zapata aislada
DESCRIPTION
Zapata aisladaTRANSCRIPT
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DISEO DE UNA ZAPATA AISLADA
las cargas PD = 180 tn y PL = 100 tn . La capacidad portante admisible del suelo es qa = 2.5 kg/cm2 ; ademas fy = 4200kg/cm2 , fy = 280 kg/cm2 en la columna y fc = 210 kg/cm2 en la zapata
DATOS:
Zapata Otros Suelo
f ' c = 210 kg/cm S/C = 550 kg/m Df = 1.4 m
Columna PD = 180 Tn g 2 = 1700 kg/m
f ' c = 280 kg/cm PL = 100 Tn qa = 2.50 kg/cm
b = 50 cm db = 2.54 cm
t = 70 cm Acero Lv = 150 cm
f y = 4200 kg/cm
1.- DIMENSIONAMIENTO DE LA ZAPATA Clculo del peralte de la zapata (hc )
Ld = 58.89 cm
Tomar Ld = 58.89 cm Df
(Del problema se emplean varillas de 1") b ( 1") = 2.54 cm
r.e. = 7.50 cm (recubrimiento)
hc = 68.93 cm
Tomar hc = 70.00 cm hc = Ld + r.e + b T
ht = Df - hc
ht = 70.00 cm
Clculo de la presin neta del suelo ( qm )
qm = 2.16 kg/cm
T
Clculo del rea de la zapata ( Az )
Azap = cm Donde:
T = cm P = Carga de servicio
B = cm Lv = Volados iguales sin
excentricidad
2.- DETERMINACIN DE LA REACCIN AMPLIFICADA ( qmu )
Donde:
kg/cm2 Pu = Carga Ultima3.26
129,629.63
370.00
350.00
Disear la zapata mostrada en la fig: Si la Columna de 70 x 50 lleva 10 fierros de 1" y transmite
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3.- VERIFICACION POR CORTE ( = 0.85 )Por Flexin:
Lv = cm
r.e = 7.50 cm
b ( 3/4") = 1.91 cm (Suponiendo varillas 3/4")
d = cm ( d = hc - b - r.e. )
Vdu = kg
= 0.85 (Coef. De reduccion por corte)
Vc = kg
Vc = kg
Vc > Vdu OK!
Por Punzonamiento :
Vu = kg
= 2m +2n
bo =
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.06 * f 'c^.5 * bo * d
b c
Vc = kg Vc= Kg
Vc = kg Vc= Kg
Vc > Vdu OK!
b c = lado mayor columna ( t ) 1.4
lado menor columna ( b )
m = t + d m =
n = t + b n =
bo = 2*m + 2*n
Vu = vc OK ! Vu =
vc =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( = 0.90 )Direccin Mayor:
Lv = cm ree =
Mu = kg-cm b ( 3/4") = 1.91
B =
d =
a = 3.89 (Valor Asumido)
As = Ab ( 3/4" ) =
As mn = 0.0018 * B * d a = 3.89 20
As > As mn OK !! Espaciam =
As = 20 3/4" @
Ab
# Varilla ( n ) = As Ab ( 3/4" ) =
Ab 15
Espaciam = B - 2*r.e - b Espaciam =
138,443.78
162,875.03
60.59
101,975.73
150.00
2.85
2.85
17.53
17.53
374,938.21
bo = 2 x ( t + d ) + 2 x ( b + d )
482.36
555,426.41472,112.45
7.50150.00
448,939.43
Vu = 1.1 x f'c x bo x d
130.59
110.59
381,598.52
# Varilla ( n ) =
# Varilla ( n ) =
(perimetro de los planos de falla)
448,939.43381,598.52
350.00
12,831,081.08
60.59
57.88
57.88
23.79
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n -1 As mn = 15 3/4" @
As > As mn OK !!
Direccin Menor:
As tranv = As * T
B T = 370 ree =
As mn = 0.0018 * B * d B = 350 b ( 3/4") = 1.91
As > As mn OK !! d =
a = 5.01 (Valor Asumido)
Ab Ab ( 3/4" ) =
# Varilla ( n ) = As 21
Ab Espaciam =
As transv = 21 3/4" @
Espaciam = B - 2*r.e - b
n -1 Ab ( 3/4" ) =
16
Espaciam =
Asmin = 16 3/4" @
As transv > As mn OK !!
Longitud de desarrollo en Traccion ( Ld )
ld = b * fy * a * b * g * l < Lv1
3.54 * f 'c^.5 * C + Kr
b
Lv1 = Lv - r.e.e
La Zapata es rectangular se debe compartir el Refuerzo adecuadamente de la siguiente manera:
Asc = 2 * Astrv
( b + 1 ) b = 1.00 b (3/4") = 1.91 C =
g = 0.80 r.e.e = 7.50 ktr = 0
b = Lado mayor Zapata l = 1.00 fy = 4200
Lado menor Zapata a = 1.00 f'c = 210 2.5 q = ( C+kt r )/ b
Ab
# Varilla ( n ) = As Longitud de desarrollo en traccin q=
AbEspaciam = B - 2*r.e.e - b Lv1 = 142.50 q >= 2.5 ,PONER 2.5 !!
n -1 Ld = 50.04
Ld < Lv1
Espaciamiento del Refuerzo
Asc = 61.19
45 cm
17.65 OK !!
3 x h 210 cm
5.- VERIFICACION DE LA CONEXIN COLUMNA - ZAPATA ( = 0.70 )
Para la seccin A colum = 70*50 = 3500 cm ( COLUMNA )
* 0.85 * f 'c * As1 Pu = # Varilla ( n ) = 6
A colum = b *t A1 =
422000
3500
q < 2.5 ,PONER q !!
23.54
OK !!
8.50
46.62
# Varilla ( n ) =
61.19
44.1
17.65
2.85
2.85
# Varilla ( n ) =
60.59
23.54
23.79
17.65
7.50
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Pu < ( * 0.85 * f 'c * A1) * 0.85 * f 'c * A1 =
Ab
As mn = 0.005 * A1
# Varilla = As1
Ab As mn =
As col. > As mn OK !! Ab ( 3/4" ) =
USAR : As1 =
As col > As min
Para la seccin A zapata = 350*370 = 129500 cm ( ZAPATA )
Pu =
A1 =
A2 =
x 0.85 x f 'c x A2/A1 x A1 =
17.50
2.85
Pu < * 0.85 * f 'c * A1 OK !!
583100
422000
3500
Pu < x 0.85 x f 'c x A2/A1 x A1
129500
874650 OK !!
17.50
OK !!
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las cargas PD = 180 tn y PL = 100 tn . La capacidad portante admisible del suelo es qa = 2.5 kg/cm2
MD,ML
PD, PL
ht
Lv
hc
B
Carga de servicio
Volados iguales sin
excentricidad
Carga Ultima
Disear la zapata mostrada en la fig: Si la Columna de 70 x 50 lleva 10 fierros de 1" y transmite
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(Suponiendo varillas 3/4")
( d = hc - b - r.e. )
(Coef. De reduccion por corte)
2.85
2.85
17.53
17.53
7.50
23.79
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La Zapata es rectangular se debe compartir el Refuerzo adecuadamente de la siguiente manera:
q = ( C+kt r )/ b
10.41
q >= 2.5 ,PONER 2.5 !!
q < 2.5 ,PONER q !!
23.54
8.50
17.65
2.85
2.85
23.54
23.79
17.65
7.50
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A2/A1 = 2