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Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Lecture Note for Solid Mechanics- Stresses in Beam -
Prof. Sung Ho YoonDepartment of Mechanical EngineeringKumoh National Institute of Technology
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Text book : Mechanics of Materials, 6th ed.,
W.F. Riley, L.D. Sturges, and D.H. Morris, 2007.
Prerequisite : Knowledge of Statics, Basic Physics, Mathematics, etc.
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Flexural Loading : Stresses in Beam
Beam : member subjected to loads applied transverse to the long dimension, which cause the member to bend.
Beams are classified on their supports or reactions.
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Introduction
(a) Simple beam- supported by a roller- having on span- normal reaction and no couple
(b) Simple beam with overhang
(c) Continuous beam- with more than two simple supports
(d) Cantilever beam- one end is built into a wall- neither move transversely nor rotate
(e) Beam fixed at left end and simply supported near the other end
(f) Beam fixed at both ends
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
:rV Resisting shear at the section:rM Resisting moment at the section
:R Reaction at the section
0yF
o is any axis perpendicular to xy plane
From a free body diagram of entire beam
R From
rV
0oM From
rM
Ar
Ar
dAyM
dAV
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Flexural strains
Neutral surface : surface of which longitudinal elements undergo no change in length
Plane section before bending remains a plane after bending
Neutral axis : intersection of neutral surface with any cross section
i
ifx L
LLL
yyx
xxx
1
)()())(('
Strain developed in a fiber is directly proportional to the distance of the fiber from the neutral surface of the beam
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Flexural stresses
For linear elastic action
Normal stress on transverse cross section of the beam varies linearly with distance y from the neutral surface
yEE xx
A xAr dAydFyM
For the equilibrium equation
0
0
AyEdAyE
dAyEdA
dAdFF
cA
AA x
A xAx
Neutral axis passes through the centroid of the cross section
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
where c is the distance to the surface of the beam farthest from the neutral surface
cE
max
A
cA xr dAy
cdAyM 2
cx cy
cyyE
max
Second moments of more complex areas can be derived from combinations of simple shapes
yEE xx by using
: second moment of area
ycE x
max
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Elastic flexural formula
For elastic flexural formula
yI
Mrx
For the non-symmetric sections about y-axis
where S is the section modulus of the beam.
SM
IcM rr max
0 yzc
Ac
Ac
A x Ic
zydAc
dAyc
zdAz
where Iyz is the mixed second moment of cross sectional area with respect to the centroidal y- and z-axes.
By considering equilibrium equation, 0yM
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
yIM
IyM x
rr
x
(Example) The maximum flexural stress at a given is 15 MPa. Determine (a) the resisting moment developed at the section, (b) percentage decrease in resisting moment if the dotted portion of the cross section is removed
(a) By using
464633
10676610676612
20010012
mmmbhI )(.)(.
mkNmNc
IM xr
10101010100
1067661015 33
66
)()(
)(.)(
(b) 4646333
106521065212
1505012
20010012
mmmbhI )(.)(.
mkNmNc
IM xr
8971089710100
106521015 33
66
.)(.)(
)(.)(
%.. 12110010
89710
Ddecreasepercent
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
AMyAydAy A
ccA
(Example) On a section where resisting moment is -75kN-m, determine (a) maximum tensile flexural stress, (b) maximum compressive flexural stress.
The neutral axis is horizontal and passes through the centroid of the cross section
mmA
My
mmMmmA
Ac
A
9550012
5001871500187120075501002515051225200
50012755025150252003
2
,,,
,,))(())(().)((,)()()(
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
For part A :
2CxCx yAII '
The second moment of area of the part w.r.t. horizontal centroidal axis of the total cross section
4623
2 1013421055075125075 mmyAII CAAxCAAx )(.))(()(
'
Similarly
4623
2
4623
2
1029345822520012
25200
101375150251215025
mmyAII
mmyAII
CCBxCCCx
CBBxCBBx
)(.).)(()(
)(.))(()(
'
'
4646 105583105583 mmmIIII CxBxAxx )(.)(.''''
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
MPamNIyM tr 7116107116
105583101301075 26
6
33
./)(.)(.
))()()((max
(a) Since resisting moment is negative, maximum tensile flexural stress occurs at the top of the beam
(b) Maximum compressive flexural stress occurs at the bottom of the beam
MPamNIyM br 385102885
10558310951075 26
6
33
./)(.)(.
