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DE ClfONG ON THI CAD HOCMON: LY THUYET MACH DleN
Chuang 1:Nhiing khal ni~mco ban v~mach di~n.
5.1 Cac phan tUmach
5.1 C6ng suat va nang hrong
5.1 Phan loai mach di~n
5.1 Cac dinh lu~t co ban cua mach di~n
5.1 Bi~n d6i wang duong mach
Chuang 2: Mach xac l,p di~uhea
2.1 Qua trinh diSu hoa
2.2 Phuong phap bien dQphirc2.3 Quan h~ di~n ap va dong di~n tren cac phAnnr R, L, C. Tro khang va d~n
n~p2.4 Dinh lu~t Ohm, dinh lu~t Kirchhoff dang phirc
2.5 Cong s~t
2.6 Ph6i hQ'Ptro khang gifra tai va nguen
2.7 Mach cong huang
Chuang 3: Cac phmrngphap phflntieh mach
3.1 Phuong phap dong nhanh
3.2 Phuong phap th~ nut
3.3 Phuong phap dong m~t lucri
3.4 Mach ghep h6 cam
3.5 Cac dinh ly mach
Chuang 4: Mang hai efra
4.1 Khai niem chung4.2 Cac h~ plnrong trinh tr~ng thai cua m~ng hai cua
4.3 Phan lo~i m~ng hai cua
. 1
i .
I .
. (
I
I .
4.4 Cach n6i cac mang hai cira
4.5 Cac thong s6lam viec
4.6 Mach lQC
Chuong 5: Ph in tich qua di}dung phuong phap kinh di~n
5.1 M~ch RL
5.2 M~chRC
5.3 M~ch RLC voi nguen DC
5.4 Mach RLC voi nguon AC
5.5 Mach RLC voi nguon hi ham unit-step u(t)
Chirong 6: Ph in tich qua di}dung phunng phap bi~n dAi Laplace
6.1 Phep blen d6i Laplace va cac tinh ch~t
6.2 Dang toan t1i cua cac dinh lu~t mach co ban ' r
6.3 Bi~n d6i nguoc Laplace
6.4 Ap dung plnrong phap toan t1i phan tich qua trinh qua dQtrong mach TTD
6.5 Ap dung plnrong phap toan t1i phan tich h~ thong TTD
Chuong 7: Ph an tich mach trong mi~n tAn sa7.1 Phuong phap chu6i Fourier
7.2 Phan tich mach TID (y trang thai xac l~p tufin hoan khong sin
7.3 Phan tich mach UD voi nhieu nguon tac dQngdi~u hoa
7.4 Phuong phap bien d6i tich phan Fourier
TAl LIEU THAM KHAo•
1. Pham Thi Cu, Truong TrQng Tufut My, Le Minh' CUOng,M~ch di~n 1, NXB DR Qu6cGia TP.HCM, 2005.
2. Pham Thi Cu, Truong Trong TuAnMy, Le Minh CUOng,Bai t~p Mach Dien 1, tnrongDl,liHQcBach khoa. NXB D!l Qu6c Gia TP. HCM. 2005.
3. Pham Thi Cu, Truong Trong TuAnMy, Le Minh CUOng,Mach di~n 2, NXB DH Qu6cGia TP.HCM, 2005.
4. Pham Thi Cu, Truong TrQng TuAnMy, ts Minh CUOng,Bai t~p Ml,lchDi~n 2, tnrongDl,liHQcBach khoa. NXB DH Qu6c Gia TP. HCM. 2005.
5. Charles K. Alexander, Matthew N. O. Sadiku, Fundamentals of Electric Circuits, 5thedition, McGraw-Hill, 2013.
I .
ON T~P MJ:\CH 2
+ PHAN TfcH M~CH TRONG MI'£N TH01 GIAN+ PHAN TfcH M~CH TRONG MI'£N TA~56
First-Order CircuitstC'O,tRc 1/ R
ic+iR = 0do U dv vc-+-=o-+-+-=odt R dt RC
v(O) = Vo1
w(O) =2CV~
Source-Free RC Circuit
do 1-= --dtv RC
tlnu= -- +1nARC
In~ = - :C v(t) = Ae-t/R~ v(O)= A = Vo
... vet) = Voe-t/RC 'T = RC v(t)= Voe-r/t
First-Order CircuitsCho v,(0)=15Y. Tim ve, Vx va ix cho e-oGI'I
20 X 5Req = 20 + 5 = 4il
sott.
+ +O.lF =I=.c 120 II,.
