. b) Mt gia tri thp phn co chm. c) Mt gia tri thp luc phn co chm. d) Ca ba cu trn u ung. 24. Vic phn lp ia chi IP do nguyn nhn sau: a) Kich thc cac mang khac nhau. b) Phu thuc vao khu vc kt ni. c) D quan ly cac thng tin. d) Ca ba cu trn u ung. 25. a ch IP gm bao nhiu byte: a) 4 byte b) 5 byte c) 6 byte

d) Tt c u sai 26. Gi s my A c a ch 172.29.14.1/24 v my B c a ch 172.29.14.100/24. Ti my A, kim tra xem c th gi d liu n my B c hay khng, ta dng lnh no: a) Ping 172.29.14.1. b) Ping 172.29.14.100. c) Ipconfig 172.29.14.100. d) Tt c u sai. 27. Dng nh phn ca s 139 l: a) 00001010 b) 10001101 c) 10001011 d) 10001010 28. Dng nh phn ca s 101 l: a) 01100111 b) 01100101 c) 11100100 d) 01100011 29. Dng thp phn ca s 10101001 l: a) 163 b) 167 c) 169 d) 168 30. Dng thp phn ca s 01010110 l: a) 83 b) 84 c) 85 d) 86 31. Gi tr 170 biu din di c s 2 l a) 1101000101 b) 1010101010 c) 1001101110 d) 1000100010 32. Biu din s 125 t c s decimal sang c s binary. a) 01111101. b) 01101111. c) 01011111. d) 01111110. 33. a ch IP no hp l: a) 172.29.2.0 b) 172.29.0.2 c) 192.168.134.255 d) 127.10.1.1 34. a ch no sau y thuc lp B: (chn cc p n ng) a) 10011001.01111000.01101101.11111000 b) 01011001.11001010.11100001.01100111 c) 10111001.11001000.00110111.01001100 d) 11011001.01001010.01101001.00110011 35. a ch no sau y l a ch broadcast ca mng lp B l : a) 149.255.255.255 b) 149.6.255.255.255 c) 149.6.7.255 d) Tt c u sai 36. Trong cc a ch sau s c mt a ch khng cng nm chung mng con vi bn a ch cn li khi s dng subnet mask l 255.255.224.0: a) 172.16.67.50

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b) 172.16.66.24 c) 172.16.64.42 d) 172.16.63.31 37. Trong cc a ch sau, a ch no khng nm cng mng vi cc a ch cn li: a) 172.29.100.10/255.255.240.0 b) 172.29.110.50/255.255.240.0 c) 172.29.97.20/255.255.240.0 d) 172.29.95.34/255.255.240.0 38. Trong cc a ch sau, a ch no khng nm cng mng vi cc a ch cn li: a) 200.29.110.54/255.255.255.248 b) 200.29.110.50/255.255.255.248 c) 200.29.110.52/255.255.255.248 d) 200.29.110.57/255.255.255.248 39. Cho ng mng 180.45.0.0/255.255.224.0 Tnh: a) S mng con hp l: b) a ch ng mng th 1: a ch broadcast: c) a ch ng mng th 4: a ch broadcast: d) S host hp l trong mi mng con 40. Cho a ch IP: 192.17.8.194/255.255.255.240 Tnh: a) a ch ng mng con cha a ch IP trn: b) a ch broadcast ca mng con trn: c) Vng a ch host hp l trong mng con trn: 41. Cho ng mng c a ch 172.17.100.0/255.255.252.0. Phng php chia mng con ny cho bao nhiu subnet v bao nhiu host trong mi mng con: a) 126 subnet, mi subnet c 510 host b) 64 subnet, mi subnet c 1022 host c) 62 subnet, mi subnet c 1022 host d) 128 subnet, mi subnet c 512 host 42. Gi s h thng mng ca bn phi chia thnh 15 mng con (subnet) v s dng mt a ch lp B. Mi mng con cha t nht 1500 host. Vy subnet mask no s c s dng: a) 255.248.0.0 b) 255.255.248.0 c) 255.255.224.0 d) 255.255.252.0 43. Gi s h thng mng ca bn phi chia thnh 8 mng con (subnet) v s dng mt a ch lp B. Mi mng con cha t nht 2500 host. Vy subnet mask no s c s dng: a) 255.248.0.0 b) 255.255.240.0 c) 255.255.224.0 d) 255.255.252.0 11. Cho bit c im ca a ch tng Data Link: (chn 2) a) Cn gi l a ch MAC. b) Cn gi l a ch mng. c) Cn gi l a ch vt l. d) Cn gi l a ch loopback. 14/ Thut ton no sau y l thut ton c th iu phi theo nguyn tc c quyn : a/ FIFO b/ Xoay vng c/ iu phi vi u tin d/ Theo cng vic ngn nht (Shortest job first) e/ Chin lc iu phi vi nhiu mc u tin f/ Cu a,c,d ng g/ Cu c,d,e ng

