2015 eup 222 notes project finance lecture 3

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EUP 222 ENGINEER IN SOCIETY PROJECT FINANCE Understand the financial concepts to appraise a project efficiently and make decisions effectively. Dr. Sharifah Akmam Syed Zakaria, PPKA . email: [email protected]

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  • EUP 222 ENGINEER

    IN SOCIETY

    PROJECT FINANCEUnderstand the financial concepts to appraise a project

    efficiently and make decisions effectively.

    Dr. Sharifah Akmam Syed Zakaria, PPKA . email: [email protected]

  • Outline

    Lecture Objective & Context

    Project Financing OwnerProject Contractor

    Financial Evaluation

  • Project Financing Investment is paid back from the project profit rather than the general assets or

    creditworthiness of the project owners

    For larger projects due to fixed cost to establish Small projects not much benefit

    Investment in project through special purpose corporations Often joint venture between several parties

    Need capacity for independent operation Benefits

    Off balance sheet (liabilities do not belong to parent) Limits risk External investors: reduced agency cost (direct investment in project)

    Drawback Tensions among stakeholders

  • OutlineLecture Objective & Context

    Project Financing Owner ProjectContractor

    Financial Evaluation

  • Contractor Financing

    Owner keeps an eye out for Front-end loaded bids (discounting)

    Unbalanced bids

    Contractors frequently borrow from Banks (Need to demonstrate low risk)

    Interaction with owners Some owners may assist in funding

    Help secure lower-priced loan for contractor

    Sometimes assist owners in funding! Big construction company, small municipality

  • PART 2: FINANCIAL

    EVALUATION

    PART 1 : PROJECT

    FINANCING

    Todays

    Focus

    In the context

    of cleaner

    production

    and

    sustainability

  • Develop or Not Develop?

    Is any individual project worthwhile?

    Given a list of feasible projects, which one is the best?

    How does each project rank compared to the others on the list?

  • Project Evaluation Example:

    Project A

    Construction=3 years

    Cost = RM 1M/year

    Sale Value= RM 4M

    Total Cost?

    Profit?

    Project B

    Construction=6 years

    Cost=RM 1M/year

    Sale Value=RM 8.5M

    Total Cost?

    Profit?

  • Quantitative Method:

    Profitability

    Create value for the company

  • OutlineLecture Objective & Context

    Project Financing Owner Project Contractor

    Financial Evaluation Project Income Inflation Operating Costs Time value of money Present value Rates Interest NPV Return on Capital Employed (Accounting Rate of Return) Payback period

  • Profit: TOTAL RM

    REVENUES 5,500,000.00

    COSTS 4,600,000.00

    Project management 400,000.00

    Engineering 800,000.00

    Material & transport 2,200,000.00

    Construction/commissioni

    ng

    1,300,000.00

    Contingencies 200,000.00

    GROSS MARGIN 900,000.00

    Time factor?

  • Quantitative Method: Profitability

    Create value for the company

    Opportunity Cost

    Time Value of Money

    A ringgit today is worth more than a dollar tomorrow

    Investment relative to best-case scenario

    E.g. Project A - 8% profit, Project B -10% profit

  • Case Study: Mbox by ECOLEX

    A small electronic firm, ECOLEX intends to produce a magnetic

    heating lunch box (Mbox)

    A Cleaner Production (CP) assessment at ECOLEX identified

    some potentially profitable

    investment projects that also has

    environmental benefits.

  • Financial Information: A

    Initial investment = RM 4 million

    Selling price (current price terms)

    = RM 40 per unit

    Variable operating costs (current price terms) = RM 16 per unit

    Expected selling price inflation

    = 6 % per year

    Fixed operating costs (current price terms) = RM340,000 per year

    Expected operating cost inflation = 8 % per year

  • Financial Information: B

    Demand forecast for Mbox by ECOLEX marketing team:

    Year 1 2 3 4

    Demand (units) 120,000 140,000 240,000 90,000

    No terminal value or machinery scrap value.

    A nominal (money) discount rate = 10% per year

    A target return on capital employed = 30% per year.

    Ignore taxation.

