cp violation (b-factories)
DESCRIPTION
CP VIOLATION (B-factories). P. Pakhlov (ITEP). The major experiments to explore CP. K + → π + νν. K L → π 0 νν. Kaon system:. Indirect CP Violation. Direct CP Violation. Not useful to constrain CKM matrix parameters (too large hadronic uncertainties). Rare K decays to πνν. - PowerPoint PPT PresentationTRANSCRIPT
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The major experiments to explore CPKaon system:
Indirect CP Violation
Direct CP Violation
Not useful to constrain CKM matrix parameters (too large hadronic uncertainties)
Rare K decays to πνν
Theoretically very clean modes, but a nightmare for experimentalists: Br ~ 10–11, two neitrinos.
K+ → π+νν
KL → π0νν
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The major experiments to explore CPD-meson system?
• Tiny CP violation, due to degenerated unitarity triangle and GIM/CKM suppression
EDM of n, p, nuclei? • The present ULs are much higher than the SM predictions (however, they are close to many models beyond SM)
B-meson system? • Large CP violation, • Many independent measurements,• Simple hadron dynamics, because of heavy b-quark• Hadronic uncertainties can be estimated or cancel in appropriate observables.
Rare η decays? • UL for CP violation in strong interaction
Dif
ficu
lt t
o ob
serv
e th
e SM
eff
ect,
test
phy
sics
bey
ond
the
SM
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B-mesons What are B mesons?
B0 = d b B+ = u b JPC = 0 – +
τ = 1.5 × 10-12 s (ct 450 μm)
How are they produced? e+e– (4S) B B is the cleanest process (large BB/other
cross section; no extra particles) Also at hadron machines: pp B + B + anything
How are they decay? Usually to charm b c, e.g. B D Much rarely to light quarks |bc|2|bu|2 100
b q
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ARGUS and CLEO – pioneers in B-physics Large mixing is observed by ARGUS in 1987
Measurements of |Vcb|, |Vub|, |Vtd| and |Vts|: the UT has
comparable sides and therefore angles are not 0 or 180º.
Large Br(B J/KS) ~ 10–3 – very attractive final state
All these were good news for physicists: Large mixing – easy to measure CP violation, as interference occurs
before B decays CP violation in B can be large Convenient final state
The Nature is more favorable to us than we could expect
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Neutral meson mixing from CKM matrix
Equal from CPT invariance
Hamiltonian is non-hermitian due to the decay;
“Box diagram”
It is just a numerical (complex) matrix 2×2:
contributes to off-diagonal elements
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Peculiarity of B-meson system
Box diagram
Thus, mass (width)-differences are approximated by
where
Contains weak phase
Common CP final states for B0 and B0
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CP violation in B mesons No “KL” methods applicable!
Lifetime difference is tiny ((BH)- (BL)/(B) ~1%): no way to work with a beam of long lived B’s.
Semileptonic asymmetry also vanishes. New ideas required!
Sanda & Carter (1980): consider a final state f common for both B0 and B0:
We arrive at decay rate asymmetry for the B0(t=0) and B0(t=0) because of interference of two amplitudes with different weak phases
The effect is large! Sanda & Carter estimated the asymmetry ~ 0.1 (compare with 0.002 CP violating effects in KL)
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Interfere B fCP with B B fCP Sanda, Bigi & Carter:
× A + × A
× A + × A
For B(t=0) = B0
For B(t=0) = B0
tree diagram (A)
box + tree diagram
Calculate t-dependent rates:
Remember: |A|=|A|,|p|=|q|
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B0 J/ KS
taking into account
Penguin diagram is difficult to estimate. But we are lucky: it’s amplitude is collinear to those of the tree one.
Vtd
V*td
d ds
b cc
J/ψ
KS b cc
d ds
J/ψ
KS
d
b
t
t
+
Why?
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B0 π π
In this case the penguin diagram is not small and has different weak phase:• The indirect CP violation ~ S sin(Δm t), where S≠ sin 2α, but sin(2α + some not-negligible phase).• There will be direct CP asymmetry ~ A cos(Δm t),
udub
udub
VV
VV
A
A*
*
Vub
d dub
du
π+
π–
V*td
du
du
d
bt π–
π+
How to take into account this?Wait for the next lecture.
