PRVA STRANATehniko veleuilite u ZagrebuPolitehniki specijalistiki diplomski struni studijSpecijalizacija graditeljstvo

KOLEGIJ: INENJERSKE GRAEVINE

ZADATAK - REETKASTA KONSTRUKCIJAPredmetni nastavnik i suradnici: Prof.v.. Boris Baljkas, dipl.ing.gra.

Dr.sc. Krunoslav Pavkovi, dipl.ing.Dr. sc. Dean izmar, dipl. ing. gra.Izradio:Ime i prezime: Damir KovaJMBAG: 0246050943e-mail: damir.kovac@prongradbiro.hr

DRUGA STRANA Tehniko veleuilite u ZagrebuPolitehniki specijalistiki diplomski struni studij Specijalizacija graditeljstvo

Sadraj:1.Zadatak2.Dispozicijski nacrt konstrukcije u mjerilu 1:2003.Analiza djelovanja na konstrukciju, unutarnje sile i momente savijanja u pojedinim elementima konstrukicje

4.Dimenzioniranje svih elemenata konstrukcije te konceptualno rijeenje i dimenzioniranje spojeve5.Nacrt glavnog reetkastog nosaa u mjerilu 1:206.Radioniki nacrt glavnog reetkastog nosaa u mjerilu 1:207.Plan armature stupa u mjerilu 1:208.Karakteristini detalji u mjerilu 1:59.Iskaz materijala10.Tehniki opis

&"Swis721 Cn BT,Roman"&9KOLEGIJ: INENJERSKE GRAEVINE&"Swis721 Cn BT,Roman"&9IZRADIO: DAMIR KOVAJMBAG 0246050943&"Swis721 Cn BT,Roman"&9SADRAJ

PRILOG 3. i 4.Tehniko veleuilite u ZagrebuPolitehniki specijalistiki diplomski struni studij Specijalizacija graditeljstvo

3. ANALIZA DJELOVANJA NA KONSTRUKCIJU, UNUTARNJE SILE I MOMENTE SAVIJANJA U POJEDINIM ELEMENTIMA KONSTRUKCIJE

ANALIZA OPTEREENJA

Stalno optereenje -trapezni lim -4.30kg/m2

sve instalacije-10.00kg/m2

S =0.14kN/m2

Zidovi -trapezni lim -9.34kg/m2

sve instalacije-5.00kg/m2

S =0.14kN/m2

OPTEREENJE SNIJEGOMIme grada i zona :Delnice (700 m.n.m.) - IV snjena zona

koeficijent izloenosti; toplinski koeficijentCe=Ct=1.00sk =1.00kN/m2(karakteristino optereenje snijegom)

Koeficijent oblika optereenja snijegom kut nagiba krova0 15o=2okoeficijent oblika optereenja od snijega - dvostreni krovovi1=2=0.80 (tablica)Optereenjes = i x Ce x Ct x skIIIsI=0.80 x1.00 x1.00 x1.00 =0.80kN/m2s = 0,5 x i x Ce x Ct x skIsIII=0.50 x0.80 x1.00 x1.00 x1.00 =0.40kN/m2

III0.80kN/m2

I0.40kN/m2

OPTEREENJE VJETROM

koeficijent smjera; koeficijent godinjeg dobac dir = c season =1.00vrefb =20.00m/s (poredbena brzina vjetra za II zonu)vb=c dir x c season x vrefb (osnovna brzina (referentna) vjetra)vb=1.00 x1.00 x20.00 =20.00m/s

Osnovni tlak izazvan brzinama vjetra

qb = 1/2 x x vb2gustoa zrakaqb = 0.50 x1.25 x400.00 =250.00N/mm2 =0.25kN/m2Kategorije zemljita -III ktg

Koeficijenti izloenosti kao funkcija visine z iznad tla, za kategorije hrapavosti terenaz e = h =5.70

c e (h) =1.30III ktgTransverzalni smjer djelovanja vjetra; F = 0o

5.7e/104.56e/104.561.144.561.144.56e/42.85FHJIb39.65

G

w

e/42.85F

2.289.1212.105.700.4225413109133.950.07961935445.375.710.414.817502B5.2911.75129.13AC

0.00

23.5

h bkoeficijent trenja -trapezni lim 0.04= ctre= min (b,2h) =min (39.6511.40 ) - uzima se manja vrijednoste= 11.4

