第1頁第1頁 chapter 2 analytic function 9. functions of a complex variable let s be a set of...
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第 1頁
Chapter 2 Analytic Function
9. Functions of a complex variable
Let S be a set of complex numbers.
A function defined on S is a rule that assigns to each z in S a complex
number w.
f
value of at , or ( )f z f z
or w f zS is the domain of definition of f
2
1
1
wz
w z
sometimes refer to the function itself, for simplicity.f
Both a domain of definition and a rule are needed in order for a function to be well defined.
第 2頁
Suppose is the value of a function atfw u i z x iy
, ,
u iv f x iy
or f z u x y iv x y
real-valued functions of real variables x, y
or , ,f z u r iv r
Ex.
2
2 2
2 2
2 2
2 2
2
( , ) , ( , ) 2
cos 2 sin 2
, cos 2 , sin 2
i
f z z
f x iy x y i xy
u x y x y v x y xy
f re r ir
u r r v r r
when v=0 is a real-valued function of a complex variable. f Z
第 3頁
is a polynomial of degree n. 20 1 2 ... n
nf z P z a a z a z a z
( )
( )
P z
Q z : rational function, defined when ( ) 0Q z
For multiple-valued functions : usually assign one to get single-valued function Ex.
12 2
2
, 0
, th root
If we choose 0,
2 2 2 and (0) 0,
then is well defined on the entrie complex plane except
the ray = .
i
i
i
z re z
z re n
f z re r
f
f
第 4頁
10. Mappings
w=f (z) is not easy to graph as real functions are.
One can display some information about the function by indicating pairs
of corresponding points z=(x,y) and w=(u,v). (draw z and w planes
separately).
When a function f is thought of in this way. it is often refried to as a mapping, or transformation.
z winverse image
of w
image of z
image of T
T
第 5頁
Mapping can be translation, rotation, reflection. In such cases
it is convenient to consider z and w planes to be the same.
w=z+1 translation +1
w=iz rotation
w= reflection in real axis.
Ex. image of curves
z2
y
x
real number 2y x
2
2 2
2
w z
u x y
v xy
a hyperbola is mapped in a one to one manner onto the line 2 21x y c 1u c
第 6頁
2xy=C2Y
X
2 21x y C
u=C1>1V
U
V=C2>0
right hand branch x>0, u=C1,
left hand branch x<0 u=C1,
image
21
21
2
2
V y y c y
V y y c y
第 7頁
x
y
D
B
A
1
L1 L2
Cx1
Ex 2.
0 1
0
x
y
u
vA’
L2’L1’
B’D’ C’
When , point moves up a vertical half line, L1, as y increases from y = 0.
10 1x 1,x y
2 21
1
2
2 2 2 21 1 1
1
, 2
2
, 42
u x y v x y
vy
x
vu x v x u x
x
a parabola with vertex at 2
1 ,0x
half line CD is mapped of half line C’D’
2 ,0y 0, y
第 8頁
Ex 3.
2 2 2
2 , 2 2 0, 1, 2,...
i
i
w z r e
let w e
r n n
x
y
u
v
20, 0r one to one 0, 0
第 9頁
11. Limits
Let a function f be defined at all points z in some deleted neighborhood of z0
00lim ( ) (1)
( )
z zf z w
f z
means: the limit of as z approaches z0 is w0
can be made arbitrarily close to w0 if we choose the point z close ( )w f z
enough to z0 but distinct from it.
(1) means that, for each positive number ,there is a positive number
such that
0 0( ) 0f z w whenver z z
x
y
z
z0
u
v
ww
w0
0
(2)
第 10頁
Note:
(2) requires that f be defined at all points in some deleted neighborhood of z0
such a deleted neighborhood always exists when z0 is an interior point of a region on which is defined. We can extend the definition of limit to the case in which z0 is a boundary point of the region by agreeing that left of (2) be satisfied by only those points z that lie in both the region and the domain
Example 1. show if
f
00 z z
1
( ) 1,2
lim ( )2z
izf z in z then
if z
第 11頁
1
1
2 2 2 2
when z in z
zi iz if z
For any such z and any positive number
2
if z whenever 0 1 2z
z
y
x
2
v
u
2
i
第 12頁
Then
Let
But
Hence
0 0 0
1 0 1
0
0
f z w whenever z z
f z w whenever z z
0 1
0
min ,
0if z z
0 1 0 1
1 0
( ) ( ) ( ) 2
2
f z w f z w f z w f z w
w w
1 0w w is a nonnegative constant, and can be chosen arbitrarily small.
