annexure a

1

Annexure - ADesign Detail for 1200kV V- Single Suspension Hardware (Drg.No : VSS-1200kV) 1. Anchor Shackle for VSS 1200KV 8 BUNDLE MOOSE (connected between tower of 20mm thickness and anchor shackle of same dimension and extension link is attached to this anchor shackle)A) Tensile Strength= (outer diameter-inner diameter)*thickness of Leg*No of Leg*410/1000

= (60-30)*25*2*410/1000= 615KN>355KNb) Bearing Strength calculation-

Given data

Bolt size =M27 Grade= 5.6Tensile strength= 500n/mm2Yield strength= 60% of 500= 300N/mm2

Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of anchor shackle)

Contact Area= 3.14*13.5*(25+25+28) = 3306.42mm2

Bearing stress= 300*0.75=225N/mm2

Bearing strength= 225*3306.42/1000 KN= 743.94KN>355KNTensile Strength at Weak point=1.5*(3.14*d2/ 4)* 62/102= 1.5*(3.14*25*25/4) = 447 KN (The cross section at flange area higher than the leg so the leg area is the weak point area. And 1.5 is multiplying factor due 30 Degree contact) [T.S of class 4 grade steel =62 kg/mm2 & to convert into Newton we have to divide by 102]2. 28mm thick Extension Link: This will be attached between anchor shackle of 25mm diameter and Horn Holder ball clevis of leg thickness 14mmA) Tensile Strength= (outer diameter-inner diameter)*thickness of Leg*No of Leg*410/1000

= (90-29)*28*410/1000= 700.28KN>355KNb) Shear Strength= Tensile strength*0.75= 700.28*0.75= 525.21 KN>>355KNc) Bearing Strength calculation-

Given data

Bolt size =M27 Grade= 5.6

Tensile strength= 500N/mm2

Yield strength= 60% of 500= 300N/mm2


Contact Area= 3.14*13.5*(14+14+28) = 2373.84mm2

Bearing stress= 300*0.75=225n/mm2

Bearing strength= 225*2373.84/1000 KN= 534.114KN>355KN3. 24mm designation Horn Holder Ball clevis for VSS 1200KV 8 BUNDLE MOOSE (connected between extension link and 320KN disc insulator)A) Tensile Strength= (outer diameter-inner diameter)*thickness of one leg *No of leg*410/1000

= (60-29)*14*2*410/1000= 355.88KN

b) Bearing Strength calculation-

Given data


Tensile strength= 500n/mm2


Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of Ball Clevis)

Contact Area= 3.14*13.5*(28+14+14) = 2373.84mm2


Bearing strength= 225*2373.84/1000 KN= 534.114KN

Tensile Strength at Weak point= 3.14*d2/ 4* 62/102= 3.14*25*25/4+298/2= 298+149 =447 KN (The cross section at flange area higher than the leg so the leg area is the weak point area.) [T.S of class 4 grade steel =62 kg/mm2 & to convert into Newton we have to divide by 102]

4. 24mm diameter Arcing Horn: It has 70 mm diameter ball (450x300mm)4. (A) 320KN Disc Insulator: It is connected between 24mm designation ball clevis and socket clevis.5. Socket clevis with 24 mm designation (this will be attached with the insulator and yoke plate of 20mm thickness)A) Tensile Strength= (outer diameter-inner diameter)*thickness*No of Leg*410/1000

= (65-29)*14*2*410/1000= 413.28 KNB) Shear Strength= Tensile strength*0.75=413.28*0.75= 309.96 KN

c) Bearing Strength calculation-

Given data

Bolt size= M27 Grade =8.8Tensile strength= 800N/mm2


Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of Socket Clevis)

Contact Area= 3.14*13.5*(20+2*14) = 2034.72mm2



6. Main Yoke plate of thickness 20mm: It is attached with two socket clevis of 24mm designation and eight clevis Eye of 80 center to center distancesA) Tensile Strength= (width of the plate outer to outer-inner diameter of the holes*number of holes)*thickness*410/1000