Vertikalne povrineh/d=0.24A=12.15m2 Cpe10 =-1.20B=50.06m2 Cpe10 =-0.80C=65.42m2 Cpe10 =-0.500.1xD=209.75m2 Cpe10 =0.70x= 0.000.750.01E=209.75m2 Cpe10 =-0.50x= 0.00

=qb x c e(z) x c peA=0.25 x1.30 x-1.20 =-0.39kN/m2B=0.25 x1.30 x-0.80 =-0.26kN/m2C=0.25 x1.30 x-0.50 =-0.16kN/m2D=0.25 x1.30 x0.70 =0.23kN/m2E=0.25 x1.30 x-0.50 =-0.16kN/m2

Djelovanje vjetra na krov (samo negativni utjecaji)=2o

F=3.25m2 Cpe1 =-2.500020G=38.70m2 Cpe10 =-1.200.2x020H=180.80m2 Cpe10 =-0.62x= 0.02101020I=180.80m2 Cpe10 =-0.30020J=45.20m2 Cpe10 =-0.300205=qb x c e(z) x c peF=0.25 x1.30 x-2.50 =-0.81kN/m2G=0.25 x1.30 x-1.20 =-0.39kN/m2H=0.25 x1.30 x-0.62 =-0.20kN/m2I=0.25 x1.30 x-0.30 =-0.10kN/m2J=0.25 x1.30 x-0.30 =-0.10kN/m2

0.39kN/m20.26kN/m20.16kN/m2

kN/m2FkN/m2

G

-0.230.16

F

0.16kN/m20.26kN/m20.39kN/m2

Presjek A-A0.20kN/m20.10kN/m200.81kN/m2ERROR:#VALUE!0.000.10kN/m2A-AkN/m2kN/m2

-0.230.16

Presjek B-B0.20kN/m20.10kN/m2

00.39kN/m2ERROR:#VALUE!0.000.10kN/m2B-BkN/m2kN/m2

-0.230.16

Longitudinalni smjer djelovanja vjetra; F = 90oe= min (b,2h) =min (39.6511.40 ) - uzima se manja vrijednoste= 11.4

23.50.000.0033.95 C39.65

I

4.56 B

H

1.14 AFGF

2.8517.802.85

w

2.289.1228.25

ABC5.29

39.65

Odreivanje klasifikacije koeficijenta izloenostiVertikalne povrineh/d=0.14A=12.06m2 Cpe10 =-1.20B=48.24m2 Cpe10 =-0.80C=149.44m2 Cpe10 =-0.50D=127.63m2 Cpe10 =0.70E=127.63m2 Cpe10 =-0.30

=qb x c e(z) x c peA=0.25 x1.30 x-1.20 =-0.39kN/m2B=0.25 x1.30 x-0.80 =-0.26kN/m2C=0.25 x1.30 x-0.50 =-0.16kN/m2D=0.25 x1.30 x0.70 =0.23kN/m2E=0.25 x1.30 x-0.30 =-0.10kN/m2Horizontalne povrine0.3xF=3.25m2 Cpe10 =-2.23x= 0.03101G=20.29m2 Cpe10 =-1.29x= 0.010.1xH=107.16m2 Cpe10 =-0.70101I=797.83m2 Cpe10 =-0.51x= 0.010.1x101=qb x c e(z) x c peF=0.25 x1.30 x-2.23 =-0.72kN/m2G=0.25 x1.30 x-1.29 =-0.42kN/m2H=0.25 x1.30 x-0.70 =-0.23kN/m2I=0.25 x1.30 x-0.51 =-0.17kN/m2

