mechanics lecture 4, slide 1 comprehensive review a) exam information b) what kind of questions? c)...
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Mechanics Lecture 4, Slide 1
Comprehensive Review
Comprehensive Reviewa) Exam informationb) What kind of questions?c) Review
Midterm 3 Exam in-class
Mechanics Lecture 8, Slide 2
Average = 5.1/12
Average = 57% (normalized to 9)
%100*943
correctedclassin NNScore
The score for Midterm 3 will be calculated with the following formula:
Final Exam Review the following material
homework problems. video pre-lectures/textbook. Lecture slides Unit Main Points
Multiple choice…but show your work and justification. Mostly Calculations…”step by step” Some Conceptual questions…like checkpoint problems. Bring calculators and up to ten sheets of notes.
It is best to prepare your own hand-written notes! Derived Equations may be helpful…(e.g. projectile
motion)
Mechanics Lecture 8, Slide 3
What we covered…
Mechanics Lecture 8, Slide 4
Kinematics Description of Motion
Force Dynamics-how objects change velocity
Energy Kinetic and Potential
Conservation Laws Momentum and Energy
Collisions Elastic and In-elastic
Rotations Torque/ Angular Momentum/Statics
Problem Solving Techniques
Mechanics Lecture 8, Slide 5
Visualize/Diagram “Sketch” problem Identify variables, input and what we are trying to solve Free-body diagrams
Express in Mathematical Equations Scalars-1d Vectors-2d,3d Break into components System of n-equations with n-unknowns Use Mathematical tools to solve:
Quadratic Equation Vector operations Trigonometry
Conceptual Understanding Does answer make sense?
Potential Problem Topics
Mechanics Lecture 8, Slide 6
Projectile MotionRelative Motion - 2dUniform Circular MotionForces
Weight (near earth) Gravitational (satellite) Springs Normal Force Tension Friction
Free-Body DiagramsWork-Kinetic EnergyPotential Energy
Center of MassConservation of
MomentumCollisions
In-elastic Elastic
Rotations Kinematics Dynamics Statics Moment of Inertia Torque
Angular Momentum
Relevant Formulae
Mechanics Review 2 , Slide 7
Relevant Formulae
Mechanics Review 2 , Slide 8
Kinematics
Mechanics Lecture 8, Slide 9
HyperphysicsMotion
Mechanics Lecture 1, Slide 10
Displacement vs timet
Velocity vs timet
Acceleration vs timet
HyperphysicsMotion
Mechanics Lecture 1, Slide 11
1d-Kinematic Equations for constant acceleration
Mechanics Lecture 1, Slide 12
))((2)))((
2
1)(
)(
)(
020
2
002
0
00
0
xtxavtv
xtvtatx
vtatv
ata
Basic Equations to be used for 1d – kinematic problems.
Need to apply to each object separately sometimes with time offset
When acceleration changes from one constant value to another say a=0 The problem needs to be broken down into segments
Ballistic Projectile Motion Quantities
Mechanics Lecture 2, Slide 13
Initial velocityspeed,angle
Maximum Height of trajectory, h=ymax
Range of trajectory, D
Height of trajectory at arbitrary x,t
“Hang Time”Time of Flight, tf
Derived Projectile Trajectory Equations
Mechanics Lecture 1, Slide 14
2
000 cos2
1
cossin)(
v
xg
v
xvxy
200 2
1)( gttvyty y
Height of trajectory as f(x), y(x)
Height of trajectory as f(t) , y(t)
g
vD
2sin20
g
v
g
vt y
f
sin2200
g
vyh
2
sin 220
0
Range of trajectory
Time of Flight (“Hang Time”)
Maximum height
Relative Motion in 2 Dimensions
Mechanics Lecture 3, Slide 15
Speed relative to shore
Direction w.r.t shoreline
Uniform Circular Motion
Mechanics Lecture 8, Slide 16
Mechanics Lecture 3, Slide 17
Uniform Circular Motion
Constant speed in circular path
Acceleration directed toward center of circle
What is the magnitude of acceleration?