= (740-29*2)*20*410/1000= 5592.4 KN

b) Shear Strength= Tensile strength*0.75= 5592.4 *0.75= 4194.3 KN


Given data




Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of socket clevis)

Contact Area= 3.14*13.5*(20+12+12) =1865.16 mm2


Bearing strength= 480*1865.16 /1000 KN= 895.27 KN

7. Corona Control Ring: 100x 5 mm thick Aluminum tube. It has Outer Diameter 700mm and welded with 38x5mm thick Aluminum tube it attached with Main yoke plate8. Clevis Eye (this will be attached with yoke plate of 20mm dimension and AGS clamp 50*6 mm thickness of aluminum strap)A) Tensile Strength= (outer diameter-inner diameter)*thickness*2*410/1000

= (40-18)*30*410/1000= 270.6 KN

B) Shear Strength= Tensile strength*0.75= 270.6*0.75= 202.95 KN


Given data





Contact Area= 3.14*8*(20+9+9) = 954.56mm2



9. AGS clamp: It consist Cushion (300mm), AGS Strap (50x6mm) ,AGS Rod(9.27x2235mm) for ACSR MOOSEDesign Detail for 1200KV Hardware (LINE SIDE QTS) 1. Anchor Shackle for 1200KV 8 BUNDLE MOOSE (connected between tower of 25mm thickness and anchor shackle of 40mm dimension and extension link is attached to this anchor shackle)A) Tensile Strength= (outer diameter-inner diameter)*thickness*2*410/1000

= (80-41)*30*2*410/1000= 959.4KN

B) Shear Strength= tensile strength*0.75= 959.4*0.75= 719.55 KN

C) Bearing Strength calculation-

Given data

Bolt size =M39 Grade= 8.8Tensile strength= 800n/mm2



Contact Area= 3.14*19.5*(30+30+34) = 5755.62mm2




2. Extension Link: This will be attached between anchor shackle of 40mm diameter in both side.

A) Tensile Strength= (outer diameter-inner diameter)*thickness*410/1000

= (130-41)*30*410/1000= 1094.7KN

b) Shear Strength= Tensile strength*0.75= 1094.7*0.75= 821.025 KN


Given data





Contact Area= 3.14*19.5*(30+30+34) =5755.62 mm2


Bearing strength= 480*5755.62/1000 KN= 2762.69 KN

1(A) . Anchor Shackle for 1200KV 8 BUNDLE MOOSE (connected between extension link of 30mm thickness and Rectangular yoke plate of thickness 30mm)A) Tensile Strength= (outer diameter-inner diameter)*thickness*2*410/1000

= (80-41)*30*2*410/1000= 959.4KN



Given data





Contact Area= 3.14*19.5*(30+30+34) = 5755.62mm2



Tensile Strength at Weak point= 3.14*d2/ 4* 62/102= 3.14*40*40/4+1256/2= 1256+628 =1884 KN (The cross section at flange area higher than the leg so the leg area is the weak point area.) [T.S of class 4 grade steel =62 kg/mm2 & to convert into Newton we have to divide by 102]3. Spacing Plate/Rectangular Yoke plate of thickness 30mm attached between anchor shackle and anchor shackle of same dimensionA) Tensile Strength= (width of the plate-inner diameter of the holes*number of holes)*thickness*410/1000

= (240-41*2)*30*410/1000= 1943.4KN



Given data





Contact Area= 3.14*19.5*(30+30+30) =5510.7 mm2



1(B). Anchor Shackle for 1200KV 8 BUNDLE MOOSE (connected between 30mm thickness rectangular yoke plate and anchor shackle of same dimension and this same dimension anchor shackle is attached to triangular yoke plate of 30mm thickness)

A) Tensile Strength= (outer diameter-inner diameter)*thickness*2*410/1000

= (80-41)*30*2*410/1000= 959.4KN



Given data





Contact Area= 3.14*19.5*(30+30+34) = 5755.62mm2




4. Triangular yoke plate: Yoke plate of thickness 30mm attached between anchor shackle and ball clevis For Tower End:

A) Tensile Strength= (outer diameter-inner diameter)*thickness*No of Holes*410/1000

