a tabu search algorithm for the min max k-chinese postman problem

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A tabu search algorithm for the min-max k-Chinese postman problem Dino Ahr, Gerhard Reinelt* Computers & Operations Research 33 (2006) 3403–3422 報報報 : 報報報

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Page 1: A tabu search algorithm for the min max k-chinese postman problem

A tabu search algorithm for the min-max k-Chinese postman problem

Dino Ahr, Gerhard Reinelt*Computers & Operations Research 33

(2006) 3403–3422報告人 : 陳政謙

Page 2: A tabu search algorithm for the min max k-chinese postman problem

Outline

• The min-max k-Chinese postman problem• Merging and separating edges• Improving tours• The tabu search algorithm• Computational results

Page 3: A tabu search algorithm for the min max k-chinese postman problem

k-Chinese postman tour• For a given graph G=(V, E), k-Chinese postman tour is k closed

walks(tours) which each tour starts and ends at the depot node and each edge e E is covered by at least one tour.∈

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Page 4: A tabu search algorithm for the min max k-chinese postman problem

k-Chinese postman tour• For a given graph G=(V, E), k-Chinese postman tour is k closed

walks(tours) which each tour starts and ends at the depot node and each edge e E is covered by at least one tour.∈

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depot node = v1

Page 5: A tabu search algorithm for the min max k-chinese postman problem

k-Chinese postman tour• For a given graph G=(V, E), k-Chinese postman tour is k closed

walks(tours) which each tour starts and ends at the depot node and each edge e E is covered by at least one tour.∈

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depot node = v1

k = 2

Page 6: A tabu search algorithm for the min max k-chinese postman problem

k-Chinese postman tour• For a given graph G=(V, E), k-Chinese postman tour is k closed

walks(tours) which each tour starts and ends at the depot node and each edge e E is covered by at least one tour.∈

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depot node = v1

k = 2

Page 7: A tabu search algorithm for the min max k-chinese postman problem

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k-Chinese postman tour• For a given graph G=(V, E), k-Chinese postman tour is k closed

walks(tours) which each tour starts and ends at the depot node and each edge e E is covered by at least one tour.∈

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depot node = v1

k = 2

Page 8: A tabu search algorithm for the min max k-chinese postman problem

The min-max k-Chinese postman problem

• The aim for the min-max k-Chinese postman problem (MM k-CPP) is to minimize the length of the longest tour of k-Chinese postman tour.

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Page 9: A tabu search algorithm for the min max k-chinese postman problem

The min-max k-Chinese postman problem

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C1:

• The aim for the min-max k-Chinese postman problem (MM k-CPP) is to minimize the length of the longest tour of k-Chinese postman tour.

Page 10: A tabu search algorithm for the min max k-chinese postman problem

The min-max k-Chinese postman problem

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C2:

C1:

• The aim for the min-max k-Chinese postman problem (MM k-CPP) is to minimize the length of the longest tour of k-Chinese postman tour.

Page 11: A tabu search algorithm for the min max k-chinese postman problem

The min-max k-Chinese postman problem

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w(C1) = 107

C2:

C1:

• The aim for the min-max k-Chinese postman problem (MM k-CPP) is to minimize the length of the longest tour of k-Chinese postman tour.

Page 12: A tabu search algorithm for the min max k-chinese postman problem

The min-max k-Chinese postman problem

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w(C2) = 78

w(C1) = 107

C2:

C1:

• The aim for the min-max k-Chinese postman problem (MM k-CPP) is to minimize the length of the longest tour of k-Chinese postman tour.

Page 13: A tabu search algorithm for the min max k-chinese postman problem

The min-max k-Chinese postman problem

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w(C2) = 78

w(C1) = 107

C2:

C1:

The maximum weight is 107

• The aim for the min-max k-Chinese postman problem (MM k-CPP) is to minimize the length of the longest tour of k-Chinese postman tour.

Page 14: A tabu search algorithm for the min max k-chinese postman problem

The min-max k-Chinese postman problem

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w(C2) = 94

w(C1) = 93

C2:

C1:

The maximum weight is 94

• The aim for the min-max k-Chinese postman problem (MM k-CPP) is to minimize the length of the longest tour of k-Chinese postman tour.