// ko bit chn cu no na? cu C phi ko? 16. Chc nng ca tng session: a) M ha d liu b) iu khin cc phin lm vic c) Thm a ch mng vo d liu d) Tt c u sai 19. Cp Network trong OSI va cp IP trong Internet tng ng nhau vi: a) Cung cung cp dich vu gi nhn thng tin gia hai may bt ky. b) Cung cung cp dich vu gi nhn thng tin tin cy. c) Co th hiu va giao tip vi nhau. d) Ca ba cu trn u ung 20. Card mng c coi nh l thit b tng no trong m hnh OSI: a. Physical b. Data Link c. Network d. Transport // phn vn ko bit a, b, c, d ??? 22. ia chi IP la: a) ia chi cua tng chng trinh. b) ia chi cua tng may. c) ia chi cua ngi s dung t ra. d) Ca ba cu trn u ung. 24. Vic phn lp ia chi IP do nguyn nhn sau: a) Kich thc cac mang khac nhau. b) Phu thuc vao khu vc kt ni. c) D quan ly cac thng tin. d) Ca ba cu trn u ung.

1. Thit b no hot ng tng Physical: a. Switch b. Card mng c. Hub v repeater d. Router 2. cp pht ng a ch IP, ta c th s dng dch v c giao thc no: a. Dng giao thc DHCP b. Dng giao thc FTP c. Dng giao thc DNS d. Dng giao thc HTTP 3. a ch IP 192.168.1.1: a. Thuc lp B b. Thuc lp C c. L a ch ring d. b v c ng 4. Tng no trong m hnh OSI lm vic vi cc tn hiu in:

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a. Data Link b. Network c. Physical d. Transport 5. Giao thc no thuc tng Application : a. IP b. HTTP c. NFS d. TCP 6. Cc thnh phn to nn mng l: a. My tnh, hub, switch b. Network adapter, cable c. Protocol d. Tt c u ng 7. Chc nng chnh ca router l: a. Kt ni network vi network b. Chia nh broadcast domain c. a v b u ng d. a v b u sai 8. Protocol l: a. L cc qui tc cho php cc my tnh c th giao tip c vi nhau b. Mt trong nhng thnh phn khng th thiu trong h thng mng c. a v b ng d. a v b sai 9. Protocol no c s dng cho mng Internet: a. TCP/IP b. Netbeui c. IPX/SPX d. Tt c 10. Cc chun JPEG, TIFF, ASCII, EBCDIC do tng no ca m hnh OSI nh ngha: a. Transport b. Network c. Application d. Presentation 11. Trong cc a ch sau, chn a ch khng nm cng ng mng vi cc a ch cn li: a. 203.29.100.100/255.255.255.240 b. 203.29.100.110/255.255.255.240 c. 203.29.103.113/255.255.255.240 d. 203.29.100.98/255.255.255.240 12. C bao nhiu vng ng (Collision Domain) trong mt mng dng 1 Repeater v 1 Hub : a. 1 b. 2 c. 3 d. 4 13. Thit b no sau y s dng ti trung tm ca mng hnh sao: a. Switch b. Brigde

c. Port d. Repeater 14. hn ch s ng ca cc gi tin trn mng ngi ta chia mng thnh cc mng nh hn v ni kt chng li bng cc thit b: a. Repeaters b. Hubs c. Switches d. Card mng (NIC) 15. Cc thit b mng no sau y c kh nng duy tr thng tin v hin trng kt ni ca ton b mt mng x nghip hoc khun vin bng cch trao i thng tin ni trn gia chng vi nhau: a. Bridge b. Router c. Repeater d. Connectors 16. Giao thc no trong cc giao thc sau dng trong m hnh mng LAN: a. TCP/IP b. IPX/SPX c. NETBEUI d. Tt c 17. Giao thc no trong cc giao thc sau dng trong m hnh mng WAN : a. TCP/IP b. NETBEUI c. DLC d. Tt c 18. Kin trc mt mng LAN c th l: a. RING b. BUS c. STAR d. C th phi hp c a, b v c 19. Pht biu no sau y m t ng nht cho tng Application a. M ho d liu b. Cung cp nhng dch v mng cho nhng ng dng ca ngi dng c. S dng a ch vt l cung cp cho vic truyn d liu v thng bo li , kin trc mng v iu khin vic truyn d. Cung cp nhng tn hiu in v nhng tnh nng cho vic lin kt v duy tr lin kt gia nhng h thng 20. iu g ng i vi mng ngang hng : a. Cung cp s an ton v mc kim sot cao hn mng da trn my phc v b. c khuyn co s dng cho mng c t 10 ngi dng tr xung c. i hi mt my phc v trung tm c cu hnh mnh d. Ngi dng phn b trong a bn rng 21. a ch no sau y l a ch broadcast ca mng lp B l a. 149.255.255.255 b. 149.6.255.255 c. 149.6.7.255 d. Tt c u sai 22. Gi tr ca 11101101 c s 2 trong c s 16 l

