chapter 2 - 1 properties depend on - arrangement of atoms - interactions between atoms study...
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Chapter 2 - 1
Properties depend on - arrangement of atoms- interactions between atoms
Study Bonding:
• What promotes bonding?• What types of bonds are there?• What properties are inferred from bonding?
CHAPTER 2:BONDING AND PROPERTIES
Chapter 2 - 2
Atomic Structure (Freshman Chem.)• atom – electrons – 9.11 x 10-31 kg
protons neutrons
• nucleus of atom: “size of a point on a page” -! فراغ
• atomic number = No. of protons in nucleus of atom = No. of electrons of neutral
species A [=] atomic mass unit = amu = 1/12 mass of 12C
Atomic wt = wt of 6.023 x 1023 molecules or atoms Unit 1 amu/atom = 1g/mol
C 12.011H 1.008 etc.
} 1.67 x 10-27 kg
Chapter 2 - 3
Atomic Structure
• Valence electrons: in the outer-shell
• determine all of the following properties1) Chemical: reactivity
2) Electrical: conductivity
3) Thermal: conductivity
4) Optical: transmittance
Chapter 2 - 4
Electronic Structure - Review
• Electrons have wavelike and particulate properties. – This means that electrons are in orbitals defined by a
probability.– Each orbital at discrete energy level determined by
quantum numbers. Quantum # Designation
n = principal (energy level-shell) K, L, M, N, O (1, 2, 3, etc.)
l = subsidiary (orbitals) s, p, d, f (0, 1, 2, 3,…, n -1)
ml = magnetic (direction in space) 1, 3, 5, 7 (-l to +l)
ms = spin ½, -½
Chapter 2 - 5
Electron Energy States
1s
2s2p
K-shell n = 1
L-shell n = 2
3s3p M-shell n = 3
3d
4s
4p4d
Energy
N-shell n = 4
• have discrete energy states• tend to occupy lowest available energy state.
Electrons...
Chapter 2 - 6
• Why? Valence (outer) shell usually not filled completely.
• Most elements: Electron configuration not stable.
SURVEY OF ELEMENTS - Review
Electron configuration
(stable)
...
...
1s22s 22p 63s23p 6 (stable)... 1s22s 22p 63s23p 63d 10 4s 24p 6 (stable)
Atomic #
18...36
Element1s1 1Hydrogen1s22Helium1s22s 1 3Lithium1s22s24Beryllium1s22s 22p 15Boron1s22s 22p 26Carbon
...
1s22s 22p 6 (stable)10Neon1s22s 22p 63s111Sodium1s22s 22p 63s2 12Magnesium1s22s 22p 63s23p 113Aluminum
...
Argon...Krypton
Chapter 2 - 7
Electron Configurations• Valence electrons – those in unfilled shells• Filled shells more stable• Valence electrons are most available for bonding and
tend to control the chemical properties
• Primary Bonding: Ionic, Covalent and Metallic
• example: C (atomic number = 6)
1s2 2s2 2p2
valence electrons
Chapter 2 - 8
Electronic Configurationsex: Fe - atomic # = 26
valence electrons
1s
2s2p
K-shell n = 1
L-shell n = 2
3s3p M-shell n = 3
3d
4s
4p4d
Energy
N-shell n = 4
1s2 2s2 2p6 3s2 3p6 3d 6 4s2
Chapter 2 - 9
The Periodic Table• Columns: Similar Valence Structure
Electropositive elements:Readily give up electronsto become + ions.
Electronegative elements:Readily acquire electronsto become - ions.
give
up
1egi
ve u
p 2e
give
up
3e iner
t ga
ses
acce
pt 1
eac
cept
2e
O
Se
Te
Po At
I
Br
He
Ne
Ar
Kr
Xe
Rn
F
ClS
Li Be
H
Na Mg
BaCs
RaFr
CaK Sc
SrRb Y
Chapter 2 - 10
• Ranges from 0.7 to 4.0,
Smaller electronegativity Larger electronegativity
• Large values: tendency to acquire electrons.
Electronegativity
Chapter 2 - 11
Ionic bond – metal + nonmetal
donates accepts electrons electrons
Dissimilar electronegativities
ex: MgO Mg 1s2 2s2 2p6 3s2 O 1s2 2s2 2p4
[Ne] 3s2
Mg2+ 1s2 2s2 2p6 O2- 1s2 2s2 2p6 [Ne] [Ne]
1s22s 22p 6 (stable)10Neon
Chapter 2 - 12
• Occurs between + and - ions.
• Requires electron transfer.
• Large difference in electronegativity required.
• Example: NaCl
Ionic Bonding
Na (metal) unstable
Cl (nonmetal) unstable
electron
+ - Coulombic Attraction
Na (cation) stable
Cl (anion) stable
Chapter 2 - 13
• Predominant bonding in CeramicsExamples: Ionic Bonding
Give up electrons Acquire electrons
NaCl
MgO
CaF2CsCl
Chapter 2 - 14
C: has 4 valence e -, needs 4 more
H: has 1 valence e -, needs 1 more
Electronegativities are comparable.
