unidad 12 - integración, problemas resueltos

Upload: fpsilva

Post on 02-Jun-2018

241 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    1/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    Pg.289 I a) as rectas concretas se cortan en ( )01 ! "or tanto la 1=x es ino"erante. #l rea triang$lar se limita "or las rectas% 0=y 33 = xy xx =

    Base & 1x 'lt$ra & 33 x ( ) = xFrea ( ) ( )3312

    1 xx

    ( ) ( )2123 = xxF ( ) ( ) = 11223

    ' xxF ( ) ( )13' = xxF

    () 30 x a recta xy= "asa "or origen ( )00 #l rea triang$lar est limitada "or% 0=y xy= xx =

    Base & 0x 'lt$ra & x ( ) xxxFrea =2

    1

    ( ) 22

    1xxF = ( ) = xxF 2

    2

    1' ( ) xxF ='

    63

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    2/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ( ) 2344

    1xxxxf += ( ) 23

    2

    1

    3

    1xxxg = [ ]( ) 234

    2

    3

    3

    4

    4

    1xxxxgf +=

    ,rea & [ ]( ) [ ]( ) [ ]( ) [ ]( )=+ 1301 fgfggfgf

    [ ]( ) [ ]( ) [ ]( )== 3012 gfgfgf =

    12

    270

    12

    52 =

    12

    52

    6

    27

    Pg.29 8 ( )x

    yxf 1' = ( ) xyxg =' ( ) 2' =xxh +orte 'f :'g =x

    x

    1 1=x

    ,rea & ring$lo ra"ecio c$r3il4neo! am(os so(re e5e hori6ontal

    ring$lo ( )=== 10 xyxy ,rea & = 112

    1

    2

    1

    ra"ecio

    ==== 02

    11 yx

    xyx ( ) = 2

    1

    xxg ,rea & ( ) ( )= 12 gg

    4

    3

    ,rea glo(al & =+4

    3

    2

    1

    4

    5

    Pg.297 9 a) ( ) =+ dxxx 132 24 Cxxx ++ 35

    52

    () ( ) =+ dxxxx 2123 =+++ ++ 121124

    121

    1

    12

    1

    4

    1xxx Cx

    xx +++ 34

    3

    21

    4

    1

    c) =

    + dxx

    xx 223 =+

    +

    +++

    xxx

    12

    11

    1

    123

    1 11123 CLxxx

    ++ 22

    12 2

    d) ==+= + 61316767

    13

    6

    167

    1xxdxx Cx +6 13

    13

    6

    Pg.297 10 a) = dxe x3 xe3 () =

    dxx

    x 43 CLx

    Lx + 43

    3

    1

    c) =

    dx

    xsenx

    21

    15 Cxx ++ arccoscos5

    d) ( = dxxx cos3 ( ) =++= + Csenxxdxxx 1323/2

    132

    1cos Csenxx +3 4

    4

    3

    Pg.29 11 a) ( ) ( ) =+++ dxttt 21

    22.32 212

    Ctt +++ 322

    () =+

    xx

    e

    e2

    2

    1

    2

    2

    1( ) CeL x ++ 21

    2

    1

    c) ( ) =+ dxxx 2125 202

    ( ) =+++ +

    Cx 1202

    1120

    1

    2

    5

    ( ) Cx ++ 212

    142

    5

    d) ( ) = dttLt 1

    cos ( ) CLtsen +

    e) ( ) =

    + dse

    e

    s

    s 21

    1( ) Cearctg s +

    ) ( ) =

    dxx

    x2

    1

    1

    22 ( ) Cxarcsen +2

    Pg.29 12 a) ( ) ( ) = dxxsenxx 2cos 242 ( ) =+

    +

    +Cx

    142cos

    14

    1Cx + 25cos

    5

    1

    2/10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    3/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ()( )

    ( ) =++

    dxx

    xsen

    23cos

    23

    ( ) ( )( ) =++ dxxsenx 32323cos

    1

    3

    1( ) CxL ++ 23cos

    3

    1

    Pg.29 13 ( )=xf ' =x

    tgx2

    cos

    12

    x

    senx3

    cos

    2( )

    ( )=

    =

    x

    senxzxg

    4

    '

    cos

    cos2

    x

    senx3

    cos

    2

    as deri3adas son id:nticas. as "rimiti3as se dierencian en $na constante.