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(4S) resonance
(4S) B0B0 / B+B– ~ 50:50 + no extra particles! Coherent BB production in P-wave B-energy is known (B momentum is very low ~ 340MeV
A very convenient process to study CP violation in B!
bb bound state JPC=1– – (≡ JPC of photon) (e+e–(4S)) 1nb Good signal/background ~
1:3
e+e– (4S) B B
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How to measure CPV at e+e– collider? The source of B mesons is the (4S), which has JPC = 1– –.The (4S) decays to two bosons with JP = 0–.Quantum Mechanics (application of the Einstein-Rosen-Podosky Effect) tells us that for a C = –1 initial state (Υ(4S)) the rate asymmetry:
0))(())((
))(())((
2121
2121
flCPflCP
flCPflCP
fBfBfBfB
fBfBfBfB
NN
NNA
N = number of eventsfCP = CP eigenstate (e.g. B0→J/ψKS)ffl = flavor state (particle or anti-particle) (e.g. B0→e+X)
However, if we measure the time dependence of A we find:
CPfBfBfBfB
fBfBfBfB
flCPflCP
flCPflCP
ttNttN
ttNttNttA 2sin
),(),(
),(),(),(
))((21))((21
))((21))((21
21
2121
2121
Need to measure the time dependence of decays to “see” CP violation using theB’s produced at the (4S).
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Asymmetric e+e– collaider CP violation asymmetry vanishes if integrated over Δt from
– to + kills good idea? No! but requires new idea:
Need to reconstruct B-decay vertex: Impossible at symmetric B-factory – we don’t know B’s production point!
But possible if (4S) has a sizeable boost in lab frame
We can measure t-dependent asymmetry!
Flavor-tag decay (B0 or B0?)
J/
KS
e
e
zt=0
Asymmetric energies
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What‘s required to discover CPV? Produce B mesons! Need accelerator
Effectively reconstruct B mesons
Correctly determine the flavor of second B
Precisely reconstruct the decay vertices
Produce a lot of B mesons! Need good accelerator
Produce a huge number of B mesons! Need accelerator with record luminosity
Need good detector with excellent PID and Vertex
very
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e+e– Asymmetric B-factories
PEP-II
BaBar~1 km in diameter
Mt. Tsukuba
KEKBBelle
SLAC 3.1 x 9GeV
3.5 x 8 GeV
stop Apr-2008
Also tau- and charm- factories: 109 ττ / cc pairs
World highest luminositiesL = 2.1 (KEKB) & 1.2 (PEP-II) × 10 34 cm–2 s–1
775(Belle) & 465(BaBar) millions BB-pairs
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PEP-II at SLAC KEKB at KEK
Belle
BaBar
9GeV (e–) 3.1GeV (e+)designed luminosity: 3.5 1033cm-2s-1
achieved 10.2 1033cm-2s-1
(3 times larger!)
8GeV (e–) 3.5GeV (e+) designed luminosity: 10.0 1033cm-2s-1
achieved 21.2 1033cm-2s-1
(2 times larger!)
11 countries, 80 institutes, ~ 600 persons
13 countries, 57 institutes, ~ 400 persons
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How to measure CPV at B-factories? Reconstruct the decay of one of the B-mesons’s into a CP
eigenstate for example: B J/ KS
Reconstruct the decay of the other B-meson to determine its flavor (“tag”)
Partial reconstruction is sufficient
Measure the distance (L) between the two B meson decays and convert to proper time
need to reconstruct the positions of both B decay vertices t = L/(c)
Correct for the wrong tag and not perfect vertex resolution Extract CP asymmetry from the dN /d t distribution:
dN/d t ~ e -|t| [1 ± cp sin2 sin(m t)]
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Step 1: Select BJ/KS
Reconstruct BCP long lived daughter:
B J/ KS ℓℓ Check the intermediate masses:
M(ℓℓ) ~ M(J/); M() ~ M(KS)
Check the mass and ENERGY (a big advantage of B-factories – we know B energy = Ebeam in the CM system) of J/KS combination
KS decay vertex
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B-candidate CM energy
B-candidate CM momentum
Use many other decays B to charmonium (ηc, χc1, ψ’) + KS to increase statistics:
• These final states have the same (odd) CP eigenvalue• They are equally theoretically clean (no penguin uncertainties)• They can be reconstructed with the similar high purity
B charmonium KSBJ/KS
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2*/
2*KsJbeambc PEM
Purity 97 %CP odd
Purity 59 %CP even
B J/KLImportant to check if the asymmetry flip the sign for the opposite CP eigen value
Difficult to detect KL: cτ ~ 15m; only nuclear interactions.
pK L information is poor
→ lower purity
Detect nuclear shower in iron: measure direction but not momentum. Use known J/KL = Ebeam energy to calculate momentum.