1 0 1 00,w w or w w
When a limit of a function exists at a point , it is unique.
If not, suppose , and
f z 0z
00lim
z zf z w
01lim
z zf z w
第 13頁
Ex 2. If (4)
then does not exist.
zf z
z
0
limz
f z
show:
0,0 1
00
0, 10
x iwhen z x f z
x iiy
when z y f ziy
since a limit is unique, limit of (4) does not exist.
(2) provides a means of testing whether a given point w0 is a limit, it does
not directly provide a method for determining that limit.
第 14頁
12. Theorems on limits
Thm 1. Suppose that
0 0 0
0 0 0
, , ,f z u x y iv x y z x iy
and w u iv
Then iff0
0 0 0 0
0
0 0( , ) ( , ) ( , ) ( , )
lim ( )
lim ( , ) lim ( , )
z z
x y x y x y x y
f z w
u x y u and v x y v
pf : ” ” 2 20 0 0 1
2 20 0 0 2
1 2
0 ( ) ( )2
0 ( ) ( )2min( , )
u u whenever x x y y
v v whenever x x y y
let
第 15頁
since
and
“ ”
But
and
0 0 0 0 0 0
2 2
0 0 0 0 0 0
0 0
0 0
( ) ( )
2 2
0
u iv u iv u u i v v u u v v
x x y y x x i y y x iy x iy
u iv u iv
whenever x iy x iy
0 0 0 00u iv u iv whenever x iy x iy
0 0 0 0 0
0 0 0 0 0
u u u u i v v u iv u iv
v v u u i v v u iv u iv
2 2
0 0 0 0
0 0
2 20 0
( )
0 ( ) ( )
x iy x iy x x y y
u u and v v
whenever x x y y
第 16頁
Thm 2. suppose that
0 0
0
0
0
0 0
0 0
0 0
0
0
0
lim ( ) lim ( ) (7)
lim ( ) ( )
lim ( ) ( ) (9)
0
( )lim
( )
z z z z
z z
z z
z z
f z w and F z W
Then f z F z w W
f z F z w W
and if W
wf z
F z W
0 0 0 0 0 0 0 0 0
( ) ( , ) ( , )
( ) ( , ) ( , )
, ,
f z u x y iv x y
F z U x y iV x y
z x iy w u iv W U iV
pf: utilize Thm 1.
for (9).
use Thm 1. and (7)
第 17頁
0 0 0 0 0 0 0 0
0 0
( ) ( ) ( )f z F z uU vV i vU uV
u U v V v U u V
w W
have the limits
An immediate consequence of Thm. 1:
0
0
0
0
0 0
0
0
20 1 2
0
0 0
lim
lim
lim ( 1,2,...)
( ) ...
lim ( ) ( )
lim ( ) , lim ( )
z z
z z
n n
z z
nn
z z
z z z z
c c
z z
z z n
P z a a z a z a z
P z P z
if f z w then f z w
by property (9) and math induction.
(11)
利用 whenever0 0( ) ( )f z w f z w 00 z z
第 18頁
13. Limits involving the point at Infinity
It is sometime convenient to include with the complex plane the point at infinity,
denoted by , and to use limits involving it.
Complex plane + infinity = extended complex plane.
NP
zO
complex plane passing thru the equator of a unit sphere.
To each point z in the plane there corresponds exactly one point
P on the surface of the sphere.
intersection of the line z-N with the surface.
north pole
To each point P on the surface of the sphere, other than the north pole N, there corresponds exactly one point z in the plane.