= (150-41)*30*1*410/1000= 1340.7 KN



Given data





Contact Area= 3.14*19.5*(30+2*30) =5510.7 mm2



Tensile Strength at Weak point= 1.5*(3.14*1502/ 4)* 62/102= 1073.60 KN ( The cross section at flange area higher than the leg so the leg area is the weak point area. ) [T.S of class 4 grade steel =62 kg/mm2 & to convert into Newton we have to divide by 102]For Insulator End:

A) Tensile Strength= (outer diameter-inner diameter)*thickness*N0 of Holes*410/1000

= (90-29)*30*2*410/1000= 1500.6 KN



Given data





Contact Area= 3.14*13.5*(30+2*30) =3815.1 mm2



5. 24mm Ball clevis for line 1200KV 8 BUNDLE MOOSE (Connected between Triangular yoke plate and Insulator)A) Tensile Strength= (outer diameter-inner diameter)*thickness of one leg *No of leg*410/1000

= (70-29)*14*2*410/1000= 470.68KN

b) Bearing Strength calculation-

Given data

Bolt size =M27 Grade= 8.8Tensile strength= 800N/mm2


Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of Ball Clevis)

Contact Area= 3.14*13.5*(28+14*2) = 2373.84mm2



Tensile Strength at Weak point=1.5*(3.14*d2/ 4)* 62/102=1.5*( 3.14*25*25/4)= =735.93 KN (The cross section at flange area higher than the leg so the leg area is the weak point area.) [T.S of class 4 grade steel =62 kg/mm2 & to convert into Newton we have to divide by 102]

5 (A). 320KN Disc Insulator: It is connected between 24mm ball clevis and socket clevis6. 24 mm socket clevis (this will be attached with the insulator and Rectangular Curved yoke plate of 22mm thickness)

A) Tensile Strength= (outer diameter-inner diameter)*Thickness of Leg*No of leg*410/1000

= (65-29)*14*2*410/1000= 413.28 KN

B) Shear Strength= Tensile strength*0.75= 413.28 *0.75= 309.96 KN


Given data

Bolt size= M27 Grade =8.8




Contact Area= 3.14*13.5*(22+2*14) =2119.5mm2



7. 27mm diameter Tubular Arcing Horn: (595x375x200mm) It is connected with Triangular Yoke Plate 30mm Thickness8. Rectangular Yoke plate of thickness 22mm attached between Socket Clevis and anchor shackle of 22mm Diameter

A) Tensile Strength= (width of the plate-inner diameter of the holes*number of holes)*thickness*410/1000

= (195-(29+26))*22*410/1000= 1262.8KN

b) Shear Strength= Tensile strength*0.75= 1262.8*0.75= 947.1KN


Given data

Bolt size =M27 Grade for M27= 8.8 Tensile strength= 800N/mm2


Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of Socket Clevis)

Contact Area= 3.14*13.5*(22+2*14) =2119.5mm2



Bolt size = M24 Grade for M24= 5.6


Yield strength= 60% of 500= 300N/mm2Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of anchor shackle)

Contact Area= 3.14*12*(22+2*21) =2411.52mm2



9. Rectangular Yoke plate of thickness 22mm attached anchor shackle of 22mm Diameter both sideA) Tensile Strength= (width of the plate-inner diameter of the holes*number of holes)*thickness*410/1000

= (195-(2*26))*22*410/1000= 1289.86 KN



Given data





Contact Area= 3.14*12*(22+2*21) =2411.52mm2



10. Rectangular Yoke plate of thickness 22mm attached anchor shackle of 22mm Diameter both side

A) Tensile Strength= (width of the plate-inner diameter of the holes*number of holes)*thickness*410/1000

