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" DE ClfONG ON THI CAD HOC MON: L Y THUYET MACH DleN Chuang 1:Nhiingkhal ni~mcoban v~machdi~n. 5.1 Cac phan tU mach 5.1 C6ng suat va nang hrong 5.1 Phan loai mach di~n 5.1 Cac dinh lu~t co ban cua mach di~n 5.1 Bi~n d6i wang duong mach Chuang 2: Mach xac l,p di~uhea 2.1 Qua trinh diSu hoa 2.2 Phuong phap bien dQphirc 2.3 Quan h~ di~n ap va dong di~n tren cac phAnnr R, L, C. Tro khang va d~n n~p 2.4 Dinh lu~t Ohm, dinh lu~t Kirchhoff dang phirc 2.5 Cong s~t 2.6 Ph6i hQ'Ptro khang gifra tai va nguen 2.7 Mach cong huang Chuang 3: Cacphmrngphap phflntiehmach 3.1 Phuong phap dong nhanh 3.2 Phuong phap th~ nut 3.3 Phuong phap dong m~t lucri 3.4 Mach ghep h6 cam 3.5 Cac dinh ly mach Chuang 4: Mang hai efra 4.1 Khai niem chung 4.2 Cac h~ plnrong trinh tr~ng thai cua m~ng hai cua 4.3 Phan lo~i m~ng hai cua .1 i. I . . ( I I.

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DE ClfONG ON THI CAD HOCMON: LY THUYET MACH DleN

Chuang 1:Nhiing khal ni~mco ban v~mach di~n.

5.1 Cac phan tUmach

5.1 C6ng suat va nang hrong

5.1 Phan loai mach di~n

5.1 Cac dinh lu~t co ban cua mach di~n

5.1 Bi~n d6i wang duong mach

Chuang 2: Mach xac l,p di~uhea

2.1 Qua trinh diSu hoa

2.2 Phuong phap bien dQphirc2.3 Quan h~ di~n ap va dong di~n tren cac phAnnr R, L, C. Tro khang va d~n

n~p2.4 Dinh lu~t Ohm, dinh lu~t Kirchhoff dang phirc

2.5 Cong s~t

2.6 Ph6i hQ'Ptro khang gifra tai va nguen

2.7 Mach cong huang

Chuang 3: Cac phmrngphap phflntieh mach

3.1 Phuong phap dong nhanh

3.2 Phuong phap th~ nut

3.3 Phuong phap dong m~t lucri

3.4 Mach ghep h6 cam

3.5 Cac dinh ly mach

Chuang 4: Mang hai efra

4.1 Khai niem chung4.2 Cac h~ plnrong trinh tr~ng thai cua m~ng hai cua

4.3 Phan lo~i m~ng hai cua

. 1

i .

I .

. (

I

I .

4.4 Cach n6i cac mang hai cira

4.5 Cac thong s6lam viec

4.6 Mach lQC

Chuong 5: Ph in tich qua di}dung phuong phap kinh di~n

5.1 M~ch RL

5.2 M~chRC

5.3 M~ch RLC voi nguen DC

5.4 Mach RLC voi nguon AC

5.5 Mach RLC voi nguon hi ham unit-step u(t)

Chirong 6: Ph in tich qua di}dung phunng phap bi~n dAi Laplace

6.1 Phep blen d6i Laplace va cac tinh ch~t

6.2 Dang toan t1i cua cac dinh lu~t mach co ban ' r

6.3 Bi~n d6i nguoc Laplace

6.4 Ap dung plnrong phap toan t1i phan tich qua trinh qua dQtrong mach TTD

6.5 Ap dung plnrong phap toan t1i phan tich h~ thong TTD

Chuong 7: Ph an tich mach trong mi~n tAn sa7.1 Phuong phap chu6i Fourier

7.2 Phan tich mach TID (y trang thai xac l~p tufin hoan khong sin

7.3 Phan tich mach UD voi nhieu nguon tac dQngdi~u hoa

7.4 Phuong phap bien d6i tich phan Fourier

TAl LIEU THAM KHAo•

1. Pham Thi Cu, Truong TrQng Tufut My, Le Minh' CUOng,M~ch di~n 1, NXB DR Qu6cGia TP.HCM, 2005.

2. Pham Thi Cu, Truong Trong TuAnMy, Le Minh CUOng,Bai t~p Mach Dien 1, tnrongDl,liHQcBach khoa. NXB D!l Qu6c Gia TP. HCM. 2005.