    #n eecto% ( ) ( ) ==== xx

    x

    xsen

    x

    xsen

    xxfxg 2

    2

    2

    2

    2

    2

    2cos

    cos

    cos

    1

    coscos

    11

    Pg.;2 14 ( ) xf 42 += xy +orte *% =0y 2=x +orte & = 422

    14

    20

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    4/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    c) +orte% ( ) xf 12 ++= xxy ( ) xg 2=y 51=x 51+=x

    ( ) ( ) =++==+

    dxxxdxgfrea 3251

    51

    =

    ++

    +

    51

    51

    233

    2

    1

    3

    1xxx 5

    3

    14

    d) +orte% ( ) xf xy = ( ) xg xy 1= 1=x

    =

    +===

    +

    1

    0

    12121

    1

    0

    1121

    1

    xdxxdxxS =

    1

    0

    3

    3

    2x 3

    2

    [ ] ==== 121 2

    1

    2

    1

    2 LLLxdxx

    S 2L =+= 21 SSrea 23

    2L+ 36,1

    e) +orte *% 0=y ( ) xf senxy= 0=x =x 2=x

    ( ) xg ( )= xxy 0=x =x

    [ ] ( ) ( ) =+==

    0

    2

    0

    0 dxxxsenxdxgfS =

    +

    0

    23

    23

    1cos xxx

    62

    3

    +

    [ ] ( ) ( ) ===

    2 222 dxsenxxxdxfgS =

    +

    223 cos23

    1 xxx 36

    72 +

    [ ] [ ] =+=

    2

    0 SSrea 34 +

    f) Con un oscurantismo impropio de texto docente, no seespecifica una de las cuatro posibles soluciones:

    Verde ABC, Marrn BCD, Rosa CDE, o bien la suma de estas tres.

    as l4neas re"resentadas son%

    @ecta A ( ) xf 3+= xy

    @ecta A ( ) xg xy 3= Par(ola A ( ) xh 122 = xxy

    os "$ntos de interseccin otros son%

    A & ( )

    +

    + 51

    2

    3

    2

    51( )85,461,1

    B& ( )21 C& ( )4943 ( )25,275,0

    D& ( )

    +

    +51

    2

    3

    2

    51( )85,162,0

    E& ( )74 M ( )03 ? ( )30 P 021

    ( )041,0 ( )021 + ( )041,2 @ ( )10

    ( ) = dxxfF xx 32

    1 2 + ( ) = dxxgG 2

    2

    3x ( ) = dxxhH xxx 23

    3

    1

    ,rea ABC& ( ) ( ) =+ C

    B

    B

    A

    dxFGdxHG24

    11510 4734,0

    ,rea BCD& ( ) ( ) =+ D

    C

    C

    BdxHGdxHF

    19259049 + 3034,1

    0/10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    5/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ,rea CDE& ( ) ( ) =+ E

    D

    D

    C

    dxHFdxGF12

    511213 7003,15

    ,rea s$ma CABDEC&64

    521123 4770,17

    Pg.;2 20 ( ) =+ dxxy 1 Cxx ++2

    2

    1 Bisectri6% =xy 22 == yx

    ( ) ( ) C++= 222

    12

    2

    2=C 2

    1

    2

    1 2 += xxy

    Pg.;2 21 a) ( ) 2xxf = ( ) xexg = ( ) =dx Cex x +2

    () ( ) Lxxf = ( ) senxxg = ( ) =dx CLxsenx +

    c) ( ) xexf = ( ) senxxg = ( ) =dx Csenxex + d) ( ) xexf = ( ) xxg cos= ( ) =dx Cxex + cos e) ( ) xxf = ( ) Lxxg = ( ) =dx CLxx + ) ( ) xxf = ( ) Lxxg = ( ) =dx CLxx +