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Step2: Flavor tagging
B0 B0
D X
D XB0 B0
Semileptonic decays
Hadronic decays
X ℓ+ ν
X ℓ– ν
In ~99% of B0 decays: B0 and B0 are distinguishable by their decay products
All charged tracks (not associated with the reconstructed BCP) are from the second Btag in the event: ℓ, K and even charge provides the information of Btag flavor.
|Δt| (ps)
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Step 3: Vertex reconstructionUse tracks from both BCP and Btag to find out z-coordinate of the two B-decay vertices.
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B0 tag_B
0 tagB0 tag_B
0 tagS = sin 2β = 0.65A=0
Take into account detector effects
)cossin(141
,1 tmAtmSetqPt
)21( w
R
R : detector resolutionw : wrong tag fraction (misidentification of flavor) (1-2w) quality of flavor tagging They are well determined by using control sample D*lν, D(*)π etc…
TrueDetector smeared
Need to solve inverse problem to get true value
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First Observation: CPV in B
1137events
Asy
mm
etry
2001
[PRL 87,091802(2001)] [PRL 87,091801(2001)]
J/ψ K*0
( )
Asy
mm
etry
Eve
nts
sin 2β = 0.99 ± 0.14 ± 0.06 sin 2β = 0.59 ± 0.14 ± 0.05
32M BB-pairs
31M BB-pairs
B0 tag_B0 tag
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The recent Belle result
Nsig= 7482
J/ψ KS
J/ψ KL
Phys.Rev.Lett., 98, 031802(2007)
sin 2β = 0.642 ± 0.031 ± 0.017 A = 0.018 ± 0.021 ± 0.014
B0 tag_B0 tag
Nsig= 6512
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B0 tag_B0 tag
Compare CP odd and even final states
Asymmetry= –ξCP sin 2β sin(Δm Δt)
B0 tag_B0 tag
sin 2β = + 0.643 ± 0.038 A = – 0.001 ± 0.028
sin 2β = + 0.641 ± 0.057 A = – 0.045 ± 0.033
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The recent BaBar result
Phys.Rev. D79, 072009 (2009)
sin 2β = 0.687 ± 0.028 ± 0.012 A = 0.024 ± 0.020 ± 0.016
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There are two solutions for β
How to avoid ambiguity?
In some B decays the asymmetry is related to cos2β. It is difficult to achieve good accuracy, but even rough measurement allows to exclude the second solution.
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We have done a great job:• CPV violation is observed in the system different from the neutral kaon system. The CPV large (~70%) compared to 0.2% in K0 decays.• The parameter of CPV is measured with great precision (~ 3%) and related to KM parameters without theoretical uncertainties.• The angle of UT triangle is measured (without ambiguity) with the precision better than 1º.
Can we relax now?
Yes, because the time for this lecture is almost over.
No, because we have not yet proved that KM anzatz works well.
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The CM+KM test
VudV*ub
VcdV*cb
VtdV*tb
β
α
γ
How to measure other UT angles?
*
*
tbtd
cbcd
VV
VVArg
*
*
tbtd
ubud
VV
VVArg
*
*
ubud
cbcd
VV
VVArg
sin2β:
**** ,,,: DDBDDBDDBDDBdccb dddd 000 ,:, sdsd KBKBsddsssb
sin2α:0000 ,,,:
dddd BBBBdudb
sin2γ:
DKBuscb : hard
experimentallyeasy
One way to test the Standard Model is to measure the 3 sides & 3 angles and check if the triangles closes!
0*00 /,/,/: KJBKJBKJBsccb dLdsd
How to measure UT sides?