3. Pham Thi Cu, Truong Trong TuAnMy, Le Minh CUOng,Mach di~n 2, NXB DH Qu6cGia TP.HCM, 2005.

4. Pham Thi Cu, Truong TrQng TuAnMy, ts Minh CUOng,Bai t~p Ml,lchDi~n 2, tnrongDl,liHQcBach khoa. NXB DH Qu6c Gia TP. HCM. 2005.

5. Charles K. Alexander, Matthew N. O. Sadiku, Fundamentals of Electric Circuits, 5thedition, McGraw-Hill, 2013.

I .

ON T~P MJ:\CH 2

+ PHAN TfcH M~CH TRONG MI'£N TH01 GIAN+ PHAN TfcH M~CH TRONG MI'£N TA~56

First-Order CircuitstC'O,tRc 1/ R

ic+iR = 0do U dv vc-+-=o-+-+-=odt R dt RC

v(O) = Vo1

w(O) =2CV~

Source-Free RC Circuit

do 1-= --dtv RC

tlnu= -- +1nARC

In~ = - :C v(t) = Ae-t/R~ v(O)= A = Vo

... vet) = Voe-t/RC 'T = RC v(t)= Voe-r/t

First-Order CircuitsCho v,(0)=15Y. Tim ve, Vx va ix cho e-oGI'I

20 X 5Req = 20 + 5 = 4il

sott.

+ +O.lF =I=.c 120 II,.

Req =Rthevenin nhin tlr 2 eve cua C

.,.= RoqC = 4(0.1) = 0.4 sII = lI(O)e-tit = 15e-1/0.4V, lie = II = 15e-2.51V

v = _1_2-v = 0 6(lSe-2.5t) = ge-2.5,Vx 12+8 .

vix == 2.. = 0 75e-2.s.A12 .

First-Order CircuitsTim v(t) khi t;:::O. r.n2OV ....~ 20mF

GI'I

9vo(t) = 9 + 3(20) = ISV, t < 0

vo(O) = Vo = 15V

R... = 1 + 9 = IOil

'T = ReqC = 10 X 20 X 10-3 == 0.2 s

v(t) = vc(O)e-t/1' = 15e-t/o2 V

610/6/2017

1

First-Order CircuitsVfdl,l

TIm Vc,Vx, iokhi t~O. Biet vc(O)=45V

First-Order CircuitsVfdl,l

Tim V(t) khi QO

First-Order Circuitst-1 2w(O)=-Llo

2i(O) = 10

0+L "it-

VL + VR = 0di di RL-dt + Ri = 0 .. - + -I = 0

dt L

f 'CI)di I'R-= - -dtI. i 0 L

In 1[(.') = - RLt 1'0 => RtIn i(t) - In 10 = -1: + 0

In i(t) = _Rt ... i(t) = loe-IUIL10 L

.. jet) = loe-tIT

A source-freeRL circuit.

L-r=-

R

~Gi. ,hi" r&ng i(O)=lOA, tlnh i(l)

Ghil

4Q

;~~

O.5H~3;~,d 40

b

1,--3A, I. = -h = 3A61, - lS, - 31, - 0 => I, - ~I'

.0 I L! 3R",-Rn.-"'-j"0 T=R:=I=I'

.... ;(1)- 1(0).-'" - 10.-(2IljrA, 1> 0

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YI.!l!iTim Iva .. a trong mach .Gil thl't ring i(O)-SA

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Vf du: dIng t~c dllO'cd6ng trong mOtthai glan dai,tal t=O.cOngt~c dllO'cma ra. Tfnh itt) khi t>O

Gi£1

~-304 + 12

40i, = 2 + 3 = SA

i(t)- _1_2_i, _ 6A t < 012 + 4 '

160 2H

i(O) - i(0-) - 6 A

R.q = (12 + 4) 116 = 8nL 2 1T-Req-i-4·

i(t) = i(O)e-t/r = 68-41 A

Vf du: Chomach nhu hlnh ve. TIm io,Vova i cho toan mien thai gian,·giathi~t r~ngcOngtk dil dllO'cma trong mOtthai gian dai,

GI£i

For t > 0,

2Q lQff111'IOV~lH

t> 0

Rn.-316-2fl

T - J:_ _ I. ;(,) - i(O)e-tl< - 2.-1 A,Rn.

dl -I -IVvJ,) = -vL = <z = -2(-2e ) =.. ,

tIt) = ilL= _;-tA"" 6 3 '

t> 0

t> 0

{6V.