    Pg.;2 22 ( ) 2321' 2 xxxf += y ( ) = dxxf ' Cxx ++ 25235

    4

    3

    2

    rigen% ( ) 00 ++= C000 0=C 535

    4

    3

    2xxy +=

    Pg.;2 23 ( ) ( )xfxx

    x

    x

    xxg +=

    ++

    ++

    ++

    112

    1

    12

    12

    12

    22 ( ) ( )xfxg '' 0 += ( ) ( )xfxg '' =

    Pg.; 24 a) =+ dxdxx 21

    CxLx ++2

    () == dxxsenxdxxsenx coscos ( ) CxL + cos

    c) ( ) ( ) == dxxdxx 35331

    53 22 ( ) =+ Cx 353

    3

    1

    3

    1( ) Cx + 353

    9

    1

    d) == +

    dxxdxx 417

    4

    53 =+

    +

    +Cx

    14

    17

    1417

    1=+ Cx 421

    21

    4Cx + 4 21

    21

    4

    e) ( ) ( ) =

    +=

    + 2222 1

    2

    2

    1

    1 x

    xdx

    x

    x( ) Cxarctg + 2

    2

    1

    ) ( ) =+= Cxdxxsen 2cos21

    222

    1Cx+ 2cos

    2

    1

    g) = dxex x2

    22

    1Cex +

    2

    2

    1

    h) = dxxxtg 23

    cos

    14

    4

    1Cxtg + 4

    4

    1

    i)

    Pg.; 25 =egCn la re"resentacin% +ada cuadroson 2 unidadesc$adradas =e c$entan $nos 15cuadros! 12 com"letos ms "or agr$"acin 1 "arcial = 25,15 ( )adradasUnidadesC31 ( ) = 3126c 5 ( ) == 3138d 7+ a res"$esta con menorse"aracin Derror a(sol$to) es c)D"or deecto)

    7/10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    6/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    Pg.; 26 ( ) ( ) ( )177

    1

    ' ffdxxf = ( ) 273 = f ( ) =+= 237f 5

    Pg.; 27 a) =

    +=

    +

    3

    1

    12

    13

    1

    2

    1

    2121

    3

    2

    23 xxdx

    xx [ ] = 313 22 xx 34

    () [ ] [ ]=== 1232

    0

    3

    2

    0

    3 eeeedee 35 ee

    c) =

    =

    3

    6

    3

    6

    2 cos

    1

    cos

    t

    dtt

    sent=

    3

    22 =

    3

    232

    3

    326

    d) ( ) =+ dxxx204

    0

    212

    2

    1 ( )[ ] =++

    4

    0

    2121

    120

    1

    2

    1x ( )117

    42

    1 21

    Pg.; 28 ( ) ===

    0

    0

    2

    cos33 xdxsenxdxsenx ( )[ ] ==+ 23113 6

    Pg.; 29 a) Verdadera% = !arf a"YEjeSi#etr$ ( ) ( ) =

    a

    a

    dxxfdxxf0

    0

    ( ) =

    a

    a

    dxxf ( ) ( ) =+

    a

    a

    dxxfdxxf0

    0

    ( )a

    dxxf0

    2

    () Verdadera% =continaf ' "or BarroE ( ) =7

    0

    ' dxxf ( ) ( )07 ff

    c) a!sa% a integral deinida es $n nCmero! 5ams de"ende de la 3aria(le.

    d) Verdadera% ( ) ++

    1

    1

    2

    dxcbxax ( ) ( ) ++1

    1

    1

    1

    2

    dxbxdxcax

    =+ Fnci%n&A'cax2 ( ) ( )

