lecture 1: the greedy method 主講人 : 虞台文. content what is it? activity selection problem...

Lecture 1: The Greedy Method

主講人 :虞台文

Content

What is it? Activity Selection Problem Fractional Knapsack Problem Minimum Spanning Tree

– Kruskal’s Algorithm– Prim’s Algorithm

Shortest Path Problem– Dijkstra’s Algorithm

Huffman Codes


What is it?

The Greedy Method

A greedy algorithm always makes the choice that looks best at the moment

For some problems, it always give a globally optimal solution.

For others, it may only give a locally optimal one.

Main Components

Configurations– different choices, collections, or values to find

Objective function– a score assigned to configurations, which we w

ant to either maximize or minimize

Example: Making Change

Problem– A dollar amount to reach and a collection of coin

amounts to use to get there. Configuration

– A dollar amount yet to return to a customer plus the coins already returned

Objective function– Minimize number of coins returned.

Greedy solution– Always return the largest coin you can

Is the solution always optimal?

Example: Largest k-out-of-n Sum

Problem– Pick k numbers out of n numbers such that the sum of

these k numbers is the largest. Exhaustive solution

– There are choices.– Choose the one with subset sum being the largest

Greedy SolutionFOR i = 1 to k

pick out the largest number and delete this number from the

input.ENDFORIs the greedy solution always optimal?

nkC

Example:Shortest Paths on a Special Graph

Problem– Find a shortest path from v0 to v3

Greedy Solution

Example:Shortest Paths on a Special Graph


Greedy Solution

Is the solution optimal?

Example:Shortest Paths on a Multi-stage Graph


Is the greedy solution optimal?




The optimal path

The optimal path




The optimal path

The optimal path

What algorithm can be used to find the optimum?

What algorithm can be used to find the optimum?

Advantage and Disadvantageof the Greedy Method

Advantage– Simple– Work fast when they work

Disadvantage– Not always work Short term solutions can

be disastrous in the long term– Hard to prove correct


Activity Selection Problem

Activity Selection Problem(Conference Scheduling Problem)

• Input: A set of activities S = {a1,…, an}

• Each activity has a start time and a finish timeai = [si, fi)

• Two activities are compatible if and only if their interval does not overlap

• Output: a maximum-size subset of mutually compatible activities

Example:Activity Selection Problem

Assume that fi’s are sorted.


0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

12

34

56

789

1011


0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

12

34

56

789

1011

Is the solution optimal?

Activity Selection Algorithm

Greedy-Activity-Selector (s, f) // Assume that f1 f2 ... fn n length [s] A { 1 } j 1 for i 2 to n if si fj then

A A { i } j i

return A

Greedy-Activity-Selector (s, f) // Assume that f1 f2 ... fn n length [s] A { 1 } j 1 for i 2 to n if si fj then

A A { i } j i

return A

Is the algorithm optimal?

Proof of Optimality

Suppose A S is an optimal solution and the first activity is k 1.

If k 1, one can easily show that B = A – {k} {1} is also optimal. (why?)

This reveals that greedy-choice can be applied to the first choice.

Now, the problem is reduced to activity selection on S’ = {2, …, n}, which are all compatible with 1.

By the same argument, we can show that, to retain optimality, greedy-choice can also be applied for next choices.


Fractional Knapsack Problem

The Fractional Knapsack Problem

Given: A set S of n items, with each item i having– bi - a positive benefit– wi - a positive weight

Goal: Choose items, allowing fractional amounts, to maximize total benefit but with weight at most W. maximize ( / )i i i

i S

b x w

subject to ,0i i ii S

x W x w

The Fractional Knapsack Problem

maximize ( / )i i ii S

b x w


x W x w

wi :bi :

1 2 3 4 5

4 ml 8 ml 2 ml 6 ml 1 ml

$12 $32 $40 $30 $50

Items:

3Value:($ per ml)

4 20 5 5010 ml

Solution:• 1 ml of 5• 2 ml of 3• 6 ml of 4• 1 ml of 2

“knapsack”