第 19頁
By letting the point N of the sphere correspond to the point at infinity, we obtain a one-to-one correspondence between the points of the sphere and the points of the extended complex plane.
upper sphere exterior of unit circle
points on the sphere close to N
neighborhood of
1z
0
0
0
lim ( )
1( ) 0
10 0
( )
z zf z
f z whenever z z
whenever z zf z
0 0
1 1
1lim ( ) lim 0
( )
3 11. lim since lim 0
1 3
z z z z
z z
f z ifff z
iz zEx
z iz
第 20頁
0
0
0
0 00
lim ( )
1( )
1( ) 0 0
1lim ( ) lim ( )
z
z z
f z w
f z w whenever z
f w whenever zz
f z w iff f wz
Ex 2.0 0
2( )2 2
lim 2 since lim lim 211 1( ) 1
z z z
iz i izzz z
z
第 21頁
10
lim ( )
1 1( )
1 1 1 1( )
10 0 0
(1/ )
1lim ( ) lim 0
( )
z
z zz
f z
f z whenever z
f wheneverz z
whenever zf z
f z ifff
2
3
3
2
1 3
320 0
2 1lim
11
since lim lim 01 2
z
z
z zz
z
z
z z
z
Ex 3.
第 22頁
14. Continuity
A function f is continuous at a point z0 if
0
0
0
0
0 0
lim ( ) exists,
( ) exists,
lim ( ) ( )
( ( ) ( ) )
z z
z z
f z
f z
f z f z
f z f z whenever z z
(1)
(2)
(3)
• if continuous at z0, then are
also continuous at z0.
1 2,f f 1 2 1 2,f f f f
((3) implies (1)(2))
12 0
2
( ) 0f
if f zf
So is
第 23頁
• A polynomial is continuous in the entire plane because of (11), section 12. p.37
• A composition of continuous function is continuous.
z w
f g
0 0
0
( ) ( ) , ( ) ( ) ,g f z g f z whenver f z f z r
whenver z z
• If a function f(z) is continuous and non zero at a point z0, then
throughout some neighborhood of that point.
when let
( ) 0f z
0( ) 0f z 0( )
2
f z
00 0
( )( ) ( )
2
f zf z f z whenever z z
if there is a point z in the at which then
, a contradiction.
0z z 0( ) 0f z
00
( )( )
2
f zf z
第 24頁
Ex. The function
is continuous everywhere in the complex plane since
(i) are continuous (polynomial)
(ii) cos, sin, cosh, sinh are continuous
(iii) real and imaginary component are continuous
complex function is continuous.
2 2 2 2( ) cos( )cosh 2 sin( )sinh 2f z x y xy i x y xy
2 2
2
x y
xy
From Thm 1., sec12.
a function f of a complex variable is continuous at a point
iff its component functions u and v are continuous there.
0 0 0( , )z x y
sinh sin2 2
cosh cos2 2
x x ix ix
x x ix ix
e e e ex x
i
e e e ex x
第 25頁
15. Derivatives
Let f be a function whose domain of definition contain a neighborhood of a point z0. The derivative of f at z0, written , is 0'f z
0
00
0
' limz z
f z f zf z
z z
provided this limit exists.
f is said to be differentiable at z0.
0
0 00 0
0
( ) ( )'( ) lim
( ) ( ).
'( ) lim
z
z
let z z z
f z z f zf z
zlet w f z z f z
dw wf z
dz z
z
0z
0z z
第 26頁
Ex1. Suppose at any point z2( )f z z2 2
0 0 0
( )lim lim lim(2 ) 2 0 2z z z
w z z zz z z z
z z
since a polynomial in .2z z z
'( ) 2dw
f z zdz
Ex2.
2
2 2
( )f z z
z z z z zzz z zw zz z z
z z z z
when thru on the real axis ,
Hence if the limit of exists, its value =
when thru on the imaginary axis.
, limit = if it exists.
0z
0z
,0x
0, y
w
z
z z
z z
z z z z
第 27頁
since limits are unique,
, if is to exist.
observe that when
exists only at , its value = 0
, 0z z z z or z dw
dzw
zz
0z
dw
dz 0z
• Example 2 shows that
a function can be differentiable at a certain point but nowhere else in any
neighborhood of that point.
• Re are continuous, partially
Im differentiable at a point.
but may not be differentiable there.
2 2 2
20
z x y
z
2
z
第 28頁
existence of derivative continuity.
