jim smith jchs arc length, sectors, sections spi.3.2.bspi.3.2.l
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Jim Smith JCHSJim Smith JCHS
Arc Length, Sectors, SectionsArc Length, Sectors, Sections
spi.3.2.Bspi.3.2.Bspi.3.2.Lspi.3.2.L
77
C = 2C = 2ππrrC = 2C = 2ππ77C = 14C = 14ππ
99
A = A = ππr²r²A = A = ππ9²9²A = A = 8181ππ
AA
BB
The length of AB represents a The length of AB represents a fractional part of the circle’s fractional part of the circle’s
circumference. If the mAB Is 90°, circumference. If the mAB Is 90°, then the length of AB is 90/360then the length of AB is 90/360thth
(1/4(1/4thth) of the circumference.) of the circumference.
AA
BB66
Find the length of ABFind the length of AB
C = 2 C = 2 ππ r rC = 2 C = 2 ππ 6 6C = 12C = 12ππ
Length of AB = Length of AB = ¼¼·12·12ππ = =
33ππ
90/36090/360 = ¼ = ¼
AA
BB
60°60°
88
C = 2C = 2ππrrC = 16C = 16ππ
AB = 60/360 of AB = 60/360 of 1616ππAB = 1/6 · 16AB = 1/6 · 16ππAB = 1 · 16AB = 1 · 16ππ 6 16 1AB = 8AB = 8ππ 33
XX YY
ZZ
120°120°
Find the length of Find the length of XYZ XYZ
99
XYZ = 240 of XYZ = 240 of 1818ππ 360360XYZ = 2 · 18XYZ = 2 · 18ππ 3 13 1XYZ = 12XYZ = 12ππ
360°360°- 120° - 120° 240°240°
C = 2C = 2ππr C = 18r C = 18ππ
Sectors are a fractional Sectors are a fractional part of a circle’s areapart of a circle’s area
Find the shaded Find the shaded areaarea
88 A = A = ππr² A = 64r² A = 64ππ
Sector area Sector area ==¼ of 64¼ of 64ππ
6464π π = 16= 16ππ 44
90 of circle’s 90 of circle’s areaarea360360
60°60°
60 of circle’s area60 of circle’s area360360
1212Area = Area = ππr² A = 144r² A = 144ππ
Sector area =Sector area =
A = 1 of 144A = 1 of 144ππ 66144144ππ = 24 = 24ππ 66
SectionSectionssLet’s talk Let’s talk
pizzapizza
AREA OF SECTIONAREA OF SECTION = = AREA OF SECTOR – AREA OF SECTOR – AREA OF AREA OF TRIANGLETRIANGLE
¼ ¼ ππ r² - r² - ½ bh½ bh
Area of sectionArea of section = = area of sector – area of sector – area of area of triangletriangle ¼ ¼ ππ r² - r² - ½ bh½ bh
1010A OF = ½∙10∙10=A OF = ½∙10∙10= 5050
A OF SECTION = A OF SECTION =
2525ππ - 50 - 50A of circle = A of circle = 100100ππ
A OF = ¼ 100A OF = ¼ 100ππ == 2525ππ
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