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NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE1 . fz§fS« rh®òfS«
1. gçkh‰W¥ g©òAUB = BUAA ∩B = B∩ A
2. nr®¥ò g©òAU( BUC) = (AUB)UCA∩( B∩C) = (A∩B)∩C
3. g§Ñ£L¥ g©òAU( B∩C) = (AUB)∩(AUC)A∩( BUC) = (A∩B)U(A∩C)
4. okh®f‹ éÂfŸi) (AUB)’ = A’ ∩B’ii) (A ∩B)’ = B’ U A’iii) A (BUC) = (A B)‐ ‐ ∩(A C)‐iv) A (B‐ ∩C) = (A B)U (A C)‐ ‐
5. fz§fë‹ MÂ v©i) n(AUB) = n(A) +n(B) n(A‐ ∩Β)ii) n(AUBUC) = n(A) + n(B) + n(C) n(A‐ ∩B) n(B‐ ∩C) n(A‐ ∩C) + n(A∩B∩C)
6. rh®òfis F¿¡F« Kiwtçir nrhofë‹ fz« , m£ltid , m«ò¡F¿¥ gl« , tiugl«
7. rh®òfë‹ tiffŸ
1.x‹W¡F x‹whd rh®òA-š cŸs x›bthU cW¥òfS« , B-š cŸs x›bthU cW¥òfSl‹bjhl®ò gL¤j¥gL«
2. nkš rh®òB-š cŸs x›bthU cW¥òfS¡F« , A-š xU K‹ cU ÏU¡F«
3. ÏUòw¢ rh®òx‹W¡F x‹whd rh®ò k‰W« nkš rh®ò ÏU¡F«
4. kh¿è¢ rh®òA-š cŸs všyh cW¥òfS« , B-š cŸs xnu xU cW¥òl‹ ãHš cUbfh©oU¡F«
5. rkå¢ rh®ò
A-š cŸs x›bthU cW¥òfS« mjDlndna bjhl®ò¥ gL¤j¥gL«
1. A = {1, 2, 3, 4, 5}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8} våš,(I) AU( BUC) = (AUB)UC vd¡fh£Lf.(II) bt‹gl§fis¥ ga‹gL¤Â AU( BUC) = (AUB)UC v‹gij rçgh®¡fΫ.
Ô®Î(I) AU( BUC) = (AUB)UC ( BUC) = {3, 4, 5, 6}U{5, 6, 7, 8}
( BUC)= {3, 4, 5, 6, 7, 8} AU( BUC) = {1, 2, 3, 4, 5}U{ 3, 4, 5, 6, 7, 8}AU( BUC) = {1, 2, 3, 4, 5, 6, 7, 8} ……………………….. (1)
(AUB) = {1, 2, 3, 4, 5}U{3, 4, 5, 6} (AUB) = {1,2,3,4,5,6}(AUB)UC = {1,2,3,4,5,6}U{5,6,7,8}(AUB)UC = {1, 2, 3, 4, 5, 6, 7, 8}………………………….. (2)
(1)k‰W« (2) AU( BUC) = (AUB)UC vd rçgh®¡f¥g£lJ.
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(ii) jFªj bt‹gl§fŸ ËtUkhW cŸsd
2. A = {a,b,c,d}, B = {a,c,e} k‰W« C = {a,e} våš,(i) A∩( B∩C) = (A∩B)∩C vd¡ fh£Lf.(ii) bt‹gl§fis¥ ga‹gL¤Â A∩( B∩C) = (A∩B)∩C
Ô®Î(i) A = {a,b,c,d}, B = {a,c,e} , C = {a,e}.
A∩( B∩C) = (A∩B)∩C
( B∩C) = {a,c,e} ∩ {a,e} = {a,e}A∩( B∩C) = {a,b,c,d}∩{a,e}A∩( B∩C) = {a}……………………………… (1)
(A∩B) = {a,b,c,d.} ∩{a,c,e} = {a,c}(A∩B)∩C = {a,c}∩{a,e} = {a} (2)
(1)= (2) A∩( B∩C) = (A∩B)∩C
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3. A = {a,b,c,d,e}, B = {a,e, i,o,u}, C = {c,d,e,u} vd¡ bfhL¡f¥g£LŸsJ våš,(i) A\(B\C) = (A\B)\C vd¡ fh£Lf.
