luythua mu logarit
TRANSCRIPT
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Chuyn 5
Hm S Ly Tha. Hm S M & HmS Lgarit
1. Ly Tha
A. Kin Thc Cn Nh
1. Cc nh ngha.Ly tha vi s m nguyn dng: an = a.a...a
n tha s
(a R, n N).
Ly tha vi s m 0: a0 = 1 (a = 0).Ly tha vi s m nguyn m: an = 1
an (a = 0, n N).
Cn bc n: bl cn bc n ca a bn =a.Lu : Khi n l th ac ng mt cn bc nl n
a.
Khi n chn th a 0 c hai cn bc nl
n
a.Ly tha vi s m hu t: amn = nam (a >0; m, n Z; n 2).Ly tha vi s m thc: a = lim
n+arn
a >0; (rn) Q; lim
n+rn=
.
2. Cc tnh cht ca ly tha vi s m thc.Cho hai s a,b >0 v, l nhng s thc tu . Ta c
a.a =a+. a
a =a.
(a) =a. (ab) =a.b.
ab
=
a
b.
Nu a >1 th a > a > . Nu 0 < a a < .
Nu >0 th 0 < a < b
a < b.
Nu b.
B. Bi Tp
5.1. Tnh gi tr cc lu tha sau
a)(0, 04)1,5 (0, 125) 23 . b)
1
16
0,75+
1
8
43
.
c)2723 +
1
16
0,75 250,5. d)(0, 5)4 6250,25
2
1
4
1 12
.
e)810,75 +
1
125
13
1
32
35
. f) 102+
7
22+7.51+
7
.
g) 423 431 .223. h) 625 + 46 31 + 26 31 26.5.2. Rt gn cc biu thc sau
a) x
54 y+ xy
54
4
x + 4
y . b)
a13
b + b
13
a
6
a + 6
b.
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Nguyn Minh Hiu
c)
a b
4
a 4b
a 4ab4
a + 4
b. d)
a b3
a 3b a + b3
a + 3
b.
e)
a23 1
a23 + a
3 + a3
3
a43 a3 .
f)
a + b3
a + 3
b 3
ab
:
3
a 3
b2
.
g) a 1a34 + a
12
.
a + 4
a
a + 1 .a
14 + 1. h) a +
b32
a12
a12 b 12
a12
+ b
12
a12
b12
23
.
5.3. Hy so snh cc cp s saua) 3
10v 5
20. b) 4
13v 5
23.c)3600 v5400. d) 3
7 +
15v
10 + 3
28.
5.4. Tnh A =
a + b + c + 2
ab + bc +
a + b + c 2ab + bc, (a, b, c >0, a + c > b)
2. Lgarit
A. Kin Thc Cn Nh
1. nh ngha. = logab
a =b (a,b >0; a
= 1).
2. Tnh cht. loga1 = 0. logaa= 1. alogab =b. loga(a) =.Khi a >1 th logab >logac b > c. Khi 0< a logac b < c.
3. Quy tc tnh. loga(bc) = logab + logac. loga bc = logab logac. loga 1b = logab. logab =logab. loga n
b= 1
nlogab. logab= logac.logcb.
logab= 1logba . logab= 1 logab.4. Lgarit thp phn v lgarit t nhin.
Lgarit thp phn: L lgarit c c s a= 10. K hiu: log xhoc lg x.Lgarit t nhin: L lgarit c c s a= e. K hiu: ln x.
B. Bi Tp
5.5. Tnha)log3
4
3. b)2log27log 1000. c)log258.log85.d) log 45 2log3. e)3log2log416 + log 1
22. f)log248 13 log227.
g)5 ln e1 + 4ln
e2
e
. h) log 72 2log 27256
+ log
108. i)log 0, 375 2log0, 5625.5.6. n gin biu thc
a) log24 + log2
10
log220 + log28 . b)
log224 12 log272log318 13 log372
. c)
log72 +
1
log57
log7.
d) logaa2. 3
a. 5
a4
4
a . e)log5log5
5
5
... 5
5 n du cn
. f)92log34+4log812.
g)161+log45 + 412log23+3log55. h)
81
14 1
2log94 + 25log1258
49log72. i)72
49
12log79log76 + 5log54
.
5.7. So snh cc cp s sau:a)log3
65 v log3
56 . b)log 12 evlog 12 . c)log210vlog530.
d) log53vlog0,32. e)log35 vlog74. f)log310vlog857.
