od khách

7/25/2019 od khch

1/14

TNH N NH

I. Gii thiu chungLoi tu Tu t hnh, ch khch

Tu v thp , kt cu hnVng hot ng Vng VR-SBChiu di ln nht Lmax = 22.80 mChiu rng ln nht Bmax = 4.00 m

Chiu di thit k L = 21.42 mChiu rng thit k B= 3.60 mChiu cao mn D= 1.65 mMn nc ton ti dSB= 0.64 mLng chim nc D= 25.27 TTrng ti ton phn P = 8.83 TH s bo th tch Cb= 0.525Thuyn vin+phc v 6 ngiHnh khch 79 ngiTng cng sut my chnh 326 CVCp tu VR- SB

VRH HSC4 FRP , VRM HSC 4Qui chun p dng Qui chun quc gia: QCVN 72: 2013/BGTVT

II. Tnh n nh

2.1 Cc trng thi tnh ton

Trng thi 1. Tu khch, 100% d trTrng thi 2. Tu khch, 10% d trTrng thi 3. Tu khng khch, 10% d tr

2

7/25/2019 od khch

2/14

TNH N NH

2.2 Tnh khi lng v trng tm tu (khch tp trung trn boong cao nht)

Trng thi 1. Tu khch, 100% d tr

Trng lng thnh phn Gi, T Xgi, m Zi, m GiXi, tm GiZi,tm

16.41 -2.72 1.05 -44.6 17.23

5.925 1.2 1.5 7.1 8.89

1 -6.25 1.64 -6.3 1.64

1.2 5.8 0.8 7.0 0.960.1 -6.25 1.64 -0.6 0.16

0.6 8 2 4.8 1.20

Nc thi 0.03 -4.0 0.2 -0.1 0.01

25.27 -32.8 30.09

Xg= -1.30 m

Zg= 1.191 m



16.41 -2.72 1.05 -44.6 17.23

5.925 1.20 1.50 7.1 8.89

0.1 -6.25 1.40 -0.6 0.14

0.12 5.80 0.30 0.7 0.04

Nc ngt

Du t

Tu khng

Tu khng

Nc ngt

Du tLng thc thc phm

Thuyn vin

Khch

Khch

Tng hp

0.01 -6.25 1.40 -0.1 0.01

0.6 8.00 2.00 4.8 1.20

Nc thi 0.3 -4.00 0.40 -1.2 0.12

Tng hp 23.5 -33.9 27.63

Xg= -1.445 m

Zg= 1.177 m

Trng thi 3. Tu khng khch, 10% d tr


16.41 -2.72 1.05 -44.6 17.23

0.00 0.00 0.00 0.0 0.00

0.10 -6.25 1.40 -0.6 0.14

0.12 5.80 0.30 0.7 0.04

0.01 -6.25 1.40 -0.1 0.01

0.60 8.00 2.00 4.8 1.20

Nc thi 0.3 -4.00 0.4 -1.2 0.12Tng hp 17.54 -41.03 18.74

Xg= -2.339 m

Zg= 1.068 m

Du t

Lng thc thc phm

Lng thc thc phm

Khch

Thuyn vin

Nc ngt

Thuyn vin

Tu khng

3

7/25/2019 od khch

3/14

TNH N NH

2.3 TNH NH HNG CA HNG LNG3.2 Tnh m men qun tnh mt thong hng lng

DMl30 = l30*V*bgCB1/2

DMh= 0.0384*V*b2*gCB1/2/h

STT Tn kt nc ngt du t

1 S ket 1 2

2 V (m3) 1.00 0.70

3 l,m 1.00 0.504 b,m 1.00 1.50

5 h,m 1.00 1.00

6 g 1 0.86

7 CB 1.00 0.93

8 DMl30 0.060 0.104

9 DMh 0.038 0.112

Tng 0.038 0.112

Dmin = 17.5 (Trng thi Dmin). Do 0.01Dmin = 0.175

Nhng kt c DMho< 0.01Dminth khng tnh nh hng mt thong

TT Trng thi Mh ,Tm

1 Trng thi 1 0.150

2 Trng thi 2 0.02

3 Trng thi 3 0.02

4

7/25/2019 od khch

4/14

TNH N NH

2.3 Tnh cn bng v n nh ban u

Cc i lng tnh Cng thc tnh TT1 TT2 TT3

Lng chim nc D 25.27 23.47 17.54

Th tch lng chim nc V = D/g 24.65 22.89 17.11

Chiu chm d 0.640 0.611 0.515

Honh tm ni (m) Xc -1.302 -1.309 -1.301

Cao tm ni (m) Zc 0.415 0.399 0.343

Honh trng tm N (m) Xf -1.189 -1.225 -1.440Chiu cao tm chi (m) ZM 74.812 79.249 97.909

Chiu cao tm nghing (m) Zm 2.480 2.595 3.104

Honh trng tm (m) Xg -1.30 -1.45 -2.34

Cao trng tm (m) Zg 1.19 1.18 1.07

Gia s chiu chm (m) dd= (Xg-Xc)L/(ZM-Zg) 0.00 -0.04 -0.23

Gia s chiu li (m) dda= (L/2+Xf)dd/L 0.00 -0.02 -0.10

Gia s chiu mi (m) ddf=(L/2-Xf)dd/L 0.00 -0.02 -0.13

Chiu chm li (m) dA = d - dda 0.64 0.63 0.61

Chiu chm mi (m) dF = d + ddf 0.64 0.59 0.38

Chiu chm trung bnh (m) dM = (dA+dF)/2 0.64 0.61 0.50M men chi 1cm (Tm) Mc1cm=D.(Zm-Zg)/100 0.87 0.86 0.79