(ii) bt‹gl§fis¥ ga‹gL¤Â A\(B\C) = (A\B)\C vd rçgh®¡fΫ.
Ô®Î(i) (B\C) = {a,e, i,o,u}\{c,d,e,u} = {a, i,o}. A\(B\C) = {a,b,c,d,e}\{a, i,o} = {b,c,d,e}. ………………….. (1)
A \ B = {a,b,c,d,e}\{a,e, i,o,u} = {b,c,d}.A \ (B \C) = {b,c,d}\{c,d,e,u} = {b}……………. ……………(2)(1) k‰W« (2)-èUªJ A\(B\C) = (A\B)\C vd ãWt¥g£lJ. Mfnt, fz§fë‹ é¤Âahr« nr®¥ò¥ g©ò cilajšy.
(ii)
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5. A\(BUC) = (A\B) ∩ (A\C) ntz;glk; %yk; rhpghh;f;f .
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6. AU(B∩C) = (AUB) ∩ (AUC) vd;gjid ntz;glk; %yk; rhpghh; .
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7. (A U B) ‘ = A’ ∩ B’ vd;gjid ntz;glk; %yk; rhpghh; .
8. A\(BnC)=(A\B)U(A\C)
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9. (AUB)’=(A’UB’)
10. U = {-2,-1, 0,1, 2, 3,g,10}, A = {- 2, 2,3,4,5} k‰W« B = {1,3, 5,8,9} v‹f. o kh®få‹ fz ãu¥Ã éÂfis¢ rçgh®¡fΫ.
Ô®Î(AUB)’ = A’ ∩B’
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(AUB) = {- 2, 2, 3, 4, 5} U {1, 3, 5, 8, 9} = {- 2, 1, 2, 3, 4, 5, 8, 9}(AUB)’ = U \ {- 2, 1, 2, 3, 4, 5, 8, 9} = {- 1, 0, 6, 7, 10}………………….. (1)
A’ = U \ A = {- 1, 0, 1, 6, 7, 8, 9, 10}B’ = U \ B = {- 2, - 1, 0, 2, 4, 6, 7, 10}
A’ ∩B’ = {- 1, 0, 1, 6, 7, 8, 9, 10} ∩ {- 2, - 1, 0, 2, 4, 6, 7, 10}A’ ∩B’ = {- 1, 0, 6, 7, 10}…………………………………………………. (2)
(1) = (2), (AUB)’ = A’ ∩B’
11. A = {0,1,2,3,4}, B = {1, - 2, 3,4,5,6} k‰W« C = {2,4,6,7} v‹f. (i) AU( B∩C) = (AUB)∩(AUC) vd¡fh£Lf.
(ii) bt‹gl§fis¥ ga‹gL¤Â AU( B∩C) = (AUB)∩(AUC) vd rçgh®¡fΫ.Ô®Î
(i) LHS
B∩C = {1, - 2, 3, 4, 5, 6} ∩ {2, 4, 6, 7 }B∩C = {4, 6}AU( B∩C) = {0,1, 2, 3, 4} U {4, 6}AU( B∩C) = {0,1,2,3,4,6}……………………….……………….. (1)
(AUB) = {0, 1, 2, 3, 4} U {1, - 2, 3,4 ,5 ,6}(AUB) = {- 2, 0, 1, 2, 3, 4, 5, 6}, (AUC) = {0,1,2,3,4} U {2,4,6,7} = {0,1, 2, 3, 4, 6, 7}.(AUB)∩(AUC) = {- 2, 0,1, 2, 3, 4, 5, 6} ∩ {0,1, 2, 3, 4, 6, 7} (AUB)∩(AUC) = {0,1, 2, 3, 4, 6}…………………………………. (2)
(1) k‰W« (2)- AU( B∩C) = (AUB)∩(AUC), v‹gJ rçgh®¡f¥g£lJ.