5.8. Tnh log41250theo a, bit a = log25.
5.9. Tnh log54168theo a, b, bit a= log712, b= log1224.
5.10. Tnh log14063theo a , b, c, bit a = log23, b= log35, c= log72.
5.11. Tnh log 325135theo a, b, bit a= log475, b= log845.
5.12. Chng minh rng ab + 5 (a b) = 1, bit a= log1218, b= log2454.5.13. Cho y = 10
11log x , z= 10
11log y . Chng minh rng x = 10
11log z .
5.14. Cho a,b,c >0. Chng minh rng (abc)a+b+c
3 aabbcc.
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Chuyn 5. Hm S Ly Tha. Hm S M & Hm S Lgarit
3. Hm S Ly Tha. Hm S M & Hm S Lgarit
A. Kin Thc Cn Nh
1. Hm s lu tha.Dng: y = x ( R).
Tp xc nh:
Nunguyn dng th D = R.Nu= 0hoc nguyn m th D= R\ {0}.Nukhng nguyn th D = (0; +).
o hm: y= x1.Tnh cht: (Xt trn (0;+))
>0: Hm s lun ng bin. 0 1: Hm s lun ng bin.a 1 0< a 1: Hm s lun ng bin.a 1 0< a 0: ax =b x= logab.
2. Bt phng trnh m c bn.Dng: ax > b (0< a = 1).Cch gii:
b 0: S= R.b >0, a >1: ax > b x >logab.
0< a b x
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B. Phng Phng Gii C Bn
a v cng c s. t n ph.Ly lgarit hai v. S dng tnh n iu ca hm s m.
C. Bi Tp
5.18. Gii cc phng trnh saua)22x1 = 3. b)2x
2x = 4.c)2x
2x+8 = 413x. d)3x.2x+1 = 72.e)32x1 + 32x = 108. f)2x + 2x+1 + 2x+2 = 3x + 3x1 + 3x2.
g)
3 + 2
2x+1
=
3 222x+8. h)5 26x23x+2 5 + 26 1x22 = 0.5.19. Gii cc bt phng trnh sau
a)2x2+3x 5x+1 5x+2. d)2x + 2x+1 + 2x+2 0, 25.128
x+17x3 . h)2x
2
.7x2+1 0. b)32.4x + 1 < 18.2x.c)5x + 51x >6. d)
2 +
3x
+
2 3x >4.5.22. Gii cc phng trnh sau
a)
5 26
x
+
5 + 2
6
x
= 10. b) (B-07)
2 1
x
+
2 + 1
x 22 = 0.
c)7 + 3
5x + 5.7 3
5x = 6.2x. d) 5 + 2
6x
+ 5 2
6x
= 10.e)
7 + 4
3x 32 3x + 2 = 0. f)26 + 153x + 27 + 43x 223x = 1.
5.23. Gii cc phng trnh saua)3.4x 2.6x = 9x. b)2.16x+1 + 3.81x+1 = 5.36x+1.c)4x+
x22 5.2x1+
x22 6 = 0. d)5.2x = 7
10x 2.5x.
e)27x + 12x = 2.8x. f) (A-06)3.8x + 4.12x 18x 2.27x = 0.5.24. Gii cc bt phng trnh sau
a)27x + 12x 4.3x + 3.2x. b)4x
2+x + 21x2 2(x+1)2 + 1.
c)52x+1 + 6x+1 >30 + 5x.30x. d)52x103x2 4.5x5
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Chuyn 5. Hm S Ly Tha. Hm S M & Hm S Lgarit
5.29. Gii cc phng trnh saua)22x 2x + 6 = 6. b)32x + 3x + 7 = 7.c)27x + 2 = 3 3
3x+1 2. d)7x1 = 6log7(6x 5) + 1.
5.30. Gii cc phng trnh saua)2x
2
= 3x. b)2x24 = 3x2.
c)5x.8x1x = 500. d)8
xx+2 = 4.34x.
5.31. Gii cc phng trnh saua)3x
2
= cos 2x. b)2|x| = sin x.c)2x1 + 2x
2 x.2x1 2x2x = (x 1)2. d)22x+1 + 232x = 8log3(4x24x+4) .