    +=+1

    1

    1

    0

    222 dxcaxdxcax

    = A'Fnci%n()&bx ( ) 01

    1

    =

    dxbx

    e) a!sa% a $ncin ( )xf cam(ia de signo en inter3alo ( )30

    ) a!sa% a integral deinida es"eciicada es correcta Pero no mide :l rea al$dida! a F$e ( )xf cam(ia de signo en ( )30

    al rea es% ( )[ ] ( ) =+ 3

    1

    2

    1

    0

    2110 dxxdxx =

    +

    3

    1

    31

    0

    3

    33x

    xxx

    3

    22

    Pg.; 30 a) ( ) xsenxf 3= es im"ar! centro ( ) += 20 x Integral & ; () ( ) senxxf = es im"ar! centro ( ) = 202 x Integral & ; c) ( ) senxxf = es im"ar! centro ( ) = 23 x Integral & ; d) ( ) senxxxf 2= es im"ar! centro ( ) += 2x Integral & ;

    e) ( ) xxf 2

    cos= es siem"re "ositi3aIn"e#ra! $%rea !imi"ada) 0 ) ( ) tgxxf = es im"ar! centro ( ) = 2110x Integral & ;

    Pg.; 31 1) +ortes ( ) :2310 2xyxyxyx ==+== 0=x 1=x 71+=x

    G/10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    7/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ( ) ( )+

    =

    +

    +

    71

    1

    21

    0

    2

    23

    21 dx

    xxdx

    xx =

    +

    +

    + 71

    1

    321

    0

    32

    623

    62

    xxx

    xx

    x

    ( ) ( ) ( ) =

    +

    +++

    +=

    6

    1

    2

    13

    6

    71

    2

    717130

    6

    11

    2

    132

    =

    ++

    +++

    =

    6

    1318

    6

    777373174733

    6

    163

    3

    1377

    2) +ortes ( ):310 xyxyx =+== 0=x 1=x

    ( ) ( )[ ] =+1

    0

    13 dxxx ( ) =1

    0

    12 dxx =

    1

    0

    2

    22 xx 1

    ) +ortes ( ) :213 2xyxyxy =+== 1=x 71+=x 31+=x

    ( ) ( )[ ] ( )[ ]+

    +

    +

    =+++31

    71

    2

    71

    1

    2331 dxxxdxxx

    =

    ++

    +

    +

    + 31

    71

    3271

    0

    2

    63

    222

    xx

    xx

    x

    ( ) ( )

    ( ) ( ) ( ) ( ) ( ) ( ) =

    +++

    +

    +++

    +

    +

    ++=

    6

    71713

    2

    71

    6

    31313

    2

    31

    712

    712

    3232

    2

    =++++++++++=3

    751173374

    3

    33533332722728

    =3

    773317 +

    0) +ortes ( ) :023 2 === yxyxy 0=x 71+=x 3=x

    ( ) =+

    +

    + 3

    71

    71

    0

    2

    0302

    dxxdxx

    =

    +

    +

    + 3

    71

    271

    0

    3

    23

    6

    xx

    x

    ( ) ( ) ( ) =+++++=2

    71713

    2

    99

    6

    7123

    6

    71447

    7) +ortes ( ) :021 2 ==+= xxyxy 1=x 31=x 0=x

    =

    +=

    +

    31

    1

    3231

    1

    2

    6221

    xx

    xdx

    xx

    ( ) ( ) ( ) ( ) ( ) =

    +

    +

    =

    6

    11

    2

    1

    6

    3131

    2

    31 3232

    3

    433

    G) +ortes ( ) :0122 =+== yxyxy 1=x 31=x 0=x

    ( ) =++

    0

    31

    231

    1 2

    1 dxx

    dxx =

    +

    +

    0

    31

    331

    1

    2

    62

    xx

    x

    ( ) ( ) ( ) ( ) =

    +

    +

    = 1

    2

    131

    2

    31 22

    6

    3611

    Pg.;0 32 a $ncin "rimiti3a (F) crece c$ando s$ deri3ada (f) es "ositi3a #n "artic$lar! la $ncin (f) es "ositi3a en ( )0 a $ncin creciente en ( )0 es !a &unci'n C