(ii) bt‹gl§fis¥ ga‹gL¤Â AU( B∩C) = (AUB)∩(AUC)
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12. U = { -2,-1, 0,1,2,3.........10} A= {-2,2,3,4,5 } B= {1,3,5,8,9 } vd;f . bkhh;fdpd; fz epug;gp tpjpfis rhpghh; .
sol LHS : (AUB)’ (AUB) = {-2,2,3,4,5 } U {1,3,5,8,9 } = {-2,1,2,3,4,5,8,9} (AUB)’ = { -2,-1, 0,1,2,3......10} \{-2,1,2,3,4,5,8,9} (AUB)’ = {-1,0,6,7,10} ------------------------------------------(1) RHS : ( A’∩B’ ) A’ = U \ A ={ -2,-1, 0,1,2,3.........10} \ A= {-2,2,3,4,5 } A’ = {-1,0,1,6,7,8,9,10} B’ = U \ B = ={ -2,-1, 0,1,2,3.........10}\{1,3,5,8,9 } B’ = {-2,-1,0,2,4,67,10 }
A’∩B’ = {-1,0,1,6,7,8,9,10} ∩ {-2,-1,0,2,4,67,10 } A’∩B’ = {-1,0,6,7,10} -----------------------------------------(2) (AUB)’ = A’∩B’
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13. U = { 4, 8, 12, 16, 20, 24, 28}. A = { 8, 16, 24}; B = {4, 16, 20, 28} vdpy;
(AB)’ A’ B’ vd epWTf.
AB {8,16,24}{4,16,20,28}= { 4, 8, 16, 20, 24, 28 } _ ……………………(1)(AB)’ U\ AB '
U\ AB = { 4, 8, 12, 16, 20, 24, 28 } \ {4, 8, 16, 20, 24, 28}(AB)’ = { 12 } ---------------------------------(2)
A’ \ A' { 4, 8, 12, 16, 20, 24, 28 } \ { 8, 16, 24 }A’= {4, 12, 20, 28 } _................................................ (3)
B’ \ B' { 4, 8, 12, 16, 20, 24, 28 } \ { 4, 16, 20, 28 }B’= { 8, 12, 24, 28 } _ ……………………..(4)A’ B’ = { 4, 12, 20, 28 } n {8, 12, 24, 28 }A’ B’ = { 12 } _ (5)(2) = (5) (AB)’ A’ B’
14. U = { a, b, c, d, e, f, g, h } ; A = { a, b, f, g }; kw;Wk; B = {a, b, c} vdpy; fzepug;gpfsf;fhd b-khu;fd; tpjpfisr; rupghu;.(AB)’ A’ B’
AB = { a, b, f, g } { a, b, c} = { a, b, c, f, g } (AB)’ \AB = { a, b, c, d, e, f, g, h } \ { a, b, c, f, g }
(AB)’ = { d, e, h } -------------------- (1)
A’ = U \A = { a, b, c, d, e, f, g, h } \ { a, b, f, g } = { c, d, e, h }
B’ = U \ B = { a, b, c, d, e, f, g, h } \ { a, b, c }
A'B' = { c, d, e, h } { d, e, h } = { d, e, h } --------------------- (2)
(AB)’ A’ B’
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15. xU FGéš 65 khzt®fŸ fhšgªJ«, 45 ng® Ah¡»Í«, 42 ng® »ç¡bf£L«éisahL»wh®fŸ. 20 ng® fhšgªjh£lK« Ah¡»Í«, 25 ng® fhšgªjh£lK« »ç¡bf£L«,15 ng® Ah¡»Í« »ç¡bf£L« k‰W« 8 ng® _‹W éiah£LfisÍ« éisahL»wh®fŸ.m¡FGéš cŸs khzt®fë‹ v©â¡ifia¡ fh©f.(x›bthU khztD« FiwªjJ xU éisah£oid éisahLth® vd¡ bfhŸf.)