-0.10kN/m2

kN/m2IkN/m2

-0.16-0.16

kN/m2HkN/m2

-0.26-0.26

FGF

-0.39kN/m2-0.39kN/m2

0.23kN/m2

Presjek A-A-0.42kN/m2-0.42kN/m2

0-0.72kN/m2ERROR:#VALUE!0.00-0.72kN/m2A-AkN/m2kN/m2

-0.39-0.39

Presjek B-B-0.23kN/m2-0.23kN/m200.000.00B-BkN/m2kN/m2

-0.26-0.26

Presjek C-C-0.17kN/m2-0.17kN/m200.000.00C-CkN/m2kN/m2

-0.16-0.16

Pritisak vjetra na unutarnju oblogu objekta

transverzalni smjer =S A o= 1.00S ACpi =-0.30(koeficijent unutarnjeg tlaka)

longitudinalni smjer =S A o= 0.00S ACpi =0.35(koeficijent unutarnjeg tlaka)

unutarnji tlaki=qb x c i(z) x c pii=0.25 x1.30 x0.35 =0.11kN/m2

unutarnji podtlaki=qb x c i(z) x c pii=0.25 x1.30 x-0.30 =-0.10kN/m2ANALIZA OPTEREENJA NA PODRONICU - 1 DIOgzgyg=500kg/m3

2stalno optereenje=og'=0.11kN/m' - teina podronice

g=0.14kN/m2 - stalno optereenjeLinijsko optereenje u smjeru zgz =((g x e) + g') x cosgz =(( 0.14 x2.94 )+ 0.11 ) xcos 2 =0.52kN/m'

Linijsko optereenje u smjeru ygy =((g x e) + g') x cosgy =(( 0.14 x2.94 )+ 0.11 ) xsin 2 =0.02kN/m'

Optereenje snijegomsz =s x (e x cos ) x cossz =0.80 x (2.94 xcos 2 ) xcos 2 =2.35kN/m'sy =s x (e x cos ) x sinsy =0.80 x (2.94 xcos 2 ) xsin 2 =0.08kN/m'

Optereenje na podronicu od vjetraz=H x e z=-0.23 x2.94 =-0.68kN/m'

unutarnji podtlakp=i x e p=-0.10 x2.94 =-0.29kN/m'

unutarnji tlakt=i x e t=0.11 x2.94 =0.32kN/m'

Kombinacija optereenja na podronicukombinacija Igdz=gG x gz + gQ x sz + gQ x x gdz= 1.35 x 0.52 + 1.50 x 2.35 + 1.50 x 0.60 x0.68gdz=4.84kN/m'

gdy=gG x gy + gQ x sy gdy= 1.35 x 0.02 + 1.50 x0.08gdy=0.15kN/m'

kombinacija IIgdz=gG x gz + gQ x z + gQ x x szgdz= 1.35 x 0.52 + 1.50 x- 0.68 + 1.50 x 0.50 x2.35gdz=1.44kN/m'

gdy=gG x gy + gQ x x sy gdy= 1.35 x 0.02 + 1.50 x 0.50 x0.08gdy=0.09kN/m'

kombinacija IIIgdz=gG x gz + gQ x szgdz= 1.35 x 0.52 + 1.50 x2.35gdz=4.23kN/m'

gdy=gG x gy + gQ x sygdy= 1.35 x 0.02 + 1.50 x0.08gdy=0.15kN/m'

kombinacija IVgdz=gF x gz + gQ x gdz= 1.00 x 0.52 + 1.50 x-0.68gdz=-0.5kN/m'

gdy=gF x gy gdy= 1.00 x0.02gdy=0.02kN/m'

kombinacija V (ubacujemo podatke s najveim optereenjem od vjetra)4.84gdz=gdz(komb.I) + gQ x x p1.44gdz=4.84 + 1.50 x 0.60 x0.294.23gdz=5.1kN/m'( mjenjamo predznak)-0.5

gdy=gdy(komb.I)0.15gdy=0.15kN/m'0.090.15kombinacija VI0.02gdz=gdz(komb.IV) + gQ x tgdz=- 0.50 - 1.50 x0.32gdz=-0.98kN/m'

gdy=gdy(komb.IV)gdy=0.02kN/m'