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a. CB b. ED c. CF d. EC 23. M t no sau y l cho mng hnh sao (star) a. Truyn d liu qua cp ng trc b. Mi nt mng u kt ni trc tip vi tt c cc nt khc c. C mt nt trung tm v cc nt mng khc kt ni n d. Cc nt mng s dng chung mt ng cp 24. Loi cp no c s dng ph bin nht hin nay a. Cp ng trc b. Cp STP c. Cp UTP (CAT 5) d. Cp quang 25. Nhc im ca mng dng hnh sao l : a. Kh ci t v bo tr b. Kh khc phc khi li cp xy ra, v nh hng ti cc nt mng khc c. Cn qu nhiu cp kt ni ti nt mng trung tm d. Khng c kh nng thay i khi lp t 26. c im ca mng dng Bus : a. Tt c cc nt mng kt ni vo nt mng trung tm (V d nh Hub) b. Tt c cc ni kt ni trn cng mt ng truyn vt l. c. Tt c cc nt mng u kt ni trc tip vi nhau. d. Mi nt mng kt ni vi 2 nt mng cn li. 27. Khi ni mng gia 2 my tnh, chng ta s dng loi cp no ni trc tip gia chng. a. Cp quang b. Cp UTP thng c. Cp STP d. Cp UTP cho (crossover) 28. Si cp xon ni gia card mng vi hub th : a. Bm th t 2 u cp ging nhau b. i v tr cc si 1, 2 vi si 3, 6 c. Mt u bm theo chun TIA/EIA T-568A, u kia theo chun TIA/EIA T568-B d. Tt c u sai. Bi 1. Cho bit a ch broadcast ca subnet 131.18.7.0/255.255.255.0 - y l a ch lp B, nhng do subnet mask l 255.255.255.0 do vy dng 3 octet u lm a ch Net, octet cui lm a ch Host. Mt khc a ch Broadcast l a ch qung b, tc l ly a ch mng gp vi a ch Host bt ht l 1. Do vy ta c a ch Broadcast ca a ch cho l: 131.18.7.255

Bi 2. Cho a ch mng: 203.162.100.0 / 255.255.255.0. Chia a ch trn thnh 5 subnet hp l. Ghi ra 5 subnet v s host ti a ca mt subnet. - y l a ch lp C, nh vy 3 octet u l a ch mng, octet cui lm a ch Host. Mun chia subnet

cho a ch ny mn mt s bit ca octet 4 lm a ch mng. S bit mn l: n th s mng con c th l: 2m(n)-2 . Do yu cu l 5 mng con hp l, nn chn n=3 bit . - Lc a ch mng con c th vit hn hp l: 203.162.100|001 00000 203.162.100|010 00000 203.162.100|011 00000 203.162.100|100 00000 203.162.100|101 00000 Hay chnh xc l: 203.162.100.32 203.162.100.64 203.162.100.96 203.162.100.128 203.162.100.160 - S host ti a ca mt subnet l: 25-2=30 V d a ch mng con: 203.162.100.32 th s host nh trn mng ny l: 203.162.100.1 203.162.100.2 . 203.162.100.31

Bi 3. C cc a ch IP: 203.162.4.15/255.255.255.240 203.162.4.25/255.255.255.240 203.162.4.26/255.255.255.240 203.162.4.125/255.255.255.240 203.162.4.215/255.255.255.240 203.162.4.205/255.255.255.240 203.162.4.65/255.255.255.240

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203.162.4.85/255.255.255.240 Sp xp cc a ch theo tng Subnet

- Trc tin y l a ch lp C, c subnet mask l 255.255.255.240. Ni cch khc l mn 4 bit t octet cui lm a ch mng con. Do vy, a ch cc mng con vit hn hp l:

203.162.4|0001 0000 203.162.4|0010 0000 203.162.4|0011 0000 203.162.4|0100 0000 203.162.4|0101 0000 203.162.4|0110 0000 203.162.4|0111 0000 203.162.4|1000 0000 203.162.4|1001 0000 203.162.4|1010 0000 203.162.4|1011 0000 203.162.4|1100 0000 203.162.4|1101 0000 203.162.4|1110 0000