    /10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    8/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    Pg.;0 33 #ntre las tres c$r3as! la corres(ondenciaes algo H#rosera. ?o o(stante% Parece III& crece / decrece! c$ando II& "ositi3a / negati3a A (((F ((f a restante de(e ser (f '

    Pg.;0 34 a) areceF$e la grica (asa"or el "$nto ( )05 . $ego 14 == yx

    > D0)% a integral es el rea entre 1=y 0=y 0=x 4=x #s decir! rectng$lo con Base & 0 'lt$ra &1 A =14 4

    Je otro modo% ( ) [ ] ==== 041 404

    0

    4

    0

    xdtdttf 4

    > D)% a grica incor"ora $n tramo de = )5(10 xy xy = 5

    #l rea est entre 1=y 0=y 1=y xy = 5 0=x 7=x #sta com"$ta $na "ositi3a Dso(re 0=y ) otra negati3a D(a5o 0=y ) Por tanto% rea com"$tada & ( ) ( )=++ 121214 3

    (ien% ( ) ( ) ( ) =

    ++

    6

    4

    7

    6

    4

    0151 dxdxxdx [ ] [ ] =+

    + 7

    6

    6

    4

    24

    0 25 x

    x

    xx

    ( ) ( ) ( ) =+=+++= 10467121204 3

    () a re"resentacin grica "edida! e3identemente! coincidecon la dada. ?o "arece necesaria eK"licacin alg$na.

    Pg.;0 35 ( ) ( )[ ] ( ) [ ] ( )=++=+=+=+= 1377.11 313

    1

    3

    1

    3

    1

    3

    1

    ddfdfdg 11

    Pg.;0 36 a) ( ) ( ) ( ) =+=+= 714

    2

    2

    0

    4

    0

    dxxfdxxfdxxf 8

    ( ) ( ) ( ) === 211

    0

    2

    0

    2

    1

    dxxfdxxfdxxf 1

    ( ) ( ) ( ) === 271

    0

    4

    0

    4

    1

    dxxfdxxfdxxf 5

    () ( ) 21

    0

    = dxxf 0> ( ) 12

    1

    = dxxf 0< #n ( )20 ha x F$e hace ( ) 0=xf

    c) =i ( ) 5,3xf ( ) ( )

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    9/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    Pg.;0 39 ( ) ( ) ( )22 11 xxfx +++ ( ) ( ) ( ) ++

    dxxdxxfdxx 21

    1

    1

    1

    211

    ( )1

    1

    31

    1

    1

    1

    3

    33

    +

    +

    xxdxxf

    xx ( )