0 0 0
0
00 0
0
0
0
( ) ( )lim ( ) ( ) lim lim( )
'( ) 0 0
lim ( ) ( )
z z z z z z
z z
f z f zf z f z z z
z z
f z
f z f z
continuity derivative exists.not necessarily
• is continuous at each point in the plane since its components are continuous at each point. ( 前一節 )
2( )f z z
第 29頁
16. Differentiation Formulas
1
0 : complex constant
1
( ) '( )
n n
dC C
dzd
zdzd
cf z cf zdzd
z nzdz
n a positive integer.
2
( ) '( ) '( )
( ) ( ) '( ) '( ) ( ) (4)
( ) 0
( ) '( ) ( ) '( )
( ) ( )
df z F z f z F z
dzd
f z F z f z F z f z F zdzwhen F z
f zd F z f z f z F z
dz F z F z
第 30頁
: (4)pf
( ) ( ) ( ) ( )
( )[ ( ) ( )] [ ( ) ( )] ( )
( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( )
f z z F z z f z F z
f z F z z F z f z z f z F z z
f z z F z z f z F z F z z F z f z z f zf z F z z
z z z
0 [ ] ( ) '( ) '( ) ( )
( ) '( ) '( ) ( )
das z fF f z F z f z F z z
dzf z F z f z F z
(F continuous at z)
第 31頁
f has a derivative at z0
g has a derivative at f(z0)
F(z)=g[f (z)] has a derivative at z0
and chain rule (6)0 0 0'( ) '[ ( )] '( )F z g f z f z
dW dW dw
dz dw dz
pf of (6)
choose a z0 at which f’(z0) exists.
let w0 = f (z0) and assume g’(w0) exists.
Then, there is of w0 such that
we can define a function , with and
0w w
0( ) 0w 0
0 00
( ) ( )( ) '( )
g w g ww g w when w w
w w
(7)
0
lim ( ) 0,w w
w
Hence is continuous at w0
第 32頁
0 0 0 0(7) ( ) ( ) '( ) ( ) ( ) ( ) (9)g w g w g w w w w w w
0w wvalid even when
since exists and therefore f is continuous at z0, then we can
have f (z) lies in
0'( )f z
0 0 0w w of w if z z
substitute w by f (z) in (9) when z in
(9) becomes
0z z
0 00
0 0
0
[ ( )] [ ( )] ( ) ( ){ '[ ( )] [ ( )]} (10)
(0 )
g f z g f z f z f zg f z f z
z z z z
z z
since f is continuous at z0 , is continuous at
is continuous at z0 , and since
0 0( )w f z
[ ( )]f z 0( ) 0w
0
lim ( ) 0z z
f z
0 0 0 0'( ) ' ( ) '( ) as F z g f z f z z z so (10) becomes
第 33頁
17. Cauchy-Riemann Equations
Suppose that 0 00
0
0 0 0,
( ) ( )'( ) lim .
z
f z z f zf z exists
zz x iy z x i y
writing
Then by Thm. 1 in sec 12
0 00 ( , ) (0,0)
0 00 ( , ) (0,0)
( ) ( )Re '( ) lim Re[ ] (3)
( ) ( )Im '( ) lim Im[ ] (4)
x y
x y
f z z f zf z
zf z z f z
f zz
where
0 0 0 0 0 0
0 0 0 0
( ) ( ) ( , ) ( , )(5)
[ ( , ) ( , )]
f z z f z u x x y y u x y
z x i y
i v x x y y v x y
x i y
第 34頁
Let tend to (0,0) horizontally through . i.e.,( , )x y ( ,0)x 0y
0 0 0 00
0
0 0 0 00
0
0 0 0 0 0
( , ) ( , )Re[ '( )] lim
( , ) ( , )Im[ '( )] lim
'( ) ( , ) ( , ) (6)
x
x
x x
u x x y u x yf z
xv x x y v x y
f zx
f z u x y iv x y
Let tend to (0,0) vertically thru , i.e. , then( , )x y (0, )y 0x
0 0 0 00 0 0 00
0 0 0 0
( , ) ( , )( , ) ( , )'( ) ( )
( , ) ( , ) (7)y y
y y
i v x y y v x yu x y y u x yf z
i y i y
v x y iu x y
iu v
(6)= (7)
0 0 0 0
0 0 0 0
( , ) ( , ) (8)
( , ) ( , )
x y
y x
u x y v x y
u x y v x y
Cauchy-Riemann Equations.