C th l: 203.162.4.16 cha 203.162.4.15/255.255.255.240

203.162.4.32 cha: 203.162.4.25/255.255.255.240 203.162.4.26/255.255.255.240

203.162.4.48 K cha host no

203.162.4.64 Khng cha host no trong danh sch

203.162.4.80, Cha 203.162.4.65/255.255.255.240 203.162.4.85/255.255.255.240

203.162.4.96

203.162.4.112 , Cha: 203.162.4.205/255.255.255.240 203.162.4.125/255.255.255.240 203.162.4.128 203.162.4.144 203.162.4.160 203.162.4.176 203.162.4.192, Cha 203.162.4.205/255.255.255.240

203.162.4.208, Cha 203.162.4.215/255.255.255.240

203.162.4.224

Bi 4: Cho a ch IP = 131.32.21.20/255.255.255.0 Hy tm: - Ch s mng con - Ch s my ch - a ch Broadcast Tr li: a) y l a ch lp B: 2 octet lm NetID, 2 Octet lm HostID. Mt khc SubnetMask l 255.255.255.0 do vy octet th ba l ch s mng con. Nh vy ch s mng con l 21. Hay ni cch khc a ch mng con l: 131.32.21.0

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b) Vi mng con 131.32.21.0 th Octet cui l a ch my ch. Do vy ch s 20 s l ch s ca my ch. c) a ch Broadcast l a ch ca NetID kt hp vi a ch HostID vi cc bit ca HostID bt thnh 1. Do vy a ch HostID l: 131.32.21.255

Bi 5: Cho a ch IP: 192.55.12.120/255.255.255.240 Hy tm: - Ch s mng con - Ch s my ch - a ch Broadcast Gii: a) a ch IP v SubnetMask c th biu din thnh nh sau: IP 1100 0000 0011 0111 0000 1100 0111 1000 SubnetMask 1111 1111 1111 1111 1111 1111 1111 0000

Do y l a ch lp C, do vy 3 Octet u lm NetID, Octet cui lm HostID. Cn c vo SubnetMask biu din trn ta thy mn 4 bit HostID lm a ch mng con. Nh vy a ch mng con s l: 1100 0000 0011 0111 0000 1100 0111 0000 Hay 192.55.12.112

b) Ch s my ch trong mng con ny s l: 0.0.0.8 a ch Broadcast s l: 1100 0000 0011 0111 0000 1100 0111 1111 Hay: 192.55.12.127

Bi 6: Cho a ch IP = 141.76.93.135/255.255.224.0 Hy tm: - Ch s mng con hay a ch mng con - Ch s my ch trn mng con - a ch Broadcast tng ng vi mng con Gii: a) Bin i a ch IP thnh nh phn ta c:

IP 1000 1101 0100 1100 0101 1101 1000 0111 SubnetMask 1111 1111 1111 1111 1110 0000 0000 0000 y l a ch lp B, dng 2 octet lm NetID, 2 octet lm HostID. Cn c vo biu din trn chng ta thy mn 3 bit octet3 lm a ch mng con. Hay ni cch khc a ch mng con s l: 1000 1101 0100 1100 0100 0000 0000 0000 Hay 174.76.64.0 b) a ch Host trn mng con s l: 0000 0000 0000 0000 0001 1101 1000 0111 Hay 0.0.29.135 c) a ch Broadcast l: (bt khu vc host thnh 1) 1000 1101 0100 1100 0101 1111 1111 1111 Hay: 174.76.95.255

Bi 7: SubnetMask ca 184.231.138.239 l bao nhiu nu 9 bit u ca a ch HostID c dng phn mng con. a/ 255.255.192.0 b/ 255.255.255.128 c/ 255.255.224.0 d/ 255.255.255.192 y l a ch lp B nn phng n (a),(c) l loi. Do mn 9 bit lm NestID do Octet cui s mn 1 bit. Do octet cui ca SubnetMask biu din dng nh phn l: 10000000 Hay 128 Vy p n b l p n ng.

Bi 8: My ch no trong cc my ch sau phi s dng Router lin lc vi my 191.24.144.12 bit SubnetMask ca my ny l 255.255.224.0 a) 191.24.153.35 b) 191.24.169.2 c) 191.24.201.3 d) 191.24.147.86

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Khi lin lc trn hai ng mng khc nhau th mi cn n Router hoc Switch. Do vy trong cc a ch trn th nhng a ch no khc ng mng vi a ch my ch cho s cn n Router khi lin lc.

- Biu din a ch Subnet Mask thnh a ch nh phn ta c: 1111 1111 1111 1111 1110 0000 0000 0000 Nh vy mn 3 bit t Octet 3 lm NetID. => S cc ng mng l: 0000 0000 0 0010 0000 32 0100 0000 64 0110 0000 96 1000 0000 128 1010 0000 160 1100 0000 192 1110 0000 224