.,,(0- 4c-'V,,<0,>0

, < 0,,,,0

Vf du: Chomach nhu hlnh ve. TIm jo, Vova i cho toan mien thai gian30

i = {12A,12e-1IA, {

6A,I. = -4e-2.A,

,<0

r « 0t"" 0'

t «: 0t>O'

i » 0

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Vi du: tim i(t) , t>O

--x120

:140 ~ D6A 1(1), 502H

DS: 2e-2t A, t > O.

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Step Responseof an RC Circuit

(I)

/I.'0+~u(1) ..... c::

(b)

Step Responseof an RC CircuitAp dvng Kl; dong qua C b~ng dong qua R

Cdu u - V,u(I) 0 du v V,dl + --R- = dt + RC = RCu(t)

Fori> 0,

dv + ~ = !L. do = _ u - V, _!!!!_ = .s:dt RC RC dt RC U - V, RC

In(o ~ V,)IV(I)= - :cl' In ~o-_ ~s = - ;CY. 0

v - V, __ '/<v._V-e ,o sv - V, = (Vo - V,)e-t/-r

10/6/2017 .1

T = RC rr-- --,

IIJ(I) = {~~.+ (V. - V,~-'T.r « 0,> 0

U(I) .. V, + (Vo - VJe-r/., t > 0

Step Responseof an RC CircuitNfu ban dliu tl,l chua dlll1C nap thl c6 thf viet Iii

{a,

U(t) = V.(l - e-I/").t < 0t> 0

Khlc6 di~n ap rtIl thl to tlm dllqc dong di~n qua tv

I(t)= Cdu .. £V,e-r/T. T =, RC.dr T

1>0

DOlkhi ngU'b'ita ce th~ viet dllOi d~ng

U(/) = U(oo) + [V(O) - u(oo)]e-t/<

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S!..!._~_'IJ.~•.1.

rf7

US""£+'lee'U~

Yl:=£+t=(00)1or

o<Iu;,ttA\

Htd'-,--WVv-r-\lV>/Ir-'

0=1

vs=CO)1=(+0)1=(0)1z vs=01=CO)I

If!!)

!~Pue!ll!.Q4~~Qw8uOJ~llu9P'CliP,~~llu9'~}I!4~'i!!9'O<~JOJ(~)!wu~!n:>J!)7?JlRIjO3Suock3~d3lS

.,,_,,!lL'A='!..1=(.)a'1!P./,_"[(00)1-(0)1)+(a;,)J=(/)1

).

.j

!.L,,[Ol/9/0,,[

:-+.L/l_~Y:=:!11.

!=..'",_OY='.11l'tl+'I=1

.... Y(...._.+l)-...._I(OI-)(g·O-)jit·O+"'0_"''0-I-.,ot;;;;.:1+.=1

h(".•_#01-0,)-1«{.:>_lI(Ol-01)+0,=",_,[(.0)0-(0)0)+(co)o-(1)0

U.!.-_.!£_-otlol-""I{Ototx01

'1\01=.hOI-(_O)n-(0)<1

S!.!,..£_:>UN•.l ,rot

hot_(0£)01+Ot_(00)11YI-=.!!.--Iat~

··c+!:J- 0.·'I001Uti!'tq41utlwU~l04)A""IWU

'0=1Ittel9W>blip'!III¥Puel.J.Q~I19W8uaJl8u9P>blipJfI8U9J:Z"8

l!n::lJ!)JlJUVJO3suods3~d3lS

0<'0>'

h(~'o_;JSI-OE)=t/,-a(0£-sn+OE=.,,_;J[(oo)/I-(0)11]+(00)/1=(J)II

Sl:=£_01xS'OxEOIx"=:J'UIJ=.I.

hSl=(+0)11=CO)II=(0)11

II.OE=(00)11

...+...,...~.~un(~••

OlltII"'"y0'1£

O<lJOl(ll"l.jU!p:>~X:!!~a

Step Response of lin RL CircuitSal 3: nm i(t) for t>O

For 1< 0 ;(0-) = /(0) - /(0+) = 0ForO~t<4

401(0)) K 4+""6 • 4 A. R... - 4 +6 - 10n 40V

L 5 11'-Rn -ii-2'51(,) - 1(.. ) + 11(0) - 1("')]0-'/'

