el problemaalgoritmo

solucion:a= 0b= 1

b-a= 1

f(a)= 1f(b)= 2.71828183

area= 1.85914091

n= 5

a= 0b= 1

a1= 0.2a2= 0.4a3= 0.6a4= 0.8

f(a1)= 1.04081077f(a2)= 1.17351087f(a3)= 1.43332941f(a4)= 1.89648088

area= 1.48065457

solucion

xa 0b 1Xm 0.5Area 1.47573058

x F(x)a 0 1x(a-1) 0.1 1.0204053871x1 0.2 1.0408107742x(1-2) 0.3 1.1071608226x2 0.4 1.173510871x(2-3) 0.5 1.3034201428x3 0.6 1.4333294146x(3-4) 0.7 1.6649051469x4 0.8 1.8964808793x(4-b) 0.9 2.3073813539b 1 2.7182818285

area 1.57126396

algoritmo del trapecio modificado

algoritmo de simson 1/3

F(x)1

2.718281831.28402542

Hoja1