    3

    8

    3

    8 1

    1

    dxxf

    ( ) 67,23

    81

    1 dxxf Lalores "osi(les & 2 1 5,2

    Pg.;0 40 a)dt

    d+anace,araci% = cidadr-fica.e,o&endienteGa=

    == 1201/ra#o 20 == 502/ra#o 0 == 4203/ra#o 5

    () = +dxees!acio Sobre"0a.e,ocidadreaGr-fice =

    =++=++= 40100102042

    1205201

    2

    1e 160

    Pg.;7 41 ( ) =

    =

    60

    0

    1,0

    60

    0

    1,0

    1,0

    1414 tt etdte [ ] [ ] [ ]== 0660

    0

    1,0100410604104 eet t

    [ ] [ ] +== 40992,02401040025,010604 244 ( )h#, 2/

    Pg.;7 42 anC"1S/A1/EAce,eraci% ( ) [ ] === ++atadtt+ 0 at+ +0

    ( ) ( ) ( ) =

    +=+==t

    att+dtat+dtt+tx0

    2

    002

    1 200

    2

    1att+x ++

    Pg.;7 43 [ ] [ ]10303 2 xx a

    = ( )3333 0120 =a 23 =a 3 2=a

    Pg.;7 44 '(scisas corte D 12 == yxy )% 1=x 1=x

    ,rea inca & ( ) =

    =

    1

    1

    31

    1

    2

    31

    xxdxx =

    +

    3

    11

    3

    11

    3

    4 @egin &

    3

    2

    '(scisas corte D ayxy == 2 )% ax = ax =

    ,rea regin & ( ) aax

    axdxxa

    a

    a

    a

    a 3

    4

    33

    2 3

    2 =

    ==

    3 2

    2

    1=a

    2

    23=a

    Pg.;7 45 ( ) 2xxxf ( ) =0xf 0=x 1=x

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    10/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ()( ) ( )

    =+

    =

    + 22

    21

    22

    2

    1

    21

    2

    x

    x

    x

    x L

    L ( ) CarctgL

    x +22

    1

    c) ( ) =+ dxxtgx 251

    cos

    13 ( ) =++

    ++

    Ctgx 15

    1

    3151

    1( ) Ctgx ++ 5 63

    6

    5

    d) = dxLLx 22

    2

    1C

    Lx + 2

    2

    1

    e) ( ) =++= + Cdxxdxsenxx 133 cos13

    1cos =+ Cx2cos21 C

    x+

    2cos2

    1

    )( ) =+ dxx 2211

    ( ) =

    + dxx 221

    2

    2

    1( ) Cxarctg +2

    2

    1

    Pg.;7 48 ( )( )( ) ( )

    ( )( )21

    12

    21

    1

    +

    = xx

    xBxA

    xx ( ) ( ) 112 + xBxA

    ( ) ( ) 12 ++ BAxBA Identidad inde"endiente del 3alor x 0=+BA 12 =+BA 1=A 1=B

    Pg.;7 49 ( )( ) = dxxx 123 = dxxx 11213 ( ) ( )[ ] =+ CxLxL 123

    Cx

    xL +

    1

    23

    Pg.;7 50 0>b #n [ ]b0 es xx 33 =

    =

    bb xdxx

    0

    2

    0 2

    33

    2

    3 2b

    Pg.;7 51 '(scisas de tramos 1=x 2=x 5=x 8=x 13=x

    ( ) ( ) ( ) ( ) ( ) =+++= 13

    8

    8

    5

    5

    2

    2

    1

    13

    1

    dxxfdxxfdxxfdxxfdxxf ( )=+Cadrantes/ri-ng,os

    =

    +

    +

    2

    35

    4

    3

    4

    3

    2

    31 22

    =2

    126

    ( ) ( )=+= /ri-ng,oCadrantedxxf13

    5

    =

    2

    35

    4

    32

    =

    +

    2

    15

    4

    9

    4

    309 +

    ( ) ( )== Cadrantesdxxf8

    2

    =

    4

    3

    4

    3 22

    0

    Pg.;7 52 +$alF$ier "ar(ola se "$ede reerir a s$ "ro"io e5e D3ertical) "asando "or D 00 ) Por tanto! toda "ar(ola "$ede eK"resarse "or la ec$acin 2axy = =ea $n segmento "ara(lico de alt$ra h

    os eKtremos de tal segmento son ahx = s$ longit$d es ah2

    ,rea segmento & ( ) =

    =

    ahahax

    hxdxaxh0

    3

    0

    2

    322 =

    a

    hh

    3

    22

    a

    hh 2

    3

    2

    Pg.;7 53 a) ( ) =+

    ++

    +

    +

    11

    1223

    2

    x

    CBx

    x

    Axf

    x

    x ( )

    1

    2

    +

    +++x

    x

    ACxxBA 2=+BA 0=C 1=A

    1=A 1=B 0=C ( ) =++

    1

    123

    2

    x

    xxf

    1

    12 +

    +x

    x

    x

    () +

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    11/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ( )( ) 23