5. Phng Trnh & Bt Phng Trnh Lgarit
A. Kin Thc Cn Nh
1. Phng trnh lgarit c bn.Dng: logax= b (0< a = 1).
Cch gii: log
a
x= b
x= ab.
2. Bt phng trnh lgarit c bn.Dng: logax > b (0< a = 1).
Cch gii: a >1: logax > b
x > ab.
0< a b 0< x < ab.Lu . Cc dng logax b;logax < b;logax bda vo du c cch gii tng ng.
B. Phng Phng Gii C Bn
a v cng c s. t n ph.S dng tnh n iu ca hm s lgarit.
C. Bi Tp
5.32. Gii cc phng trnh saua)log3(x
2) = 2. b)log3(5x + 3) = log3(7x + 5).
c)log2 x2 1= log 12 (x 1). d)log2x + log2(x 2) = 3.e)log2
x2 + 8
= log2x + log26. f) log3(x + 2) + log3(x 2) = log35.
g)log3x + log4x= log5x. h)log2x + log3x + log4x= log20x.
5.33. Gii cc bt phng trnh saua)log8(4 2x) 2. b)log3
x2 + 2
+ log 1
3(x + 2) < 0.
c)log 15
(3x 5)> log 15
(x + 1). d)log2(x + 3) < log4(2x + 9).
5.34. Gii cc phng trnh saua)log2
x2 + 3x + 2
+ log2
x2 + 7x + 12
= log224. b)log
x3 + 8
= log (x + 58) + 12log
x2 + 4x + 4
.
c) 12
log2(x + 3) + 14
log4(x 1)8 = log24x. d) 32 log 14 (x + 2)2 3 = log 1
4(4 x)3 + log 1
4(x + 6)
3.
e)log2
x + 1 log 12
(3 x) log8(x 1)3 = 0. f) log 12 (x 1) + log 12 (x + 1) log 12 (7 x) = 1.g)log2 8 x2 + log 12 1 + x +1 x 2 = 0. h)log2(4x + 15.2x + 27) + 2log2 14.2x3 = 0.
5.35. Gii cc phng trnh saua)log2
x x2 1 + 3log2 x + x2 1= 2. b) (A-08)log2x1 2x2 + x 1+logx+1(2x 1)2 = 4.
c)log2
x x2 1 .log3 x +x2 1= log6 x x2 1.5.36. Gii cc bt phng trnh sau
a) (A-07)2log3(4x 3) + log 13
(2x + 3) 2. b)log 12
x + 2log 14
(x 1) + log26 0.c) (D-08)log 1
2
x23x+2x 0. d)log0,5 x+12x1 >1.
e) log2
3.2x1 1
x 1. f)
log2(1 3log27x) 1log2x
log3log 1
5
x2 + 1 x.
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5.38. Gii cc phng trnh saua)log22 x 3log2x + 2 = 0. b)log 12 x + log
22 x= 2.
c)2log2x log3x= 2 log x. d)log2x3 20logx + 1 = 0.e)
log3x +
4 log3x= 2. f) log2(2x + 1) .log2
2x+1 + 2
= 2.g)log3(3
x + 1) .log3
3x+2 + 9
= 3. h)log2(5x 1) .log4(2.5x 2) = 1.
5.39. Gii cc bt phng trnh sau
a)log22(2x + 1) 3log(2x + 1) + 2 > 0. b)log29(x 1) 3log3(x 1) + 1 0.c)logx14 1 + log2(x 1). d)log2(2x 1)log 12
2x+1 2> 2.
e)log4(19 2x)log2 192x
8 1. f) log5(4x + 144) 4log52< 1 + log5
2x2 + 1
.
5.40. Gii cc bt phng trnh sau
a)
log2x +
logx2 43 . b) 3
log 12
x + log4x2 2> 0.
c)
log22 x + log 12
x2 3> 5 log4x2 2. d) log22 x + log2x4 8> log2 x24.5.41. Gii cc bt phng trnh sau
a)log2x64 + logx216 3. b)logx(125x) .log25x > 32 + log25 x.c) (C-2012)log2(2x). log3(3x)> 1. d)log 1
3x + 1 4log
212
x 11 x. b)1 +15x 4x.c)1 + 2x+1 + 3x+1 2.3log x2+2.e)log7x 0, h phng trnh
ex ey = ln (1 + x) ln (1 + y)y x= a c nghim duy nht.
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