Proportional to:1. Speed
2. time rate of change of angle or angular velocity
fTdt
d 22
v = wR
R
vac
2
Dynamics
Mechanics Lecture 8, Slide 18
Inventory of Forces
Mechanics Lecture 5, Slide 19
Weight Normal Force Tension Gravitational Springs …Friction
Mechanics Lecture 5, Slide 20
Mechanics Lecture 5, Slide 21
http://hyperphysics.phy-astr.gsu.edu/hbase/N2st.html#c1
Mechanics Lecture 6, Slide 22
m2
m2g
T
N
f
m1
m1g
T
m2
m1
g
1) FBD
1) FBD2) SF=ma
add
N = m2g
T – m m2g = m2a m1g – T = m1a
m1g – m m2g = m1a + m2a
a = m1g – m m2g
m1 + m2
m2
m2g
T
N
f
m1
m1g
T
m2
m1
g
Mechanics Lecture 6, Slide 23
T is smaller when a is bigger
m1g – T = m1a
T = m1g – m1aa = m1g – m m2g
m1 + m2
m2
m2g
T
N
f
m1
m1g
T
m2
m1
g
Mechanics Lecture 6, Slide 24
1) FBD2) SF=ma
Gravitation Problems…too!
Mechanics Lecture 5, Slide 25
2221
satellitemarscenter
satellitemars
r
mmG
r
mmGF
Mechanics Lecture 5, Slide 26
m
F
R
va
r
mmGF
gravc
grav
2
221
r
mGr
m
Fv
m
r
r
mmGr
m
Fv
rm
Frav
mars
sat
grav
sat
satmars
sat
grav
sat
gravc
2
Be careful what value you use for r !!! Should be distance between centers of mass of the two objects
Work-Kinetic Energy Theorem
The work done by force F as it acts on an object that moves between positions r1 and r2 is equal to the change in the object’s kinetic energy:
Mechanics Lecture 7, Slide 27
KW
ldFWr
r
2
1
2
2
1mvK
But again…!!!
Energy Conservation Problems in general
Mechanics Lecture 8, Slide 28
)()( tUtKUKUKE ffiimechanical
For systems with only conservative forces acting
0 mechanicalE
Emechanical is a constant
Determining Motion
Force Unbalanced Forces acceleration
(otherwise objects velocity is constant)
Determine Net Force acting on object
Use kinematic equations to determine resulting motion
Mechanics Lecture 8, Slide 29
Energy Total Energy Motion, Location
Work Conservative forces
Motion from Energy conservation
aF
m
Fa
1221 FF
UKEmechanical
veconservatinonmechanical WE
KldFWfr
r
netnet
0
0
KUE
KWU
mechanical
net
fmechanicaliif
fmechanicaliif
mechanicaliifinalmechanical
fffinalmechanical
UEUKm
v
UEUKK
EUKE
UKE
2
,
,
;...0vatv f
Friction
Mechanics Lecture 8, Slide 30
“It is what it has to be.”
Block
Mechanics Lecture 5, Slide 31
2
22
2sinsin
sin
2
2
1
t
xgmmamgf
m
fmg
m
Fa
t
xaatx
k
knet
Work & Kinetic Energy
Mechanics Lecture 8, Slide 32
Example Problem
Mechanics Lecture 8, Slide 33
xTldTWtension
20
2
20
2
2
12
1
vvmWW
vvmK
KWW
KWWW
ftensionfriction
f
tensionfriction
frictiontensionnet
Potential Energy
Mechanics Lecture 8, Slide 34
Example Problems
Mechanics Lecture 8, Slide 35
xhh
xhmgxmgmghmgh
WEE
xmgW
WE
ki
kiki
frictioninitialmechanicalfinalmechanical
kfriction
frictionmechanical
,,
Conserve Energy from initial to final position.
2v ghhh
Example: Pendulum
Mechanics Review 2 , Slide 36
2
2
1mvmgh ghv 2
ghv 2
Gravitational Potential Problems
Mechanics Lecture 8, Slide 37
gravitymechanical hUhmvUKE )()(2
1 2
conservation of mechanical energy can be used to “easily” solve problems.