    24

    ' 12

    xx

    xxxf

    +

    ++= < 0 ( )xf es decreciente

    ( ) 0= fx,$# 's4ntota hori6ontal% 0=y ( ) += + fx,$# 0 's4ntota 3ertical% 0=x a grica se "arece a la de la ig$ra

    c) ( ) =

    ++=

    ++

    ee

    xLLxdxx

    x

    x 1

    2

    112

    1

    1

    12 ( ) =++ 22

    1

    11 2

    LeL

    ++ 2

    1

    1

    2e

    L

    Pg.;7 54 a) ( )xf ( )xg =on in3ersas entre s4 =im:tricas res"ecto xy= se cortan en ( )00 ( )11

    =$ma integrales =$ma reas (a5o c$r3as Un rea la sim:trica de la otra dan +$adrado lado 1 1 () 'nlogamente! las $nciones Lxy= xey= son in3ersas

    =on sim:tricas res"ecto (isectri6 xy= no se cortan

    $ego! e

    dxLx1 ,rea entre 0=x 1=x 0=y 1=

    y @ectng$lo = e1e

    Pg.;8 A1 a) &x =

    21

    2

    x

    xy

    ( ) ( )( )

    =

    =

    22

    2'

    1

    2212

    x

    xxxy

    ( )222

    1

    22

    x

    x

    +

    ( ) = += 222

    '

    21222&& y#

    910 ( )2

    910

    34 =+ xy 32910 = yx

    () =0y = 320910x = 1032x = 516x ( )0516 c) 's4ntota "rKima 1=x = 329110 y = 922y ( )9221

    Pg.;8 A4 ( ) dcxbxaxxf +++ 23 ( ) cbxaxxf ++= 23 2' ( ) baxxf 26" += ( ) 31 dcba +++= 3

    ( ) =01"

    f 026 =+ ba

    11/10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    12/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ( )10 d=1 ( ) =00"f 0=c #l sistema acilita% 2=a 6=b 0=c 1=d

    Pg.;8 A5 a) ( )

    =

    20

    1

    20

    1

    '

    20

    11000 eet1 ( )

    =

    20

    11000 20' tet1

    t

    ( ) =0' t1 20=t

    ( ) =01 000.25 ( ) 357.3220 =1 ( ) 673.25100 =1.%-imo& 357.32 20=t ./nimo& 000.25 0=t

    ()

    ( )

    =

    20

    11000 20

    "

    t

    et1

    2

    2050 20

    te

    t

    ( ) =0' t1 40=t

    ( ) 000.10'

    =1 ( ) 13540'

    =1 ( ) 27100'

    =1=0t >0'1 crece1= == 100,40tt 0213"y )$ni#oy=

    Jimensiones "ara coste m4nimo% = 3 21x 7932,0 ( )d# = 3 4h 5874,1

    ( )d#

    Pg.;8 A7 a) Verdadera. #n [ ]31 la grica indica ( ) 0' >xf ( ) Crecientexf =() >alsa. a grica indica ( ) 00' >f ( )xf no tiene ah4 eKtremo relati3o c) Verdadera. ( ) = 10'f ( ) 1=ftg# xy# = tg a ( )xf "aralela a xy= d) >alsa. =egCn a) la ( ) crecexf = ! "ero "$ede! a la 3e6! ser negati3ae) >alsa. ( ) crcientexf = "$ede an$larse o no! en el inter3alo citado.

