mos 10 stress strain-sm

INTRODUCTIONINTRODUCTION

NameName : Mohamad Redhwan Abd Aziz: Mohamad Redhwan Abd AzizPostPost : Lecturer @ DEAN CENTER OF HND STUDIES: Lecturer @ DEAN CENTER OF HND STUDIESSubjectSubject : Solid Mechanics: Solid MechanicsCodeCode : BME 2033: BME 2033RoomRoom : CENTER OF HND STUDIES OFFICE: CENTER OF HND STUDIES OFFICEH/P No.H/P No. : 019-2579663: 019-2579663W/SITEW/SITE : : Http://tatiuc.edu.my/redhwanHttp://tatiuc.edu.my/redhwanemailemail : redhwan296@yahoo.com: redhwan296@yahoo.com

INTRODUCTION (Cont..)INTRODUCTION (Cont..)

Monday 11-1pm (L13/Mech lab) Monday 11-1pm (L13/Mech lab) TutorialTutorial LabLab

Tuesday 10-12pm (L9)Tuesday 10-12pm (L9) LectureLecture

INTRODUCTION (Cont..)INTRODUCTION (Cont..)

BME 2023 SOLID MECHANICSBME 2023 SOLID MECHANICS 3 CREDIT HOURS3 CREDIT HOURS

2 Hours for lecture2 Hours for lecture 2 hours for lab/tutorial2 hours for lab/tutorial

Assessment/marks distributionAssessment/marks distribution Quizzes/Assignments Quizzes/Assignments - 10%- 10% TestTest - 30%- 30% Lab reportLab report - 20%- 20% Final ExamFinal Exam - 40%- 40%

INTRODUCTION (Cont…)INTRODUCTION (Cont…)

ObjectiveObjective Understand different methods that used to Understand different methods that used to

analyse stress and strain in solid bodyanalyse stress and strain in solid body Apply various principles to solve problems in Apply various principles to solve problems in

solid mechanicssolid mechanics Analyse forces of solid body cause by Analyse forces of solid body cause by

external forceexternal force Analyse the result of solid mechanics Analyse the result of solid mechanics

experimentsexperiments

INTRODUCTION (Cont…)INTRODUCTION (Cont…) Learning OutcomeLearning Outcome

Apply the concepts of stress, strain, torsion and bending and Apply the concepts of stress, strain, torsion and bending and deflection of bar and beam in engineering fielddeflection of bar and beam in engineering field

Explain the stress, strain, torsion and bendingExplain the stress, strain, torsion and bending Calculate and determine the stress, strain and bending of solid Calculate and determine the stress, strain and bending of solid

body that subjected to external and internal loadbody that subjected to external and internal load Use solid mechanic apparatus and analyse the experiments Use solid mechanic apparatus and analyse the experiments

resultresult

Work in-group that relates the basicWork in-group that relates the basic theory with application of theory with application of solid mechanicssolid mechanics

TOPICSTOPICS Topic coverTopic cover

Stress and strainStress and strain• Introduction to stress and strain, stress strain diagramIntroduction to stress and strain, stress strain diagram• Elasticity and plasticity and Hooke’s lawElasticity and plasticity and Hooke’s law• Shear Stress and Shear strainShear Stress and Shear strain• Load and stress limitLoad and stress limit• Axial force and deflection of bodyAxial force and deflection of body

TorsionTorsion• Introduction, round bar torsion, non-uniform torsion.Introduction, round bar torsion, non-uniform torsion.• Relation between Young’s Modulus E, Relation between Young’s Modulus E, and G and G• Power transmission on round barPower transmission on round bar

TOPICS (Cont…)TOPICS (Cont…) Topic coverTopic cover

Shear Force and bending momentShear Force and bending moment• Introduction, types of beam and loadIntroduction, types of beam and load• Shear force and bending momentShear force and bending moment• Relation between load, shear force and bending momentRelation between load, shear force and bending moment

Bending StressBending Stress• Introduction, Simple bending theoryIntroduction, Simple bending theory• Area of 2Area of 2ndnd moment, parallel axis theorem moment, parallel axis theorem• Deflection of composite beamDeflection of composite beam

TOPICS (Cont…)TOPICS (Cont…) Topic coverTopic cover

Non Simetric BendingNon Simetric Bending• Introduction, non-simetric bendingIntroduction, non-simetric bending• Product of 2Product of 2ndnd moment area, determination of stress moment area, determination of stress

