network solving
TRANSCRIPT
80V
R1 10Ω
R212Ω
R320Ω
80V
R1 10Ω
Redraw circuit , replace 2 parrellel resistors with one:
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
80V
R1 10Ω
Redraw circuit , replace 2 parrellel resistors with one:1/Rt = 1/R2 + 1/R3
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
80V
R1 10Ω
Redraw circuit , replace 2 parrellel resistors with one:1/Rt = 1/R2 + 1/R31/Rt = 1/12 + 1/20
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
80V
R1 10Ω
Redraw circuit , replace 2 parrellel resistors with one:1/Rt = 1/R2 + 1/R31/Rt = 1/12 + 1/201/Rt = 2/15
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
80V
R1 10Ω
7.5 Ω
Redraw circuit , replace 2 parrellel resistors with one:1/Rt = 1/R2 + 1/R31/Rt = 1/12 + 1/201/Rt = 2/15 Rt = 7.5 Ω
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
80V
R1 10Ω
7.5Ω
80V 17.5Ω
Replace 2 resistors in series, for one:10 Ω + 7.5Ω = 17.5 Ω
80V
R1 10Ω
R212Ω
R320Ω
80V
R1 10Ω
7.5Ω
80V 17.5Ω
R total = 17.5ΩI total = Vt/ Rt = 80V/17.5ΩI total = 4.57A
80V
R1 10Ω
R212Ω
R320Ω
4.57A
80V
R1 10Ω
7.5Ω
4.57A
80V 17.5Ω
4.57A
R total = 17.5ΩI total = Vt/ Rt = 80V/17.5ΩI total = 4.57ADRAW THIS ON YOUR CIRCUITS
80V
R1 10Ω
R212Ω
R320Ω
4.57A
80V
R1 10Ω
7.5Ω
4.57A
80V 17.5Ω
4.57A
Work out Voltdrops:VR1 = R1x IVR1 = 10Ω x 4.57A
80V
R1 10Ω
R212Ω
R320Ω
4.57A
80V
R1 10Ω
7.5Ω
4.57A
80V 17.5Ω
4.57A
Work out Voltdrops:VR1 = R1x IVR1 = 10Ω x 4.57AVR1 = 45.7 V
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
80V 17.5Ω
4.57A
Work out Voltdrops:VR1 = R1x IVR1 = 10Ω x 4.57AVR1 = 45.7 VDRAW RESULT ON THE CIRCUIT
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
80V 17.5Ω
4.57A
Work out Voltdrops:VR1 = R1x IVR1 = 10Ω x 4.57AVR1 = 45.7 VDRAW RESULT ON THE CIRCUITV7.5Ω = 7.5Ωx 4.57A
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
80V 17.5Ω
4.57A
Work out Voltdrops:VR1 = R1x IVR1 = 10Ω x 4.57AVR1 = 45.7 VDRAW RESULT ON THE CIRCUITV7.5Ω = 7.5Ωx 4.57A = 34.275V
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
80V 17.5Ω
4.57A
Work out Voltdrops:VR1 = R1x IVR1 = 10Ω x 4.57AVR1 = 45.7 VDRAW RESULT ON THE CIRCUITV7.5Ω = 7.5Ωx 4.57A = 34.275VDRAW RESULT ON THE CIRCUIT
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
Work out Voltdrops:VR1 = R1x IVR1 = 10Ω x 4.57AVR1 = 45.7 VDRAW RESULT ON THE CIRCUITV7.5Ω = 7.5Ωx 4.57A = 34.275VDRAW RESULT ON THE CIRCUIT
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTS
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2 = 34.275V/12Ω
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2 = 34.275V/12Ω = 2.85A
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2 = 34.275V/12Ω = 2.85AIR3 = VR3/ R3
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2 = 34.275V/12Ω = 2.85AIR3 = VR3/ R3 = 34.275V/20Ω
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2 = 34.275V/12Ω = 2.85AIR3 = VR3/ R3 = 34.275V/20Ω = 1.71A
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2 = 34.275V/12Ω = 2.85AIR3 = VR3/ R3 = 34.275V/20Ω = 1.71ADRAW RESULTS ON CIRCUIT
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
1.71A
2.85A
80V
R1 10Ω
7.5Ω
4.57A 45.7 V
34.275V
80V 17.5Ω
4.57A
WORK OUT BRANCH CURRENTSIR2 = VR2/ R2 = 34.275V/12Ω = 2.85AIR3 = VR3/ R3 = 34.275V/20Ω = 1.71ADRAW RESULTS ON CIRCUIT
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
1.71A
2.85A
Now that you have all the branch currents you can work out anything required:
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
1.71A
2.85A
Now that you have all the branch currents you can work out anything required:Power: PR1 = I x V
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
1.71A
2.85A
Now that you have all the branch currents you can work out anything required:Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
1.71A
2.85A
Now that you have all the branch currents you can work out anything required:Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
1.71A
2.85A
Now that you have all the branch currents you can work out anything required:Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W
Solve the Network:
80V
R1 10Ω
R212Ω
R320Ω
4.57A 45.7 V
34.275V
1.71A
2.85A
Now that you have all the branch currents you can work out anything required:Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W PR3 = I x V
Solve the Network: