warm up - 2/15 on page 50
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Warm Up - 2/15 on page 50. What is kept constant in Boyle ’ s Law? Solve for the unknown: P 1 = 0.456 atm V 1 = 289 mL P 2 = 0.287 atm V 2 = ???. Gay-Lussac ’ s Law. Gay-Lussac ’ s Law. Created by Joseph Gay-Lussac - PowerPoint PPT PresentationTRANSCRIPT
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Warm Up - Warm Up - 2/15 on page 2/15 on page 5050 What is kept constant in BoyleWhat is kept constant in Boyle’’s s
Law?Law?
Solve for the unknown:Solve for the unknown: PP11 = 0.456 atm = 0.456 atm VV11 = 289 mL = 289 mL PP22 = 0.287 atm = 0.287 atm VV22 = ??? = ???
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Gay-LussacGay-Lussac’’s Laws Law
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Gay-LussacGay-Lussac’’s Laws Law
Created by Joseph Gay-LussacCreated by Joseph Gay-Lussac Deals with changes in pressure Deals with changes in pressure
and temperature (volume kept and temperature (volume kept constant)constant)
As one increases, the other As one increases, the other increases as well (direct increases as well (direct relationship)relationship)
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FormulaFormula
PP11 = = PP22
TT11 T T22
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ExampleExample
At 120At 120°C, the pressure of a sample °C, the pressure of a sample of nitrogen is 1.07 atm. What will of nitrogen is 1.07 atm. What will the pressure be at 205°C?the pressure be at 205°C?
PP11 = 1.07 atm = 1.07 atm TT11 = 120°C = 120°C PP22 = ??? = ??? TT22 = 205°C = 205°C
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ExampleExample
(1.07 atm)(1.07 atm) = = P P22 (120(120°C) (205°C)°C) (205°C)
(1.07 atm)*(205°C)(1.07 atm)*(205°C) = P = P22
(120°C)(120°C)
PP22 = 1.80 atm = 1.80 atm
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CharlesCharles’’ Law Law
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CharlesCharles’’ Law Law
Created by Jacques CharlesCreated by Jacques Charles Deals with changes in Deals with changes in volumevolume
and and temperaturetemperature (pressure (pressure kept constant)kept constant)
As one increases, the other As one increases, the other increases as well (direct increases as well (direct relationship)relationship)
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FormulaFormula
VV11 = = VV22
TT11 T T22
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ExampleExample
A gas at 65A gas at 65°C occupies 4.22 L. °C occupies 4.22 L. At what Celsius temperature will At what Celsius temperature will the volume be 3.87 L?the volume be 3.87 L?
VV11 = 4.22 L = 4.22 L TT11 = 65°C = 65°C VV22 = 3.87 L = 3.87 L TT22 = ??? = ???
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ExampleExample
(4.22 L)(4.22 L) = = (3.87 L)(3.87 L) (65(65°C) T°C) T22
(4.22 L)*T(4.22 L)*T22 = (3.87 L)*(65°C) = (3.87 L)*(65°C)
TT22 = = (3.87 L)*(65°C)(3.87 L)*(65°C) = 59.6°C = 59.6°C (4.22 L)(4.22 L)