Page 15: A tabu search algorithm for the min max k-chinese postman problem

Merging and separating edges

• Two Algorithms– SeparateWalkFromTour– MergeWalkWithTour

Page 16: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

• Input: The tour Ci and the walk H to be separated.

• Output: The tour represents a feasible tour formed from the remaining of edges of Ci after removing edges from H and possibly additional edges needed to re-establish feasibility.

Page 17: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour• Step1: Let u and v be the endnodes of H (u = v is possible).

Check whether the depot node v1 is an internal node of H.

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C1: C2:

Page 18: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2:

u = v4

• Step1: Let u and v be the endnodes of H (u = v is possible). Check whether the depot node v1 is an internal node of H.

Page 19: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2: H:

u = v4

• Step1: Let u and v be the endnodes of H (u = v is possible). Check whether the depot node v1 is an internal node of H.

Page 20: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2: H:

u = v4

• Step1: Let u and v be the endnodes of H (u = v is possible). Check whether the depot node v1 is an internal node of H.

Page 21: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2:

v = v8

H:

u = v4

• Step1: Let u and v be the endnodes of H (u = v is possible). Check whether the depot node v1 is an internal node of H.

Page 22: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2:

v1 is not an internal node of H.

H:

u = v4

v = v8

• Step1: Let u and v be the endnodes of H (u = v is possible). Check whether the depot node v1 is an internal node of H.

Page 23: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2: H:

• Step2: Remove all edges of H from Ci to yield Ĉi. Check whether the depot node v1 is contained in Ĉi.

u = v4

v = v8

Page 24: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2: H:

u = v4

v = v8

• Step2: Remove all edges of H from Ci to yield Ĉi. Check whether the depot node v1 is contained in Ĉi.

Page 25: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C1: C2: H:

u = v4

v = v8

• Step2: Remove all edges of H from Ci to yield Ĉi. Check whether the depot node v1 is contained in Ĉi.

Page 26: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C2: H:Ĉ1:

u = v4

v = v8

• Step2: Remove all edges of H from Ci to yield Ĉi. Check whether the depot node v1 is contained in Ĉi.

Page 27: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C2: H:Ĉ1:

v1 is contained in Ĉ1.

u = v4

v = v8

• Step2: Remove all edges of H from Ci to yield Ĉi. Check whether the depot node v1 is contained in Ĉi.

Page 28: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C2: H:Ĉ1:

• Step3: We have to consider two cases when we connect u and v:– If v1 is an internal node of H and v1 is not contained in Ĉi , then we let

evolves from Ĉi by connecting u and v with SP(u, v1), SP(v1, v).– Otherwise we let evolves from Ĉi by connecting u and v with SP(u,

v). u = v4

v = v8

Page 29: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: SeparateWalkFromTour

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C2: H:Ĉ1:

• Step3: We have to consider two cases when we connect u and v:– If v1 is an internal node of H and v1 is not contained in Ĉi , then we let

evolves from Ĉi by connecting u and v with SP(u, v1), SP(v1, v).– Otherwise we let evolves from Ĉi by connecting u and v with SP(u,

v). u = v4

v = v8

Page 30: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

• Input: The tour Ci and the walk H to be merged.

• Output: The tour represents a feasible tour formed from edges contained in Ci and H and possibly additional edges.

Page 31: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour• Step1: Remove those edges from the beginning and the end

of H which also occur in Ci to yield the result Ĥ.

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C1: C2:

Page 32: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2: H:

• Step1: Remove those edges from the beginning and the end of H which also occur in Ci to yield the result Ĥ.

Page 33: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2: Ĥ:

• Step1: Remove those edges from the beginning and the end of H which also occur in Ci to yield the result Ĥ.

Page 34: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2:

• Step2: Let u and v be the endnodes of Ĥ. Determine the node t on Ci which minimizes w(SP(u, t)) + w(SP(v, t)).

Ĥ:

Page 35: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2: Ĥ:

u = v4

• Step2: Let u and v be the endnodes of Ĥ. Determine the node t on Ci which minimizes w(SP(u, t)) + w(SP(v, t)).

Page 36: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2: Ĥ:

u = v4

v = v8

• Step2: Let u and v be the endnodes of Ĥ. Determine the node t on Ci which minimizes w(SP(u, t)) + w(SP(v, t)).