Mfnt, FGéš cŸs khzt®fë‹ v©â¡if = 28 + 12 + 18 + 7 + 10 + 17 + 8 = 100
16.gšfiy¡fHf khzt®fë‹ fz¡bfL¥Ãš, 64 ng® fâj«, 94 ng® fâ¥bgh¿m¿éaš, 58 ng® Ïa‰Ãaš M»a ghl§fis¡ f‰»‹wd®. 28 ng® fâjK« Ïa‰ÃaY«,26 ng® fâjK« fâ¥bgh¿ m¿éaY«, 22 ng® fâ¥bgh¿ m¿éaY« Ïa‰ÃaY« k‰W«14 ng® _‹W ghl§fisÍ« f‰»‹wd®. fz¡bfL¥Ãš fyªJ¡ bfh©l khzt®fë‹v©â¡ifia¡ fh©f. nkY«, xU ghl¤ij k£L« f‰»‹w khzt®fë‹v©â¡ifia¡ fh©f.
ԮΠbfhL¡f¥g£l étu§fis bt‹gl¤Âš F¿¥ÃLnth«.
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fz¡bfL¥Ã‹ nghJ ÏUªj khzt®fë‹ v©â¡if= 24 + 12 + 60 + 8 + 22 + 14 + 14 = 154fâj« k£L« f‰»‹w khzt®fë‹ v©â¡if = 24fâ¥bgh¿ m¿éaš k£L« f‰»‹w khzt®fë‹ v©â¡if = 60Ïa‰Ãaš k£L« f‰»‹w khzt®fë‹ v©â¡if = 22vdnt, xU ghl¤ij k£L« f‰»‹w khzt®fë‹ v©â¡if = 24+60+22 = 106.
17. xU thbdhè ãiya« 190 khzt®fël« mt®fŸ éU«ò« Ïiræ‹ tiffis¤Ô®khå¡f xU fz¡bfL¥ò el¤ÂaJ. 114 ng® nk‰f¤Âa ÏiriaÍ«, 50 ng® »uhäaÏiriaÍ«, 41 ng® f®ehlf ÏiriaÍ«, 14 ng® nk‰f¤Âa ÏiriaÍ« »uhäa ÏiriaÍ«,15 ng® nk‰f¤Âa ÏiriaÍ« f®ehlf ÏiriaÍ«, 11 ng® f®ehlf ÏiriaÍ« »uhäaÏiriÍ« k‰W« 5 ng® Ï«_‹W ÏirfisÍ« éU«ò»‹wd® vd¡ fz¡bfL¥Ãš btë¥g£lJ.ϤjftšfëèUªJ ËtUtdt‰iw¡ fh©f.(1) _‹W tif ÏirfisÍ« éU«ghj khzt®fë‹ v©â¡if.(2) ÏU tif Ïirfis k£L« éU«ò« khzt®fë‹ v©â¡if.(3) »uhäa Ïiria éU«Ã nk‰f¤Âa Ïiria éU«ghj khzt®fë‹ v©â¡if.
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(1) bt‹gl¤ÂèUªJ, VnjD« xU tif ÏiriaahtJ éU«ò« khzt®fë‹v©â¡if 90 + 9 + 30 + 6 + 20 + 10 + 5 = 170.fz¡bfL¡f¥g£l khzt®fë‹ v©â¡if = 190.Mfnt, _‹W tif ÏirfisÍ« éU«ghjt®fë‹ v©â¡if = 190 - 170 = 20.(2) VnjD« ÏUtif Ïirfis k£L« éU«ògt®fŸ v©â¡if = 9 + 6 + 10 = 25.(3) »uhäa Ïiria éU«Ã, nk‰f¤Âa Ïiria éU«ghj khzt®fë‹v©â¡if = 30 + 6 = 36.