))()()((max
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Shear forces and bending moments
Force equilibrium equation,
rr VVorVPwxR
where V is the resultant of the external transverse forces called as transverse shear at the section
Moment equilibrium equation,
rr MMorMhxPwxRx )(2
2
where M is the algebraic sum of the moments of the external forces called as bending moment at the section
0yF
0oM
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(Example) Write equations for the shear force V and the bending moment M (a) in the interval AB, (b) in the interval BC, (c) in the interval CD.
062000564008
022000364008
2
1
)())(()(
)())(()(
RM
RM
A
D
lbRandlbR 30001400 21
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(a)
)( ftxlbVVFy
201400
01400
)( ftxlbftxMMxMo
201400
01400
(b)
)()(
ftxlbxVVxFy
622200400
024001400
)(
)(
ftxlbftxxM
MxxxMo
628002200200
02
224001400
2
(c)
)()(
ftxlbxVVxFy
86200400
0200024001400
)(
)()(
ftxlbftxxM
MxxxxMo
8611200200200
0620002
224001400
2
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(c)
)()(
ftxlbxVVxFy
86200400
0200024001400
)(
)()(
ftxlbftxxM
MxxxxMo
8611200200200
0620002
224001400
2
similarly
)()(
ftxlbxVxVFy
86200400
030008400
)(
)()(
ftxlbftxxM
xxxMMo
8611200200200
0830002
88400
2
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(Example) On a section 3m to the right of A, determine (a) flexural stress at a point 25mm below the top of the beam, (b) maximum flexural stress on the section.
kNRRM
A
AB
62
081210768220
)()())(()(
S152X19
mkNMMMo
16
07103625258 )()().)((
mdmSmI
1524.0)10(121)10(20.9
36
46
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(a) At a point 25mm below the top of the beam,
MPamNIyM
mmmdy
08910048910209
051201016
05120251252
4152252
266
3
./)(.)(.
).)((
...
(b) Maximum flexural stress
)(.)(.
/)(.)(
)(max
CMPaTMPa
mNSM
IMc
2313223132
1023132101211016 26
6
3
on the bottomon the top
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Load, Shear force and Bending moment
Mathematical relationships between loads, shear forces, and bending moments
0yF
From force equilibrium
xwPVVVPxwV
avg
LavgL
0)(
(1) If P=0 and w=0, shear force is constant
RL VVV 0
(2) If , shear force jumps by the concentrated load as
PVVPV LR
(3) If , the slope of shear force graph is equal to the intensity of loading as
wdxdV
xVxwV
xavg
0
lim
0P
2
1
2
1120
x
x
V
VxwdxdVVVw
dxdV
xVlim
Change in shear between sections is equal to the area under the load diagram
0x
0P0x
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
0centerM
From moment equilibrium
022
)()()( xwaxVVxVCMMM avgLLLL
wwandaxas
xaxforxwaxVxVCM
avg
avgL
00222
,
)(
(1) If , bending moment jumps by C as
CMMCM LR
(2) If , the slope of bending moment is equal to the value of shear force at that section as
)( xwaxVxVM avgL
2
0C
00 PC ,
VdxdM
xM
x
0lim
2
1
2
112
x
x
M
MVdxdMMM
0x
0x
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
Shear and bending moment diagrams provide a convenient method for obtaining maximum values of shear and bending moment.
(2) algebraic equations in case of uniformly distributed or varies according to a known equation
(3) drawing shear diagram from the load diagram and bending moment diagram from shear diagram
(1) calculating values of shear and bending moment at various sections
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(Example) (a) write equations for shear and bending moment in AB, (b) write equations for shear and bending moment in BC, (c) draw complete shear and bending moment diagrams for the beam
(a) Section in AB
lbftMandlbVMM
VF
CC
CC
Cy
86001700
03620010500
06200500
))(()(
)(
:0 yFftxforlbV
VFy
40500
0500
:0 OMftxforlbftxM
MxMO
40500
0500
)(
(b) Section in BC
:0 yFftxforlbxV
VxFy
104200300
04200500
)(
:0 OM
ftxforlbftxxM
MxxxMO
1041600300100
02442005002
/))(()(
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(Example) (a) write equations for shear and bending moment for any section in CD, (b) draw complete shear and bending moment diagrams for the beam
(a) Section in (c)
kNRandkNRRM
RM
A
D
2610
0538537445
0518517445
21
2
1
).().)(()(
).().)(()(
:0 yFmxforkNxV
VxFy
55324
08410
.
)(
:0 OM
mxformkNxxM
MxxxxMO
5533222
0538424102
.