Req =Rthevenin nhin tlr 2 eve cua C
.,.= RoqC = 4(0.1) = 0.4 sII = lI(O)e-tit = 15e-1/0.4V, lie = II = 15e-2.51V
v = _1_2-v = 0 6(lSe-2.5t) = ge-2.5,Vx 12+8 .
vix == 2.. = 0 75e-2.s.A12 .
First-Order CircuitsTim v(t) khi t;:::O. r.n2OV ....~ 20mF
GI'I
9vo(t) = 9 + 3(20) = ISV, t < 0
vo(O) = Vo = 15V
R... = 1 + 9 = IOil
'T = ReqC = 10 X 20 X 10-3 == 0.2 s
v(t) = vc(O)e-t/1' = 15e-t/o2 V
610/6/2017
1
First-Order CircuitsVfdl,l
TIm Vc,Vx, iokhi t~O. Biet vc(O)=45V
First-Order CircuitsVfdl,l
Tim V(t) khi QO
First-Order Circuitst-1 2w(O)=-Llo
2i(O) = 10
0+L "it-
VL + VR = 0di di RL-dt + Ri = 0 .. - + -I = 0
dt L
f 'CI)di I'R-= - -dtI. i 0 L
In 1[(.') = - RLt 1'0 => RtIn i(t) - In 10 = -1: + 0
In i(t) = _Rt ... i(t) = loe-IUIL10 L
.. jet) = loe-tIT
A source-freeRL circuit.
L-r=-
R
~Gi. ,hi" r&ng i(O)=lOA, tlnh i(l)
Ghil
4Q
;~~
O.5H~3;~,d 40
b
1,--3A, I. = -h = 3A61, - lS, - 31, - 0 => I, - ~I'
.0 I L! 3R",-Rn.-"'-j"0 T=R:=I=I'
.... ;(1)- 1(0).-'" - 10.-(2IljrA, 1> 0
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YI.!l!iTim Iva .. a trong mach .Gil thl't ring i(O)-SA
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ilDJ·"- 102H 40. .~ 2'!,
Vf du: dIng t~c dllO'cd6ng trong mOtthai glan dai,tal t=O.cOngt~c dllO'cma ra. Tfnh itt) khi t>O
Gi£1
~-304 + 12
40i, = 2 + 3 = SA
i(t)- _1_2_i, _ 6A t < 012 + 4 '
160 2H
i(O) - i(0-) - 6 A
R.q = (12 + 4) 116 = 8nL 2 1T-Req-i-4·
i(t) = i(O)e-t/r = 68-41 A
Vf du: Chomach nhu hlnh ve. TIm io,Vova i cho toan mien thai gian,·giathi~t r~ngcOngtk dil dllO'cma trong mOtthai gian dai,
GI£i
For t > 0,
2Q lQff111'IOV~lH
t> 0
Rn.-316-2fl
T - J:_ _ I. ;(,) - i(O)e-tl< - 2.-1 A,Rn.
dl -I -IVvJ,) = -vL = <z = -2(-2e ) =.. ,
tIt) = ilL= _;-tA"" 6 3 '
t> 0
t> 0
{6V.
.,,(0- 4c-'V,,<0,>0
, < 0,,,,0
Vf du: Chomach nhu hlnh ve. TIm jo, Vova i cho toan mien thai gian30
i = {12A,12e-1IA, {
6A,I. = -4e-2.A,
,<0
r « 0t"" 0'
t «: 0t>O'
i » 0
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Vi du: tim i(t) , t>O
--x120
:140 ~ D6A 1(1), 502H
DS: 2e-2t A, t > O.
so
Step Responseof an RC Circuit
(I)
/I.'0+~u(1) ..... c::
(b)
Step Responseof an RC CircuitAp dvng Kl; dong qua C b~ng dong qua R
Cdu u - V,u(I) 0 du v V,dl + --R- = dt + RC = RCu(t)
Fori> 0,
dv + ~ = !L. do = _ u - V, _!!!!_ = .s:dt RC RC dt RC U - V, RC
In(o ~ V,)IV(I)= - :cl' In ~o-_ ~s = - ;CY. 0
v - V, __ '/<v._V-e ,o sv - V, = (Vo - V,)e-t/-r
10/6/2017 .1
T = RC rr-- --,
IIJ(I) = {~~.+ (V. - V,~-'T.r « 0,> 0
U(I) .. V, + (Vo - VJe-r/., t > 0
Step Responseof an RC CircuitNfu ban dliu tl,l chua dlll1C nap thl c6 thf viet Iii
{a,
U(t) = V.(l - e-I/").t < 0t> 0
Khlc6 di~n ap rtIl thl to tlm dllqc dong di~n qua tv
I(t)= Cdu .. £V,e-r/T. T =, RC.dr T
1>0
DOlkhi ngU'b'ita ce th~ viet dllOi d~ng
U(/) = U(oo) + [V(O) - u(oo)]e-t/<
I.