The Fractional Knapsack Algorithm


b x w


x W x w

Greedy choice: Keep taking item with highest value

Algorithm fractionalKnapsack(S, W)

Input: set S of items w/ benefit bi and weight wi; max. weight W

Output: amount xi of each item i to maximize benefit w/ weight at most W

for each item i in S

xi 0

vi bi / wi {value}w 0 {total weight}

while w < W

remove item i with highest vi

xi min{wi , W w}

w w + min{wi , W w}

Algorithm fractionalKnapsack(S, W)

Input: set S of items w/ benefit bi and weight wi; max. weight W

Output: amount xi of each item i to maximize benefit w/ weight at most W

for each item i in S

xi 0

vi bi / wi {value}w 0 {total weight}

while w < W

remove item i with highest vi

xi min{wi , W w}

w w + min{wi , W w}

Does the algorithm always gives an optimum?

Does the algorithm always gives an optimum?

Proof of Optimality


b x w


x W x w

Suppose there is a better solution Then, there is an item i with higher value than a chos

en item j, but xi < wi, xj > 0 and vi > vj

Substituting some i with j, we’ll get a better solution

How much of i: min{wi xi, xj}

Thus, there is no better solution than the greedy one

Recall: 0-1 Knapsack Problem

Which boxes should be chosen to maximize the amount of money while still keeping the overall weight under 15 kg ?

Is the fractional knapsack algorithm applicable?

Is the fractional knapsack algorithm applicable?

Exercise

1. Construct an example show that the fractional knapsack algorithm doesn’t give the optimal solution when applying it to the 0-1 knapsack problem.


MinimumSpanning Tree

What is a Spanning Tree?

A tree is a connected undirected graph that contains no cycles

A spanning tree of a graph G is a subgraph of G that is a tree and contains all the vertices of G

Properties of a Spanning Tree

The spanning tree of a n-vertex undirected graph has exactly n – 1 edges

It connects all the vertices in the graph A spanning tree has no cycles

Undirected Graph

Some Spanning Trees

AA

EEDD

CC

BB AA

EEDD

CC

BB AA

EEDD

CC

BB

What is a Minimum Spanning Tree?

A spanning tree of a graph G is a subgraph of G that is a tree and contains all the vertices of G

A minimum spanning tree is the one among all the spanning trees with the lowest cost

Applications of MSTs

Computer Networks– To find how to connect a set of computers

using the minimum amount of wire

Shipping/Airplane Lines– To find the fastest way between locations

Two Greedy Algorithms for MST

Kruskal’s Algorithm– merges forests into tree by adding small-

cost edges repeatedly

Prim’s Algorithm– attaches vertices to a partially built tree

by adding small-cost edges repeatedly

Kruskal’s Algorithm

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MST-Kruksal(G)T ← Øfor each vertex v V[G]

Make-Set(v) // Make separate sets for verticessort the edges by increasing weight wfor each edge (u, v) E, in sorted order

if Find-Set(u) ≠ Find-Set(v) // If no cycles are formedT ← T {(u, v)} // Add edge to TreeUnion(u, v) // Combine Sets

return T

MST-Kruksal(G)T ← Øfor each vertex v V[G]



return T

G = (V, E) – Graph

w: ER+ – Weight

T Tree


w: ER+ – Weight

T Tree

Time Complexity

MST-Kruksal(G , w)T ← Øfor each vertex v V[G]



return T

MST-Kruksal(G , w)T ← Øfor each vertex v V[G]



return T


w: ER+ – Weight

T Tree


w: ER+ – Weight

T TreeO(1)O(1)

O(|V|)O(|V|)

O(|E|)O(|E|)

O(|V|)O(|V|)

O(1)O(1)

O(|E|log|E|)

O(|E|log|E|)O(|E|log|E|)

Prim’s Algorithm

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Prim’s Algorithm

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Prim’s AlgorithmMST-Prim(G, w, r)

Q ← V[G] // Initially Q holds all verticesfor each u Q Key[u] ← ∞ // Initialize all Keys to ∞ Key[r] ← 0 // r is the first tree node π[r] ← Nil

while Q ≠ Ø u ← Extract_min(Q) // Get the min key node for each v Adj[u] if v Q and w(u, v) < Key[v] // If the weight is less than the Key