第 35頁
Thm : suppose
exists at a point
Then
0 00
( ) ( , ) ( , )
'( )
f z u x y iv x y
f z z x iy
0 0, , , exist at ( , )
and , ; also '( )
x y x y
x y y x x x
u u v v x y
u v u v f z u iv
2 2 2( ) 2
2 2
2 2
,
'( ) 2 2 2( ) 2
x x
y y
x y y x
f z z x y i xy
u x v y
u y v x
u v u v
f z x i y x iy z
Ex 1.
Cauchy-Riemann equations are Necessary conditions for the existence of
the derivative of a function f at z0.
Can be used to locate points at which f does not have a derivative.
第 36頁
2
2 2
( ) ,
( , ) ( , ) 0
2 0 , '( )
2 0
x x x y
y y
f z z
u x y x y v x y
u x v u v f z
u y v
Ex 2.
does not exist
at any nonzero point.
The above Thm does not ensure the existence of f ’(z0)
(say)
第 37頁
18. Sufficient Conditions For Differentiability
but not0'( ) exist ,
" "
x y y xf z u v u v
Let be defined throughout some
neighborhood of a point
suppose exist everywhere in the neighborhood and
are continuous at .
, , ,x y x yu u v v
0 0( , )x y
( ) ( , ) ( , )f z u x y iv x y Thm.
0 0 0z x iy
0 0
0
, at ( , )
'( ) .
x y y xu v u v x y
f z exists
Then, if
第 38頁
0 0
0 0 0 0
: , 0
( ) ( )
( ) ( ) [ ( ) ( )]
pf let z x i y where z
w f z z f z
w u i v u z z u z i v z z v z
Thus
where0 0 0 0
0 0 0 0
( , ) ( , )
( , ) ( , )
u u x x y y u x y
v v x x y y v x y
Now in view of the continuity of the first-order partial derivatives of u and v at the point
0 0 0 0 0 0 0 0( , ) ( , ) ( , ) ( , )x y xyu u x y u x y x u x y y u x y x y 2
0 0( , )2!xx
xu x y
2
0 0( , )2!
...
yy
yu x y
0 0
2 20 0 0 0 1
( , )
( , ) ( , ) ( ) ( )x y
u x y
u x y x u x y y x y
0 0( , )x y
第 39頁
2 20 0 0 0 2
1 2
( , ) ( , ) ( ) ( )
, 0, ( , ) (0,0)x yv v x y x v x y y x y
as x y
w u i v
above
where and tend to 0 as in the -plane.
(3)
1 2 ( , ) (0,0)x y z
assuming that the Cauchy-Riemann equations are satisfied at , we can
replace in (3), and divide thru by
to get
0 0( , )x y,y x y xu by v and v by u z
2 2
0 0 0 0 1 2
2 2
2 2
( , ) ( , ) (4)
1
x x
x ywu x y iv x y i
z z
but x y z
x yso
z
also tends to 0, as
The last term in(4) tends to 0 as
1 2i , 0,0x y
0z
0 0 0 0 0 The limit of exists, and '( ) ( , ) ( , ).x x
wf z u x y iv x y
z
第 40頁
Ex 1. ( ) (cos sin )
( , ) cos
( , ) sin
,
'( )
'( ) (cos sin )
x
x
x
x y y x
xx x
f z e y i y
u x y e y
v x y e y
u v u v
f z
f z u iv e y i y
everywhere, and continuous.
exists everywhere, and
Ex 2.2
2 2
( )
( , ) 2 2
( , ) 0 0 0
'(0) 0 0
x y
x y
f z z
u x y x y u x u y
v x y v v
f i
has a derivative at z=0.
can not have derivative at any nonzero point.