ANALIZA OPTEREENJA NA PODRONICU - 2 DIOgdz

- unutarnje sile u podronicigdy - kombinacija IIIgdz=4.23kN/m'gdy=0.15kN/m'02=o

M, N, Tl'l' =3.05m4.5

MB

RAMuRBRC

RBmax =1,132 x q x l

MBmax = - 0,105 x q x l2

M =0,078 x q x l2

RRmaxy = 1.132 x 0.40 x 3.05 =1.38kN

RRmaxz = 1.132 x 4.23 x 3.05 =14.60kN

MBmaxy = - 0,105 x q x l2MBmaxy =-0.105 x 4.23 x 9.30 =4.13kN

MBmaxz= - 0,105 x q x l2MBmaxz=-0.105 x 0.40 x 9.30 =0.39kN

My =0,078 x q x l2My = 0.078 x 4.23 x 9.30 =3.06kN

Mz =0,078 x q x l2Mz = 0.078 x 0.40 x 9.30 =0.29kN

My4.13

My3.06

14.60

Mz0.39

Mz0.29

1.38

UNUTARNJE SILE U REETKIFyFxFyFxFyFy/2FxFx/2

- pojasevi 70x70x5g= 0.14 x47.80 =6.69kN53.14 - ispuna 50x50x5g= 0.11 x35.17 =3.87kN37.64S =10.56kN - vlastita reetka po vorovimaFy =10.56= 1.320kN8Fy/2 =0.660kN

Fy = 1.320 x 1.35 + 14.60 =16.38kNFy/2 =8.190kN

Fx =1.38kNFx/2 =0.69kN

TIP IIS1yS1

S1x8.19

=20.69=214

RRRR =16.38 x 4.00 =65.52kNS2x

S2yS2

S Fy =0-8.19 + RR - S1y - S2y =0 S1y = S1 xsin -8.19+65.52 - S1y - S2 xsin =0 S1x = S1 xcos 57.33 - S1y -S1x +1.195x sin =0 S2y = S2 xsin cos S2x = S2 xcos 57.33 - S1 xsin -S1 x cos +1.195x sin =0cos 57.33 - S1 x0.035 -S1 x0.999 +1.195x 0.358= 00.9342y-52.5157.33- 0.035 S1- 0.999S1 +1.195x 0.358= 01y0.93457.33- 0.035 S1- 0.358S1 +0.4282496997= 00.93457.33- 0.035 S1- 0.384S1 +0.46= 00.419S1 =57.79S1 =138.08kN-8.19 + RR - S1y - S2y =0-8.19+65.52-4.82 - S2y =0 S2y =52.51kN S1y = S1 xsin S1y =138.08 x0.0348994967 S1y =4.82kN

S Fx =0-0.69 + S2x -S1x =0 S1x = S1 xcos S2x = S1x +0.69 S1x =138.08 x0.999390827 S2x =138.00+0.69 S1x =138.00kN S2x =138.69kN

S2 = S2x =138.69 =148.56kNcos 0.9335804265

S2S2yS4

S2x

S6

S Fy =0S Fx =0 + S2y -S4 =0 + S6 -S2x =0 S4 = + S2y S6 = + S2x S4 =52.51kN S6 =138.69kN

S3S3y

16.38S3x

1.38=25.1

S1xS5xS1S1yS4S5yS5

S Fy =0-16.38 - S3y + S1y + S4 - S5y =0 S3y = S3 xsin -16.38 - S3y+ 4.82+ 52.51 - S5 xsin =0 S3x = S3 xcos 40.95 - S3y - -S1x +1.38 + S3xx sin =0 S5y = S5 xsin cos S5x = S5 xcos 40.95 - S3 xsin --138.001.38 + S3 xcos x sin =0cos 40.95-0.035S3 --136.62+ 0.999S3 x 0.424= 00.90640.95-0.035S3 -0.424S3 -57.9541251355= 00.90640.95-0.035 S3-0.468S3 64.00= 00.503S3 =104.95S3 =208.62kN

S3y = S3 xsin S3x = S3 xcos S3y = 208.62x 0.035 S3x = 208.62x 0.999 S3y =7.28kN S3x =208.49kN S5y = S5 xsin S Fx =0 S5y = 79.36x 0.424S1x -1.38 - S3x + S5x= 0 S5y =33.67kN138.00-1.38-208.49 + S5 xcos =0 S5x = S5 xcos 0.906S5 =71.87 S5x = 79.36x 0.906S5 =79.36kN S5x =71.87kN