Page 37: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2: Ĥ:

u = v4

v = v8

t = v4

• Step2: Let u and v be the endnodes of Ĥ. Determine the node t on Ci which minimizes w(SP(u, t)) + w(SP(v, t)).

Page 38: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2: Ĥ:

u = v4

v = v8

t = v4

• Step3: The result evolves from splicing SP(t, u), Ĥ, SP(v, t) into Ci at node t.

Page 39: A tabu search algorithm for the min max k-chinese postman problem

• Step3: The result evolves from splicing SP(t, u), Ĥ, SP(v, t) into Ci at node t.

Algorithm: MergeWalkWithTour

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C1: C2: Ĥ:

u = v4

v = v8

t = v4

Page 40: A tabu search algorithm for the min max k-chinese postman problem

Algorithm: MergeWalkWithTour

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C1: C2: Ĥ:

u = v4

v = v8

t = v4

• Step3: The result evolves from splicing SP(t, u), Ĥ, SP(v, t) into Ci at node t.

Page 41: A tabu search algorithm for the min max k-chinese postman problem

Required edge and redundant edge• Øi(e) denote the frequency of e which occurs in Ci.

• Ø(e) = Øi(e)

• An edge e is called required for Ci if Øi(e) ≥ 1 and Ø(e) = Øi(e).

• An edge e is called redundant for Ci if Øi(e) ≥ 1 and Ø(e) > Øi(e).

C1: C2:

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Page 42: A tabu search algorithm for the min max k-chinese postman problem

Required edge and redundant edge• Øi(e) denote the frequency of e which occurs in Ci.

• Ø(e) = Øi(e)

• An edge e is called required for Ci if Øi(e) ≥ 1 and Ø(e) = Øi(e).

• An edge e is called redundant for Ci if Øi(e) ≥ 1 and Ø(e) > Øi(e).

(v1, v7) is a required edge for C1.

C1: C2:

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Page 43: A tabu search algorithm for the min max k-chinese postman problem

Required edge and redundant edge• Øi(e) denote the frequency of e which occurs in Ci.

• Ø(e) = Øi(e)

• An edge e is called required for Ci if Øi(e) ≥ 1 and Ø(e) = Øi(e).

• An edge e is called redundant for Ci if Øi(e) ≥ 1 and Ø(e) > Øi(e).

(v4, v6) is a redundant edge for C1.

C1: C2:

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Page 44: A tabu search algorithm for the min max k-chinese postman problem

Improving tours

• Three improvement procedures– RemoveReplicateEdgesKeepingParity– RemoveEvenRedundantEdges– ShortenRequiredEdgeConnections

Page 45: A tabu search algorithm for the min max k-chinese postman problem

RemoveReplicateEdgesKeepingParity

• For edge e which occurs n ≥ 3 times in Ci, we can remove n – 2 times (n – 1 times) e if n is even(odd).

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C1:

C2:

Page 46: A tabu search algorithm for the min max k-chinese postman problem

RemoveReplicateEdgesKeepingParity

• For edge e which occurs n ≥ 3 times in Ci, we can remove n – 2 times (n – 1 times) e if n is even(odd).

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C1:

C2:

Page 47: A tabu search algorithm for the min max k-chinese postman problem

RemoveReplicateEdgesKeepingParity

• For edge e which occurs n ≥ 3 times in Ci, we can remove n – 2 times (n – 1 times) e if n is even(odd).

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C1:

C2:

Page 48: A tabu search algorithm for the min max k-chinese postman problem

RemoveEvenRedundantEdges• If edge e is a redundant edge with even frequency, e will be

removed completely from Ci if the remaining of Ci remains connected and still contains the depot node.

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C1: C2:

Page 49: A tabu search algorithm for the min max k-chinese postman problem

RemoveEvenRedundantEdges• If edge e is a redundant edge with even frequency, e will be

removed completely from Ci if the remaining of Ci remains connected and still contains the depot node.

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C1: C2:

Page 50: A tabu search algorithm for the min max k-chinese postman problem

RemoveEvenRedundantEdges• If edge e is a redundant edge with even frequency, e will be

removed completely from Ci if the remaining of Ci remains connected and still contains the depot node.