Mmen m.thong hng lng (Tm) Mh 0.15 0.02 0.02

Hiu chnh do mt thong (m) dh = SMh/D 0.01 0.00 0.00

Chiu cao n nh ban u (m) ho =Zm -Zg- dh 1.28 1.42 2.04

M men nghing 1 (Tm) Md = D.ho/57,3 0.57 0.58 0.62

5

7/25/2019 od khch

5/14

TNH N NH

2.4. Tnh gc lc

C hoc khng c vy gim lc C

Dng tuyn hnh " B GC

Tng din tch vy gim lc 0.00 m2

STT Hng mc tnh TT1 TT2 TT3

1 h- chiu cao tm nghing, m (dh=0) 1.289 1.417 2.036

2 V-th tch chim nc ca tu, m3 24.65 22.89 17.11

3 Zg- chiu cao trng tm ca tu, m 1.191 1.177 1.0684 B- chiu rng ca tu, m 3.6 3.600 3.600

5 n1=(ho/V1/3)/(Zg/B) 1.34 1.53 2.66

6 mo- tr s ly theo Bng 7/2.4 2.81 3.02 3.53

7 m1= mo/ho0,5 2.47 2.53 2.48

8 B/d 5.63 5.89 6.99

9 m2 -h s tra treo B/d 0.85 0.86 0.92

10 Cb - H s bo th tch 0.525 0.511 0.453

11 m3 -h s tra treo Cb Bng 7/2.6 0.90 0.93 1.00

12 m = m1x m2x m3 1.89 2.04 2.27

13 Bin lc c bn qm 31.00 31.00 31.0014 Bin lc theo dng hng tu 23.25 23.25 23.25

15 Sx/ (L*B) 0.00 0.00 0.00

16 Cw, h s bo din tch ng nc 0.84 0.83 0.80

17 r1 0.14 0.14 0.1418 r2 0.12 0.09 0.00

19 r3 1.94 1.98 2.17

20 r =r1+r2+r3 2.20 2.21 2.31

21 q = rCwB^0.5 3.49 3.48 3.52

22 H s gim do vy gim lc 1.00 1.00 1.00

23 qm, - Bin lc p dng * 23 23 23

2.5. Tnh gc vo nc v gc mp boong nhng nc

im vo nc: Ca thng tng

Ta im vo nc Ypvn, m Zpvn, m

1.85 1.90

STT Hng mc tnh TT1 TT2 TT3

1 Chiu chm tu, m 0.64 0.61 0.52

2 Gc mp boong nhng nc, 29.30 29.99 32.23

3 Cao im vo nc t ng nc, m 1.26 1.29 1.384 Gc vo nc, 34.3 34.9 36.8

6

7/25/2019 od khch

6/14

TNH N NH

2.6 Tnh din tch v trng tm mt hng gi so vi ng nc ZTTrng thi 1. Tu khch, 100% d tr

STT Thnh phn Si, m Zi, m Ki KiSi, m2 MZ,m

2

1 Mn kh 24.88 1.20 1.0 24.88 29.91

2 Thng tng 24.96 2.30 1.0 24.96 57.41

3 Be gi ui 0.40 2.40 2.0 0.80 1.92