S5S5yS8

S5x

S10S6S Fy =0S Fx =0 - S5y +S8 =0 - S6 + S10 -S5x =0 S8 = + S5y -138.69 + S10 +-71.87= 0 S8 =33.67kN S10 =210.56kN

S7S7y

16.38S7x

1.38=28.1

S3xS9xS3S3yS8S9yS9

S Fy =0-16.38 - S7y + S3y + S8 - S9y =0 S7y = S7 xsin -16.38 - S7y+ 7.28+ 33.67 - S9 xsin =0 S7x = S7 xcos 24.57 - S7y - -S3x +1.38 + S7xx sin =0 S9y = S9 xsin cos S9x = S9 xcos 24.57 - S7 xsin --208.49+ 1.38 + S7 xcos x sin =0cos 24.57-0.035S7 --207.11+ 0.999S7 x 0.471= 00.88224.57-0.035S7 -0.471S7 -97.5512707194= 00.88224.57-0.035 S7 -0.534S7 +110.59= 00.569S7 =135.16S7 =237.73kN

S7y = S7 xsin S7x = S7 xcos S7y = 237.73x 0.035 S7x = 237.73x 0.999 S7y =8.30kN S7x =237.59kN S9y = S9 xsin S Fx =0 S9y = 34.55x 0.471S3x -1.38 - S7x + S9x= 0 S9y =16.27kN208.49-1.38-237.59 + S9 xcos =0 S9x = S9 xcos 0.882S9 =30.48 S9x = 34.55x 0.882S9 =34.55kN S9x =30.48kN

S9S9yS12

S9x

S14S10S Fy =0S Fx =0 - S9y +S12 =0 - S10 + S14 -S9x =0 S12 = + S9y -210.56 + S14 +-30.48= 0 S12 =16.27kN S14 =241.04kNS11S11y

16.38S11x

1.38=30.9

S7xS13xS7S7yS12S13yS13

S Fy =0-16.38 - S11y + S7y + S12 - S13y =0 S11y = S11 xsin -16.38 - S11y+ 8.30 16.27 - S13 xsin =0 S11x = S11 xcos 8.19 - S11y - -S7x +1.38 + S11xx sin =0 S13y = S13 xsin cos S13x = S13 xcos 8.19 - S11 xsin --237.59+ 1.38 + S11 xcos x sin =0cos 8.19-0.035S11 --236.21+ 0.999S11 x 0.514= 00.8588.19-0.035S11 -0.513S11 -121.3035791487= 00.8588.19-0.035S11 -0.598S11 +141.37= 00.633S11 =149.56S11 =236.26kN

S11y = S11 xsin S11x = S11 xcos S11y = 236.26x 0.035 S11x = 236.26x 0.999 S11y =8.25kN S11x =236.12kN S13y = S13 xsin S Fx =0 S13y =- 0.10x 0.514S7x -1.38 - S11x + S13x= 0 S13y =-0.05kN237.59-1.38-236.12 + S13 xcos =0 S13x = S13 xcos 0.858S13 =-0.09 S13x =- 0.10x 0.858S13 =-0.10kN S13x =-0.09kN-236.2611-237.737-208.623-138.081-0.1034.5579.36-33.67-16.27148.56-52.51913458122

138.69210.56241.0461014

-935.57918.29-17.294. DIMENZIONIRANJE SVIH ELEMENATA KONSTRUKCIJE TE KONCEPTUALNO RIJEENJE I DIMENZIONIRANJE SPOJEVA

DIMENZINIRANJE ELEMENATA REETKE - DONJI POJASNEd =241.04kNCijev -70 x 70 x 5,01501508elik -S 235A =12.4cm2gM0=1.00

OtpornostNRd =fy x A23.50x 12.40 = 291.40 kNgM01.00

NEd 241.04 = 0.83NRd291.40

DIMENZINIRANJE ELEMENATA REETKE - ISPUNANEd =148.56kNCijev -50 x 50 x 5,01501505elik -S 235A =8.36cm2

OtpornostNRd =fy x A23.50x 8.36 = 196.46kNgM01.00

NEd 148.56 = 0.76NRd196.46

DIMENZINIRANJE ELEMENATA REETKE - GORNJI POJASNEd =237.73kNLi =3.13