π[v] ← u Key[v] ← w(u, v)

MST-Prim(G, w, r)Q ← V[G] // Initially Q holds all verticesfor each u Q Key[u] ← ∞ // Initialize all Keys to ∞ Key[r] ← 0 // r is the first tree node π[r] ← Nil



G = (V, E) – Graphw: ER+ – Weight

r – Starting vertex

Q – Priority Queue

Key[v] – Key of Vertex v

π[v] –Parent of Vertex v

Adj[v] – Adjacency List of v







MST-Prim(G, r)Q ← V[G] // Initially Q holds all verticesfor each u Q Key[u] ← ∞ // Initialize all Keys to ∞ Key[r] ← 0 // r is the first tree node π[r] ← Nil



MST-Prim(G, r)Q ← V[G] // Initially Q holds all verticesfor each u Q Key[u] ← ∞ // Initialize all Keys to ∞ Key[r] ← 0 // r is the first tree node π[r] ← Nil



Time ComplexityO(|E|log|V|)













Optimality

Kruskal’s Algorithm– merges forests into tree by adding small-

cost edges repeatedly

Prim’s Algorithm– attaches vertices to a partially built tree

by adding small-cost edges repeatedly

Are the algorithms optimal?Are the algorithms optimal?

Yes


Shortest Path Problem

Shortest Path Problem (SPP)

Single-Source SPP– Given a graph G = (V, E), and

weight w: ER+, find the shortest path from a source node s V to any other node, say, v V.

All-Pairs SPP– Given a graph G = (V, E), and

weight w: ER+, find the shortest path between each pair of nodes in G.

Dijkstra's Algorithm

Dijkstra's algorithm, named after its discoverer, Dutch computer scientist Edsger Dijkstra, is an algorithm that solves the single-source shortest path problem for a directed graph with nonnegative edge weights.


Start from the source vertex, s Take the adjacent nodes and update the

current shortest distance Select the vertex with the shortest distance,

from the remaining vertices Update the current shortest distance of the

Adjacent Vertices where necessary,– i.e. when the new distance is less than the existing

value Stop when all the vertices are checked


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1399


Dijkstra(G, w ,s)for each vertex v V[G]

d[v] // Initialize all distances to π[v] Nil

d[s] 0 // Set distance of source to 0 S Q V[G]while Q ≠

u Extract_Min(Q) // Get the min in Q S S {u} // Add it to the already known list for each vertex v Adj[u] if d[v] > d[u] + w(u, v) // If the new distance is shorter

d[v] d[u] + w(u, v) π[v] u

Dijkstra(G, w ,s)for each vertex v V[G]

d[v] // Initialize all distances to π[v] Nil

d[s] 0 // Set distance of source to 0 S Q V[G]while Q ≠

u Extract_Min(Q) // Get the min in Q S S {u} // Add it to the already known list for each vertex v Adj[u] if d[v] > d[u] + w(u, v) // If the new distance is shorter

d[v] d[u] + w(u, v) π[v] u


s – Source

d[v] – Current shortest distance from s to v

S – Set of nodes whose shortest distance is known

Q – Set of nodes whose shortest distance is unknown


s – Source

d[v] – Current shortest distance from s to v

S – Set of nodes whose shortest distance is known

Q – Set of nodes whose shortest distance is unknown


Huffman Codes

Huffman Codes

Huffman code is a technique for compressing data.– Variable-Length code

Huffman's greedy algorithm look at the occurrence of each character and it as a binary string in an optimal way.

Example

a b c d e f

Frequency 45,000 13,000 12,000 16,000 9,000 5,000

Suppose we have a data consists of 100,000 characters with following frequencies.

Fixed vs. Variable Length Codes

a b c d e f

Frequency 45,000 13,000 12,000 16,000 9,000 5,000

Suppose we have a data consists of 100,000 characters with following frequencies.

