tugas
TRANSCRIPT
TUGAS MTK
SoalH2O = 3 liter/menit
3 Liter/menit H2O = 2 liter/menitTangki AV = 500 lNaOH = 50 kg
Tangki BV = 600 lNaOH= 90 kg
Q = 5 l/menita.) Θ = 1 jam CA = ? CB = ?b.) Θ = ? CA=CB
Penyelesaian Masalah
TAngki A a. Neraca Total
3 = 3 + dV dΘ
b. Neraca garam
ddCa AVC
30
d
dVC
d
dCaVCa A30
ddC
VCA A30
60
0 1,03
500
3
500
3
ACC
C A
A
A
A
A
A
C
dCdt
C
dC
C
VdCd
1,0ln
3
50060 AC
36,0)10ln( AC
697,010 AC
LkgCA /0697,0
?BCNeraca garam:
Input = output + akumulasi
)(00 22 dCV
dCvCvCv BBBBHHAA
)()(00 22 d
VdC
d
CdVCvCvCv B
BB
BBBHHAA
0*60050*20697,0*3 BB
B Cd
dCC
ddC
C BB 600521,0
CATATAN:
ddC
C BB 600)521,0(
B
CC
CB
dCC
dtB
60
0600
90 )521,0(
600
5)521,0(
B
B
dC
Cd
5
)521,0( BB
CddC
Maka, didapat:
5
)521,0(
)521,0(
60060
0600
90
B
CC
CB
Cd
Cdt
B
60
0600
90 )521,0(
)521,0(
5
600
BCC
CB
B
C
Cddt
BC
BC
600
90)521,0ln(
5
60060
60090
*521,0
521,0ln12060 BC
75,021,0
521,0ln5,0
BC
BC521,03294,0
5394,05 BC
LkgCB /107,0
b.) ? BA CC
tC
A
A dtC
dCA
0500
50 500
3
tC
A tCA
01,0 500
3ln
tCA
500
3
1,0ln
tCA 500
310ln
t
A eC 500
3
10
t
A eC 500
3
10
1
dt
dCVCC BBBA 53Tangki A
Tangki B
BA
B
CC
dCdt
53600
Cat. 5
53
BAB
CCddC
tC
BA
BA dtCC
CCdB
0600
90 600
5
53
53
tC
BA tCCB
015,0 600
553ln
t
AAB eCCC 600
5
4
3335
ttt
B eeeC 600
5
3000
43
500
3
20
3
50
3
50
3
BA CC
te 500
3
10
1 ttteee 600
5
3000
43
500
3
20
3
50
3
50
3
Dengan menggunakan metode Trial and Error, didapatkan hasil:
menitt 488,560
Soal
H20 7 liter / menit
7 liter / menit30 kg300 liter
C2=?
C1=0
ddCa AVC
70
d
dVC
d
dCaVC A 170
ddC
C A700170
60
0 1,0 1
1
1
1
7
300
7
700
7
700
CC
C
A
AA
C
dCdt
C
dC
C
dCd
1,0ln
7
30060 1C
4.1)10ln( 1 C
246,010 1 C
LkgC /0246,01
TAngki A a. Neraca Total
7 = 7 + dV dΘ
b. Neraca garam
0ddv
mntLt
V
mntLmntLmntLt
V
/4
/2/8/10
3.
10 liter / menit
2 liter / menit
8 liter / menit