Tng hp 1.85 50.64 93.70

Trng thi 2. Tu khch, 10% d trSTT Thnh phn Si, m2 Zi, m Ki KiSi, m

2 MZ,m2

1 Trng thi 1 50.64 1.85 1.00 50.64 93.70

2 Phn ni thm 0.61 0.63 1.00 0.61 0.38

Tng hp 51.25 1.84 94.09


STT Thnh phn Si, m2 Zi, m Ki KiSi, m2 MZ,m

2

1 Trng thi 1 50.64 1.85 1.00 50.64 93.70

2 Phn ni thm 2.68 0.58 1.00 2.68 1.55

Tng hp 53.32 1.79 95.25

7

7/25/2019 od khch

7/14

TNH N NH

2.7. th n nh, n nh ng v tay n cho php


d= 0.64 m

Zg = 1.191 m

Dh = 0.006 m

a = 0.782 m

q, Sinq a sinq lf, m lt, m l, m

-30 0.194-20 0.095

-10 0.026

-5 0.006

0 0.000 0.000 0.000 0.000 0.000

5 0.087 0.068 0.217 0.149 0.006

10 0.174 0.136 0.431 0.295 0.026

20 0.342 0.267 0.767 0.500 0.095

30 0.500 0.391 1.019 0.628 0.194

40 0.643 0.503 1.220 0.717 0.311

50 0.766 0.599 1.321 0.722 0.437

60 0.866 0.677 1.339 0.662 0.557

70 0.940 0.735 1.285 0.550 0.663

80 0.985 0.770 1.177 0.407 0.747

qm= 23.0 qvn= 34.3 lqvn- lqm= 0.119

lm= 0.125 qvn= 0.24 lcf= 0.119

lt max= 0.722

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

-30 -20 -10 0 10 20 30 40 50 60 70 80

lt,

ld(m)

o)

lcf

8

7/25/2019 od khch

8/14

TNH N NH


d= 0.611 m

. Zg = 1.177 m

Dh = 0.001 m

a = 0.779 m


-30 0.199

-20 0.099-10 0.027

-5 0.007

0 0.000 0.000 0.000 0.000 0.000

5 0.087 0.068 0.226 0.158 0.007

10 0.174 0.135 0.446 0.311 0.027

20 0.342 0.266 0.777 0.511 0.099

30 0.500 0.390 1.026 0.636 0.199

40 0.643 0.501 1.230 0.729 0.318

50 0.766 0.597 1.339 0.742 0.447

60 0.866 0.675 1.355 0.680 0.571

70 0.940 0.732 1.297 0.565 0.679

80 0.985 0.767 1.186 0.418 0.765

qm= 23.0 qvn= 34.9 lqvn- lqm= 0.128

lm= 0.129 lvn= 0.26 lcf= 0.127lt max= 0.742

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

-30 -20 -10 0 10 20 30 40 50 60 70 80

lt,

ld(m)