Fixed Length Code 000 001 010 011 100 101

Variable Length Code 0 101 100 111 1101 1100

Total Bits:

Fixed Length Code

Variable Length Code

145,000 + 313,000 + 312,000 + 316,000 + 49,000 + 45,000= 224,000

345,000 + 313,000 + 312,000 + 316,000 + 39,000 + 35,000= 300,000

Prefix Codes

a b c d e f

Frequency 45% 13% 12% 16% 9% 5%


In which no codeword is a prefix of other codeword.

a:45a:45

c:12c:12 b:13b:13 d:16d:16

f:5f:5 e:9e:9

0 1

0 1

0 1 0 1

0 1

Encode

Decode

aceabfd=0100110101011100111

0100110101011100111

a c e a b f d

Huffman-Code Algorithm

a b c d e f

Frequency 45% 13% 12% 16% 9% 5%


a:45a:45

c:12c:12 b:13b:13 d:16d:16

f:5f:5 e:9e:9

0 1

0 1

0 1 0 1

0 1

100

14

3025

55


a:45a:45c:12c:12 b:13b:13 d:16d:16f:5f:5 e:9e:9

5%9%16%12%13%45%Frequency

110011011111001010Variable Length Code

fedcba

5%9%16%12%13%45%Frequency


fedcba

f:5f:5 e:9e:9

0 1

14


a:45a:45c:12c:12 b:13b:13 d:16d:16f:5f:5 e:9e:9

5%9%16%12%13%45%Frequency


fedcba

5%9%16%12%13%45%Frequency


fedcba

f:5f:5 e:9e:9

0 1

14

a:45a:45c:12c:12 b:13b:13 d:16d:16

f:5f:5 e:9e:9

0 1

14


a:45a:45c:12c:12 b:13b:13 d:16d:16

f:5f:5 e:9e:9

0 1

14

c:12c:12 b:13b:13

0 125


a:45a:45c:12c:12 b:13b:13 d:16d:16

f:5f:5 e:9e:9

0 1

14

c:12c:12 b:13b:13

0 125

a:45a:45d:16d:16

f:5f:5 e:9e:9

0 1

14

c:12c:12 b:13b:13

0 125


a:45a:45d:16d:16

f:5f:5 e:9e:9

0 1

14

c:12c:12 b:13b:13

0 125

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30


a:45a:45d:16d:16

f:5f:5 e:9e:9

0 1

14

c:12c:12 b:13b:13

0 125

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

a:45a:45

c:12c:12 b:13b:13

0 125

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30


a:45a:45

c:12c:12 b:13b:13

0 125

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

0 1

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

c:12c:12 b:13b:13

0 125

55


a:45a:45

c:12c:12 b:13b:13

0 125

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

0 1

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

c:12c:12 b:13b:13

0 125

55

a:45a:450 1

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

c:12c:12 b:13b:13

0 125

55


c:12c:12 b:13b:13

0 125

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

a:45a:450 1

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

c:12c:12 b:13b:13

0 125

55

a:45a:45

0 1100

0 1

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

c:12c:12 b:13b:13

0 125

55


c:12c:12 b:13b:13

0 125

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

a:45a:450 1

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

c:12c:12 b:13b:13

0 125

55

a:45a:45

0 1100

0 1

d:16d:16

0 1

f:5f:5 e:9e:9

0 1

14

30

c:12c:12 b:13b:13

0 125

55

Huffman tree built


Huffman (C)n |C| Q C for i 1 to n 1 z Allocate-Node () x left[z] Extract-Min (Q) // least frequent y right[z] Extract-Min (Q) // next least f[z] f[x] + f[y] // update frequency Insert ( Q, z ) return Extract-Min (Q)

Huffman (C)n |C| Q C for i 1 to n 1 z Allocate-Node () x left[z] Extract-Min (Q) // least frequent y right[z] Extract-Min (Q) // next least f[z] f[x] + f[y] // update frequency Insert ( Q, z ) return Extract-Min (Q)

Optimality

Exercise

lecture 1: the greedy method 主講人 : 虞台文. content what is it? activity selection problem...

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