cpe 5238
TRANSCRIPT
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CONFIDENTIAL EH/OCT 2008/CPE523
UNIVERSITI TEKNOLOGI MARAFINAL EXAMINATION
COURSE
COURSE CODE
EXAMINATION
TIME
: TRANSPORT PHENOMENA
: CPE523
: OCTOBER 2008
: 2 HOURS
INSTRUCTIONS TO CANDIDATES
1. This question paper consists of three (3) questions.
Answer ALL questions in the Answer Booklet. Start each answer on a new page.2.
3.
4.
Do not bring any material into the examination room unless permission is given by theinvigilator.
Please check to make sure that this examination pack consists of:
i) the Question Paperii) a two - pages Appendicesiii) an Answer Booklet - provided by the Faculty
DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO
This examination paper consists of 3 printed pages
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CONFIDENTIAL 2 EH/OCT 2008/CPE523
QUESTION 1
a) Using Newton's law of viscosity, define viscosity and give its physical meanings.
(4 marks)
b) Explain the boundary conditions used for fluid-solid and liquid-gas interfaces(6 marks)
c) A viscous liquid overflows from a vertical cylindrical pipe causing a thin liquid film to flowcontinuously on the outside of the pipe. Ignoring end effects, derive the followingvelocity distribution of the film, vz as a function r:
v , = R
where R = outer pipe radius, kR = distance from the center of the pipe to the surface ofthe overflowing liquid film, p = density of the liquid, |j. = viscosity of liquid and g =gravitational constant. Navier-Stokes equations are given in Appendix 1.
(20 marks)
d) List all of the assumptions required for the solution of part (c) above. Give two reasonswhy Bernoulli equation is not satisfactory for solving the problem in part (c) above.
(10 marks)
QUESTION 2
a) The formulae for Biot and Nusselt numbers are similar. Give the physical meanings ofboth Nusselt and Biot numbers and state their differences.
(6 marks)
b) Water at 10 °C enters a smooth heat exchanger tube with inner diameter of 2.5 cm anda length of 3 m. The water flows at 75 L/min and exits at the temperature of 60 °C.
i). Obtain the temperature profile of the water in the tube(10 marks)
ii). Calculate the appropriate (bulk or film) average temperature of the moving water
(4 marks)
iii). For a constant wall temperature of 100°C, calculate the heat transferred to thewater using Colburn analogy.
(10 marks)
Colburn analogy St= — ^ — = - P r2 / 3
pv.Cp 2
0 0791Blasius equation for smooth tube and turbulent flow f =
Re02 5
The properties of water are given in Appendix 2
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CONFIDENTIAL 3 EH/OCT 2008/CPE523
QUESTION 3
The general species A diffusion equation in terms of molar fluxes expressed in Cartesiancoordinates is as follows:
A(N )+A(N )+A(N ) + ^ A . _ R = 0
a). Simplify the above equation for steady state, one dimensional diffusion with nohomogeneous reactions.
(4 marks)
b). Derive the molar flux of species A for the case of diffusion through a stagnant gas film.
(10 marks)
c). A pseudo-steady-state Arnold cell is used to determine the diffusivity of methanol in airat 25°C and 1 atm. The cell has a cross sectional area of 0.8 cm2. If the tube was initiallyfilled to within 3 cm of the lip of the tube, calculate the time required for the methanollevel to fall to 4 cm of the lip of the tube. The vapor pressure of methanol is 1.7 x 104 Paand its specific gravity is 0.791 at the system temperature. The molecular mass ofmethanol is 32 and the binary diffusivity of methanol in air is 1.62 x 10"
5 m
2 /s. The
universal gas constant is R = 8.3143 Pam3mor1K"1.(16 marks)
END OF QUESTION PAPER
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CONFIDENTIAL APPENDIX 1 EH/OCT 2008/CPE523
Navier-Stokes Equation for Cartesian Coordinates
Navier-Stokes Equation for Cylindrical Coordinates
6vr
at
at
5vz
at
5vr
l V r 5r
+ r 5r
5vz
' Vr 5r
r
ve
r
w
r
5vr
56
9Ve
a e
5vz
56
5vr
V z 5z
6vz
V z dz
ve2
r
i i
iJ
lJV |̂
r J
dP
dz^
5F)
5r TH>
15P
r 56
"1 5
r5r
5 |r \ 5
V0
r
+
rv
5r
1
r2
K,
52vz
562
1 52vr 5
2vr 2
CO OZ \
\ . 1 52ve 5
2ve
J r2 562 5z 2
, S 2
v z l
6z2 + pg z
5ve
56
2 i
% 2
1 (
56
P9r
P9e
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CONFIDENTIAL APPENDIX 2 EH/OCT 2008/CPE523
Thermo-physical properties of water at atmospheric pressure
T(°C)
5
10
15
20
25
30
35
40
45
50
55
60
65
70
75
80
85
90
95
( k g / m 3)
1 0 0 0
1 0 0 0
999
998
997
996
994
992
990
988
986
983
981
978
975
972
969
965
962
c P(kJ/kg-K)
4.21
4.20
4.19
4.19
4.18
4.18
4.18
4.18
4.18
4.18
4.18
4.18
4.19
4.19
4.19
4.20
4.20
4.21
4.21
H-103
(Pas)
1.518
1.306
1.138
1.002
0.890
0.797
0.719
0.653
0.596
0.547
0.504
0.466
0.433
0.404
0.378
0.354
0.333
0.314
0.297
k(W/m-K)
0.571
0.580
0.589
0.598
0.607
0.615
0.623
0.631
0.637
0.644
0.649
0.654
0.659
0.663
0.667
0.670
0.673
0.675
0.677
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