settlement pondasi sederhana
TRANSCRIPT
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8/9/2019 Settlement Pondasi Sederhana
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)
SETTLEMENT TOTAL
1.
Mencari qu (terzaghi) table
Sudut geser Nc Nq N c' Df h L B SF
Pondasi - - - - - 1 - 5 53.0sand loose ( 30) 37.16 22.46 19.73 16.5 0 - 5 - -
medium dense sand ( 40) 95.66 81.27 100.39 17.8 0 - 8 - -
clay ( 20) 17.69 7.44 4.97 18.2 20 - 10 - -
qu = 1.3cNc+ qNq+ 0.4BN = 1.3 (0x37.16) + (1x16.5)(22.46) + 0.4 (16.5x5x19.73) = 410.05 KN/m2
q ijin = qu / SF = 410.05 / 3 = 136.683 KN/m2
Q = q ijin (BxL) = 136.683 (5x5) = 3417.08 KN
2.
z ( distribusi tegangan), z = 5
q = x Df = 16.5 x 1 =16.5 KN/m3
m = 5/5 = 1 n = 5/5 = 1 I = 0.1752 (table 5.2)
z= q x I = 136.683 x 0.1752 = 23.94 KN/m2
B
5 m
8 m
10 m
sand loose
= 16.5 KN/m3
M. dense sand
= 17.8 KN/m3
clay
= 18.2 KN/m3
e = 0.9
Cc = 0.35
qu
1m
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)
3.
Settlement Elastic (Se)
Sudut geser Q B Es m n I3 I4
v Se
corner
(m)
I5 Se
center(m)
Pondasi - 5 - 1 1 0.838 0.167 - - 1.122 -
loose sand (35) 16.5 - 20000 - - - - 0.25 0.00140 - 0.00434
medium sand (40) 16.5 - 25000 - - - - 0.25 0.00112 - 0.00347
clay (20) 16.5 - 750 - - - - 0.5 - - 6.00674
m = L/B = 5/5 = 1
n = B/z = 5/5 = 1
I3= 0.838 (table 5.6)
I4= 0.167 (table 5.7)
I5= 1.122 (table 5.8)
Sand loose
Se(edge) =
(1-0,252) [0,838 -( -
). 0,167]
Se = 0.00140 m = 1.4 mm
Se(center) =
(1-0,25
2) . 1,122
se = 0.00434 m = 4.34 mm
Medium Dense Sand
Se(edge) =
(1-0,252) [0,838 -( -
). 0,167]
Se = 0.00112 m = 1.12 mm
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)
Se(center) =
(1-0,252) . 1,122
se = 0.00347 m = 3.47 mm
Clay
rumus janbu
Df/B 1 h/B L/B 2 Se
2 0.9 2 1 0.36 6.00674
1 = 0.9 (table 5.15)
2 = 0.36 (table 5.16)
Se = 6.00674 m
4. Settlement Pondasi (Sc)
Sudut geser E Cc Hc h1 h2 Iav(h1) Iav(h2) 0 av Sc
Pondasi - - - - 65.274 -
loose sand (30) - - -12
0.37 0.2
99
- 0.11288medium sand(40) - - -
22
63,92- 0.11288
clay (20) 0.9 0.35 10267,813
- -
h1= h medium dense sandDf + h sand loose = 81 + 5 = 12 m
h2= h sand loosedf + h medium dense sand + h clay = 51 + 8 + 10 = 22 m
0 = (Df/h)*I3=1/5 *0.838 = 99
0 = h*(9.81) = 8(17.8-9.81) = 63.92
0 = 3/2*(9.81) = 3/2(18.2-9.81) = 267.813
0 (total) = 430.733
Iav(h1) = 0.37 ( table 5.31)
Iav(h2) = 0.2(table 5.31)
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)
av = 65.274
Untuk loose sand dan medium sand
Sc = 0.11288 m
Stotal = Se + Sc = (0.00434+0.00347+6.00674) + 0.11288 = 6.12744m
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)
LAMPIRAN
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)
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REKAYASA PONDASI
M.SAM SUL HI DAYAT (022113145)