o)

lcf

9

7/25/2019 od khch

9/14

TNH N NH


d= 0.515 m

Zg = 1.068 m

Dh = 0.001 m

a = 0.726 m


-30 0.226

-20 0.116-10 0.034

-5 0.009

0 0.000 0.000 0.000 0.000 0.000

5 0.087 0.063 0.268 0.205 0.009

10 0.174 0.126 0.495 0.369 0.034

20 0.342 0.248 0.817 0.569 0.116

30 0.500 0.363 1.055 0.692 0.226

40 0.643 0.467 1.254 0.788 0.355

50 0.766 0.556 1.391 0.835 0.497

60 0.866 0.629 1.403 0.774 0.637

70 0.940 0.682 1.337 0.655 0.762

80 0.985 0.715 1.214 0.499 0.862

(Trng thi 3)

qm= 23.0 qvn= 36.8 lqvn- lqm= 0.165lqm= 0.149 lqvn= 0.31 lcf= 0.158

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

-30 -20 -10 0 10 20 30 40 50 60 70 80

lt,

ld(m)

o)

lcf

10

7/25/2019 od khch

10/14

TNH N NH

2.8 Tnh n nh theo tiu chun c bn

Tiu chun n nh K = Mchp / Mng > 1,0

Mcf : M men cho php xc nh :

Mchp= D.Lcf (KN)

lchp: Cnh tay n cho php

Mng: M men nghing do gi

Mng= 0,001 p A z (tm)

A : Din tch hng gi, m2

P : p lc ng tnh ton ca gi , Pa

ZT: l chiu cao tm hng gi trn mt phng ng nc ang xt.

i lng tnh TT1 TT2 TT3

D - Lng chim nc trng lng ca tu, kN 247.8 230.2 172.1

Mn nc d, m 0.64 0.61 0.52

A -Din tch mt hng gi 50.64 51.25 53.32

ZT -Chiu cao tmhng gi so vi ng nc , m 1.21 1.224 1.271

P- p sut gi git, Pa, ly theo Bng 7/2.2-1 204.42 204.97 206.86

z -Cnh tay n nghing quy i, m z =ZT+a1*a2*d 1.33 1.36 1.45

a1- h s theo (B/d) 0.73 0.79 1.00

a2 - h s theo (Zg/B) 0.27 0.28 0.35

Mn = 0,001 P A z, KN 13.819 14.252 15.993

Lcf, m 0.119 0.127 0.158

Mcf = D. Lcf, KNm 29.5 29.2 27.2

H s K 2.1 2.0 1.7

11

7/25/2019 od khch

11/14

TNH N NH

2.9 Kim tra cc yu cu b sung v n nh cho tu ch khch:

Tnh gc nghing tnh cho php

TT I TT II

1 2 2

2 1.65 1.65

3 0.64 0.61

4 34.3 34.9

5 29.30 29.99

6 27.4 27.9

7 12.0 12.0

2.9.1 Kim tra n nh khi khch tp trung mt bn mn:

TT I TT II

1 D T 25.3 23.5

2 Pk T 5.925 5.925

3 Y m 0.42 0.42

4 Mk = Pk.Y Tm 2.49 2.49

5 h'o m 1.28 1.42

Chiu cao tm nghing, c nh hng ca mt thong

Kt qa

0.8qvn

Lng chim nc trng lng

Trng lng hnh khch

Tay n nghing

Momen nghing do khch

K.hiui lng tnh

Gc mp boong mn kh nhng nc

Chiu rng mp boong/2

i lng tnh

Kt qa

No

Gc nghing cho php gii hn khi khch tptrung mt bn mn

n v

No.