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S!..!._~_'IJ.~•.1.
rf7
US""£+'lee'U~
Yl:=£+t=(00)1or
o<Iu;,ttA\
Htd'-,--WVv-r-\lV>/Ir-'
0=1
vs=CO)1=(+0)1=(0)1z vs=01=CO)I
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).
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.... Y(...._.+l)-...._I(OI-)(g·O-)jit·O+"'0_"''0-I-.,ot;;;;.:1+.=1
h(".•_#01-0,)-1«{.:>_lI(Ol-01)+0,=",_,[(.0)0-(0)0)+(co)o-(1)0
U.!.-_.!£_-otlol-""I{Ototx01
'1\01=.hOI-(_O)n-(0)<1
S!.!,..£_:>UN•.l ,rot
hot_(0£)01+Ot_(00)11YI-=.!!.--Iat~
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l!n::lJ!)JlJUVJO3suods3~d3lS
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Sl:=£_01xS'OxEOIx"=:J'UIJ=.I.
hSl=(+0)11=CO)II=(0)11
II.OE=(00)11
...+...,...~.~un(~••
OlltII"'"y0'1£
O<lJOl(ll"l.jU!p:>~X:!!~a
Step Response of lin RL CircuitSal 3: nm i(t) for t>O
For 1< 0 ;(0-) = /(0) - /(0+) = 0ForO~t<4
401(0)) K 4+""6 • 4 A. R... - 4 +6 - 10n 40V
L 5 11'-Rn -ii-2'51(,) - 1(.. ) + 11(0) - 1("')]0-'/'
- 4 +'(0- 4)o-~- 4(l- .-,,)AFor I .. 4 1(4) - 1(4-) - 4(1 - .~ - 4 A
v 30 4X2 221(<<»-6"-TI-2.727A Rn-412+6--6-+6-TO
1(1)- 1(<<»+ [1(4) - I(m»)f-CHlf., ... 4
M- 2.727 + (4 - 2.727)t-<t-il/·. 15.--220, I sO
1(1) - 4(1 - .-"). 0 oS • oS 42.727 + 1.273.-1MI7(t-~). I ,;e"
SECOND-ORDER CIRCUITS
R L
·Q-f·fcf'1"f f<3 ·Gl
'K
SECOND-ORDER CIRCUITSFinding Initilll lind Finlll Vlllues
The swild> i. Fi,. 8.2 Iw been closed for • Ioog time ... t is ope•• tI - O. FlDd: (I) I(O'~ 0(0·). (b) dI(O,,)ldl. dv(O·)/dl. (c) 1(00).0(.. ).
40..!._O.lSHI2VCD=t__;1U1(0-) _....!.L = 2A, v(0-) ~ 2/(0,- 4 V I(O'}- 1(0-) - 2A. v(o') - v(O-) - 4V
4+2At. - O· 1c(0+)- /(0+) - 2 A SinceC .tvl'" - Ie. .tvldl - IdC. and
dv(0') _ 1c(0")_.2.. _ 20VI. -12 + 4/(0+)+ v,(O') + v(0+) - 0til C 0,1
v,(O') • 12 - 8 - 4 _ 0 dl(O,,)_ ",(0,,) - ~ - 0 AI.<II L 0.25
ForI> 01(00) - OA. u(co) a 12V
SECOND-ORDER CIRCUITSThe Source-Free Series RLC Circuit
M,ch dll'lC kith thlth bOl nang h/qng ban d}u Irong l 11<1 C [23R Lv(O)=.!.J·,tIl=yo 1(0)-1. .c_ ,
• <Ii I f' CAppIyiog KVL RI + L'dr +c _1., = 0
~ + ,!.!!!.+ _!_ =- 0 ~ glAI pt nay chung ta dung 2 di~u kien ban dau.r Lal LC
dl(O) ITr - -Z(1I4 + "oJ
"l--a+~ ,s-l·-a-~
10/6/2017
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'D,JI>-7<--OOJ:D:,HI
,.?I!'+.,,..'I!'=(1)11
·,),V~<1uoq.....<D
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IP~-fl11 O=-:J+lpn-+- np,In
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V('6S('.II!'ZH9'O+l<!H'.10».....-(1)1...