第 41頁
19. Polar Coordinates
cos sin
( 0)i
x r y r
z x iy re z
Suppose that exist everywhere in some neighborhood of a
given non-zero point z0 and are continuous at that point.
also have these properties, and ( by chain rule )
, , ,x y x yu u v v
, , ,r ru u v v
cos sin (2)
sin cosr x y
x y
u u x u y
r x r y r
u u x u y
x y
u u u
u u r u r
Similarly,cos sin (3)
sin cosr x y
x y
v v v
v v r v r
第 42頁
If ,
cos sin (5)
sin cos
x y y x
r y x
y x
u v u v
v u u
v u r u r
from (2) (5),
Thm. p53…
0
1at (6)
1
r
r
u v zr
u vr
第 43頁
2
cos sin
sin cos sin sin
cos sin
r y x
r y x
r r x
u v v
u v v
v u v
2
cos sin
cos cos sin cos
r x y
r x y
v v v
v v v
0'( ) cos sin cos sin
(cos sin )( )
( ) (7)
r r r r
r r
ir r
f z u v i v u
i u iv
e u iv
0
2
'( )
?
cos sin
cos cos sin cos
x x
r x y
r x y
f z u iv
u u u
u u u
2
cos sin
cos sin
sin cos sin sin
r x y
y x
r y x
v v v
u u
v u u
cos sinr r xu v u
第 44頁
1 1,
'
r ru v u vr r
f
at any non-zero point iz re
exists
2 2
22 2 2
1' ( cos sin )
1 1 1( )
i
i i i
if e
r r
e e er r z
2 2
1 1( )
1 1( , ) cos ( , ) sin
1 1cos sin
1 1sin cos
i
r r
f zz re
u r v rr r
u vr r
u vr r
Ex : Consider
第 45頁
A function f of the complex variable z is analytic in an open set if it has a derivative at each point in that set.
f is analytic at a point z0 if it is analytic in a neighborhood of z0.
20. Analytic Functions
Note:
• is analytic at each non-zero point in the finite plane
• is not analytic at any point since its derivative exists only at z = 0 and
not throughout any neighborhood.
- An entire function is a function that is analytic at each point in the entire finite
plane. Ex: every polynomial.
- If a function f fails to be analytic at a point z0 but is analytic at some point in
every neighborhood of z0 , then z0 is called a singular point, or singularity, of f .
2
1( )
( )
f zz
f z z
第 46頁
Ex: • z=0 is a singular point of
• has no singular point since it is no where analytic.
1( )f z
z
2( )f z z
Sufficient conditions for analyticity
• continuity of f throughout D.
• satisfication of Cauchy-Riemann equation.
• Sum, Product of analytic functions is/are analytic.
• Quotient of analytic functions is/are analytic . if denominator 0
A composition of two analytic function is analytic
( ) ' ( ) '( )d
g f z g f z f zdz
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Thm : If everywhere in a domain D, then must be constant thr
oughout D.
pf : write
'( ) 0f z ( )f z
( ) ( , ) ( , )
'( ) 0
0by cauchy-Riemann
0
0
x x
y y
x y x y
f z u x y iv x y
Assume f z
u iv
v iu
u u v v
in D
at each point in D.
,x yu u
are x and y components of vector grad u.
grad u is always the zero vector.
( , )
( , )
( )
u x y a
similarly v x y b
f z a bi
u is constant along any line segment lying entirely in D.
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21. Reflection Principle
predicting when the reflection of f (z) in the real axis corresponds to the
reflection of z. ( )f z
( )f z
Thm: f analytic in domain D which contains a segment of the x axis and is symmetric to that axis.
Then for each point z in the domain iff f (x) is real for each point x on the segment.
( ) ( )f z f z
pf: “ ” f (x) real on the segment
Let ( ) ( )F z f z
( ) ( , ) ( , ), ( ) ( , ) ( , )
(z) ( , ) ( , ) (3)
( , ) ( , ) ( , ) (4)
( , ) ( , ) ( , )
f z u x y iv x y F z U x y iV x y
f u x y iv x y
U x y u x y u x t where t y
V x y v x y v x t
write
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Now, since f (x+i t) is an analytic function of x + i t. , (5)x t t xu v u v
From (4),
x x
y t t
U u
dtV v v
dy
From (5), x yU V
Similarly, y t x x
y x
dtU u ut V v
dy
U V
From (5),
since , continuous
F(z) is analytic in D.
,x y y xU V U V
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Since f (x) is real on the segment of the real axis lying in D,
on the segment
,0 0v x
( ) ( ,0) ( ,0)
( ,0) ( ,0) ( ,0)
( ) ( )
F x U x iV x
u x iv x u x
F z f z
This is at each point z = x on the segment. (6)From Chap 6 (sec.58)A function f that is analytic in D is uniquely determined by its value along any line segment lying in D. (6) holds throughout D.