Chiu chm

Gc vo nc

Chiu cao mp boong

6 qchp 12.0 12.0

7 M1 Tm 0.57 0.58

8 qk=Mk/M1 4 4

9 lcpk m 0.112 0.118

10 Mcpk Tm 2.83 2.76

11 1.14 1.11

(Trng thi 1)

Gc nghing cho php gii hn khi khch tp trung

M men nghing / 1

Momen nghing cho php Mcpk

K1 = Mcpk / Mk =

Tay n cho php lcpk

Gc nghing do khch tp trung mt mn

0

0.1

0.2

0.3

0.4

-10 0 10 20 30 40

lt(m)

o)qcpk

lt

qk

lcpk S1

S2

12

7/25/2019 od khch

12/14

TNH N NH

(Trng thi 2)

2.9.2 Kim tra n nh khi tu quay vng

TT I TT IISTT K.hiu n vi lng tnhMomen quay vng

Kt qu

0

0.1

0.2

0.3

0.4

-10 0 10 20 30 40

lt(m)

o)

qcpk

lt

qk

lcpk

S1

S2

1 Mqv KNm 13.04 12.61

2 c - 0.029 0.0293 V0 m/s 4 4

4 Zg m 1.191 1.177

5 D KN 247.8 230.26 d m 0.64 0.61

7 L m 21.42 21.42

8 B/d - 5.63 5.89

9 a3 - -1.93 -2.21

10 qcpq 27.41 27.89

11 lcpk m 0.278 0.289

12 Mcpk KNm 68.86 66.51

13 Kq - 5.28 5.27

H s c xc nh ti Bng 7/3.1

T s B/d

Vn tc ca tu trc lc quay vng

Lng chim nc trng lngChiu chm

H s xc nh ph thuc thit b y ca tu

Chiu cao trng tm ca tu

Chiu di tu

Kq = Mcpq / Mqv =

Gc nghing cho php qcpq

Tay n cho php lcpq

Momen nghing cho php Mcpk

0qv G 3

VM =c (Z -a d)

L

13

7/25/2019 od khch

13/14

TNH N NH

(Trng thi 1)

(Trng thi 2)

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

-20 -10 0 10 20 30 40 50 60

lt(m)

o)qcpk

lt

qk

lcpk

S1

S2

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

-20 -10 0 10 20 30 40 50 60

lt(m)

o)qcpk

lt

qk

lcpk S1

S2

14

7/25/2019 od khch

14/14

TNH N NH

2.10 Bng so snh vi tiu chun tu cao tc v tiu chun cp VR-SB

TT1 TT2 TT3

0.194 0.199 0.150

0.048 0.072 0.0860.628 0.636 0.692

50 50 50

108.41 108.44 112.16

t t t

TT1 TT2 TT3

Tay n ln nht ca th n nh tnh > 0.25m 0.722 0.742 0.835

108.41 108.44 112.16

Chiu cao tm nghing ban u > 0.2 m 1.29 1.42 2.04

t t t

Gi tr

Theo tiu chun tu cao tcDin tch ng cong GZ

n 30o 0.055 m.rad

Din tch ng cong GZ

t 30o n min(40o,qvn) 0.03 m.radGZ min 0.2m ti gc 30o

GZ max ti gc nghing 15o

Gii hn ng cong n nh tnh 50o

Gc ln ca th n nh tnh khng c nh

hn 50o

Theo cp VR-SB

nh gi

nh gi

2.11 Kt lun + Lu :

- Tu khch n nh hot ng cc trng thi ti trng theo tiu chun c bn

- Tu khch n nh trong trng hp khch tp trung mt bn mn.

- Tu khch n nh trong trng hp phng tin quay vng v khch tp trung 1 bn mn.

- Khi khai thc yu cu hnh khch mc o phao, ngi ng v tr qui nh, hn ch i li trn tu ,hn ch khch ng tp trung sang mt pha mn

- Khi quay vng phi gim tc 14.4 (km/h) = 4 ( m/s)

od khách

Documents