Shear Stress in beamShear Stress in beam• Introduction, Stream of shear forceIntroduction, Stream of shear force• Shear stress and shear strain in edge beamShear stress and shear strain in edge beam

Deflection of Beam Deflection of Beam • IntroductionIntroduction• Equation of elastic curve, slope equation and integral Equation of elastic curve, slope equation and integral

deflectiondeflection• Statically indeterminate Beams and shaftStatically indeterminate Beams and shaft

REFERENCESREFERENCES

1.1. James M. Gere (2006) “ Mechanics of Materials”. 6James M. Gere (2006) “ Mechanics of Materials”. 6thth Edition, Thompson Edition, Thompson

2.2. R.C. Hibbeler (2003) “ Mechanics of Materials”. 5R.C. Hibbeler (2003) “ Mechanics of Materials”. 5 thth Edition, Prentice Hall Edition, Prentice Hall

3.3. Raymond Parnes (2001), “Solid Mechanics in Engineering”. John Willey and Raymond Parnes (2001), “Solid Mechanics in Engineering”. John Willey and SonSon

Stress and strainStress and strainDIRECT STRESSDIRECT STRESS When a force is applied to an elastic body, the body deforms. The When a force is applied to an elastic body, the body deforms. The

way in which the body deforms depends upon the type of force way in which the body deforms depends upon the type of force applied to it.applied to it.

Compression force makes the body shorter.

A tensile force makes the body longer

A

F

Area

ForceStress

2/mN

Tensile and compressive forces are called DIRECT FORCESStress is the force per unit area upon which it acts.

….. Unit is Pascal (Pa) or

Note: Most of engineering fields used kPa, MPa, GPa.

( Simbol – Sigma)

L

xStrain

DIRECT STRAIN ,

In each case, a force F produces a deformation x. In engineering, we usually change this force into stress and the deformation into strain and we define these as follows:Strain is the deformation per unit of the original length.

The symbol

Strain has no unit’s since it is a ratio of length to length. Most engineering materials do not stretch very mush before they become damages, so strain values are very small figures. It is quite normal to change small numbers in to the exponent for 10-6( micro strain).

called EPSILON

MODULUS OF ELASTICITY (E)

•Elastic materials always spring back into shape when released. They also obey HOOKE’s LAW.

•This is the law of spring which states that deformation is directly proportional to the force. F/x = stiffness = kN/m

•The stiffness is different for the different material and different sizes of the material. We may eliminate the size by using stress and strain instead of force and deformation:

•If F and x is refer to the direct stress and strain , then

AF Lx L

A

x

F

Ax

FL hence and

E

Ax

FL

•The stiffness is now in terms of stress and strain only and this constant is called the MODULUS of ELASTICITY (E)

• A graph of stress against strain will be straight line with gradient of E. The units of E are the same as the unit of stress.

ULTIMATE TENSILE STRESS•If a material is stretched until it breaks, the tensile stress has reached the absolute limit and this stress level is called the ultimate tensile stress.

STRESS STRAIN DIAGRAM

STRESS STRAIN DIAGRAM

Elastic behaviourThe curve is straight line trough out most of the regionStress is proportional with strainMaterial to be linearly elasticProportional limit

The upper limit to linear lineThe material still respond elasticallyThe curve tend to bend and flatten out

Elastic limitUpon reaching this point, if load is remove, the specimen still return to original shape

STRESS STRAIN DIAGRAMYielding

A Slight increase in stress above the elastic limit will result in breakdown of the material and cause it to deform permanently.This behaviour is called yieldingThe stress that cause = YIELD STRESS@YIELD POINTPlastic deformationOnce yield point is reached, the specimen will elongate (Strain) without any increase in loadMaterial in this state = perfectly plastic

STRESS STRAIN DIAGRAM STRAIN HARDENING

When yielding has ended, further load applied, resulting in a curve that rises continuously

Become flat when reached ULTIMATE STRESS The rise in the curve = STRAIN HARDENING While specimen is elongating, its cross sectional will decrease The decrease is fairly uniform

NECKING At the ultimate stress, the cross sectional area begins its localised

region of specimen it is caused by slip planes formed within material Actual strain produced by shear strain As a result, “neck” tend to form Smaller area can only carry lesser load, hence curve donward Specimen break at FRACTURE STRESS

SHEAR STRESS •Shear force is a force applied sideways on the material (transversely loaded).