18. xU fy;Y}hpapy; NrUtjw;F 60 khztHfs; NtjpapaypYk;> 40 NgH,aw;gpaypYk;> 30 NgH caphpaypYk; gjpT nra;Js;sdH. 15 NgH NtjpapaypYk;,aw;gpaypYk;> 10 NgH ,aw;gpaypYk; caphpaypYk; kw;Wk; 5 NgH caphpapaypYk NtjpapaypYk; gjpT nra;Js;sdH. %d;W ghlq;fspYk; xUtUNk gjpTnra;atpy;iy vdpy; VNjDk; xU ghlj;jpw;fhtJ gjpT nra;Js;stHfspd;vz;zpf;if ahJ?
VNjDk; xU ghlj;jpw;fhtJ gjpT nra;Js;stHfspd; vz;zpf;if
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= 60 + 40 + 30 – 15 – 10 – 5 + 0 = 100
19.xU efuj;jpy; 85% NgH Mq;fpyk;> 40% NgH jkpo;> 20% NgH ,e;jp nkhopfisNgRfpwhHfs;. 42% NgHfs; jkpOk; Mq;fpyKk;> 23% NgH jkpOk; ,e;jpAk;> 10%NgH Mq;fpyKk; ,e;jpAk; NgRfpwhHfs; vdpy; %d;W nkhopfisAk; Ngrj;njhpe;jtHfs; vj;jid NgH?
100 = 40-2-3+32+13+10+X100 =
100 = 70 + X100 – 70 = X X = 10 x = 10%
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20.120 FLk;gq;fs; cs;s xU fpuhkj;jpy; 93 FLk;gq;fs; rikaYf;F tpwifg;gad;gLj;Jfpd;wdu;. 63 FLk;gq;fs; kz;nzz;nziag; gad; gLj;Jfpd;wdh;. 45FLk;gq;fs; rikay; vhpthAitg; gad;gLj;Jfpwhu;fs;. 45 FLk;gq;fs; tpwFkw;Wk; kz;nzz;nza;> 24 FLk;gq;fs; kz;nzz;nza; kw;Wk; vhpthA> 27FLk;gq;fs; vhpthA kw;Wk; tpwF Mfpatw;iwg; gad;gLj;Jfpd;wdu;. tpwF>kz;nzz;nza;> rikay; vhpthA ,k;%d;iwAk; gad;gLj;Jgtu;fs; vj;jidFLk;gq;fs;?
120=21-6-6+45+24+27+X120=117-12+x120=105+x120-105=X15=x%d;iwAk; gad;gLj;Jgtu;fs; = 15
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21. A= { 0, 1, 2, 3 } k‰W« B = { 1, 3, 5, 7, 9 } v‹gd ÏU fz§fŸ v‹f. f : A -> Bv‹D« rh®ò f (x) = 2x + 1 vd¡ bfhL¡f¥g£LŸsJ. Ï¢rh®Ãid (i) tçir¢ nrhofë‹fz« (ii) m£ltiz (iii) m«ò¡F¿¥ gl« (iv) tiugl« M»at‰whš F¿¡f.ԮΠA = { 0, 1, 2, 3 }, B = { 1, 3, 5, 7, 9 },
f (x) = 2x + 1 f (0) = 2(0) + 1 = 1, f (1) = 2(1)+1 = 3 , f (2) = 2(2) + 1 = 5, f (3) = 2(3) + 1 = 7
(i) tçir¢ nrhofë‹ fz« f = { (0, 1), (1, 3), (2, 5), (3, 7) }.
(ii) m£ltiz mik¥ò
(iii) m«ò¡F¿¥ gl«
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X 0 1 2 3F(x) 1 3 5 7
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(iv) tiugl«
F(x)={(0,1), (1, 3), (2, 5), (3, 7)}
22.A = { 6, 9, 15, 18, 21}; B = {1, 2, 4, 5, 6 } kw;Wk; f : A _ B vd;gJ f(X) = X-3/3tiuaWf;fg; gl;bUg;gpd; rhu;G f- I (1) mk;Gf;Fwp glk; (ii) ml;ltiz (iii)tupir Nrhbfspd; fzk; (iv) tiuglk; %yk; Fwpf;fTk;.A = { 6, 9, 15, 18, 21 }; B = { 1, 2, 4, 5, 6}
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(i) tçir¢ nrhofë‹ fz«
f = { (6,1), (9,2), (15,4), (18,5),(21,6) }.
