vigas
DESCRIPTION
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ESFUERZOS EN VIGAS
Vigas GI=R−A−3
- Vigas apoyo simple
- Vigas con voladizo
- Vigas con doble voladizo
- Vigas empotrada
1) Resolver:
V
5
5 – 2 = 3
3 – 2 = 1
1 – 2 = -1
-1 – 2 = -3
-3 – 2 = -5
-5 + 5 = 0
M
0
0 + (1) (5) = 5
5 + (1) (3) = 8
8 + 1 = 9
9 + (1) (-1) = 8
8 + (1) (-3) = 5
5 + (1) (-5) = 0
2) Resolver:
V
7
7 – (2) (4) = -1
-1 – 4 = -5
-5 + 5 = 0
M
0
0+(3.5 )(7)2
=12.25
12.25+(0.5)(−1)
2=12
12+(2 ) (−1 )=10
10 + (2) (-5) = 0
3) Resolver:
V
4.8
4.8 – (2) (4) = -3.2
-3.2 – 4 = -7.2
-7.2 + 7.2 = 0
M
0
0+(3.5 )(7)2
=12.25
12.25+(0.5)(−1)
2=12
12+(2 ) (−1 )=10
10 + (2) (-5) = 0
4) Resolver:
[∑M A=0 ]
−2 (3 )−1 (3 )+2.4 (5.2 )−5.4 (1.2 )−By (4)=0
By=0.75
[∑M B=0 ]
−5.4 (1.2 )+2.4 (0.8 )+1 (1 )+8 (4 )−2 (3 )−Ay (4)=0
Ay=8.25
Lado I
[∑MC=0 ]
8 (2 )+2 (3 )+Ax (6 )−8.25 (2 )=0
Ax=−0−92
Lado II
[∑MC=0 ]
−1 (1 )−2.4 (0.8 )+5.4 (4.8 )−Bx (6 )=0
Bx=4.8