zm'o-'Y._(ty+o-l6sn+(0+11')6-_9-0=1!~I{l6S("tIlO>'y+l<!S('tllJS'Y-)(6Sn),,_'+
(16SHII!"Y+I6SHso.>'n......6--* SfV9--[9-(1)6),--(0)/1+(O)R{lt--°l'I'_1_(0)1
nwuequ91~ntiPo.41Z\I'"t\l4ulp"X(16"'.""'I'+,'6S£·.<O'''''.._.-(,)I
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nt•dto·O01•",9
rr:a.'O.-O=llttdtl'\!X'1IP4'tw1f141elB'4'~wBuOJ,(1)1wU·PAl!n:)J!))1lJ'$3!A~33J,:j-3::>AnOS341
SllnJHIJH30HO-ONOJ3S
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<,...,_alY+,,,,,,,,In,JO_a=Jf'<'of+"l_aly+__"l_a'y=(J)I
'..r-XI_.(e-!")-/\-o__'f'19{+D__~+D__I,
OOl>D:EHI
{:~J' '.-sr--'"-i"::~:':::+2-..... 1'+-,/1'1'-(/)1
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SllnJHIJH30HO-ONOJ3S
006'0:ZHl
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SECOND-ORDER CIRCUITS
Khll<O
The Source-free ParallelRLC Circuit
"H~!Khil>O
SECOND-ORDER CIRCUITSThe Source-free ParallelRLC Circuit
xac dlnh Al va A2T~i1=0: 11(0)= 25 =A, + A, .... A, = 2S - A,
!!!!.. = -8SY,.- .... - 1-46.C,.-'....atdv(O)= 0 = -8S4A, - 1444, -+ 0 = 8S4A, + 146.(,at
-----> A, = -5.156. A,= 30.16
Vd: 11mviI) khl 1>0
GiOl
11(0)=~(40) =lx 40 =25V30 + 50 8
1(0)= -~= -OSA30+50 .iv(0). _1>(0) +.RI(O) = _ 2S - SOX O.S _ 0« JtC SOX 20 X 10-'
1 1o-iiC-1X 5OXlOX 10.... 500
.... 1. 1 -354"Vz:C Vo... X 20 )( 1021
s = -854, " = -146 -+ v(t) = .041,-- + ..4,.-loa.
PHANTfcH M~CH TRONGMIEN TAN56/(1) = Qo + ~ ...t.<os(nWo' + 4>.)
11=1
00 +~ A"eos(nwol + "'oJ = 00 + ~ (A.cos <I>.)e05nWot11'=1
- (A.sUI 4>.) sin nWot
b. - -...t. sin 4>.
Cac bLf6'e giai:
1. BI'u diln nguon kfchthich dU'ai d,ng chuBi Fourier noi tiep2. 811ndol m,cn tll miin Inal glan ,ang miin tan so3. Tim dap lrng cua cae thimh phin DC va AC trong chua! Fourier nol tiep4. Glal mach vai cae thilnh phin Dcva AC sau do xep chong kit qua I,i val nhau
PHANTfcH M~CH TRONGMIEN TAN56
Cae bLf6'e giai:
1. Bi~udien nguonkfchthfch dU'ai diiimi chuai Fourier nol til~p2. Bien c!ol moch tLr mien thai gian sang mien tan so3. TImdap Ltngcua cae tnann phlin DCva ACtrong chubi Fourier nc5iti~p
. 4. Giai m,ch v6i cae thanh phin Dc va AC sau do xep chong kit qua 1,1voi nhau
10/6/2017
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PHAN TfcH M~CH TRONG MI'£N TAN s6Bai4:nm Io(t).Biet .!!!!... 40 20
V(I) - 1 + i 2(-1~(""SIlI_ IIsin nr) [!J'll).=11 + II .(f) 2H 20
Wo =I,(1). - IIrad/s.
Z = 4 + j .. .2 Y4 = 4 + 1"",s _ 8 + j"',,84+jw.2 2+1 ....
V 2 +j61.I-----VZ 8+j.._s
I =_4_1=_V_• 4 + j ...2 4 +juI,,4
Thanh ph~n DC: ( .... = 0 or n = 0)
Thanh ph~n hai:
PHAN TrCH M~CH TRONG MI'£N TAN s6
rFl.(f)LLJ20
J., 1 2(-1)"/taD-1" _ (-1)"4~/taD-ln ~ - 2(1 + 112)
1 c--i=.!.L1.(1) - - + ~ 2 cos IIIA
4.=12{I+II)
PHAN TfcH M~CH TRONG MIEN TAN s6Bai5:Tim I(t).Blet
.. 1i,(I) - 1 + ~ ~cos 3111A.-1
PHAN TfcH M~CH TRONG MIEN TAN s6Ba;6:nm volt).Biet
vJ.t) - 3 + ~ i lsW(n1rt)11' __ I "
100·,(~rn·;oo
10/6/2011.