).())(()(
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Shear stresses in beams
Beam by stacking flat slabs one on top of another without fastening them together
Relative motion of the ends of the cards with respect to each otherSolid beam does not exhibit this relative movementIndication of presence of shearing stress on longitudinal planes
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
stressflexuralI
MywheredAF
dytdAdF
:
c
yA
c
yA
dytyI
MMdAyI
MMF
dytyIMdAy
IMF
1
1
2
1
)()()(
)(
c
yH dytyIMFFV
112 )(
c
y
c
yx
c
ys
Havg
dytytIdx
dMdytytIx
M
dytyxtI
MAV
11
1
110
)()(lim
)(
tIQV
H
Differential force on area dA
Resultant normal forces
Summation in horizontal direction
(continued)
: Q is first moment of area
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
21
22
221
1
yhI
VdytytI
V
dytytI
VtIQV
h
y
c
y
Transverse shear stress at a point of section
(continued)
AV
htV
hthV
IhV
23
23
1288 3
22
max
This equation is used for rectangular cross section Maximum shear stress is 1.5 times average shear stress
This equation is worthless for I-beam or T-sections
For rectangular cross sections3% error : beam with depth having twice width
12% error : beam with square cross section100% error : beam with width having four times depth
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
inyC 4)2(10)10(2
)1)(2(10)7)(10(2
(continued)
Transverse shear stress at a point of section
)( 82822 1
21
221
21
1
1
yyI
VycI
V
dytytI
VtIQV c
y
Location of centroid
Discontinuity at a junction of flange and stem because of abrupt thickness change
Maximum longitudinal and transverse shear stresses occur at the neutral surface at a section where transverse shear V is maximum.
)( 24422 1
21
221
22
2
1
yyI
VycI
V
dytytI
VtIQV c
y
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
Let shear V be 37.5 kN for W203 X 22 section (I=20*106mm4)
at the neutral axis
MPamNtIQV
mmmQ
w
NANA
NA
932108932
10261002010761081053710761081076108
5472695998102
26
36
63
3633
./)(.))(.)((.))(.)((.)(.)(.
).)(.())((
at the junction between web and flange
MPamNtIQV
mmmQ
w
JJ
J
424104324
10261002010788010537
107880107880998102
26
36
63
3633
./)(.))(.)((.))(.)((.
)(.)(.))((
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
Beam with a solid circular cross section subjected to V
- Shear force cause shear stress, yxxy
- Resolve this shear stress into n-t coordinate system
xnxtxy and
0 nxxn - Outside surface is a free surface
- At neutral axis, shear stress in the direction of V is
AV
rrrrV
ItVQ
NA
NANA 3
424
3424
2
)()(
))((max
- Any shearing stress at point A must be tangential to the surface of the shaft and not in the direction of shear force
32
34
2
32 rrrQNA
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(Example) Determine
(a) average shearing stress on a horizontal plane 4” above the bottom of the beam and 6’ from the left support
Shear force V on 6’ from the left support is 900 lbFirst moment Q4 is
3444 48426 inAyQ C ))((
Second moment of area about the neutral axis is
Average shearing stress on a horizontal plane 4” above is
42323 253332102101213102102
121 inINA .))(())(())(())((
psitI
VQNA
54022533
48900
4
44 .
)(.)(
(b) Maximum transverse shearing stress in the beam
Maximum shearing stress will occur at the neutral axis on the cross section occurring largest shear force V.
364824 inQNA ))((
psitI
VQsNA
NA 05422533
64900 .)(.)(
max
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(c) Average shearing stress in the joint between the flange and the stem at 6’ from the left support
psitI
VQinAyQ
sNA
FJ
FCFF
65022533
60900602103 3
.)(.)(
))((
(d) Force transmitted from the flange to the stem by the glue in a 12” length of the joint at a section 6’ from the left support
lbAV JJg 112152126350 .))((.
(e) Maximum tensile flexural stress in the beam
)(..
))((maxmax Tpsi
IcM 11215
35338126750
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Principal stresses in flexural members
To find principal stresses and maximum shearing stresses at the selected points on the sections of maximum shear V and maximum bending moment M
flexural stress is maximum
transverse and longitudinal shearing stresses are zero
flexural stresses are principal stress
20
pmax
transverse and longitudinal shearing stressesare maximum
flexural stress is zero
Shearing stresses are maximum shearing stresses
At point on the top and bottom edge of the section
At point on neutral axis
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(Example) Cantilever beam carries a uniformly distributed load of 160kN/m on a span of 2.5m. Determine maximum normal and shearing stresses in the beam.