When a pair of shears cut a material

When a material is punched

When a beam has a transverse load

Shear stress is the force per unit area carrying the load. This means the cross sectional area of the material being cut, the beam and pin.

A

F and symbol is called Tau•Shear stress,

The sign convention for shear force and stress is based on how it shears the materials as shown below.

L

x

L

x

SHEAR STRAIN

The force causes the material to deform as shown. The shear strain is defined as the ratio of the distance deformed to the height

. Since this is a very small angle , we can say that :

( symbol called Gamma)

Shear strain

•If we conduct an experiment and measure x for various values of F, we would find that if the material is elastic, it behave like spring and so long as we do not damage the material by using too big force, the graph of F and x is straight line as shown.

MODULUS OF RIGIDITY (G)

The gradient of the graph is constant so tconsx

Ftan

and this is the spring stiffness of the block in N/m.

•If we divide F by area A and x by the height L, the relationship is still a constant and we get

tconAx

FL

x

Lx

A

F

L

xA

F

tan

A

F

Where

L

x

tconAx

FL

x

Lx

A

Ftan

then

•If we divide F by area A and x by the height L, the relationship is still a constant and we get

This constant will have a special value for each elastic material and is called the Modulus of Rigidity (G).

G

ULTIMATE SHEAR STRESS

If a material is sheared beyond a certain limit and it becomes permanently distorted and does not spring all the way back to its original shape, the elastic limit has been exceeded.

If the material stressed to the limit so that it parts into two, the ultimate limit has been reached.

The ultimate shear stress has symbol and this value is used to calculate the force needed by shears and punches.

DOUBLE SHEAR

Consider a pin joint with a support on both ends as shown. This is called CLEVIS and CLEVIS PIN By balance of force, the force in the two supports is F/2 eachThe area sheared is twice the cross section of the pinSo it takes twice as much force to break the pin as for a case of single shearDouble shear arrangements doubles the maximum force allowed in the pin

LOAD AND STRESS LIMIT

DESIGN CONSIDERATIONWill help engineers with their important task in Designing structural/machine that is SAFE and ECONOMICALLY perform for a specified function

DETERMINATION OF ULTIMATE STRENGTH An important element to be considered by a designer is how the material that has been selected will behave under a loadThis is determined by performing specific test (e.g. Tensile test)ULTIMATE FORCE (PU)= The largest force that may be applied to the specimen is reached, and the specimen either breaks or begins to carry less load ULTIMATE NORMAL STRESS

(U) = ULTIMATE FORCE(PU) /AREA

ALLOWABLE LOAD / ALLOWABLE STRESS

Max load that a structural member/machine component will be allowed to carry under normal conditions of utilisation is considerably smaller than the ultimate loadThis smaller load = Allowable load / Working load / Design loadOnly a fraction of ultimate load capacity of the member is utilised when allowable load is appliedThe remaining portion of the load-carrying capacity of the member is kept in reserve to assure its safe performanceThe ratio of the ultimate load/allowable load is used to define FACTOR OF SAFETY

FACTOR OF SAFETY = ULTIMATE LOAD/ALLOWABLE LOAD@FACTOR OF SAFETY = ULTIMATE STRESS/ALLOWABLE STRESS

SELECTION OF F.S.

1. Variations that may occur in the properties of the member under considerations

2. The number of loading that may be expected during the life of the structural/machine

3. The type of loading that are planned for in the design, or that may occur in the future

4. The type of failure that may occur5. Uncertainty due to the methods of analysis6. Deterioration that may occur in the future because of poor

maintenance / because of unpreventable natural causes7. The importance of a given member to the integrity of the whole

structure

WORKED EXAMPLE 8

0.6 m

SOLUTION

SOLUTION

SELF ASSESSMENT NO. 5

AXIAL FORCE & DEFLECTION OF BODY

Deformations of members under axial loadingIf the resulting axial stress does not exceed the proportional limit of the material, Hooke’s Law may be appliedThen deformation (x / ) can be written as

AE

FL

E

WORKED EXAMPLE 9

0.4 m

WORKED EXAMPLE 9

WORKED EXAMPLE 9

SELF ASSESSMENT NO. 6