( ) ( ) ( ) ( ) ( ) (7)F z f z f z or f z f z
“ ” ( ) ( )
(3) ( ) ( , ) ( , )
f z f z
from f z u x y iv x y
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expand (7):
for (x,0) on real axis
( , ) ( , ) ( , ) ( , )u x y iv x y u x y iv x y
( ,0) ( ,0) ( ,0) ( ,0)
( ,0) 0
( )
u x iv x u x iv x
v x
f x
is real on the segment of real axis lying in D.
Ex:
22
2
1 1
1,
z z
z z
x x
for all z.
since are real when x is real.
do not have reflection property since are not real when x is real.
2
,z i
iz
2
x i
ix
第 52頁
22. Haronic Functions
A real-valued function H of two real variables x and y is said to be harmonic in a given domain of the xy plane if, throughput that domain, it has continuous partial derivatives of the first and second order and satisfies the partial differential equation
( , ) ( , ) 0xx yyH x y H x y
known as Laplace's equation.
Applications: Temperatures T(x,y) in thin plate.
Electrostatic potential in the interior of a region of 3-D space.
Ex 1. is harmonic in any domain of the xy plane.( , ) sinyT x y e x
sin
sin
yxx
yyy
T e x
T e x
0xx yyT T
Thm 1. If a function is analytic in a domain D, then its component functions u and v are harmonic in D.
( ) ( , ) ( , )f z u x y iv x y
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Pf: Assume f analytic in D. (then its real and imaginary components have
continuous partial derivatives of all orders in D)
“proved in chap 4”
,
,:
,:
,
0 0
x y y x
xx yx yx xxx
xy yy yy xyy
yx xy xy yx
xx yy yy xx
then u v u v
u v u v
u v u v
u u v v
u u v v
the continuity of partial derivatives of u and v ensures this (theorem in calculus)
Ex 2. ( ) sin cos
( , ) sin
y y
y
f z e x ie x
T x y e x
is entire.
in Ex 1. must be harmonic.Hence
cos sin
sin cos
y yx y
y yx y
u e x u e x
v e x v e x
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is harmonic.
• If u , v are harmonic in a domain D, and their first-order partial derivatives satisfy Cauchy-Riemann equation throughout D, v is said to be harmonic conjugate of u. (u is not necessary harmonic conjugate of v )
• Thm 2( ) ( , ) ( , ) analyic ifff z u x y iv x y � v is a harmonic conjugate of u.
Ex 4: and are real & imag. parts of 2 2( , )u x y x y ( , ) 2v x y xy 2( )f z z
v is a harmonic conjugate of .
But is not analytic.2 2( ) 2 ( )
2 2
2 2
x y
x y
g z xy i x y
u y u x
v x v y
u
2 2Re ( ) ( ) ( )sin 2 cosyf z g z e x y x xy x
Ex 3. 2 2 2 2( ) ( ) 2g z z x iy x y i xy is entire.
so is f (z)g(z). ( f (z) in Ex 2 )
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• It can be shown that [Ex 11(b).] if two functions u and v are to be harmonic conjugates of each other, then both u and v must be constant functions.
• In chap 9, shall show that a function u which is harmonic in a domain of certain type always has a harmonic conjugate.
─ Thus, in such domains, every harmonic function is the real part of an analytic function.
─ A harmonic conjugate, when it exists, is unique except for an additive constant.
• If v is a harmonic conjugate of u in a domain D, then -u is a harmonic
conjugate of v in D.
( ) analytic
( ) ( , ) analytic
f z u iv
if z v iu x y
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2 2 2
2
3
2 3
3 '( ) 3 3
'( ) 3
( )
( , ) 3 is a harmonic conjugate of .
y x y x
x x
x x c
v x y xy x c u
3 2
2
( , ) 3
6 6
6
since
6
3 ( )
xx yy
x
x y
y
x y
u x y y x y
u u
u xy
u v
v xy
v xy x
v u
harmonic
Ex 5. To obtain a harmonic conjugate of a given harmonic function