= (195-(2*26))*22*410/1000= 1289.86 KN



Given data





Contact Area= 3.14*12*(22+2*21) =2411.52mm2



11. Anchor Shackle for 1200KV 8 BUNDLE MOOSE (connected between 22mm thickness Yoke Plate and anchor shackle of same dimension and Sag Adjuster Plate of 22mm thickness is attached to this anchor shackle)A) Tensile Strength= (outer diameter-inner diameter)*thickness of Leg *No of Leg *410/1000

= (48-26)*21*2*410/1000= 378.84 KN

B) Shear Strength= tensile strength*0.75= 378.84 *0.75= 284.13 KN


Given data





Contact Area= 3.14*12*(22+2*21) =2411.52mm2




12. Sag Adjuster Plate: It is attached between Anchor shackle of 22mm diameter attached with 22mm thickness of the sag plate, in middle sag plate of 12mm thickness (2 pcs) with 22mm thickness sag plate and at end part attached with Extension Link (60x22mm).Calculation for first partA) Tensile Strength= (outer diameter-inner diameter)*thickness*410/1000

= (64-26)*22*410/1000= 342.76 KN



Given data




Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of the anchor shackle )

Contact Area= 3.14*12*(22+2*21) =2411.52 mm2 (for sag plate & shackle attachment) Bearing stress= 300*0.75=225N/mm2

Bearing strength= 225*2411.52 /1000 KN= 542.592 KN Calculation for middle partA) Tensile Strength= (outer diameter-inner diameter)*thickness*410/1000

= (64-26)*46*410/1000= 716.68 KN



Given data




Contact Area= 3.14*Bolt Radius*(plate thickness of 22mm & plate thickness of 12mm*2)

Contact Area= 3.14*12*(22+2*12) =1733.28mm2 (for sag plate & shackle attachment)



Calculation for end partA) Tensile Strength= (outer diameter-inner diameter)*thickness*410/1000

= (64-26)*46*410/1000= 716.68 KN



Given data




Contact Area= 3.14*Bolt Radius*(extension plate thickness of 22mm & plate thickness of 12mm*2)

Contact Area= 3.14*12*(22+2*12) =1733.28mm2 (for sag plate & shackle attachment)



13. Corona Control Ring: 100x 5 mm thick Aluminum tube. It has Outer Rectangular dimension 1550x2390 mm and welded with 50x10 mm thick Mild Steel flat it attached with yoke plate (Serial No.-8)14 to 17 Extension Link: This will be attached between Sag adjuster plate and anchor shackle of 22mm diameter having center distance of extension link 340mm, 265mm, 190mm & 115mm respectively.A) Tensile Strength= (outer diameter-inner diameter)*thickness*410/1000

= (60-26)*12*2*410/1000= 334.56 KN



Given data




Contact Area= 3.14*Bolt Radius*(plate thickness+ Hub thickness of the sag end or anchor shackle )

Contact Area= 3.14*12*(22+2*12) =1733.28 mm2 (for sag attachment) &

Contact Area= 3.14*12*(22+2*21) =2411.52mm2 ( for shackle attachment)Bearing stress= 300*0.75=225N/mm2

Bearing strength= 225*1733.28/1000 KN= 389.988 KN0 (for sag attachment)

Bearing strength= 225*2411.52/1000 KN= 542.592 KN0 ( for shackle attachment)18. Dead end assembly for ACSR Moose for QTS 1200 KV 8 Bundle moose attached with 22mm dia anchor shackle

A) Tensile Strength= (outer diameter-inner diameter)*thickness*410/1000

= (68-25)*21.5*410/1000= 379.045 KN



Given data

Contact Area= 3.14*Shackle Radius*(Diameter of steel sleeve of I+ Diameter of the end anchor shackle)

Contact Area= 3.14*11*(21.5+22) =1502.49 mm2 &


Bearing strength= 225*1502.49/1000 KN= 338.06 KN0

19 & 20. Rigid jumper spacer for ACSR Moose (31.77 diameter) for QTS 1200KV 8 bundle moose This will be attached between two moose conductors having spacer center distance 250mm & 750mm (2pcs each).PAGE 1

annexure a

Documents