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C1: C2:

Page 51: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

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C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 52: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

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P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 53: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

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P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 54: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

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vh = v1

P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 55: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 56: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 57: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 58: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 59: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 60: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 61: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 62: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 63: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 64: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 65: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

Q:P:C1: C2:

C1: {v1, v2, v3, v5, v6, v4, v6, v8, v7, v1, v3, v4, v7, v1}

Page 66: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v3

C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Q:P:

Page 67: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 68: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 69: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 70: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 71: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 72: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step1: Construct the longest possible walk P (while traversing

Ci) which consists of redundant edges. Let vh be the origin and vj be the terminus of walk P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 73: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 74: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 75: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 76: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 77: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 78: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 79: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 80: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 81: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 82: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 83: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnections• Step2: Traverse the tour Ci further on to build up walk Q until a redundant

edge (vl, vj) entering vj is found. If such a walk Q = {vj, ..., vl, vj} is found, reverse the orientation of Q in Ci and continue with step 1 starting again at vh

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 84: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnectionsStep3: Replace P by the shortest path SP(vh, vj) if w(SP(vh, vj)) <

w(P). Continue with step 1 with the edge following the last edge of P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 85: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnectionsStep3: Replace P by the shortest path SP(vh, vj) if w(SP(vh, vj)) <

w(P). Continue with step 1 with the edge following the last edge of P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 86: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnectionsStep3: Replace P by the shortest path SP(vh, vj) if w(SP(vh, vj)) <

w(P). Continue with step 1 with the edge following the last edge of P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 87: A tabu search algorithm for the min max k-chinese postman problem

ShortenRequiredEdgeConnectionsStep3: Replace P by the shortest path SP(vh, vj) if w(SP(vh, vj)) <

w(P). Continue with step 1 with the edge following the last edge of P.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

vh = v1

vj = v1

Q:P:C1: C2:

C1: {v1, v2, v3, v1, v7, v8, v6, v4, v6, v5, v3, v4, v7, v1}

Page 88: A tabu search algorithm for the min max k-chinese postman problem

What is Tabu search?

• Tabu search is created by Fred W. Glover in 1986.• Tabu search is used for optimization problem.• Neighborhood is a solution set which improves

the current solution.• If a potential solution has been previously visited

within a certain short-term period or if it has violated a rule, it is marked as "tabu" (forbidden) so that the algorithm does not consider that possibility repeatedly.

Page 89: A tabu search algorithm for the min max k-chinese postman problem

Neighborhoods

• Three Neighborhood structures– TwoEdgeExchange– RequiredEdgeWalkExchange– SingleRequiredEdgeExchange

Page 90: A tabu search algorithm for the min max k-chinese postman problem

The flow of exchange

The longest tour Ci another tour Cj

Page 91: A tabu search algorithm for the min max k-chinese postman problem

The flow of exchange

The longest tour Ci Walk H another tour Cj

Separate

Page 92: A tabu search algorithm for the min max k-chinese postman problem

The flow of exchange

The longest tour Ci Walk H

Apply improvement procedure

another tour Cj

Separate

Page 93: A tabu search algorithm for the min max k-chinese postman problem

The flow of exchange

The longest tour Ci Walk H

Apply improvement procedure

another tour Cj

Separate Merge

Page 94: A tabu search algorithm for the min max k-chinese postman problem

The flow of exchange

The longest tour Ci Walk H

Apply improvement procedure

another tour Cj

Apply improvement procedure

Separate Merge

Page 95: A tabu search algorithm for the min max k-chinese postman problem

TwoEdgeExchange• The TwoEdgeExchange neighborhood considers two

consecutive edges e and f in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 96: A tabu search algorithm for the min max k-chinese postman problem

TwoEdgeExchange• The TwoEdgeExchange neighborhood considers two

consecutive edges e and f in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 97: A tabu search algorithm for the min max k-chinese postman problem

TwoEdgeExchange• The TwoEdgeExchange neighborhood considers two

consecutive edges e and f in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 98: A tabu search algorithm for the min max k-chinese postman problem

RequiredEdgeWalkExchange• P is composed of redundant edges.• e is a required edge.• The RequiredEdgeWalkExchange neighborhood considers

walks H = {P1, e, P2} in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 99: A tabu search algorithm for the min max k-chinese postman problem

RequiredEdgeWalkExchange• P is composed of redundant edges.• e is a required edge.• The RequiredEdgeWalkExchange neighborhood considers

walks H = {P1, e, P2} in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 100: A tabu search algorithm for the min max k-chinese postman problem