  • Financial Information: C

    Given discount rates :

    Year 0 1 2 3 4

    Discount at 10% 1.000 0.909 0.826 0.751 0.683

    Discount at 20% 1.000 0.833 0.694 0.579 0.482

  • Year 1 2 3 4

    RM RM RM RM

    Inflated selling

    price

    (RM/unit)

    RM 40 +

    .06 (40)

    42.40

    RM 42.40 +

    .06(42.40)

    44.94

    RM 44.94 +

    .06(44.94)

    47.64

    RM 47.64 +

    .06(47.64)

    50.50

    Demand(units/year) X 120,000 X 140,000 X 240,000 X 90,000

    Income(RM/year)

    5,088,000 6,291,600 11,433,600 4,545,000

    Project Income: Selling price (current price terms)

    = RM 40 per unitExpected selling price inflation

    = 6 % per year

  • OutlineLecture Objective & Context

    Project Financing Owner Project Contractor

    Financial Evaluation Project Income Inflation Operating Costs Time value of money Present value Rates Interest NPV Return on Capital Employed (Accounting Rate of Return) Payback period

  • Inflation & DeflationInflation means that the prices of goods and services increase over time

    either undetectably or in leaps and bounds.

    Inflation effects need to be included in investment because cost and benefits are measured in money and paid in current ringgit, dollars or

    pounds.

    An inflationary trend makes future ringgit have less purchasing power than present ringgit.

    Deflation means the opposite of inflation. Prices of goods & services decrease as time passes.

  • OutlineLecture Objective & Context

    Project Financing Owner Project Contractor

    Financial Evaluation Project Income Inflation Operating Costs Time value of money Present value Rates Interest NPV Return on Capital Employed (Accounting Rate of Return) Payback period

  • Project Evaluation Example: Which one is better?

    Project A

    Construction=3 years

    Cost = RM 1M/year

    Sale Value = RM 4M

    Total Cost?

    Profit?

    Project B

    Construction=6 years

    Cost = RM 1M/year

    Sale Value = RM 8.5M

    Total Cost?

    Profit?

  • Drawing out the examples:

    Project A

    Project B

    RM 1M

    RM 4M

    RM 1M

    1

    RM 8.5M

    6

    RM 1M MR 1M RM1M

    RM 1M

    RM 1MRM 1M

    Assume 10% discount rate

    0 32

    RM 1M

    0 1

  • Variable Costs:

    Variable costs are corporate expenses that vary in direct proportion to the quantity of output.

    Variable costs are those costs that vary depending on a company's production volume; they rise as production increases and fall as production decreases.

    Variable costs can include direct material costs or direct labour costs necessary to complete a certain project.

    Fixed costs are expenses that have to be paid by a company, independent of any business activity.

    Fixed costs are costs that are independent of output. These remain constant throughout the relevant range.

    Fixed costs are not relevant to output decisions.

    Fixed costs often include rent, buildings, machinery, etc.

    Fixed Costs:

  • Financial Information: A

    Initial investment = RM 4 million

    Selling price (current price terms)

    = RM 40 per unit

    Variable operating costs (current price terms) = RM 16 per unit

    Expected selling price inflation

    = 6 % per year

    Fixed operating costs (current price terms) = RM340,000 per year

    Expected operating cost inflation = 8 % per year

  • Financial Information: B

    Demand forecast for Mbox by ECOLEX marketing team:

    Year 1 2 3 4

    Demand (units) 120,000 140,000 240,000 90,000

    No terminal value or machinery scrap value.

    A nominal (money) discount rate = 10% per year

    A target return on capital employed = 30% per year.

    Ignore taxation.

  • 1 2 3 4

    RM RM RM RM

    Inflated variable cost

    (RM/unit)

    RM 16 +

    .08 (16)

    17.28

    RM 17.28 +

    .08 (17.28)

    18.66

    RM 18.66 +

    .08 (18.66)

    20.15

    RM 20.15 +

    .08 (20.15)

    21.76

    Demand (units/year) X 120,000 X 140,000 X 240,000 X 90,000

    Total Variable costs (RM/year) 2,073,600 2,612,400 4,836,000 1,958,400

    (+) Inflated Fixed

    Costs(RM/year)

    RM 340,000 + .08

    (340,000)

    367,200

    RM 367,200

    + .08 (367,200)

    396,576

    RM 396,576 +

    .08(396,576)

    428,302

    RM 428,302 + .08

    (428,302)

    462,566

    Total Operating costs (RM/year) 2,440,800 3,008,976 5,264,302 2,420,966

    Operating Costs: Variable operating costs

    (current price terms)

    = RM 16 per unit

    Fixed operating costs

    (current price terms)

    = RM340,000 per year

    Expected operating

    cost inflation

    = 8 % per year

  • OutlineLecture Objective & Context

    Project Financing Owner Project Contractor

    Financial Evaluation Project Income Inflation Operating Costs Time value of money Present value Rates Interest NPV Return on Capital Employed (Accounting Rate of Return) Payback period

  • Time Value of Money:

    If we assume That money can always be invested in the bank (or some other reliable

    source) now to gain a return with interest later.

    That as rational actors, we never make an investment which we know to offer less money than we could get in the bank.

    Then Money in the present can be thought as of equal worth to a larger

    amount of money in the future.