(ii) m£ltiz mik¥ò
(iii) m«ò¡F¿¥ gl«
23. A = {4, 6, 8, 10 } k‰W« B = { 3, 4, 5, 6, 7 } v‹f. f : A - B v‹gJ vd tiuaW¡f¥g£LŸsJ. rh®ò f (i) m«ò¡F¿ gl« (ii) tçir¢ nrhofë‹ fz« (iii) m£ltiz
M»at‰¿‹ _y« F¿¡fΫ.
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X 6 9 15 18 21F(x) 1 2 4 5 6
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(i) tçir¢ nrhofë‹ fz«
f ={(4,3)(6,4)(8,5)(10,6)}
(ii) m£ltiz mik¥ò
(iii)m«ò¡F¿¥ gl«
(iv) tiugl«
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X 4 6 8 10F(x) 3 4 5 6
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24. rh®ò f : [1, 6)$R MdJ ËtUkhW tiuaW¡f¥g£LŸsJ.
1+x 1≤ x <2 (1,2)
f(x) = 2x – 1 2 ≤ x <4 (2,3,4)
3x2 – 10 4≤ x <6 (4,5,6)
(i). f(5) (ii) f(3) (iii).f(1) (iv). f(2) – f(4) (v). 2f(5) – 3(1)
Sol
(i) f(x) = 3x2 -10 (ii)
f(5) = 3(5)2 – 10
= 3(5x5) -10
= 3 (25) – 10
= 75 – 10
(iv) f(x) = 2x – 1 f(x)= 3x2 – 10 f(2) = 2(2)-1 f(4)=3(4)2 – 10 = 4 – 1 =3(4 X4) – 10 =3(16) – 10
= 48 – 10
(v) 2f(5) – 3f(1)
2f (5) - 3f(1) = 2(65) – 3(2)
= 130 – 6
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f (5) = 65
f(x) = 2x -1
f(3) = 2(3) -1
= 6 – 1
f(3) = 5
(iii) f(x) = 1 + x
f(1) = 1+1
f(1) = 2
f(2) = 3
f(4)= 38
f(2) – f(4) = 3- 38 = -35
2f (5) - 3f(1) = 124
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25. rh®ò f : [1, 6)$R MdJ ËtUkhW tiuaW¡f¥g£LŸsJ.
4x2 – 1 -3 ≤ x<2
f(x) = 3x – 2 2 ≤ x ≤ 4
2x – 3 4< x ≤ 6
(i) f(5) + f(6) (ii) f(1) – f(-3) (iii) f(-2) – f(4) =
sol
(i) f(x) = 2x – 3
f(5) = 2(5) – 3 f(6) = 2(6) – 3
= 10 – 3 = 12 – 3
f(5) + f(6) = 7 + 9 = 16
(ii) f(1) – f(-3)f(1) => f(x) = 4x2 - 1 f(3) => f (x) = 4x2 -1 f(1) = 4(1)2 – 1 f(-3) = 4(-3)2 - 1 = 4(1) -1 = 4(-3 x -3) – 1 = 4-1 = 3 = 4 (9) - 1
= 36 – 1
(iii) f(-2) – f(4)
f(-2) => f(x) = 4x2 – 1 f(4)=> f(x) = 3x – 2
f(-2) = 4(-2)2 – 1 f(4) = 3(4) – 2
f(-2) = 4(-2 x -2) – 1 = 12 - 2
= 4(4) – 1
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f (5) = 7 f(6) = 9
f(5) + f(6) = 16
f (1) = 3
f(1) – f(-3) = 3 – 35 = -32
f(3) = 35
f(4) = 10
NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
= 16 – 1
(iv) f(x) = 3x – 2 f(3) = 3(3) – 2 = 9 - -2 = 7 f(x) = 4x2 – 1 f(-1) = 4(-1)2 – 1 = 4 – 1 = 3 f(x) = 2x – 3 f(6) = 2(6) – 3 = 12 – 3 = 9 f(x) = 4x2 – 1 f(1) = 4(1)2 – 1 = 4 – 1 = 3
26. . rh®ò f : (- 7,6)=>R MdJ ËtUkhW tiuaW¡f¥g£LŸsJ.