RequiredEdgeWalkExchange• P is composed of redundant edges.• e is a required edge.• The RequiredEdgeWalkExchange neighborhood considers

walks H = {P1, e, P2} in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 101: A tabu search algorithm for the min max k-chinese postman problem

RequiredEdgeWalkExchange• P is composed of redundant edges.• e is a required edge.• The RequiredEdgeWalkExchange neighborhood considers

walks H = {P1, e, P2} in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 102: A tabu search algorithm for the min max k-chinese postman problem

RequiredEdgeWalkExchange• P is composed of redundant edges.• e is a required edge.• The RequiredEdgeWalkExchange neighborhood considers

walks H = {P1, e, P2} in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 103: A tabu search algorithm for the min max k-chinese postman problem

SingleRequiredEdgeExchange• The SingleRequiredEdgeExchange neighborhood

considers required edges e in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 104: A tabu search algorithm for the min max k-chinese postman problem

SingleRequiredEdgeExchange• The SingleRequiredEdgeExchange neighborhood

considers required edges e in the longest tour Ci.

7

1

1

v2

v1

v5

v3

v6

v4

v7

v8

13

38 8

2 2427

18

7

26

210

w(C2) = 94

w(C1) = 93

C2:

C1:

Page 105: A tabu search algorithm for the min max k-chinese postman problem

The tabu search algorithm

• Input: A k-postman tour, the maximum number of iterations without improvement called maxNOfItsWithoutImprovement, a tabu tenure called tabuTenure and a flag called improvementProcedure.

• Output: A possibly improved k-postman tour

Page 106: A tabu search algorithm for the min max k-chinese postman problem

The tabu search algorithmA k-postman tour

Page 107: A tabu search algorithm for the min max k-chinese postman problem

The tabu search algorithm

Compute a list of neighborhood solutions N in decreasing order of improvement value.

A k-postman tour

Page 108: A tabu search algorithm for the min max k-chinese postman problem

The tabu search algorithm

Compute a list of neighborhood solutions N in decreasing order of improvement value.

Select the first solution of the list as current solution if it is non-tabu or tabu but better than the best solution. (if no such solution then the algorithm terminates)

A k-postman tour

Page 109: A tabu search algorithm for the min max k-chinese postman problem

The tabu search algorithm

Compute a list of neighborhood solutions N in decreasing order of improvement value.

Select the first solution of the list as current solution if it is non-tabu or tabu but better than the best solution. (if no such solution then the algorithm terminates)

A k-postman tour

If current solution value < best solution value then best solution = current solution.

Page 110: A tabu search algorithm for the min max k-chinese postman problem

The tabu search algorithm

Compute a list of neighborhood solutions N in decreasing order of improvement value.

Select the first solution of the list as current solution if it is non-tabu or tabu but better than the best solution. (if no such solution then the algorithm terminates)

If the number of iterations < the max number of iterations then continue this algorithm, or the algorithm terminates.

A k-postman tour

If current solution value < best solution value then best solution = current solution.

Page 111: A tabu search algorithm for the min max k-chinese postman problem

Computational results

• Parameters– tabuTenure = 20– maxNOfIterationsWithoutImprovement = 100

Page 112: A tabu search algorithm for the min max k-chinese postman problem

Computational results

• Two improvement index– Let x be the value of the best heuristic solution from [2]– Let y be the best solution value obtained by the tabu

search algorithm for all possible configurations of neighborhood structures and improvement procedures.

– Let z be the best lower bound obtained by the lower bounds SPT-LB and CPP/k-LB presented in [2].

– Average impr.(%) = (x - y) * 100 / x– Average gap(%) = (y - z) * 100 / y

Page 113: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 114: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 115: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 116: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 117: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 118: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 119: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 120: A tabu search algorithm for the min max k-chinese postman problem

Computational results

Page 121: A tabu search algorithm for the min max k-chinese postman problem

References

Page 122: A tabu search algorithm for the min max k-chinese postman problem

References

Page 123: A tabu search algorithm for the min max k-chinese postman problem

References

Page 124: A tabu search algorithm for the min max k-chinese postman problem

References

Page 125: A tabu search algorithm for the min max k-chinese postman problem

References