    Money in the future can be thought of as having an equal worth to a lesser present value of money.

  • Time Value of Money: Revisit If we assume

    That money can always be invested in the bank (or some other reliable source) now to gain a return with interest later

    That as rational actors, we never make an investment which we know to offer less money than we could get in the bank

    Then Money in the present can be thought as of equal worth to a larger amount of

    money in the future

    Money in the future can be thought of as having an equal worth to a lesser present value of money

  • OutlineLecture Objective & Context

    Project Financing Owner Project Contractor

    Financial Evaluation Project Income Inflation Operating Costs Time value of money Present value Rates Interest NPV Return on Capital Employed (Accounting Rate of Return) Payback period

  • Basic Compounding:

    Suppose we invest RM x in a bank offering interest rate, i

    If interest is compounded annually, asset will be worth

    $x(1+i) after 1 year

    $x(1+i)2 after 2 years

    $x(1+i)3 after 3 years .

    $x(1+i)n after n years

    RM x

    0 1 RM x(1+i) 2 RM x(1+i)2 n RM x(1+i)n

  • Present Value (Revenue)

    How is it that some future revenue, r at time, t has a present value?

    Answer: Given that we are sure that we will be gaining revenue, r at time t, we can take and spend an immediate loan from the bank

    We choose size of this loan l so that at time t, the total size of the loan (including accrued interest) is r

    The loan, l is the present value of r

    l = PV(r)

  • Future to Present Revenue:

    x

    t

    -x

    tPV(x)

    0 Ill pay this back to the bank later

    I can borrow this from the bank now

    tPV(x)

    If I know this is coming

    The net result is that I can convert a sure x at time tinto a (smaller) PV(x) now!

  • Present Value (Cost) How is it that some future cost c at time t has a present value?

    Answer: Given that we are sure that we will bear cost c at time t, we immediately deposit a sum of money x into the bank yielding a known

    return

    We choose size of deposit x so that at time t, the total size of the investment (including accrued interest) is c

    We can then pay off c at time t by retrieving this money from the bank

    The size of the deposit (immediate cost) x is the present value of c.

  • Future to Present Cost

    x

    tPV(x)

    I retrieve this back from the bank later

    I can deposit this in the bank now

    t

    The net result is that I can convert a sure cost x at time tinto a (smaller) cost of PV(x) now!

    PV(x)

    -x

    t0

    If I know this cost is coming

  • Summary: Present Value

    Because we can flexibly switch from one such value to another without cost, we can view these values as equivalent

    Given a reliable source offering annual return i (i.e., interest) we can shift without additional costs between cash v at time 0 and v(1+i)t at time t

  • OutlineLecture Objective & Context

    Project Financing Owner Project Contractor

    Financial Evaluation Project Income Inflation Operating Costs Time value of money Present value Rates Interest NPV Return on Capital Employed (Accounting Rate of Return) Payback period

  • Rates

    Difference between PV (v)

    and FV ( =v(1+i)t ) depends

    on interest, i and time, t.

  • Rates

    Difference between PV (v) and FV ( =v(1+i)t ) depends on i and t.

    Interest Rate

    Contractual arrangement between a borrower and a lender

    Discount Rate (real change in value to a person or group)

    Worth of Money + Risk

    Discount Rate > Interest Rate

    Minimum Attractive Rate of Return (MARR)

    Minimum discount rate accepted by the market corresponding to the risks of a project (i.e., minimum standard of desirability)

  • OutlineLecture Objective & Context

    Project Financing Owner Project Contractor

    Financial Evaluation Project Income Inflation Operating Costs Time value of money Present value Rates Interest NPV Return on Capital Employed (Accounting Rate of Return) Payback period

  • Interest Formulas

    i = Effective interest rate per interest period (discount rate or MARR)

    n = Number of compounding periods

    PV = Present Value

    FV = Future Value

    A = Annuity (i.e., a series of payments of set size) at end-of-period

  • Interest Formulas: Payment - Example

    If you wish to have RM100,000 at the end of five years in an account that pays 12 percent annually, how much would you need to deposit now?

  • Interest Formulas: Payment - Example

    If you wish to have RM 100,000 at the end of five years in an account that pays 12 percent annually, how much would you need to deposit now?

    (P/F, 0.12, 5) or (F/P, 0.12, 5)?

    P=?

    n0

    F=RM 100,000

  • Interest Formulas: Payment - Example

    If you wish to have RM 100,000 at the end of five years in an account that pays 12 percent annually, how much would you need to deposit now?

    P = F(P/F, 0.12, 5)

    P = 100,000 (P/F, 0.12, 5)

    P = 100,000 0.5674 = RM 56,740