- 4 +'(0- 4)o-~- 4(l- .-,,)AFor I .. 4 1(4) - 1(4-) - 4(1 - .~ - 4 A

v 30 4X2 221(<<»-6"-TI-2.727A Rn-412+6--6-+6-TO

1(1)- 1(<<»+ [1(4) - I(m»)f-CHlf., ... 4

M- 2.727 + (4 - 2.727)t-<t-il/·. 15.--220, I sO

1(1) - 4(1 - .-"). 0 oS • oS 42.727 + 1.273.-1MI7(t-~). I ,;e"

SECOND-ORDER CIRCUITS

R L

·Q-f·fcf'1"f f<3 ·Gl

'K

SECOND-ORDER CIRCUITSFinding Initilll lind Finlll Vlllues

The swild> i. Fi,. 8.2 Iw been closed for • Ioog time ... t is ope•• tI - O. FlDd: (I) I(O'~ 0(0·). (b) dI(O,,)ldl. dv(O·)/dl. (c) 1(00).0(.. ).

40..!._O.lSHI2VCD=t__;1U1(0-) _....!.L = 2A, v(0-) ~ 2/(0,- 4 V I(O'}- 1(0-) - 2A. v(o') - v(O-) - 4V

4+2At. - O· 1c(0+)- /(0+) - 2 A SinceC .tvl'" - Ie. .tvldl - IdC. and

dv(0') _ 1c(0")_.2.. _ 20VI. -12 + 4/(0+)+ v,(O') + v(0+) - 0til C 0,1

v,(O') • 12 - 8 - 4 _ 0 dl(O,,)_ ",(0,,) - ~ - 0 AI.<II L 0.25

ForI> 01(00) - OA. u(co) a 12V

SECOND-ORDER CIRCUITSThe Source-Free Series RLC Circuit

M,ch dll'lC kith thlth bOl nang h/qng ban d}u Irong l 11<1 C [23R Lv(O)=.!.J·,tIl=yo 1(0)-1. .c_ ,

• <Ii I f' CAppIyiog KVL RI + L'dr +c _1., = 0

~ + ,!.!!!.+ _!_ =- 0 ~ glAI pt nay chung ta dung 2 di~u kien ban dau.r Lal LC

dl(O) ITr - -Z(1I4 + "oJ

"l--a+~ ,s-l·-a-~

10/6/2017

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!.

-.?tNt>7+--00»'0:EHl..._-<tty+If')=(1)11

'D,JI>-7<--OOJ:D:,HI

,.?I!'+.,,..'I!'=(1)11

·,),V~<1uoq.....<D

OOkD:tHI

l!n:lJI=>)7?I13111UQd33J.:I-3:>JnOS341SllnJHIJH30HO-ONOJ3S

j.

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j.

L"[OZ/9/0"[

UtJll~UI~It~Buhpdy

IP~-fl11 O=-:J+lpn-+- np,In

l!n:>JD,7?I13111UQd33J.:I-3:>JnOS341SllnJHIJH30HO-ONOJ3S

V('6S('.II!'ZH9'O+l<!H'.10».....-(1)1...

zm'o-'Y._(ty+o-l6sn+(0+11')6-_9-0=1!~I{l6S("tIlO>'y+l<!S('tllJS'Y-)(6Sn),,_'+

(16SHII!"Y+I6SHso.>'n......6--* SfV9--[9-(1)6),--(0)/1+(O)R{lt--°l'I'_1_(0)1

nwuequ91~ntiPo.41Z\I'"t\l4ulp"X(16"'.""'I'+,'6S£·.<O'''''.._.-(,)I

6snf:;:6-=<I,._001-18/\:;6-_~:;D_•~I,

01-~.~.'"'6.(f)'.1!.DII61I

KSOOO'0<1I4~-1.01h9=(0)19=(0)11'VI=!.!..!=(0)1

nt•dto·O01•",9

rr:a.'O.-O=llttdtl'\!X'1IP4'tw1f141elB'4'~wBuOJ,(1)1wU·PAl!n:)J!))1lJ'$3!A~33J,:j-3::>AnOS341

SllnJHIJH30HO-ONOJ3S

(I'''lI!S("y-lJ!'){+1''''~o:J('1'+I"L_~=[(lPmII!S{-"toSOJ'jty+(,''''01$1+"PtoSOJ)'r:L.._"E,(1)1