Define coordinates: where is U=0?
M
M
E
Etotal
M
MMMoon
E
EEEarth
rr
mGM
rr
mGMrU
r
mGMrU
r
mGMrU
)(
)(
)(
0)( r
mGMrU E as r
rEr
Err
Mr
Mrr
Add potential energy from each source.
Collisions
Mechanics Lecture 8, Slide 38
Center of Mass Conservation of
Momentum
Inelastic collisions
Elastic Collisions
Impulse and Reference Frames
Multiple particles, Solid Objects
00 tottot
ext Pdt
dPF
Isolated system, No external force
Non-conservative internal force
0
0
tot
tot
P
K
Conservative internal force
0
0
tot
tot
P
K
Individual Particle changes momentum due to Force acting over a given duration
Favg = DP/Dt
Systems of Particles
Mechanics Lecture 8, Slide 39
Example Problem
Mechanics Lecture 8, Slide 40
58.0231
125.0301
ii
iii
cm m
xmx
1
22
2
12
1
21
2
2
12
211
222
211
2
1
21
2
2
122
2
112
221121
2211
2121
00
m
m
mm
m
m
vmm
m
vm
vm
vm
K
K
vm
mv
m
vmv
vmvmmm
vmvm
m
vmv
ii
iii
cm
Collisions
Mechanics Lecture 8, Slide 41
Example Problem
Mechanics Lecture 8, Slide 42
fiif
ffii
ffftotal
iiitotal
total
vmvmvmm
v
vmvmvmvm
vmvmp
vmvmp
p
,11,22,112
,2
,22,11,22,11
,22,11,
,22,11,
1
0
222
2
12
,22,11,1,2
,22,112
,22
1
,21,22,112
,2
,1,2
3)(22
1)2(
2
1
0)
21
1(2
22
)1(
1)1(
1
mvvmvmK
m
mvvm
mm
m
vmvmvv
vmvmm
vm
m
vmvmvmm
v
vv
i
iiff
iif
fiif
ff
23
0
mvK
K f
Example Problem :
Mechanics Review 2 , Slide 43
21
1,1,
*1,
*1
21
1,1,1,
*1
21
112211
21
1
1
1
mm
mvvv
mm
mvvvv
mm
vmvmvm
mmv
iif
iCMii
CM
Impulse
Mechanics Lecture 8, Slide 44
|Favg | = |DP | /Dt = 2mv cosq /Dt
Mechanics Lecture 13, Slide 45
Rotations
Mechanics Lecture 8, Slide 46
Rotational Kinematics
Moment of Inertia
Torque
Rotational Dynamics
Rotational Statics
Angular Momentum
Description of motion about a center of mass
Resistance to changes in angular velocity
Force applied at a lever arm resulting in angular acceleration
Newton’s 2nd law for rotations
How to ensure stability
Vector Quantity describing object(s) rotation about an axis
Rotational Kinematics
Mechanics Lecture 8, Slide 47
Rotational Dynamics
Mechanics Lecture 8, Slide 48
Example Problem
Mechanics Lecture 8, Slide 49
I
MRI
MLL
MMLI
MRI
hoop
endrod
disk
2
222,
2
3
1)
2(
12
12
1
Example Problem
Mechanics Lecture 8, Slide 50
Work & Energy (rotations)
Mechanics Lecture 8, Slide 51
Example Problem
Mechanics Lecture 8, Slide 52
f
f
f
FMa
R
a
RFMR
FMgMa
MgN
5
2
5
2
sin
cos
2
sin7
5
sin)5
21(
5
2sin
ga
ga
MaMgMa
sin7
2sin
7
5
5
25
2
MggMF
MaF
f
f
Statics
Mechanics Lecture 8, Slide 53
Statics Problems
Mechanics Lecture 18, Slide 54
Example Problem
Mechanics Lecture 8, Slide 55
Angular Momentum
Mechanics Lecture 8, Slide 56
Example Problem
Mechanics Lecture 8, Slide 57
Relevant Formulae
Mechanics Review 2 , Slide 58
Relevant Formulae
Mechanics Review 2 , Slide 59