Covalent Bonding• similar electronegativity share electrons• bonds determined by valence – s & p orbitals
dominate bonding
• Example: CH4shared electrons from carbon atom
shared electrons from hydrogen atoms
H
H
H
H
C
CH4
Chapter 2 - 15
Primary Bonding• Metallic Bond -- delocalized as electron cloud
• Ionic-Covalent Mixed Bonding
% ionic character =
where XA & XB are Pauling electronegativities
%)100( x
1 e
(XA XB )2
4
ionic 70.2% (100%) x e1 characterionic % 4)3.15.3(
2
Ex: MgO XMg = 1.3XO = 3.5
Chapter 2 - 16
Arises from interaction between dipoles
• Permanent dipoles-molecule induced
• Fluctuating dipoles
-general case:
-ex: liquid HCl
-ex: polymer
Adapted from Fig. 2.14, Callister 7e.
SECONDARY BONDING
asymmetric electron clouds
+ - + -secondary
bonding
HH HH
H2 H2
secondary bonding
ex: liquid H2
H Cl H Clsecondary bonding
secondary bonding+ - + -
secondary bondingsecondary bonding
Chapter 2 - 17
Type
Ionic
Covalent
Metallic
Secondary
Bond Energy
Large!
Variablelarge-Diamondsmall-Bismuth
Variablelarge-Tungstensmall-Mercury
smallest
Comments
Nondirectional (ceramics)
Directional(semiconductors, ceramicspolymer chains)
Nondirectional (metals)
Directionalinter-chain (polymer)inter-molecular
Summary: Bonding
Chapter 2 - 18
Interactions Between Atoms
+-
+-
r
+-
+-
Spacing (r)
Atomic Radius (R)
Far Atoms: Attraction Close Atoms: Repulsion
Equilibrium spacing = ro
ro = 2 R
+-
+-
Dynamic Equilibrium
Chapter 2 - 19
Chapter 2 - 20
Bonding Curve
Chapter 2 - 21
Bonding Curve
• Energy – minimum energy most stable– Energy balance of attractive and repulsive terms
Attractive energy EA
Net energy EN
Repulsive energy ER
Interatomic separation r
rA
nrBEN = EA + ER = ro
Chapter 2 - 22
Bonding - Estimations
• Estimation of Bonding Energy (Eo) and Equilibrium Spacing (ro)• Given:
• Bonding occurs at energy minimum
• At minimum: Derivative dE/dr = g(r) = 0• Solve g(r) = 0 for r ro
• Substitute r=ro in the Energy Eqn:• Get Eo = E (r=ro)• Atomic radius R = ro/2
Eo =
“bond energy”
Energy
r o r
rA
nrBE = certain f(r) e.g. E =
For many atoms, ro is approximately 0.3 nm.
Chapter 2 - 23
• Bond length, r
• Bond energy, Eo
• Melting Temperature, Tm
Tm is larger if Eo is larger.
Properties From Bonding: Tm
r o r
Energyr
larger Tm
smaller Tm
Eo =
“bond energy”
Energy
r o r
unstretched length
Chapter 2 - 24
• Coefficient of thermal expansion,
• ~ symmetry at ro
is larger if Eo is smaller.
Properties From Bonding :
= (T2 -T1)LLo
Coefficient of thermal expansion
L
length, Lo
unheated, T1
heated, T2
r or
Smaller
Larger
Energy
unstretched length
Eo
Eo
Chapter 2 - 25
Ceramics(Ionic & covalent bonding):
Metals(Metallic bonding):
Polymers(Covalent & Secondary):
Large bond energylarge Tm
large Esmall
Variable bond energymoderate Tm
moderate Emoderate
Directional PropertiesSecondary bonding dominates
small Tm
small E large
Summary: Primary Bonds
secondary bonding
Bonding in Solids > Liquids > Gases
Chapter 2 - 26
Reading: Focus on Atomic Bonding in Solids
Core Problems: 2.7, 2.8, 2.12, 2.13,2.17, 2.19, 2.21 (Callister 3rd Addition)
Quiz: Next Class
ANNOUNCEMENTS
Chapter 2 - 27
Quiz
Energy
Atomic Spacing r
A B
c
Rank materials A, B and C according to 1. Increasing melting temperature > > 2. Decreasing bonding energy >
>3. Increasing Atomic Radius >
>4. Increasing coefficient of thermal expansion >
>
Chapter 2 - 28
Quiz
Energy
Atomic Spacing r
A
B
c
Rank materials A, B and C according to 1. Increasing melting temperature > > 2. Decreasing bonding energy >
>3. Increasing Atomic Radius >
>4. Increasing coefficient of thermal expansion >
>