<,...,_alY+,,,,,,,,In,JO_a=Jf'<'of+"l_aly+__"l_a'y=(J)I

'..r-XI_.(e-!")-/\-o__'f'19{+D__~+D__I,

OOl>D:EHI

{:~J' '.-sr--'"-i"::~:':::+2-..... 1'+-,/1'1'-(/)1

111l!n::>A!):mJ$3!J~3lU;j-3::>JnOS341

SllnJHIJH30HO-ONOJ3S

006'0:ZHl

00l<D:tHI

SECOND-ORDER CIRCUITS

Khll<O

The Source-free ParallelRLC Circuit

"H~!Khil>O

SECOND-ORDER CIRCUITSThe Source-free ParallelRLC Circuit

xac dlnh Al va A2T~i1=0: 11(0)= 25 =A, + A, .... A, = 2S - A,

!!!!.. = -8SY,.- .... - 1-46.C,.-'....atdv(O)= 0 = -8S4A, - 1444, -+ 0 = 8S4A, + 146.(,at

-----> A, = -5.156. A,= 30.16

Vd: 11mviI) khl 1>0

GiOl

11(0)=~(40) =lx 40 =25V30 + 50 8

1(0)= -~= -OSA30+50 .iv(0). _1>(0) +.RI(O) = _ 2S - SOX O.S _ 0« JtC SOX 20 X 10-'

1 1o-iiC-1X 5OXlOX 10.... 500

.... 1. 1 -354"Vz:C Vo... X 20 )( 1021

s = -854, " = -146 -+ v(t) = .041,-- + ..4,.-loa.

PHANTfcH M~CH TRONGMIEN TAN56/(1) = Qo + ~ ...t.<os(nWo' + 4>.)

11=1

00 +~ A"eos(nwol + "'oJ = 00 + ~ (A.cos <I>.)e05nWot11'=1

- (A.sUI 4>.) sin nWot

b. - -...t. sin 4>.

Cac bLf6'e giai:

1. BI'u diln nguon kfchthich dU'ai d,ng chuBi Fourier noi tiep2. 811ndol m,cn tll miin Inal glan ,ang miin tan so3. Tim dap lrng cua cae thimh phin DC va AC trong chua! Fourier nol tiep4. Glal mach vai cae thilnh phin Dcva AC sau do xep chong kit qua I,i val nhau

PHANTfcH M~CH TRONGMIEN TAN56

Cae bLf6'e giai:

1. Bi~udien nguonkfchthfch dU'ai diiimi chuai Fourier nol til~p2. Bien c!ol moch tLr mien thai gian sang mien tan so3. TImdap Ltngcua cae tnann phlin DCva ACtrong chubi Fourier nc5iti~p

. 4. Giai m,ch v6i cae thanh phin Dc va AC sau do xep chong kit qua 1,1voi nhau

10/6/2017

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PHAN TfcH M~CH TRONG MI'£N TAN s6Bai4:nm Io(t).Biet .!!!!... 40 20

V(I) - 1 + i 2(-1~(""SIlI_ IIsin nr) [!J'll).=11 + II .(f) 2H 20

Wo =I,(1). - IIrad/s.

Z = 4 + j .. .2 Y4 = 4 + 1"",s _ 8 + j"',,84+jw.2 2+1 ....

V 2 +j61.I-----VZ 8+j.._s

I =_4_1=_V_• 4 + j ...2 4 +juI,,4

Thanh ph~n DC: ( .... = 0 or n = 0)

Thanh ph~n hai:

PHAN TrCH M~CH TRONG MI'£N TAN s6

rFl.(f)LLJ20

J., 1 2(-1)"/taD-1" _ (-1)"4~/taD-ln ~ - 2(1 + 112)

1 c--i=.!.L1.(1) - - + ~ 2 cos IIIA

4.=12{I+II)

PHAN TfcH M~CH TRONG MIEN TAN s6Bai5:Tim I(t).Blet

.. 1i,(I) - 1 + ~ ~cos 3111A.-1

PHAN TfcH M~CH TRONG MIEN TAN s6Ba;6:nm volt).Biet

vJ.t) - 3 + ~ i lsW(n1rt)11' __ I "

100·,(~rn·;oo

10/6/2011.

PHAN TfcH M~CH TRONG MI'EN TlN s6~17:nmlo(ll. Bift 10.

p(t)=i+ ~ i(r"'-~")v oIIIm+1'::.-1

PHAN TfcH M~CH TRONG MI'EN TlN s6eal B:Tlm I{II.Bift

1,(1)-1+ f;;\eoo:lltlA_I

. r

10/6/2017II.

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