    Pg.;8 A8 = axaxy 22 +ortes con 0=y 0=x ax 2=

    12/10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    13/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    ,rea encerrada =

    a

    dxxa

    xa

    2

    0

    2

    32

    12=

    ax

    a

    x

    a

    2

    0

    3

    3

    2

    23

    1

    2

    2=

    a

    a

    x

    a

    x 2

    0

    3

    3

    2

    2

    3

    ( ) ( )==

    3

    3

    2

    2

    3

    22

    a

    a

    a

    a =3

    84

    3

    4 Inde(endien"ede a

    '(scisa 3:rtice "ar(ola% =x ( )=+ a202

    1 a =

    =

    a

    a

    x

    ay 2

    2 a

    1

    L:rtice% ax = a

    y 1

    = Dec$aciones "aram:tricas del l$gar geom:trico

    #c$acin cannica Deliminando el "armetro)% 1=yx #l l$gar geom:trico es $na i(ro!a eui!%"erade as4ntotas e5es coordenados

    Pg.;9 B1 a) a $ncin com"$esta "or H"arte entera de 3aria(le!am%s es con"inua =iem"re est constit$ida! como m$cho! "or Htramos! sino "or "$ntos () enteroax = ( ) ( ) [ ] ==+= aaaaafxf 0

    =on "$ntos aislados en *#n [ ]44 son -0! -! -2! -1! ;! l! 2! ! 0

    1oEnteroax = ( )1+ aax( ) ( ) ( ) =++=+ 1aaxxxf 1

    #s la recta 1=y DeKce"to a(scisas Henteras)

    Pg.;9 B2 ( ) +

    16

    3277

    xx,$#

    0

    0

    ( (( )

    =

    ++1

    2

    16

    1632

    x

    xx ( (7

    1632

    ++

    x

    xx 0

    0

    ( ) ( )

    ( ) ( ) =

    ++

    +

    +

    327

    1632 22

    xx

    xx [ ]( )( ) ( )

    =+++

    327

    167

    xx

    xx

    32

    16

    ++

    +

    x

    x =

    6

    2

    3

    1

    Pg.;9 B3 Primero! se tra6a la recta as4ntota 32 += xy ( )2 ( ) crecientexf = ( ) ntotaDerechaAs$xf =

    ( ) 10' =f = 1tg# angente en origen% xy= ( ) 02' =f MKimo relati3o% 2=x ( ) 13' =f angente en 3=x 3+= xy ( ) 04' =f M4nimo relati3o% 4=x ( ) 65' =f angente en 5=x 306 = xy

    Pg.;9 B4 a) #n [ ]102 es ( ) t& ( )2610 += xy ( )2610 = xy

    Par(ola 3ertical a(ierta hacia arri(a! de 3:rtice ( )106 ( ) 62 ( ) decrecet& = ( )106 ( ) crecet& =

    #n ( )1210 es ( ) tf 9228 = xy xy 2512

    128 =

    #K"onencial decreciente% ( )106 ( ) decrecet& = () ( ) 102t ( ) ( )62' = ttf ( ) 1210t ( ) 22 9' Ltf t =

    ( ) =0' tf

    6=t

    ( )=2f 26

    ( ) =6f 10

    ( )=10f 26

    ( ) =12f 20

    #n [ ]122 ha .%-imoD2G) en 2=t 10=t ./nimoD1;) en 6=t

    1/10

  • 8/10/2019 Unidad 12 - Integracin, problemas resueltos

    14/14

    1 Bachillerato - Matemticas - Unidad 12 - Integracin

    c) >12t ( ) 9228 = tt& ( ) =0t& +=2

    289

    L

    Lt 8,13 ( )a2os

    Pg.;9 B5 a) ( ) iaAbajoAbiertaHac,Eje.ertica&ar-bo,atf ,,= +ortes *% ( ) =0tf 0=t / 3=t Fina,(nicio/

    )(reni%n

    ( ) ttf 600900' ( ) =0

    '

    tf 23=t ( ) 230 ( ) crecetf = ( ) 323 ( ) decrecetf = () +a"acidad mKima en 3:rtice "ar(ola% 23=t c) #s la "ar(ola re"resentada al margen

    Pg.;9 B6 ( )#Ladox= ( )#A,tray= ( ) ++= 22 50410720 xxyxCoste ( ) xxy 2336 2= ( ) ( )23365,0 xxxf. = ( ) ( )2' 9365,0 xxf = ( ) = 0' xf 2=x

    >0. 12