X 2 + 2x + 1 ; -7 ≤ x < - 5
F(x) = X + 5; - 5 ≤ x 2
X+1 2 < x < 6
(i) 2f (-4) + 3f (2) (ii) f (-7) – f (-3)
Sol
(i) 2f (-4) + 3f (2)
f (x) = x + 5 f (-4) = -4 + 5 = 1
f (x) = x + 5 f (2) = 2 + 5 = 7
2f (-4) + 3f (2) = 2 (1) + 3 (7)
= 2 + 21 = 23
(ii) F (-7) – f (-3)
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f(-2) = 15
f(-2) – f(4) = 15 – 10 = 5
NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
f (x) x2 + 2x + 1 f (-7) = (-7)2 +2 (-7) + 1
= 49 – 14 + 1 = 36
f (x) = x + 5 f (-3) = -3 + 5 = 2
f(-7)- f (-3) = 36 – 2 = 34
4f (-3) = f (x) = 4 (x + 5 )
f (3) = 4 (-3 + 5) = 4 (2)
f (-3) = 8
2f (4) => f (x) = x – 1
2f (4) = 2 (4 – 1)
= 2 (3)
2f (4) = 6
f (-6) => f (x) = x2 + 2x +1
f (-6) = (-6)2 + 2 (-6) + 1
= (-6 x -6) + 2 (6) + 1
= 36 -12 + 1
= 24 + 1 = 25
3f (1) => f (x) = x + 5
3f (1) = 3 (1+5) = 3 (6)
23
f (-3) = 8
2f (4) = 6
f (-6) = 25
3f (x) = 18
NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
1. 6 + 66 + 666 + ............. vd;w njhlu;thpirapd; n cWg;Gfs; tiu $Ljy; fhz;f. = 6 [1+11+111 +…………………..+n]
2. 7 + 77 + 777 + ............. vd;w njhlu;thpirapd; n cWg;Gfs; tiu $Ljy; fhz;f.
= 7 [1+11+111 +…………………..+n]
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NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
3.300 f;Fk; 500 f;Fk; ,ilNa 11My; tFgLk; midj;J ,ay; vz;fspd; $Ljy; fhz;f.
4.308+319………………………………………+495
a=308 ;d = 11; l = 495
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NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
5. 12 nr.kP> 13 nr.kP> ...........23 nr.kP gf;f msTfSs;s rJuq;fspd; gug;Gfspd; $Ljy; fhz;f
122+132+……………………………………….+232
(12+22+32+……………..+232) – (12+22+32+………………..+112)
6. 11 nr.kP> 12 nr.kP> ......... 24 nr.kP vd;w gf;f msTfSs;s rJuq;fspd; gug;Gfspd; $Ljy; fhz;f.
7. 16 nr.kP> 17 nr.kP> ........ 30 nr.kP vd;w gf;f msTfSs;s fdrJuq;fspd;fdmsTfspd; $Ljy; fhz;f.
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,aw;fzpjk;x4 - 10X3 + 37X2 – 60x – 36
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X4-6X3+19X2-30X+25 - d; th;f;f%yj;ij fhz;f.
NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
m – nx + 28x2 + 12x3 + 9x4 ----------- n = ? ; m = ?
…………………………………………………………………………………………………
fhuzpgLj;Jf:
(i) x3 – 2x2 – 5x + 6
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9x4+12x3+28x2-nx+m d; th;f;f%yj;ij fhz;f.
NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
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NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
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NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
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Maj;njhiy tbtpay;
NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
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NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
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mzpfs;
NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
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NEW SAKTHI ACADEMY AND EDUCATION CENTER,CUDDALORE
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S.SAKTHIVEL M.Phil
NEW SAKTHI ACADEMY AND EDUCATION CENTER
CUDDALRE – 1
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