Maximum bending moment and shearing transverse shear are
kNwLV
mkNwLM
400)5.2(160
5002
)5.2(1602
22
W610x145I=1243x106 mm2
S=4079x103 mm3
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
At neutral axis, flexural stress is zero and
MPamNtI
VQmmQNA
06110986001190101243
10255210400
102552614291112852957198304
266
33
36
./)(.).)((
))(.)(()(.).)(.(.))(.(.
In the web at the junction with top flange
MPamNtI
VQmmQJ
94710894701190101243
10771110400
1077112957198304
266
33
36
./)(.).)((
))(.)(()(.))(.(.
)(./)(.)(
).)()(( TMPamNIyM 71141068114
1012432851010500 26
6
3
At the top surface, transverse shearing stress is zero and
)(./)(.)(
)( TMPamNSM
IyM 61221058122
10409710500 26
6
3
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
For the points at the junction of web and flange
deg..
).(tantan
..).(.)(....)(....
..
).(..
minmaxmax
,
9319068114
89472212
21
47441742
3717051322
3417341741743457
1132051324174345741743457
89472
0681142
068114
22
11
2
1
22
22
21
yx
xyp
p
p
xyyxyx
pp
MPaMPa
CMPaMPaTMPaMPa
Stress Top edge Junction Neutral axis
p1 122.6 MPa(T) 132.1 MPa(T) 61.0 MPa (T)
p2 0 17.37 MPa (C) 61.0 MPa (C)
max 61.3 MPa 74.7 MPa 61.0 MPa
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Flexural stresses – Unsymmetric bending
zkyka 21
stress variation is
Arz
Ary
A
dAyM
dAzM
dAR
0
force and moment equilibrium are
AAArz
AAAry
AAA
dAyzkdAykdAyaM
dAzkdAyzkdAzaM
zdAkydAkdAaR
22
1
221
21 0
The origin of coord. is at the centroid of cross section
AyzAyAz
AA
dAyzIdAzIdAyI
dAzdAy
,, 22
0
Iy, Iz : second moment of areaIyz : mixed second moment of area
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Flexural stresses – Unsymmetric bending
yzzrz
yyzry
IkIkMIkIkM
AaR
21
21
0
22
21
0
yzzy
yzrzzry
yzzy
yzryyrz
IIIIMIM
k
IIIIMIM
k
a
elastic flexural formula for unsymmetric bending is
rzyzzy
yzyry
yzzy
yzz
yzzy
yzrzzry
yzzy
yzryyrz
MIII
zIyIM
IIIyIzI
zIII
IMIMy
IIIIMIM
22
22
orientation of neutral axis is
0 zIMIMyIMIM yzrzzryyzryyrz )()(
zIMIMIMIM
yyzryyrz
yzrzzry
slope of neutral axis is
yzryyrz
yzrzzry
IMIMIMIM
dzdy
tan
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
(Example) (a) Flexural stress at A
)(..)()()(
).()( Cksiksi
MIII
zIyI
MIII
zIyIM
IIIyIzI
A
rzyzzy
yzy
rzyzzy
yzyry
yzzy
yzz
78107810300108240135
5410841352
2
22
(b) Orientation of neutral axis
deg.
.tan
738
8000135108
y
yz
yzryyrz
yzrzzry
II
IMIMIMIM
(c) Maximum tensile and compressive flexural stresses
)(..)()()(
).()().,(
)(..)()()(
).()().,(
Tksiksi
CAt
Cksiksi
BAt
B
B
16101610300108240135
511084135514
16101610300108240135
511084135514
2
2
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Stress concentrations under flexural loadings
flexural stress in smooth member
IMy
flexural stress in the vicinity of discontinuity
IMyK K : stress concentration factor that depends on geometry of the member
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
(continued)
494333
1016510165122550
12
41252
10301030
mmmbhI
MPaFS
MPa
uall
u
)(.)(.)(.
(Example) Cantilever is made of SAE 4340 steel and is 50mm wide. Determine the maximum safe moment M if FS of 2.5 with respect to failure by fracture is specified.
(1) For r=5mm,5112025532575 .., tKhrhw
(2) For r=10mm
28140251032575 .., tKhrhw
(3) For r=15mm18160251532575 .., tKhrhw
ttt
a
KKyKIM 2146
105121016510412
3
96
))(.())(.)((
yI
KyIM
IMy
t
all
(1) For r=5mm mNK
Mt
1421511
21462146.
using
Advanced Materials & Smart Structures Lab.금오공대기계공학과 윤성호교수
Homework
(7-4), (7-21), (7-35), (7-40), (7-55), (7-72),
(7-80), (7-109)